I am stuck with the ObjectBox Like Query. I have done as below when I search for something.
QueryBuilder<MItemDetail> builder = mItemDetailListBox.query();
builder.contains(MItemDetail_.productName, search);
itemList = builder.build().find();
For example, My data is:
paracetamol
paracetamol potest
paracetamol_new
Problem:
Now as you know the contains works simply as that returns a list of items that contain a given search string.
What I Want:
If I search para new, I want the result paracetamol_new
If I search para p, I want the result paracetamol potest
If I search para e e, I want the result paracetamol potest and paracetamol_new
Is there any function or utility available in ObjectBox that can help me to achieve this?
Do let me know If you have any questions.
Edited:
The given links in a comment, My question is different. I know all the methods contains(), startsWith, and endsWith but my problem not getting solved using that.
With Reference to this answer I have done some changes as given and I got a perfect solution as I wanted.
QueryBuilder<MItemDetail> builder = mItemDetailListBox.query();
// builder.contains(MItemDetail_.productName, search);
builder.filter(new QueryFilter<MItemDetail>() {
#Override
public boolean keep(#NonNull MItemDetail entity) {
return like(entity.getProductName(), "%"+ search + "%");
}
}).order(MItemDetail_.productName);
businessModels = builder.build().find();
In the following methods, I have added one more replace statement .replace(" ",".*?")
private static boolean like(final String str, final String expr) {
String safeString = (str == null) ? "" : str;
String regex = quoteMeta(expr);
regex = regex.replace("_", ".").replace(" ",".*?").replace("%", ".*?");
Pattern p = Pattern.compile(regex,
Pattern.CASE_INSENSITIVE | Pattern.DOTALL);
return p.matcher(safeString).matches();
}
private static String quoteMeta(String s) {
if (s == null) {
throw new IllegalArgumentException("String cannot be null");
}
int len = s.length();
if (len == 0) {
return "";
}
StringBuilder sb = new StringBuilder(len * 2);
for (int i = 0; i < len; i++) {
char c = s.charAt(i);
if ("[](){}.*+?$^|#\\".indexOf(c) != -1) {
sb.append("\\");
}
sb.append(c);
}
return sb.toString();
}
Thank you.
I am an android noobie. What I am trying to do is to make this String an ArrayList. This is done. When i Print it On (with tv.setText) , the result is what i need but in this if i have right below i cannot find the "1".
The result i want to have is to store the text between the noumbers inside another ArrayList but to go there i have to be able to read the strings from the ArrayList.
public class MainActivity extends AppCompatActivity {
String text = "1Hello12People22Paul22Jackie21Anna12Fofo2";
TextView tv;
List<String> chars = new ArrayList<>();
#Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
tv = (TextView)findViewById(R.id.tv);
PrinThemNow();
}
public void PrinThemNow(){
chars = Arrays.asList(text.split(""));
tv.setText(toString().valueOf(chars));
for(int i=0;i<chars.size();i++){
if(toString().valueOf(chars.get(i)) == " 1"){
Toast.makeText(this,"I found One",Toast.LENGTH_LONG).show();
//This if is not working while the TV's text shows " 1"
}
}
}
}
First, just a tip, from string to char[] you can use
char[] chars = myString.toCharArray();
because it has no sense to save a char array as a string ArrayList
but now the problem. you have your string and you wanna print the text between the numbers.
It's not really clear what is your goal but lets try.
I will suppose you used the char[] because it's 10 times better and easier
case 1) you wanna print text betweens "1"s
//lets loop the chars
bool firstOneFound = false;
int firstOccurrence = -1;
int secondOccurrence = -1;
int i = 0;
for(char c : chars){
//is it equals to 1?
if(c.equals('1')){
//check if we are already after the first 1
if(firstOneFound){
//if yes, we found the final one
secondOccurrence = i;
break;
}
else{
//this is the first occurrence
firstOccurrence = i;
firstOneFound = true;
}
}
i++;
}
if(firstOccurrence != -1 && secondOccurrence != -1){
String myFinalString = myString.subString(firstOccurrence, secondOccurrence);
}
case 2) you wanna print all text except numbers (maybe with a space instead)
for(char c : chars){
//check if it's a number
if(c >= '0' && c <= '9'){
//replace the number with anything else
c = ' '; //if you wanna have it as a space
}
}
//print the final string
String myFinalString = new String(chars);
NOTE:
You can also use ArrayList of string, just replace ' with "
hope it helps
I want to get a text that it is a part of an string.For example: I have a string like "I am Vahid" and I want to get everything that it's after "am".
The result will be "Vahid"
How can I do it?
Try:
Example1
String[] separated = CurrentString.split("am");
separated[0]; // I am
separated[1]; // Vahid
Example2
StringTokenizer tokens = new StringTokenizer(CurrentString, "am");
String first = tokens.nextToken();// I am
String second = tokens.nextToken(); //Vahid
Try:
String text = "I am Vahid";
String after = "am";
int index = text.indexOf(after);
String result = "";
if(index != -1){
result = text.substring(index + after.length());
}
System.out.print(result);
Just use like this, call the method with your string.
public String trimString(String stringyouwanttoTrim)
{
if(stringyouwanttoTrim.contains("I am")
{
return stringyouwanttoTrim.split("I am")[1].trim();
}
else
{
return stringyouwanttoTrim;
}
}
If you prefer to split your sentence by blank space you could do like this :
String [] myStringElements = "I am Vahid".split(" ");
System.out.println("your name is " + myStringElements[myStringElements.length - 1]);
I have setup an edittext box and set the maxlength to 10. When I copy the edittext to a string myTitles. I need the myTiles to be 10 chars long and not dependent on what is entered in the edittext box.
myTitles[0] = TitlesEdit.getText().toString();
The edittext was filled with ABCD so I need to add 6 spaces or placeholders after the ABCD. I have seen other post with str_pad and substr without success
myTitles[0] = str_pad(strTest, 0, 10);
myTitles[0] = substr(strTest,0, 10);
Try something like
public static String newString(String str) {
for (int i = str.length(); i <= 10; i++)
str += "*";
return str;
}
This will return a String with * replaced for the empty ones.
So, for eg, if your String is abcde, then on calling newString() as below
myTitles[0] = newString("abcde");
will return abcde***** as the output.
String s = new String("abcde");
for(int i=s.length();i<10;i++){
s = s.concat("-");
}
Then output your string s.
Thank you Lal, I use " " to fill and it worked fine. here is my new code.
String strTest = TitlesEdit.getText().toString();
for (int i = strTest.length(); i <= 10; i++) {
strTest += " ";
}
Log.d("TAG", "String" + strTest);
myTitles[intLinenumber] = strTest;
I have a String separated by commas as follows
1,2,4,6,8,11,14,15,16,17,18
This string is generated upon user input. Suppose the user wants to remove any of the numbers, I have to rebuild the string without the specified number.
If the current string is:
1,2,4,6,8,11,14,15,16,17,18
User intents to remove 1, the final string has to be:
2,4,6,8,11,14,15,16,17,18
I tried to achieve this using the following code:
//String num will be the number to be removed
old = tv.getText().toString(); //old string
newString = old.replace(num+",",""); //will be the new string
This might be working sometimes but it is sure that it won't work for the above example I have shown, if I try to remove the 1, it also removes the last part of 11, because there also exists 1.
well you can use this. Its the most simplest approach i can think of:
//String num will be the number to be removed
old=","+tv.getText().toString()+",";//old string commas added to remove trailing entries
newString=old.replace(","+num+",",",");// will be the new string
newString=newString.substring(1,newString.length()-1); // removing the extra commas added
This would work for what you want to do. I have added a comma at the start and end of your string so that you can also remove the first and last entries too.
You can split the string first and check for the number where you append those value that is not equivalent to the number that will get deleted;
sample:
String formated = "1,2,4,6,8,11,14,15,16,17,18";
String []s = formated.split(",");
StringBuilder newS = new StringBuilder();
for(String s2 : s)
{
if(!s2.equals("1"))
newS.append(s2 + ",");
}
if(newS.length() >= 1)
newS.deleteCharAt(newS.length() - 1);
System.out.println(newS);
result:
2,4,6,8,11,14,15,16,17,18
static public String removeItemFromCommaDelimitedString(String str, String item)
{
StringBuilder builder = new StringBuilder();
int count = 0;
String [] splits = str.split(",");
for (String s : splits)
{
if (item.equals(s) == false)
{
if (count != 0)
{
builder.append(',');
}
builder.append(s);
count++;
}
}
return builder.toString();
}
String old = "1,2,4,6,8,11,14,15,16,17,18";
int num = 11;
String toRemove = "," + num + "," ;
String oldString = "," + old + ",";
int index = oldString.indexOf(toRemove);
System.out.println(index);
String newString = null;
if(index > old.length() - toRemove.length() + 1){
newString = old.substring(0, index - 1);
}else{
newString = old.substring(0, index) + old.substring(index + toRemove.length() -1 , old.length());
}
System.out.println(newString);