Develop Reference

How to capitalize the first letter in custom textview?

In Custom TextView suppose if first character as a number then next character would be a character. How to find the first character amoung numbers.

If you are using Kotlin you may go for:
Capitalize first word:
var str = "whaever your string is..."
str.capitalize()
// Whaever your string is...
Capitalize each word
var str = "whaever your string is..."
val space = " "
val splitedStr = str.split(space)
str = splitedStr.joinToString (space){
it.capitalize()
}
// Whaever Your String Is...

Try this method by splitting the entire word
String input= "sentence";
String output = input.substring(0, 1).toUpperCase() + input.substring(1);
textview.setText(output);
Output:
Sentence

You're looking for the inputType parameter in the xml layout file for the TextView. Basically in the layout file where you wish to set the TextView in camel case, add the following line:
android:inputType = "textCapWords"
//This would capitalise the first letter in every word.
If you wish to only capitalise the first letter in the TextView, use the following instead.
android:inputType = "textCapSentences"
//This would capitalise the first letter in every sentence.
If you have a textView which has more than one sentence, and you only want to capitalise the first letter in the TextView, I would recommend using code to do this:
String[] words = input.getText().toString().split(" ");
StringBuilder sb = new StringBuilder();
if (words[0].length() > 0) {
sb.append(Character.toUpperCase(words[0].charAt(0)) + words[0].subSequence(1, words[0].length()).toString().toLowerCase());
for (int i = 1; i < words.length; i++) {
sb.append(" ");
sb.append(Character.toUpperCase(words[i].charAt(0)) + words[i].subSequence(1, words[i].length()).toString().toLowerCase());
}
}
String titleCaseValue = sb.toString();
Hope this helps :)

Use this function pass your string and return capitalize string.
public static String wordCapitalize(String words)
{
String str = "";
boolean isCap = false;
for(int i = 0; i < words.length(); i++){
if(isCap){
str += words.toUpperCase().charAt(i);
}else{
if(i==0){
str += words.toUpperCase().charAt(i);
}else {
str += words.toLowerCase().charAt(i);
}
}
if(words.charAt(i)==' '){
Utility.debug(1,TAG,"Value of i : "+i+" : "+words.charAt(i)+" : true");
isCap = true;
}else{
Utility.debug(1,TAG,"Value of i : "+i+" : "+words.charAt(i)+" : false");
isCap = false;
}
}
Utility.debug(1,TAG,"Result : "+str);
return str;
}

String text = textView.getText().toString();
for(Character c : text){
if(c.isLetter){
//First letter found
break;
}

How can I validate Android edittext for accepting string and integer

What is the validation expression for string(space)integer? I want to enter the data in the format of "month date"(eg.March 22) in database.

I think it'll help you
String abc = "March 2";
String[] split = abc.split(" ");
StringBuilder sb = new StringBuilder();
for (int i = 0; i < split.length; i++) {
sb.append(split[i]);
if (i != split.length - 1) {
sb.append(" ");
}
}
String combined = sb.toString();
At 0 position you'll get your months then get into a String and matches with your static array.
And at 1 position, you'll get your date, you can match it too.

Deleting a word in a String/String Array

So if you are adding in a string, you can just add them via += method(the one i know and using atm). but how can you delete a word in a string/string array?
example: i have a string
String="Monday,Tuesday,Wednesday"
how do you make it into
String="Monday,Wednesday"
any help please?

You could use the replace method.
String sentence = "Monday,Tuesday,Wednesday";
String replaced = sentence.replace("Tuesday,", "");

its easy
just use
yourString = yourString.replaceAll("the text to replace", ""); //the second "" show empty string so the text will get replace by empty string
finally yourString will contain the text u desire Thats it :)

You can use the "public String replace(char oldChar, char newChar)" method if you want to remove "Tuesday" and not the second element
https://stackoverflow.com/questions/16702357/how-to-replace-a-substring-of-a-string

I think, i will use it for simplicity otherwise go to other suggested answer...
Use Arraylist for storing days:
ArrayList<String> days = new ArrayList<String>();
days.add("Monday");
days.add("Tuesday");
days.add("Wednesday");
Use it for creating days string:
public String getDays() {
String daysString = "";
for (int i = 0; i < days.size(); i++) {
if (i != 0)
daysString += ", ";
daysString += days.get(i);
}
return daysString;
}
And whenever you want to remove use
days.remove(1);
or
days.remove("Tuesday");
then again call getDays();
IInd Method if you want to use only string:
String list = "Monday,Tuesday,Wednesday";
System.out.println("New String : " + removeAtIndex(list, 1));
and
public String removeAtIndex(String string, int index) {
int currentPointer = 0;
int lastPointer = string.indexOf(",");
while (index != 0) {
currentPointer = string.indexOf(',', currentPointer) + 1;
lastPointer = string.indexOf(',', lastPointer + 1);
index--;
}
String subString = string.substring(currentPointer,
lastPointer == -1 ? string.length() : lastPointer);
return string.replace((currentPointer != 0 ? "," : "") + subString
+ (currentPointer == 0 ? "," : ""), "");
}

Something like this using a regular expression:
String contents = "Monday,Tuesday,Wednesday";
contents = contents.replaceAll("[\\,]+Tuesday|^Tuesday[\\,]*", "");

How can I effectively replace one or more characters

I have a String separated by commas as follows
1,2,4,6,8,11,14,15,16,17,18
This string is generated upon user input. Suppose the user wants to remove any of the numbers, I have to rebuild the string without the specified number.
If the current string is:
1,2,4,6,8,11,14,15,16,17,18
User intents to remove 1, the final string has to be:
2,4,6,8,11,14,15,16,17,18
I tried to achieve this using the following code:
//String num will be the number to be removed
old = tv.getText().toString(); //old string
newString = old.replace(num+",",""); //will be the new string
This might be working sometimes but it is sure that it won't work for the above example I have shown, if I try to remove the 1, it also removes the last part of 11, because there also exists 1.

well you can use this. Its the most simplest approach i can think of:
//String num will be the number to be removed
old=","+tv.getText().toString()+",";//old string commas added to remove trailing entries
newString=old.replace(","+num+",",",");// will be the new string
newString=newString.substring(1,newString.length()-1); // removing the extra commas added
This would work for what you want to do. I have added a comma at the start and end of your string so that you can also remove the first and last entries too.

You can split the string first and check for the number where you append those value that is not equivalent to the number that will get deleted;
sample:
String formated = "1,2,4,6,8,11,14,15,16,17,18";
String []s = formated.split(",");
StringBuilder newS = new StringBuilder();
for(String s2 : s)
{
if(!s2.equals("1"))
newS.append(s2 + ",");
}
if(newS.length() >= 1)
newS.deleteCharAt(newS.length() - 1);
System.out.println(newS);
result:
2,4,6,8,11,14,15,16,17,18

static public String removeItemFromCommaDelimitedString(String str, String item)
{
StringBuilder builder = new StringBuilder();
int count = 0;
String [] splits = str.split(",");
for (String s : splits)
{
if (item.equals(s) == false)
{
if (count != 0)
{
builder.append(',');
}
builder.append(s);
count++;
}
}
return builder.toString();
}

String old = "1,2,4,6,8,11,14,15,16,17,18";
int num = 11;
String toRemove = "," + num + "," ;
String oldString = "," + old + ",";
int index = oldString.indexOf(toRemove);
System.out.println(index);
String newString = null;
if(index > old.length() - toRemove.length() + 1){
newString = old.substring(0, index - 1);
}else{
newString = old.substring(0, index) + old.substring(index + toRemove.length() -1 , old.length());
}
System.out.println(newString);

String Multiline - Android

i got this issue and i don't know how to solve it. Here is the problem:
1 - i have a data in my database who i split into a strings[] and then i split this strings[] into another 2 strings[] (even and odd lines). Everything works fine but when i want to join all the lines into a single String i got a multi line string intead of a single line. Someone can help me?
data
abcdef//
123456//
ghijkl//
789012
code:
String text = "";
vec1 = data.split("//"); //split the data
int LE = 0;
for (int a = 0; a < vec1.length; a++) { //verify how many even and odds line the data have
if (a % 2 == 0) { //if 0, LE++
LE++;
}
}
resul1 = new String[LE];
int contA = 0, contB = 0;
for (int c = 0; c < resul1.length; c++) {
if (c % 2 != 0) {
text += " " + resul1[c].toLowerCase().replace("Á","a").replace("Ã","a").replace("ã","a").replace("â","a").replace("á","a").replace("é","e").replace("É","e")
.replace("ê","e").replace("í","i").replace("Í","i").replace("ó","o").replace("Ó","o").replace("õ","o").replace("Õ","o").replace("ô","o").replace("Ô", "o")
.replace("Ú","u").replace("ú","u").replace("ç","c").replace("_","").replace("<","").replace(">","");
contA++;
}
}
And the String looks like
abcdef
ghijkl
instead of
abcdefghijkl

You should use replaceAll() method.
text.replaceAll("\\r\\n|\\r|\\n", ""); // the method removes all newline characters