Develop Reference

How to change First letter of each word to Uppercase in Textview xml

i need to change the text="font roboto regular" to Font Roboto Regular in xml itself, how to do?
<TextView
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:gravity="center"
android:textSize="18sp"
android:textColor="#android:color/black"
android:fontFamily="roboto-regular"
android:text="font roboto regular"
android:inputType="textCapWords"
android:capitalize="words"/>

If someone looking for kotlin way of doing this, then code becomes very simple and beautiful.
yourTextView.text = yourText.split(' ').joinToString(" ") { it.capitalize() }

You can use this code.
String str = "font roboto regular";
String[] strArray = str.split(" ");
StringBuilder builder = new StringBuilder();
for (String s : strArray) {
String cap = s.substring(0, 1).toUpperCase() + s.substring(1);
builder.append(cap + " ");
}
TextView textView = (TextView) findViewById(R.id.textView);
textView.setText(builder.toString());

Try this...
Method that convert first letter of each word in a string into an uppercase letter.
private String capitalize(String capString){
StringBuffer capBuffer = new StringBuffer();
Matcher capMatcher = Pattern.compile("([a-z])([a-z]*)", Pattern.CASE_INSENSITIVE).matcher(capString);
while (capMatcher.find()){
capMatcher.appendReplacement(capBuffer, capMatcher.group(1).toUpperCase() + capMatcher.group(2).toLowerCase());
}
return capMatcher.appendTail(capBuffer).toString();
}
Usage:
String chars = capitalize("hello dream world");
//textView.setText(chars);
System.out.println("Output: "+chars);
Result:
Output: Hello Dream World

KOTLIN
val strArrayOBJ = "Your String".split(" ".toRegex()).dropLastWhile { it.isEmpty() }.toTypedArray()
val builder = StringBuilder()
for (s in strArrayOBJ) {
val cap = s.substring(0, 1).toUpperCase() + s.substring(1)
builder.append("$cap ")
}
txt_OBJ.text=builder.toString()

Modification on the accepted answer to clean out any existing capital letters and prevent the trailing space that the accepted answer leaves behind.
public static String capitalize(#NonNull String input) {
String[] words = input.toLowerCase().split(" ");
StringBuilder builder = new StringBuilder();
for (int i = 0; i < words.length; i++) {
String word = words[i];
if (i > 0 && word.length() > 0) {
builder.append(" ");
}
String cap = word.substring(0, 1).toUpperCase() + word.substring(1);
builder.append(cap);
}
return builder.toString();
}

you can use this method to do it programmatically
public String wordFirstCap(String str)
{
String[] words = str.trim().split(" ");
StringBuilder ret = new StringBuilder();
for(int i = 0; i < words.length; i++)
{
if(words[i].trim().length() > 0)
{
Log.e("words[i].trim",""+words[i].trim().charAt(0));
ret.append(Character.toUpperCase(words[i].trim().charAt(0)));
ret.append(words[i].trim().substring(1));
if(i < words.length - 1) {
ret.append(' ');
}
}
}
return ret.toString();
}
refer this if you want to do it in xml.

You can use
private String capitalize(final String line) {
return Character.toUpperCase(line.charAt(0)) + line.substring(1);
}
refer this How to capitalize the first character of each word in a string

android:capitalize is deprecated.
Follow these steps: https://stackoverflow.com/a/31699306/4409113
Tap icon of ‘Settings’ on the Home screen of your Android Lollipop
Device
At the ‘Settings’ screen, scroll down to the PERSONAL section and
tap the ‘Language & input’ section.
At the ‘Language & input’ section, select your keyboard(which is
marked as current keyboard).
Now tap the ‘Preferences’.
Tap to check the ‘Auto – Capitalization’ to enable it.
And then it should work.
If it didn't, i'd rather to do that in Java.

https://stackoverflow.com/a/1149869/2725203
Have a look at ACL WordUtils.
WordUtils.capitalize("your string") == "Your String"

Another approach is to use StringTokenizer class. The below method works for any number of words in a sentence or in the EditText view. I used this to capitalize the full names field in an app.
public String capWordFirstLetter(String fullname)
{
String fname = "";
String s2;
StringTokenizer tokenizer = new StringTokenizer(fullname);
while (tokenizer.hasMoreTokens())
{
s2 = tokenizer.nextToken().toLowerCase();
if (fname.length() == 0)
fname += s2.substring(0, 1).toUpperCase() + s2.substring(1);
else
fname += " "+s2.substring(0, 1).toUpperCase() + s2.substring(1);
}
return fname;
}

in kotlin, string extension
fun String?.capitalizeText() = (this?.toLowerCase(Locale.getDefault())?.split(" ")?.joinToString(" ") { if (it.length <= 1) it else it.capitalize(Locale.getDefault()) }?.trimEnd())?.trim()

Kotlin extension function for capitalising each word
val String?.capitalizeEachWord
get() = (this?.lowercase(Locale.getDefault())?.split(" ")?.joinToString(" ") {
if (it.length <= 1) it else it.replaceFirstChar { firstChar ->
if (firstChar.isLowerCase()) firstChar.titlecase(
Locale.getDefault()
) else firstChar.toString()
}
}?.trimEnd())?.trim()

As the best way for achieving this used to be the capitalize() fun, but now it got depricated in kotlin. So we have an alternate for this. I've the use case where I'm getting a key from api that'll be customized at front end & will be shown apparently. The value is coming as "RECOMMENDED_OFFERS" which should be updated to be shown as "Recommended Offers".
I've created an extension function :
fun String.updateCapitalizedTextByRemovingUnderscore(specialChar: String): String
that takes a string which need to be replaced with white space (" ") & then customise the words as their 1st character would be in caps. So, the function body looks like :
fun String.updateCapitalizedTextByRemovingUnderscore(
specialChar: String = "") : String {
var tabName = this
// removing the special character coming in parameter & if
exist
if (spclChar.isNotEmpty() && this.contains(specialChar)) {
tabName = this.replace(spclChar, " ")
}
return tabName.lowercase().split(' ').joinToString(" ") {
it.replaceFirstChar { if (it.isLowerCase())
it.titlecase(Locale.getDefault()) else it.toString() } }
}
How to call the extension function :
textView.text =
"RECOMMENDED_OFFERS".updateCapitalizedTextByRemovingUnderscore("_")
OR
textView.text = <api_key>.updateCapitalizedTextByRemovingUnderscore("_")
The desired output will be :
Recommended Offers
Hope this will help.Happy coding :) Cheers!!

capitalize each word
public static String toTitleCase(String string) {
// Check if String is null
if (string == null) {
return null;
}
boolean whiteSpace = true;
StringBuilder builder = new StringBuilder(string); // String builder to store string
final int builderLength = builder.length();
// Loop through builder
for (int i = 0; i < builderLength; ++i) {
char c = builder.charAt(i); // Get character at builders position
if (whiteSpace) {
// Check if character is not white space
if (!Character.isWhitespace(c)) {
// Convert to title case and leave whitespace mode.
builder.setCharAt(i, Character.toTitleCase(c));
whiteSpace = false;
}
} else if (Character.isWhitespace(c)) {
whiteSpace = true; // Set character is white space
} else {
builder.setCharAt(i, Character.toLowerCase(c)); // Set character to lowercase
}
}
return builder.toString(); // Return builders text
}
use String to txt.setText(toTitleCase(stringVal))
don't use android:fontFamily to roboto-regular. hyphen not accept. please rename to roboto_regular.

To capitalize each word in a sentence use the below attribute in xml of that paticular textView.
android:inputType="textCapWords"

I am trying to validate my mobile number(whic I picked up form my contact list) in my registration page but it is picking up space in between it

I am trying to validate my mobile number which I am picking up from Contac List but the problem is that it is picking contact like +91 95 xx xxxxxx and there is space between numbers so the validation is not happening.
For now I am using this validation
String Mobile = "^[+]?[01]?[- .]?(\\([2-]\\d{2}\\)|[2-9]\\d{2})[- .]?\\d{3}[- .]?\\d{4}$";
But it's a failure.
Any help is appreciable.
Thank you.

In android sdk One class is there PhoneNumberUtils by using that class you can validate your phone number:
check the documentation link here

Replace the spaces then validate..
String phone=phone.replace(" ","");
Now the String phone has the text without spaces and you can compare.

Just try this.
String number = " " //Your mobile number
number.replaceAll("[^+\\d]|(?<=.)\\+", ""));
This will remove all the spaces, (, ) symbols

you can use below code :
phoneNumber = phoneCursor.getString(phoneCursor.getColumnIndex(NUMBER));
try
{
if (phoneNumber != null)
phoneNumber = extractDigits(phoneNumber);
}
catch (Exception e)
{
e.printStackTrace();
}
where extractDigits() method is as :
public static String extractDigits(String src)
{
StringBuilder builder = new StringBuilder();
String firstchar = src.substring(0, 1);
for (int i = 0; i < src.length(); i++)
{
char c = src.charAt(i);
if (Character.isDigit(c) || firstchar.equals("+"))
{
firstchar = "";
builder.append(c);
}
}
return Checkvalidnumber(builder.toString());
}
where Checkvalidnumber() method is as :
public static String Checkvalidnumber(String number)
{
String validnumber = "";
String Countrycode = chatPrefs.getString("countryCode", "");
if (number.startsWith("+"))
{
validnumber = number.trim();
}
else if (number.startsWith("0"))
{
validnumber = (Countrycode + number.substring(1, number.length())).trim();
}
else
{
validnumber = (Countrycode + number).trim();
}
return validnumber;
}

You should try the following to remove the white spaces and then you can do the validation.
var str = "PB 10 CV 2662";
str = str.replace(/ +/g, "");

How to remove duplicates from ArrayList of type Object? [duplicate]

This question already has answers here:
How to remove duplicates from a list?
(15 answers)
Closed 8 years ago.
I want to remove duplicates from ArrayList of type Alerts where Alerts is a class.
Class Alerts -
public class Alerts implements Parcelable {
String date = null;
String alertType = null;
String discription = null;
public Alerts() {
}
public Alerts(String date, String alertType, String discription) {
super();
this.date = date;
this.alertType = alertType;
this.discription = discription;
}
}
Here is how I added the elements -
ArrayList<Alerts> alert = new ArrayList<Alerts>();
Alerts obAlerts = new Alerts();
obAlerts = new Alerts();
obAlerts.date = Date1.toString();
obAlerts.alertType = "Alert Type 1";
obAlerts.discription = "Some Text";
alert.add(obAlerts);
obAlerts = new Alerts();
obAlerts.date = Date2.toString();
obAlerts.alertType = "Alert Type 1";
obAlerts.discription = "Some Text";
alert.add(obAlerts);
What I want to remove from them-
I want all alerts which have unique obAlerts.date and obAlerts.alertType. In other words, remove duplicate obAlerts.date and obAlerts.alertType alerts.
I tried this -
Alerts temp1, temp2;
String macTemp1, macTemp2, macDate1, macDate2;
for(int i=0;i<alert.size();i++)
{
temp1 = alert.get(i);
macTemp1=temp1.alertType.trim();
macDate1 = temp1.date.trim();
for(int j=i+1;j<alert.size();j++)
{
temp2 = alert.get(j);
macTemp2=temp2.alertType.trim();
macDate2 = temp2.date.trim();
if (macTemp2.equals(macTemp1) && macDate1.equals(macDate2))
{
alert.remove(temp2);
}
}
}
I also tried-
HashSet<Alerts> hs = new HashSet<Alerts>();
hs.addAll(obAlerts);
obAlerts.clear();
obAlerts.addAll(hs);

You need to specify yourself how the class decides equality by overriding a pair of methods:
public class Alert {
String date;
String alertType;
#Override
public boolean equals(Object o) {
if (this == 0) {
return true;
}
if ((o == null) || (!(o instanceof Alert)))
return false;
}
Alert alert = (Alert) o;
return this.date.equals(alert.date)
&& this.alertType.equals(alert.alertType);
}
#Override
public int hashCode() {
int dateHash;
int typeHash;
if (date == null) {
dateHash = super.hashCode();
} else {
dateHash = this.date.hashCode();
}
if (alertType == null) {
typeHash = super.hashCode();
} else {
typeHash = this.alertType.hashCode();
}
return dateHash + typeHash;
}
}
You can then loop through your ArrayList and add elements if they aren't already there as Collections.contains() makes use of these methods.
public List<Alert> getUniqueList(List<Alert> alertList) {
List<Alert> uniqueAlerts = new ArrayList<Alert>();
for (Alert alert : alertList) {
if (!uniqueAlerts.contains(alert)) {
uniqueAlerts.add(alert);
}
}
return uniqueAlerts;
}
However, after saying all that, you may want to revisit your design to use a Set or one of its family that doesn't allow duplicate elements. Depends on your project. Here's a comparison of Collections types

You could use a Set<>. By nature, Sets do no include duplicates. You just need to make sure that you have a proper hashCode() and equals() methods.

In your Alerts class, override the hashCode and equals methods to be dependent on the values of the fields you want to be primary keys. Afterwards, you can use a HashSet to store already seen instances while iterating over the ArrayList. When you find an instance which is not in the HashSet, add it to the HashSet, else remove it from the ArrayList. To make your life easier, you could switch to a HashSet altogether and be done with duplicates per se.
Beware that for overriding hashCode and equals, some constraints apply.
This thread has some helpful pointers on how to write good hashCode functions. An important lesson is that simply adding together all dependent fields' hashcodes is not sufficient because then swapping values between fields will lead to identical hashCodes which might not be desirable (compare swapping first name and last name). Instead, some sort of shifting-operation is usually done before adding the next atomic hash, eg. multiplying with a prime.

First store your datas in array then split at as one by one string,, till the length of that data execute arry and compare with acyual data by if condition and retun it,,
HashSet<String> hs = new HashSet<String>();
for(int i=0;i<alert.size();i++)
{
hs.add(alert.get(i).date + ","+ alert.get(i).alertType;
}
alert.clear();
String alertAll[] = null;
for (String s : hs) {
alertAll = s.split(",");
obAlerts = new Alerts();
obAlerts.date = alertAll[0];
obAlerts.alertType = alertAll[1];
alert.add(obAlerts);
}

Comparing two strings in android [duplicate]

This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Comparing two identical strings with == returns false
I am having real hard time with solving this code. This might look silly but I am not able to figure out what is happening. I am parsing a JSONArray(No big deal!) I am traversing the array with a for loop. I want to break the loop when the user input and the value matches. Here is my code
String regi = null;
JSONObject studentObject = null;
try {
JSONArray returned = test.getInternetData();
int i;
for (i = 0; i < returned.length(); i++) {
studentObject = returned.getJSONObject(i);
regi = studentObject.getString("REGISTRATION_NO");
if (regi == reg) {
name = studentObject.getString("STUDENT_NAME");
break;
}
}
course = studentObject.getString("COURSE_CODE");
Log.d("Details", name + course + regi + i);//Out put: nullGraduate081018394:name - null
//course: Graduate (same for all), regi: last registration number,
//i: giving totalnumber of objects
As per my knowledge the loop should stop when it finds a match. The COURSE_CODE will be corresponding to the student. Am I missing something?
Please note: The function getInternetData() is returning the whole JSON Array. The loop is completely traversing every object.

Strings cannot be compared with == in Java. You have to use string1.equals(string2).

Use regi.equals(reg) or regi.contentEquals(reg) instead of == and you will be fine :-)

use regi.contentEquals(reg) or !regi.contentEquals(reg) for comparison

you should use regi.contentEquals(reg)

try using this
JSONArray returned = test.getInternetData();
int i;
for (i = 0; i < returned.length(); i++) {
// added the below line
studentObject = new JsonObject();
studentObject = returned.getJSONObject(i);
regi = studentObject.getString("REGISTRATION_NO");
if (regi.equals(reg)) {
name = studentObject.getString("STUDENT_NAME");
break;
}
}
instead of just
JSONArray returned = test.getInternetData();
int i;
for (i = 0; i < returned.length(); i++) {
studentObject = returned.getJSONObject(i);
regi = studentObject.getString("REGISTRATION_NO");
if (regi == reg) {
name = studentObject.getString("STUDENT_NAME");
break;
}
}

Parse big xml file in android

In my application there is a search option. If the user enters a search value, I have to get a value from the webservice. I am getting a large webservice value. In my webservice string values are coming. I am getting like <> like xml character entity reference like. I want to replace all characters and parse xml. Can anybody tell me how to do this and give an example?
I tried with StringBuffer for unescapexml character, I am getting out of memory error
public String unescapeXML(String str) {
if (str == null || str.length() == 0)
return "";
StringBuffer buf = new StringBuffer();
int len = str.length();
for (int i = 0; i < len; ++i) {
char c = str.charAt(i);
if (c == '&') {
int pos = str.indexOf(";", i);
if (pos == -1) { // Really evil
buf.append('&');
} else if (str.charAt(i + 1) == '#') {
int val = Integer.parseInt(str.substring(i + 2, pos), 16);
buf.append((char) val);
i = pos;
} else {
String substr = str.substring(i, pos + 1);
if (substr.equals("&"))
buf.append('&');
else if (substr.equals("<"))
buf.append('<');
else if (substr.equals(">"))
buf.append('>');
else if (substr.equals("""))
buf.append('"');
else if (substr.equals("&apos;"))
buf.append('\'');
else if (substr.equals(" "))
buf.append(" ");
else
// ????
buf.append(substr);
i = pos;
}
} else {
buf.append(c);
}
}
return buf.toString();
}
I tried with stream, I am not able to do it. Can anybody give an example how to do this?

You should not parse it on your own. There are better ways - SAX or DOM.
This resource contains a lot of useful inforamtion about these both ways (and code examples too): http://onjava.com/pub/a/onjava/2002/06/26/xml.html

Take a look here in order to get more details about android included parsers :
http://developer.android.com/reference/javax/xml/parsers/package-summary.html
But make your own parser with SAX is probably the best choice in your case ;)