I got a FileNotFoundException error.
Code:
File getpath=Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_MOVIES);
String dir= getpath.getAbsolutePath();
Log.e("filename of dir",dir);
//"/storage/emulated/0/Movies/"
try {
FileInputStream fstrm = new FileInputStream(dir+filename);
VideoFileUploadNew hfu = new VideoFileUploadNew( ServerURL.VIDEO_UPLOAD, filename);
upflag = hfu.Send_Now(fstrm);
Log.e("filename of v up",filename);
} catch (FileNotFoundException e) {
e.printStackTrace();
}
public class VideoFileUploadNew implements Runnable {
URL connectURL;
String responseString;
String Title;
String fileName;
String Description;
byte[ ] dataToServer;
FileInputStream fileInputStream = null;
public VideoFileUploadNew(String urlString, String file){
try{
connectURL = new URL(urlString);
fileName = file;
}catch(Exception ex){
Log.i("HttpFileUpload","URL Malformatted");
}
}
public Boolean Send_Now(FileInputStream fStream){
fileInputStream = fStream;
return Sending();
}
Boolean Sending(){
System.out.println("file Name is :"+fileName);
String iFileName = fileName;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
String Tag="fSnd";
try
{
Log.e(Tag,"Starting Http File Sending to URL");
// Open a HTTP connection to the URL
HttpURLConnection conn = (HttpURLConnection)connectURL.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
DataOutputStream dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes("Content-Disposition: form-data; name=\"vfile\";filename=\"" + iFileName +"\"" + lineEnd);
dos.writeBytes(lineEnd);
Log.e(Tag,"Headers are written");
// create a buffer of maximum size
int bytesAvailable = fileInputStream.available();
int maxBufferSize =9024;
int bufferSize = Math.min(bytesAvailable, maxBufferSize);
byte[ ] buffer = new byte[bufferSize];
// read file and write it into form...
int bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable,maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0,bufferSize);
}
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
fileInputStream.close();
dos.flush();
Log.e(Tag,"File Sent, Response: "+String.valueOf(conn.getResponseCode()));
InputStream is = conn.getInputStream();
// retrieve the response from server
int ch;
StringBuffer b =new StringBuffer();
while( ( ch = is.read() ) != -1 ){ b.append( (char)ch ); }
String s=b.toString();
Log.i("Response",s);
dos.close();
if(String.valueOf(conn.getResponseCode()).equals("200"))
{
return true;
}else{
return false;
}
}
catch (MalformedURLException ex)
{
Log.e(Tag, "URL error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e(Tag, "IO error: " + ioe.getMessage(), ioe);
}
return false;
}
#Override
public void run() {
}
}
Your question is still pretty vague, but one of the reasons this happens is- when you're fetching the relative URI of the File, but need the Absolute URI for the upload.
You can check out different FileUtil classes like this https://github.com/z0rawarr/AndroidUtilCode/blob/master/utilcode/src/main/java/com/blankj/utilcode/utils/FileUtils.java
Get the absolute path from the URI and use that to upload.
Also, do not forget to use the Debugger, and apply a breakpoint on uploadFile() to debug the URIs.
Related
I'm uploading a file and want to display a progress dialog to see the upload progress. I already included a horizontal dialog which works incorrectly, because it goes to 100% in 1 second and then it waits (because it's still uploading).
I used the following function for uploading:
private void doFileUpload(String selectedPath){
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
String urlString = "https://xxxxxxxxxx.com";
try
{
//------------------ CLIENT REQUEST
File f = new File(selectedPath);
FileInputStream fileInputStream = new FileInputStream(f);
//calculate size of file
wholeFilesize = f.length(); //returns the length in Bytes
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"upfile\";filename=\"" + selectedPath + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
totalReadFilesize+=bytesRead;
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
int progress = (int)((totalReadFilesize*100)/(wholeFilesize));
//Log.i("Progress: ", (int)((totalReadFilesize*100)/(wholeFilesize))+"");
dialog.setProgress(progress);
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
//publishProgress(100);
Log.i("Size: ", wholeFilesize+"");
Log.i("Bytes read: ", totalReadFilesize+"");
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
Log.e("Debug","File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.e("Debug", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("Debug", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("Debug","Server Response "+str);
JSONObject jsonObj = new JSONObject(str);
//String status=(String) jsonObj.get("status");
Log.i("TEST", (String) jsonObj.get("message"));
uploadResultMessage = (String) jsonObj.get("message");
Log.i("TEST", uploadResultMessage);
}
inStream.close();
}
catch (IOException ioex){
Log.e("Debug", "error: " + ioex.getMessage(), ioex);
} catch (JSONException e) {
e.printStackTrace();
}
}
Does someone know, how should I modify the code to see the real progress of the file, which is being uploaded? I find it strange, because I'm doing the same as the user in his doInBackground() in this thread.
I want to upload an image to web server.For that i have written code,but when ever i upload the file to web server instead of file name i am getting the image path.
COde
protected String sendFile(final Context context, final String url, final String params, String fileName, final File f) {
DataOutputStream dos = null;
int bytesRead = 0, bytesAvailable = 0, bufferSize;
int maxBufferSize = 1024;
byte[] buffer;
String serverResponseMessage = null;
String uploaded_file = fileName;
URL url1 = null;
try {
FileInputStream fileInputStream = new FileInputStream(f);
url1 = new URL(url + "?" + params);
HttpURLConnection connection = (HttpURLConnection) url1.openConnection();
connection.setRequestMethod("POST");
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);
connection.setRequestProperty("Connection", "Keep-Alive");
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
connection.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
connection.setRequestProperty("uploaded_file", fileName);
fileName = String.valueOf(f);
//connection.setRequestProperty ("uploaded_file", "sample");
dos = new DataOutputStream(connection.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\"hello" + fileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
bytesAvailable = fileInputStream.available(); // create a buffer of maximum size
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
dos.close();
// Responses from the server (code and message)
int serverResponseCode = connection.getResponseCode();
serverResponseMessage = connection.getResponseMessage();
StringBuffer b;
int ch;
InputStream is;
is = connection.getInputStream();
// retrieve the response from server
b = new StringBuffer();
while ((ch = is.read()) != -1) {
b.append((char) ch);
}
String response = b.toString();
Log.e("Response", "" + response);
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (ProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
Log.e("Error message", "" + e);
}
return serverResponseMessage;
}
protected File saveFile(Context context, int value, String name) {
File directory = new File(Environment.getExternalStorageDirectory() + "/pocketDocs/Camera/Gallery/Others");
if (!directory.exists()) {
directory.mkdirs();
}
if (value == 0) {
f = new File(Environment.getExternalStorageDirectory() + "/pocketDocs/Gallery", name);
try {
FileOutputStream out = new FileOutputStream(f);
out.flush();
out.close();
} catch (Exception e) {
e.printStackTrace();
}
}
return f;
}
}
When i use
fileName = String.valueOf(f);
dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\"hello" + fileName + "\"" + lineEnd);
at server side i am getting the file name as the path of image.
And when i don't use
fileName = String.valueOf(f);
i am gettin the proper file name but i am not getting the extension of the image.
Now how can i solve this problem because the peoblem is in this line
dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\"hello" + fileName + "\"" + lineEnd);
You were using String.valueOf() in a file to get its name, it was returning an empty String, so it was not working.
Instead, you have to get the file name using file.getName().
I am trying to upload the video file into server with convert into base64. But I am getting out of memory exception even size is 2 mb also. How to resolve this issue. Please help me to over out, much appreciate your help.
Here what I am doing
byte [] ba = convertByteArray(videoUri);
String baseimage=Base64.encodeToString(ba, Base64.NO_WRAP);
public byte[] convertByteArray(Uri videoUri){
InputStream iStream=null;
byte[] inputData=null;
try {
iStream = getContentResolver().openInputStream(videoUri);
inputData = getBytes(iStream);
} catch (FileNotFoundException e) {
e.printStackTrace();
}
catch (IOException e) {
e.printStackTrace();
}
return inputData;
}
public byte[] getBytes(InputStream inputStream) throws IOException {
ByteArrayOutputStream byteBuffer = new ByteArrayOutputStream();
int bufferSize = 1024;
byte[] buffer = new byte[bufferSize];
int len = 0;
while ((len = inputStream.read(buffer)) != -1) {
byteBuffer.write(buffer, 0, len);
}
return byteBuffer.toByteArray();
}
Code :
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String lineEnd = "rn";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
String urlString = "http://your_website.com/upload_audio_test/upload_audio.php";
try
{
//------------------ CLIENT REQUEST
FileInputStream fileInputStream = new FileInputStream(new File(selectedPath) );
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name="uploadedfile";filename="" + selectedPath + """ + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
Log.e("Debug","File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.e("Debug", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("Debug", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("Debug","Server Response "+str);
}
inStream.close();
}
catch (IOException ioex){
Log.e("Debug", "error: " + ioex.getMessage(), ioex);
}
}
Go through the following Sample for more reference :
http://coderzheaven.com/2011/08/uploading-audio-video-or-image-files-from-android-to-server/
For uploading video to server see doFileUpload() method from the above url.
I'm trying to upload more than one image taken from the camera. I call the camera via Intent:
public void TakePicture(int actionCode)
{
Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
try
{
photo[0] = createTemporaryFile("spot", ".jpg");
}
catch(Exception e)
{
Log.v("ERROR SD!!", "Can't create file to take picture!");
Toast.makeText(this, "Please check SD card! Image shot is impossible!", 10000);
}
fileUri = Uri.fromFile(photo[0]);
intent.putExtra(MediaStore.EXTRA_OUTPUT, fileUri);
startActivityForResult(intent, CAPTURE_IMAGE_ACTIVITY_REQUEST_CODE);
}
And then I upload it to a PHP server:
public void UploadImg()
{
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
// String exsistingFileName = "/sdcard/prueba.png"; --> Used for local files!!
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String urlString = "http://myUrl.com/uploadimg.php";
try
{
FileInputStream fileInputStream = new FileInputStream(photo[0].toString());
// Open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true);
conn.setDoOutput(true);
conn.setUseCaches(false);
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + photo[0] +"\"" + lineEnd);
dos.writeBytes(lineEnd);
// Create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// Read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// Send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Close streams
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex) { Log.e("MediaPlayer", "error: " + ex.getMessage(), ex); }
catch (IOException ioe) { Log.e("MediaPlayer", "error: " + ioe.getMessage(), ioe); }
try {
inStream = new DataInputStream (conn.getInputStream());
String str;
while ((str = inStream.readLine()) != null)
{
System.out.println("Server Response" + str);
}
inStream.close();
}
catch (IOException ioex) { Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex); }
}
I save 3 different images: photo[0], photo[1] and photo[2]. The problem is that when I take, for example, two pictures, it only uploads one of them and with size = 0.
In the code of the UploadImg() I show only the photo[0], but in the 'real' code I use a for loop after the first try so that it upload all of the images taken.
Any idea of what am I doing wrong?
Thank you very much in advance!
I've already solved my problem! I did the following: Instead of saving the photo File, I save the it in a String with the location of the image.
if (requestCode == CAPTURE_IMAGE_ACTIVITY_REQUEST_CODE) {
if (resultCode == RESULT_OK) {
for (int u = 0; u <= 2; u++)
{
if (savedImgs[u].equals(""))
{
// Saving important info to be used later
imgs = u + 1;
savedImgs[u] = photo.toString();
break;
}
} ...
And then, when uploading the images to the server, I make a for loop like this:
public void UploadImg()
{
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
// String exsistingFileName = "/sdcard/prueba.png"; --> Used for local files!!
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String urlString = "http://myUrl.com/uploadimg.php";
for (int n = 0; n < imgs; n++)
{
try
{
FileInputStream fileInputStream = new FileInputStream(savedImgs[n]);
// Open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true);
conn.setDoOutput(true);
conn.setUseCaches(false);
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + savedImgs[n] +"\"" + lineEnd);
dos.writeBytes(lineEnd);
// Create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// Read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// Send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Close streams
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex) { Log.e("MediaPlayer", "error: " + ex.getMessage(), ex); }
catch (IOException ioe) { Log.e("MediaPlayer", "error: " + ioe.getMessage(), ioe); }
try {
inStream = new DataInputStream (conn.getInputStream());
String str;
while ((str = inStream.readLine()) != null)
{
System.out.println("Server Response" + str);
}
inStream.close();
}
catch (IOException ioex) { Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex); }
}
}
I want to copy all the video files on my server & save it in the web contents folder of a web service , so that it can be visible to all later on !
How should i proceeed ?
Basically you need two sides. The first one is on Android. You have to send (Do it in an ASyncTask e.x.) the data to your webservice. Here I made a little method for you, which sends a file and some additional POST values to an URL:
private boolean handleFile(String filePath, String mimeType) {
HttpURLConnection connection = null;
DataOutputStream outStream = null;
DataInputStream inStream = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String urlString = "http://your.domain.com/webservice.php";
try {
FileInputStream fileInputStream = null;
try {
fileInputStream = new FileInputStream(new File(filePath));
} catch(FileNotFoundException e) { }
URL url = new URL(urlString);
connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);
SharedPreferences prefs = PreferenceManager.getDefaultSharedPreferences(getBaseContext());
connection.setRequestMethod("POST");
connection.setRequestProperty("Connection", "Keep-Alive");
connection.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
outStream = new DataOutputStream(connection.getOutputStream());
// Some POST values
outStream.writeBytes(addParam("additional_param", "some value");
outStream.writeBytes(addParam("additional_param 2", "some other value");
// The file with the name "uploadedfile"
outStream.writeBytes(twoHyphens + boundary + lineEnd);
outStream.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + filePath +"\"" + lineEnd + "Content-Type: " + mimeType + lineEnd + "Content-Transfer-Encoding: binary" + lineEnd);
outStream.writeBytes(lineEnd);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
outStream.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
outStream.writeBytes(lineEnd);
outStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
fileInputStream.close();
outStream.flush();
outStream.close();
} catch (MalformedURLException e) {
Log.e("APP", "MalformedURLException while sending\n" + e.getMessage());
} catch (IOException e) {
Log.e("APP", "IOException while sending\n" + e.getMessage());
}
// This part checks the response of the server. If its "UPLOAD OK" the method returns true
try {
inStream = new DataInputStream( connection.getInputStream() );
String str;
while (( str = inStream.readLine()) != null) {
if(str=="UPLOAD OK") {
return true;
} else {
return false;
}
}
inStream.close();
} catch (IOException e){
Log.e("APP", "IOException while sending\n" + e.getMessage());
}
return false;
}
Now, we have got the other side: http://your.domain.com/webservice.php
Your server. It needs some logic, for example in PHP, to handle the sent POST request.
Something like this would work:
<?php
$target_path = "videos/";
$target_path = $target_path.'somename.3gp';
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
exit("UPLOAD OK");
} else {
exit("UPLOAD NOT OK");
}
?>