Out of Memory Issue when encode into base64 video file - android

I am trying to upload the video file into server with convert into base64. But I am getting out of memory exception even size is 2 mb also. How to resolve this issue. Please help me to over out, much appreciate your help.
Here what I am doing
byte [] ba = convertByteArray(videoUri);
String baseimage=Base64.encodeToString(ba, Base64.NO_WRAP);
public byte[] convertByteArray(Uri videoUri){
InputStream iStream=null;
byte[] inputData=null;
try {
iStream = getContentResolver().openInputStream(videoUri);
inputData = getBytes(iStream);
} catch (FileNotFoundException e) {
e.printStackTrace();
}
catch (IOException e) {
e.printStackTrace();
}
return inputData;
}
public byte[] getBytes(InputStream inputStream) throws IOException {
ByteArrayOutputStream byteBuffer = new ByteArrayOutputStream();
int bufferSize = 1024;
byte[] buffer = new byte[bufferSize];
int len = 0;
while ((len = inputStream.read(buffer)) != -1) {
byteBuffer.write(buffer, 0, len);
}
return byteBuffer.toByteArray();
}

Code :
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String lineEnd = "rn";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
String urlString = "http://your_website.com/upload_audio_test/upload_audio.php";
try
{
//------------------ CLIENT REQUEST
FileInputStream fileInputStream = new FileInputStream(new File(selectedPath) );
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name="uploadedfile";filename="" + selectedPath + """ + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
Log.e("Debug","File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.e("Debug", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("Debug", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("Debug","Server Response "+str);
}
inStream.close();
}
catch (IOException ioex){
Log.e("Debug", "error: " + ioex.getMessage(), ioex);
}
}
Go through the following Sample for more reference :
http://coderzheaven.com/2011/08/uploading-audio-video-or-image-files-from-android-to-server/
For uploading video to server see doFileUpload() method from the above url.

Related

Displaying upload progress in progress dialog

I'm uploading a file and want to display a progress dialog to see the upload progress. I already included a horizontal dialog which works incorrectly, because it goes to 100% in 1 second and then it waits (because it's still uploading).
I used the following function for uploading:
private void doFileUpload(String selectedPath){
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
String urlString = "https://xxxxxxxxxx.com";
try
{
//------------------ CLIENT REQUEST
File f = new File(selectedPath);
FileInputStream fileInputStream = new FileInputStream(f);
//calculate size of file
wholeFilesize = f.length(); //returns the length in Bytes
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"upfile\";filename=\"" + selectedPath + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
totalReadFilesize+=bytesRead;
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
int progress = (int)((totalReadFilesize*100)/(wholeFilesize));
//Log.i("Progress: ", (int)((totalReadFilesize*100)/(wholeFilesize))+"");
dialog.setProgress(progress);
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
//publishProgress(100);
Log.i("Size: ", wholeFilesize+"");
Log.i("Bytes read: ", totalReadFilesize+"");
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
Log.e("Debug","File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.e("Debug", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("Debug", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("Debug","Server Response "+str);
JSONObject jsonObj = new JSONObject(str);
//String status=(String) jsonObj.get("status");
Log.i("TEST", (String) jsonObj.get("message"));
uploadResultMessage = (String) jsonObj.get("message");
Log.i("TEST", uploadResultMessage);
}
inStream.close();
}
catch (IOException ioex){
Log.e("Debug", "error: " + ioex.getMessage(), ioex);
} catch (JSONException e) {
e.printStackTrace();
}
}
Does someone know, how should I modify the code to see the real progress of the file, which is being uploaded? I find it strange, because I'm doing the same as the user in his doInBackground() in this thread.

Save and upload more than one image

I'm trying to upload more than one image taken from the camera. I call the camera via Intent:
public void TakePicture(int actionCode)
{
Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
try
{
photo[0] = createTemporaryFile("spot", ".jpg");
}
catch(Exception e)
{
Log.v("ERROR SD!!", "Can't create file to take picture!");
Toast.makeText(this, "Please check SD card! Image shot is impossible!", 10000);
}
fileUri = Uri.fromFile(photo[0]);
intent.putExtra(MediaStore.EXTRA_OUTPUT, fileUri);
startActivityForResult(intent, CAPTURE_IMAGE_ACTIVITY_REQUEST_CODE);
}
And then I upload it to a PHP server:
public void UploadImg()
{
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
// String exsistingFileName = "/sdcard/prueba.png"; --> Used for local files!!
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String urlString = "http://myUrl.com/uploadimg.php";
try
{
FileInputStream fileInputStream = new FileInputStream(photo[0].toString());
// Open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true);
conn.setDoOutput(true);
conn.setUseCaches(false);
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + photo[0] +"\"" + lineEnd);
dos.writeBytes(lineEnd);
// Create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// Read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// Send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Close streams
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex) { Log.e("MediaPlayer", "error: " + ex.getMessage(), ex); }
catch (IOException ioe) { Log.e("MediaPlayer", "error: " + ioe.getMessage(), ioe); }
try {
inStream = new DataInputStream (conn.getInputStream());
String str;
while ((str = inStream.readLine()) != null)
{
System.out.println("Server Response" + str);
}
inStream.close();
}
catch (IOException ioex) { Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex); }
}
I save 3 different images: photo[0], photo[1] and photo[2]. The problem is that when I take, for example, two pictures, it only uploads one of them and with size = 0.
In the code of the UploadImg() I show only the photo[0], but in the 'real' code I use a for loop after the first try so that it upload all of the images taken.
Any idea of what am I doing wrong?
Thank you very much in advance!
I've already solved my problem! I did the following: Instead of saving the photo File, I save the it in a String with the location of the image.
if (requestCode == CAPTURE_IMAGE_ACTIVITY_REQUEST_CODE) {
if (resultCode == RESULT_OK) {
for (int u = 0; u <= 2; u++)
{
if (savedImgs[u].equals(""))
{
// Saving important info to be used later
imgs = u + 1;
savedImgs[u] = photo.toString();
break;
}
} ...
And then, when uploading the images to the server, I make a for loop like this:
public void UploadImg()
{
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
// String exsistingFileName = "/sdcard/prueba.png"; --> Used for local files!!
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String urlString = "http://myUrl.com/uploadimg.php";
for (int n = 0; n < imgs; n++)
{
try
{
FileInputStream fileInputStream = new FileInputStream(savedImgs[n]);
// Open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true);
conn.setDoOutput(true);
conn.setUseCaches(false);
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + savedImgs[n] +"\"" + lineEnd);
dos.writeBytes(lineEnd);
// Create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// Read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// Send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Close streams
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex) { Log.e("MediaPlayer", "error: " + ex.getMessage(), ex); }
catch (IOException ioe) { Log.e("MediaPlayer", "error: " + ioe.getMessage(), ioe); }
try {
inStream = new DataInputStream (conn.getInputStream());
String str;
while ((str = inStream.readLine()) != null)
{
System.out.println("Server Response" + str);
}
inStream.close();
}
catch (IOException ioex) { Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex); }
}
}

Uploading MS Word files from Android to .Net WCF?

I have problem in uploading .doc file to .Net WCF from my Android app. I am able to send file but it is not supported on WCF end.
Here is my method for uploading:
protected void checkinmethod(String rid) throws Exception {
File SDCardRoot = Environment.getExternalStorageDirectory();
//create a new file, specifying the path, and the filename
//which we want to save the file as.
File file = new File(SDCardRoot, rid+".doc");
InputStream in = new FileInputStream(file);
byte[] bytearray=new byte[(int) file.length()];
int ab=0;
do
{
ab=in.read(bytearray, 0, bytearray.length);
} while(ab>0);
InputStream mystream= new ByteArrayInputStream(bytearray);
InputStreamEntity se=new InputStreamEntity(mystream, 10000);
HttpPost request = new HttpPost("http://10.66.52.247/tutorwcf/Service.svc/Service/updateMyDoc1");
request.setHeader("Accept", "application/json");
request.setHeader("Content-type", "application/msword");
request.setEntity(se);
try {
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpResponse response = httpClient.execute(request);
HttpEntity responseEntity = response.getEntity();
// Read response data into buffer
char[] buffer = new char[(int)responseEntity.getContentLength()];
InputStream stream = responseEntity.getContent();
InputStreamReader reader = new InputStreamReader(stream);
reader.read(buffer);
stream.close();
statuss.setText(new String(buffer));
//
}
catch (Exception e) {
// TODO: handle exception
Log.e("hi", "exception is", e);
statuss.setText("exception");
}
}
here is .net code:
FileStream fileToupload = new FileStream("D:\\myfile.doc", FileMode.Create, FileAccess.Write);
byte[] bytearray = new byte[10000];
int bytesRead, totalBytesRead = 0;
do
{
bytesRead = mystream.Read(bytearray, 0, bytearray.Length);
totalBytesRead += bytesRead;
} while (bytesRead > 0);
fileToupload.Write(bytearray, 0, bytearray.Length);
fileToupload.Close();
fileToupload.Dispose();
return "success";
}
Please send links or code or any thing.
If you don't have idea about this please rank up this question..
thanks
public void checkinstream(String rid, String filename ) throws IOException
{
URL url=null;
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String existingFileName= null;
existingFileName= "/mnt/sdcard/"+rid+".doc";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = Integer.MAX_VALUE;
String responseFromServer = "";
url = new URL("http://10.66.51.241/mywcf/Service.svc/Service/uploadMyDoc");
try
{
//------------------ CLIENT REQUEST
FileInputStream fileInputStream = new FileInputStream(new File(existingFileName) );
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "application/stream");
dos = new DataOutputStream( conn.getOutputStream() );
// dos.writeBytes(twoHyphens + boundary + lineEnd);
//dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + existingFileName + "\"" + lineEnd);
// dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
// close streams
Log.e("Debug",twoHyphens + boundary + twoHyphens + lineEnd);
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.e("Debug", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("Debug", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("Debug","Server Response "+str);
statuss.setText(str);
}
inStream.close();
}
catch (IOException ioex){
Log.e("Debug", "error: " + ioex.getMessage(), ioex);
}
}
On the .net end create a wcf method which receives stream.
Thanks.

Android video upload error?

I use this to upload the video to php server, when i try to upload the image ,it was working fine, but when i tried to upload the Video the following error occur,
"02-22 18:22:35.588: ERROR/dalvikvm-heap(780): Out of memory on a 14680278-byte allocation."
***
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String exsistingFileName = "/sdcard/Video/dance.wmv";
// Is this the place are you doing something wrong.
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
String urlString = "http://172.17.0.146/viddygo/upload.php";
try
{
//------------------ CLIENT REQUEST
Log.e("MediaPlayer","Inside second Method");
FileInputStream fileInputStream = new FileInputStream(new File(exsistingFileName) );
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + exsistingFileName +"\"" + lineEnd);
dos.writeBytes(lineEnd);
Log.e("MediaPlayer","Headers are written");
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
BufferedReader in = new BufferedReader(
new InputStreamReader(
conn.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null)
tv.append(inputLine);
// close streams
Log.e("MediaPlayer","File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.e("MediaPlayer", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("MediaPlayer", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("MediaPlayer","Server Response"+str);
}
inStream.close();
}
catch (IOException ioex){
Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex);
}
can anyone suggest some idea to solve this.
I think error happened in follow line because DataOutputStream size is exceeds VM budget when you write
dos.write(buffer, 0, bufferSize);

Working with web service?

I want to copy all the video files on my server & save it in the web contents folder of a web service , so that it can be visible to all later on !
How should i proceeed ?
Basically you need two sides. The first one is on Android. You have to send (Do it in an ASyncTask e.x.) the data to your webservice. Here I made a little method for you, which sends a file and some additional POST values to an URL:
private boolean handleFile(String filePath, String mimeType) {
HttpURLConnection connection = null;
DataOutputStream outStream = null;
DataInputStream inStream = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String urlString = "http://your.domain.com/webservice.php";
try {
FileInputStream fileInputStream = null;
try {
fileInputStream = new FileInputStream(new File(filePath));
} catch(FileNotFoundException e) { }
URL url = new URL(urlString);
connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);
SharedPreferences prefs = PreferenceManager.getDefaultSharedPreferences(getBaseContext());
connection.setRequestMethod("POST");
connection.setRequestProperty("Connection", "Keep-Alive");
connection.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
outStream = new DataOutputStream(connection.getOutputStream());
// Some POST values
outStream.writeBytes(addParam("additional_param", "some value");
outStream.writeBytes(addParam("additional_param 2", "some other value");
// The file with the name "uploadedfile"
outStream.writeBytes(twoHyphens + boundary + lineEnd);
outStream.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + filePath +"\"" + lineEnd + "Content-Type: " + mimeType + lineEnd + "Content-Transfer-Encoding: binary" + lineEnd);
outStream.writeBytes(lineEnd);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
outStream.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
outStream.writeBytes(lineEnd);
outStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
fileInputStream.close();
outStream.flush();
outStream.close();
} catch (MalformedURLException e) {
Log.e("APP", "MalformedURLException while sending\n" + e.getMessage());
} catch (IOException e) {
Log.e("APP", "IOException while sending\n" + e.getMessage());
}
// This part checks the response of the server. If its "UPLOAD OK" the method returns true
try {
inStream = new DataInputStream( connection.getInputStream() );
String str;
while (( str = inStream.readLine()) != null) {
if(str=="UPLOAD OK") {
return true;
} else {
return false;
}
}
inStream.close();
} catch (IOException e){
Log.e("APP", "IOException while sending\n" + e.getMessage());
}
return false;
}
Now, we have got the other side: http://your.domain.com/webservice.php
Your server. It needs some logic, for example in PHP, to handle the sent POST request.
Something like this would work:
<?php
$target_path = "videos/";
$target_path = $target_path.'somename.3gp';
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
exit("UPLOAD OK");
} else {
exit("UPLOAD NOT OK");
}
?>

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