Develop Reference

Android BreakIterator hyphenated words?

I using breakIterator to get each word from a sentence and there is problem when a sentence like "my mother-in-law is coming for a visit" where i am not able to get mother-in-law as a single word.
BreakIterator iterator = BreakIterator.getWordInstance(Locale.ENGLISH);
for (int end = iterator.next(); end != BreakIterator.DONE; start = end, end = iterator.next())
{
String possibleWord = sentence.substring(start, end);
if (Character.isLetterOrDigit(possibleWord.charAt(0)))
{
// grab the word
}
}

As I'm seeing in your code what are you trying to do is to check if the first character in every word are a character or a digit. Every time you use the BreakIterator.getWordInstance() you will always get all the words depending on the boundary rules of the Locale and it is a little hard to accomplish what you want to do with the use of this class until I know, so my advice is this:
String text = "my mother-in-law is coming for a visit";
String[] words = text.split(" ");
for (String word : words){
if (Character.isLetterOrDigit(word.charAt(0))){
// grab the word
}
}

SKipping image while converting html text to string android

Iam converting some Html text from a webpage into a String by doing the following
mydescription =Html.fromHtml(data.getBody()).toString();
This is what data.getBody() returns:-
<div><p>​It's great to have great dynamic companies to work with, and NXP is no exception.</p><p><img alt="This is an image of NXP Logo" src="https://anprodstorage.blob.core.windows.net/b75ef288-0381-45c4-a4cd-809097370bec/untitled.png" style="margin:5px;" /><br></p><div><iframe width="560" height="315" src="https://www.youtube.com/embed/I6191gXXGog" frameborder="0"></iframe> </div><p>​<br></p></div>
But within that html text there is a image source as well. When I do the above I get a square image with obj written inside it instead of the image.
This is myDescription

I just want to get the text and not the image.
How do i just get the text and not the image

Try this way,hope this will help you to solve your problem.
String htmlString = "<div><p>​It's great to have great dynamic companies to work with, and NXP is no exception.</p><p><img alt=\"This is an image of NXP Logo\" src=\"https://anprodstorage.blob.core.windows.net/b75ef288-0381-45c4-a4cd-809097370bec/untitled.png\" style=\"margin:5px;\" /><br></p><div><iframe width=\"560\" height=\"315\" src=\"https://www.youtube.com/embed/I6191gXXGog\" frameborder=\"0\"></iframe> </div><p>​<br></p></div>";
String first = htmlString.substring(0,htmlString.indexOf("<img"));
String second = htmlString.substring(htmlString.indexOf("/>",htmlString.indexOf("<img"))+2,htmlString.length());
textview.setText(Html.fromHtml(first+second));

use this code:
String clippedBody = htmlString.replaceAll("<img[^>]*?>.*?/[^>]*?>", "");

I advise using libraries, like jsoup when working with HTML (with soup you will be able to get only text by calling Jsoup.parse(html).text())
Haven't tried it myself
private static final Pattern REMOVE_TAGS = Pattern.compile("<img>(\\S+)</img>");
public static String removeTags(String string) {
if (string == null || string.length() == 0) {
return string;
}
Matcher m = REMOVE_TAGS.matcher(string);
return m.replaceAll("");
}
If you want to strip down all the HTML code, then you can use:
replaceAll("\\<[^>]*>","")
For your second question (from Source 2):
// the pattern we want to search for
Pattern p = Pattern.compile("<p>(\\S+)</p>");
Matcher m = p.matcher(string);
// if we find a match, get the group
if (m.find())
{
// get the matching group
String codeGroup = m.group(1);
// print the group
System.out.format("'%s'\n", codeGroup);
}
Source: 1, 2 and 3

Separating the words after the last integer in a large String

I've seen many people do similar to this in order to get the last word of a String:
String test = "This is a sentence";
String lastWord = test.substring(test.lastIndexOf(" ")+1);
I would like to do similar but get the last few words after the last int, it can't be hard coded as the number could be anything and the amount of words after the last int could also be unlimited. I'm wondering whether there is a simple way to do this as I want to avoid using Patterns and Matchers again due to using them earlier on in this method to receive a similar effect.
Thanks in advance.

I would like to get the last few words after the last int.... as the number could be anything and the amount of words after the last int could also be unlimited.
Here's a possible suggestion. Using Array#split
String str = "This is 1 and 2 and 3 some more words .... foo bar baz";
String[] parts = str.split("\\d+(?!.*\\d)\\s+");
And now parts[1] holds all words after the last number in the string.
some more words .... foo bar baz

What about this one:
String test = "a string with a large number 1312398741 and some words";
String[] parts = test.split();
for (int i = 1; i < parts.length; i++)
{
try
{
Integer.parseInt(parts[i])
}
catch (Exception e)
{
// this part is not a number, so lets go on...
continue;
}
// when parsing succeeds, the number was reached and continue has
// not been called. Everything behind 'i' is what you are looking for
// DO YOUR STUFF with parts[i+1] to parts[parts.length] here
}

Format Android EditText to specific pattern

I need the user to enter text in an EditText according to this specfic pattern:
123.456-7890-123.456
The user can input any number of integers, so they could as well enter 123.456-7
I do not want the user to enter . or - just the numbers, like an input mask.
Also the numeric keyboard should only show.
I've searched StackOverflow extensively and have seen examples that use InputFilter, ChangedListener, TextWatcher but have not found anything simlar to what I'm trying to do. I've tried in various implementations of what I've found, but I'm inexperienced in using these so I may have overlooked something.
Any suggestions would be welcome.

You're going to have to use a TextWatcher and a regular expression pattern matcher to accomplish what you're trying to do.
This answer should be helpful: Android AutoCompleteTextView with Regular Expression?

You can create your own class that implements InputFilter. Then you would apply it as follows:
MyInputFilter filter = new MyInputFilter(...);
editText.setFilters(new InputFilter[]{filter});
Refer to the docs for how InputFilter is intended to work, then refer to the source code for some of the InputFilters used in Android for some ideas how to implement them.

After many failed attempts to implement InputFilter or Regular Expressions I opted for something a little more straight forward:
public void onTextChanged(CharSequence s, int start, int before, int count) {
String a = "";
String str = id.getText().toString();
String replaced = str.replaceAll(Pattern.quote("."),"");
replaced = replaced.replaceAll(Pattern.quote("-"),"");
char[] id_char = replaced.toCharArray();
int id_len = replaced.length();
for(int i = 0; i < id_len; i++) {
if(i == 2 || i == 12) {
a += id_char[i] + ".";
}
else if (i == 5 || i == 9) {
a += id_char[i] + "-";
}
else a += id_char[i];
}
id.removeTextChangedListener(this);
id.setText(a);
if(before > 0) id.setSelection(start);
else id.setSelection(a.length());
id.addTextChangedListener(this);
}
I don't know if this is the best approach but it does work. One problem I still haven't solved is how to handle cursor placement after the user deletes or inserts a number. If the user inserts the cursor somewhere in the EditText and enters a new number the cursor jumps to the end of the EditText. I would like the cursor to stay where it is at. Another problem if the user inserts the cursor within the EditText number and backspaces to delete a number, then the first key entry doesn't work and on the second key the number is entered. I can only guess this has to do with focus?

Use this: https://github.com/alobov/SimpleMaskWatcher.
Just set your mask for this watcher (###.###-####-###.###). It will add special symbols automatically and wont check your input string for being complete.
But showing the numeric keyboard you must handle by your own using android:inputType="number" tag for your EditText.

How to read word by word from file?

Could anybody post here some code how can I read word by word from file? I only know how to read line by line from file using BufferedReader. I'd like if anybody posted it with BufferedReader.
I solved it with this code:
StringBuilder word = new StringBuilder();
int i=0;
Scanner input = new Scanner(new InputStreamReader(a.getInputStream()));
while(input.hasNext()) {
i++;
if(i==prefNamePosition){
word.append(prefName);
word.append(" ");
input.next();
}
else{
word.append(input.hasNext());
word.append(" ");
}
}

There's no good way other than to read() and get a character at a time until you get a space or whatever criteria you want for determining what a "word" is.

If you're trying to replace the nth token with a special value, try this:
while (input.hasNext()) {
String currentWord = input.next();
if(++i == prefNamePosition) {
currentWord = prefName;
}
word.append(currentWord);
word.append(" ");
}

Another way is to employ a tokenizer (e.g. in Java) and using the delimiter space character (i.e. ' '). Then just iterate through the tokens to read each word from your file.

You can read lines and then use splits. There is no clear definition of word but if you want the ones separated by blank spaces you can do it.
You could also use regular expressions to do this.