Could anybody post here some code how can I read word by word from file? I only know how to read line by line from file using BufferedReader. I'd like if anybody posted it with BufferedReader.
I solved it with this code:
StringBuilder word = new StringBuilder();
int i=0;
Scanner input = new Scanner(new InputStreamReader(a.getInputStream()));
while(input.hasNext()) {
i++;
if(i==prefNamePosition){
word.append(prefName);
word.append(" ");
input.next();
}
else{
word.append(input.hasNext());
word.append(" ");
}
}
There's no good way other than to read() and get a character at a time until you get a space or whatever criteria you want for determining what a "word" is.
If you're trying to replace the nth token with a special value, try this:
while (input.hasNext()) {
String currentWord = input.next();
if(++i == prefNamePosition) {
currentWord = prefName;
}
word.append(currentWord);
word.append(" ");
}
Another way is to employ a tokenizer (e.g. in Java) and using the delimiter space character (i.e. ' '). Then just iterate through the tokens to read each word from your file.
You can read lines and then use splits. There is no clear definition of word but if you want the ones separated by blank spaces you can do it.
You could also use regular expressions to do this.
Related
I am new to android studio and kotlin. I need to find a way to check if a string contains a char, which is, in this case, "/"
I want to form a piece of code in the following manner:
if (string input contains a character "/") = true {
<code>
}
else{
<code>
}
Please tell me how to do this, and if possible, give me the code I'll need to specify as the condition.
You can use contains, like this:
val a = "hello/"
val b = a.contains("/")
When the string has the character will return true.
i want find a Arabic word with Nunation in a TextView and highlight this,
for example if my word is "اشهد" whitout Nunation i want to find word position in "وَ اَشْهَدُ اَنْ لا اِلهَ اِلاَّ اللَّهُ" with Nunation .
Hi Please see below class i created. It is so basic and did not bother about memory consumption. You guys can optimise yourself.
http://freshinfresh.com/sample/ABHArabicDiacritics.java
If you want to check without nunation(harakath) contains in an arabic String,
ABHArabicDiacritics objSearchd = new ABHArabicDiacritics();
objSearchdobjSearch.getDiacriticinsensitive("وَ اَشْهَدُ اَنْ لا اِلهَ اِلاَّ اللَّهُ").contains("اشهد");
If you want to return Highlighed or redColored searched portion in String.
Use below code
ABHArabicDiacritics objSearch = new ABHArabicDiacritics( وَ اَشْهَدُ اَنْ لا اِلهَ اِلاَّ اللَّهُ, اشهد);
SpannableString spoutput=objSearch.getSearchHighlightedSpan();
textView.setText(spoutput);
To see start and end position of search text,
Use below methods,
/** to serch Contains */
objSearch.isContain();//
objSearch.getSearchHighlightedSpan();
objSearch.getSearchTextStartPosition();
objSearch.getSearchTextEndPosition();
Please copy shared java class and enjoy.
I will spend more time for more feature if you guys request.
Thanks
search ولد in INPUT :
public void RegexMatches() {
String INPUT ="ى لَیْلَهِ تَمامِهِ وَکَمالِهِ فَما کانَتْ اِلاّ ساعَهً وَاِذا بِوَلَدِىَ الْحَسَنِ قَدْ" ;
Pattern p = Pattern.compile("و[\\u064B-\\u064F\\u0650-\\u0656]*ل[\\u064B-\\u064F\\u0650-\\u0656]*د");
Matcher m = p.matcher(INPUT); // get a matcher object
int count = 0;
while(m.find()) {
count++;
System.out.println("Match number "+count);
System.out.println("start(): "+m.start());
System.out.println("end(): "+m.end());
}
}
I using breakIterator to get each word from a sentence and there is problem when a sentence like "my mother-in-law is coming for a visit" where i am not able to get mother-in-law as a single word.
BreakIterator iterator = BreakIterator.getWordInstance(Locale.ENGLISH);
for (int end = iterator.next(); end != BreakIterator.DONE; start = end, end = iterator.next())
{
String possibleWord = sentence.substring(start, end);
if (Character.isLetterOrDigit(possibleWord.charAt(0)))
{
// grab the word
}
}
As I'm seeing in your code what are you trying to do is to check if the first character in every word are a character or a digit. Every time you use the BreakIterator.getWordInstance() you will always get all the words depending on the boundary rules of the Locale and it is a little hard to accomplish what you want to do with the use of this class until I know, so my advice is this:
String text = "my mother-in-law is coming for a visit";
String[] words = text.split(" ");
for (String word : words){
if (Character.isLetterOrDigit(word.charAt(0))){
// grab the word
}
}
I seem to be getting what seems like some extra line breaks after using this method to set the text of a TextView
message.setText(Html.fromHtml( message ));
How can I remove these? They cause my layout to get warped since it adds two extra lines to the output.
The string was saved to my sqlite database via Html.toHtml( editText.getText() ).trim();
Initial string input : hello
Log output of the message variable: <p dir="ltr">hello</p>
you can use this lines ... totally works ;)
i know your problem solved but maybe some one find this useful .
try{
string= replceLast(string,"<p dir=\"ltr\">", "");
string=replceLast(string,"</p>", "");
}catch (Exception e) {}
and here is replaceLast ...
public String replceLast(String yourString, String frist,String second)
{
StringBuilder b = new StringBuilder(yourString);
b.replace(yourString.lastIndexOf(frist), yourString.lastIndexOf(frist)+frist.length(),second );
return b.toString();
}
For kotlin you can use
html.trim('\n')
Looks like toHtml assumes everything should be in a <p> tag. I'd strip off the beginning and ending <p> and </p> tags before writing to the database.
This is working as below in Kotlin.
val myHtmlString = "<p>Test<\/p>"
HtmlCompat.fromHtml(myHtmlString.trim(), FROM_HTML_MODE_COMPACT).trim('\n')
I have a string like this:
_id:2 thread_id:189 address:0292 m_size:null person:0 date:1372494272447 date_sent:0 protocol:0 read:1 status:-1 type:1 reply_path_present:0 subject:null body:Ok. Reply message. service_center:051108 locked:0 sim_id:0 error_code:0 seen:1 _id:1 thread_id:189 address:292 m_size:null person:0 date:1372493695831 date_sent:0 protocol:null read:1 status:-1 type:2 reply_path_present:null subject:null body:Test message service_center:null locked:0 sim_id:0 error_code:0 seen:0
I want to retrieve only parts of this string, for example the address:0292 and the body:xyz from the entire string. I want all instances of these two from a very large String (above is just a sample). Let's assume its more than 20000 characters.
How can I achieve this?
Looks like every address is followed by m_size, so use the string.split() function, to split over the keyword address then select the string.substring() (from each string in the resulting array) until reaching the keyword m_size. And repeat the entire thing for the keywords body and service_center. I can't think of any other way.
You are right, it doesn't seem pretty. But it works :)
String[] splitString = string.split(" ");
for (int i = 0; i < splitString.length; i++) {
if (splitString[i].startsWith("body") || splitString[i].startsWith("address"))
Log.i(TAG, "Found: " + splitString[i]);
// Do whatever you need to do
}