Develop Reference

Android TextView not showing multiple lines, even though String has newlines [duplicate]

For the input text:
<p>Arbit string <b>of</b><br><br>text. <em>What</em> to <strong>do</strong> with it?
I run the following code:
Whitelist list = Whitelist.simpleText().addTags("br");
// Some other code...
// plaintext is the string shown above
retVal = Jsoup.clean(plaintext, StringUtils.EMPTY, list,
new Document.OutputSettings().prettyPrint(false));
I get the output:
Arbit string <b>of</b>
text. <em>What</em> to <strong>do</strong> with it?
I don't want Jsoup to convert the <br> tags to line breaks, I want to keep them as-is. How can I do that?

Try this:
Document doc2deal = Jsoup.parse(inputText);
doc2deal.select("br").append("br"); //or append("<br>")

This is not reproducible for me. Using Jsoup 1.8.3 and this code:
String html = "<p>Arbit string <b>of</b><br><br>text. <em>What</em> to <strong>do</strong> with it?";
String cleaned = Jsoup.clean(html,
"",
Whitelist.simpleText().addTags("br"),
new Document.OutputSettings().prettyPrint(false));
System.out.println(cleaned);
I get the following output:
Arbit string <b>of</b><br><br>text. <em>What</em> to <strong>do</strong> with it?
Your problem must be somewhere else I guess.

find arabic word in a string with Nunation

i want find a Arabic word with Nunation in a TextView and highlight this,
for example if my word is "اشهد" whitout Nunation i want to find word position in "وَ اَشْهَدُ اَنْ لا اِلهَ اِلاَّ اللَّهُ" with Nunation .

Hi Please see below class i created. It is so basic and did not bother about memory consumption. You guys can optimise yourself.
http://freshinfresh.com/sample/ABHArabicDiacritics.java
If you want to check without nunation(harakath) contains in an arabic String,
ABHArabicDiacritics objSearchd = new ABHArabicDiacritics();
objSearchdobjSearch.getDiacriticinsensitive("وَ اَشْهَدُ اَنْ لا اِلهَ اِلاَّ اللَّهُ").contains("اشهد");
If you want to return Highlighed or redColored searched portion in String.
Use below code
ABHArabicDiacritics objSearch = new ABHArabicDiacritics( وَ اَشْهَدُ اَنْ لا اِلهَ اِلاَّ اللَّهُ, اشهد);
SpannableString spoutput=objSearch.getSearchHighlightedSpan();
textView.setText(spoutput);
To see start and end position of search text,
Use below methods,
/** to serch Contains */
objSearch.isContain();//
objSearch.getSearchHighlightedSpan();
objSearch.getSearchTextStartPosition();
objSearch.getSearchTextEndPosition();
Please copy shared java class and enjoy.
I will spend more time for more feature if you guys request.
Thanks

search ولد in INPUT :
public void RegexMatches() {
String INPUT ="ى لَیْلَهِ تَمامِهِ وَکَمالِهِ فَما کانَتْ اِلاّ ساعَهً وَاِذا بِوَلَدِىَ الْحَسَنِ قَدْ" ;
Pattern p = Pattern.compile("و[\\u064B-\\u064F\\u0650-\\u0656]*ل[\\u064B-\\u064F\\u0650-\\u0656]*د");
Matcher m = p.matcher(INPUT); // get a matcher object
int count = 0;
while(m.find()) {
count++;
System.out.println("Match number "+count);
System.out.println("start(): "+m.start());
System.out.println("end(): "+m.end());
}
}

how to convert plain text into html text in android?

I am uploading the text to server, i just want to upload those string in html format
example
input:
Do you know the relation between two eyes...???
They never see each other... BUT
They blink together.
They move together.
They cry together.
They see together.
They sleep together.
They share a very deep bonded relationship...
However, when they see a pretty woman, one will blink and another will not...
sendtext = adding_textjoke.getText().toString();
//String htmlString = Html.toHtml(sendtext);
String str = "(?i)\\b((?:https?://|www\\d{0,3}[.]|[a-z0-9.\\-]+[.][a-z]{2,4}/)(?:[^\\s()<>]+|\\(([^\\s()<>]+|(\\([^\\s()<>]+\\)))*\\))+(?:\\(([^\\s()<>]+|(\\([^\\s()<>]+\\)))*\\)|[^\\s`!()\\[\\]{};:\'\".,<>?«»“”‘’]))";
Pattern patt = Pattern.compile(str);
Matcher matcher = patt.matcher(sendtext);
sendtext = matcher.replaceAll("$1");
System.out.println(sendtext);
Log.e("sendtext", sendtext);
new AddJokesTask().execute(sendtext);
How to do this in android?

You can do it like this
SpannableString contentText = (SpannableString) contentView.getText();
String htmlEncodedString = Html.toHtml(contentText)

SpannableStringBuilder text = (SpannableStringBuilder) contentView.getText();
String htmlEncodedString = Html.toHtml(text);

HTML String tags are not replaced (Android)

I have the following piece of HTML:
<p>Bla bla bla...</p>
<p><strong>4. others</strong></p>
<p> </p>
It contains a random <p> </p> tag combination which needs to be filtered out in my Android app. I'm using the following Java code for it:
String html = object.get("Content").toString(); // this is the HTML
html = html.replace("<p> </p>", "");
html = html.replace("<p></p>", "");
html = html.replace("<p><span></span></p>", "");
content.setText(Html.fromHtml(html));
However, when I debug and put a break point on the replace functions, it doesn't replace the strings. Now I have useless <p> tags which I don't want. How do I solve this?

It contains a random tag combination which needs to be filtered out in my Android app.
You need to replace it separately. Because replace() function works case-sensitive and sequential strings.
So, Use below code
String html = object.get("Content").toString().trim(); // this is the HTML
html = html.replace("<p>", "");
html = html.replace("</p>", "");
html = html.replace("<span>", "");
html = html.replace("</span>", "");
content.setText(Html.fromHtml(html));
instead of your joint string in replace()
String html = object.get("Content").toString(); // this is the HTML
html = html.replace("<p> </p>", "");
html = html.replace("<p></p>", "");
html = html.replace("<p><span></span></p>", "");
content.setText(Html.fromHtml(html));
You get result as per you want.
Note: But, remember that anytime you want to replace any character/string than just replace it sequential with case-sensitive. because It gives you exact result.

You are doing it in wrong way.
Correct way:
1. Use StringBuffer instead of String.
2. Find index of < and put it in a variable say int startIdx
3. Find index of > and put it in a variable say int endIdx
4. then use delete() of StringBuffer and specify this startIdx and endIdx to delete HTML tag.
This will remove all HTML code from your string.
Ok so as per your comment, this is how you do it
String replaceThis="<p></p>";
int len = replaceThis.length();
StringBuffer buff="your html string from which you want to replace";
int i;
while((i = buff.indexOf(replaceThis)!=-1)
{
buff.delete(i,len-1);
}

how to get text with using substring

I try to get only this part "9916-4203" in "Region Code:9916-4203 " in android. How can I do this?
I tried below code, I used substring method but it doesn't work:
firstNumber = Integer.parseInt(message.substring(11, 19));

If you know that string contains "Region Code:" couldn't you do a replace?
message = message.replace("Region Code:", "");

Assumed that you have only one phone number in your String, the following will remove any non-digit characters and parse the resulting number:
public static int getNumber(String num){
String tmp = "";
for(int i=0;i<num.length();i++){
if(Character.isDigit(num.charAt(i)))
tmp += num.charAt(i);
}
return Integer.parseInt(tmp);
}
Output in your case: 99164203
And as already mentioned, you won't be able to parse any String to Integer in case there are any non-digit characters

Im going to guess that what you want to extract is the full region code text minus the title. So maybe using regex would be a good simple fit for you?
String myString = "Region Code:9916-4203";
String match = "";
String pattern = "\:(.*)";
Pattern regEx = Pattern.compile(pattern);
Matcher m = regEx.matcher(myString);
// Find instance of pattern matches
Matcher m = regEx.matcher(myString);
if (m.find()) {
match = m.group(0);
}
Variable match will contain "9916-4203"
This should work for you.
Java code sourced from http://android-elements.blogspot.in/2011/04/regular-expressions-in-android.html

In Java the substring() method works with the first parameter being inclusive and the second parameter being exclusive. Meaning "Hello".substring(0, 2); will result in the string He.
In addition to excluding the parsing of something that isn't a number like #Opiatefuchs mentioned, your substring method should instead be message.substring(12, 21).