how to show only specific part of website in android webview - android

I wish to show only the login-page element of a URL. My current approach which is not working:
web.setWebViewClient(new WebViewClient() {
#Override
public void onPageFinished(WebView view, String url)
{
view.loadUrl("javascript:document.getElementByClassName('login-page')");
}
});
web.loadUrl("https://www.reddit.com/reddits/login");

For mobile screens you should develop separate screens and embed it.
Another way is if your web page supports p/# tag (i.e) like
https://developer.android.com/guide/components/fundamentals.html#Components
https://www.reddit.com/reddits#login this should navigate the page directly to login form
Anyhow I prefer you should develop the page for mobile screens.

Your approach is close to working, but you should modify the existing page instead of trying to load a subset of the existing page as a new one.
The following hides elements with class SectionToRemove, you could instead hide all and only make visible the area you need:
#Override
public void onPageFinished(final WebView view, String url) {
super.onPageFinished(view, url);
view.loadUrl("javascript:$('.SectionToRemove').hide();");
}
That being said, Reddit has extensive APIs that should be used if possible, this approach may breach Terms of Service.

Related

How to prevent the user from going to the apps and continue with browser

In my mobile site I have links to other websites that also have apps. when my users click on the links they get options in Android (I don't know about iPhone) to go to the app or continue with the browser. How do I prevent the user from going to the apps and just cntinue with the browser after clicking my links without seeing this menu (browser/app)?
What you're asking is how to prevent the expected behavior of a webpage you load in your app. That's generally not good UI/UX design. But, to do so you would need to set a WebViewClient on your WebView and evaluate the url that is being loaded to see if it is for the download of an app:
webView.setWebViewClient(new WebViewClient(){
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url){
if (url.contains("play.google.com")) {
//handle alternate action here
}
}
#Override
public void onPageFinished(WebView view, String url){
}
#Override
public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) {
}
});
That's something that's been set up on the 3rd party site, not something that's being done by the OS. There's no way to control the behavior of the browser after the user has left your web site.
For example LinkedIn will do this but Last Pass does not, even though they also have an app. This is something LinkedIn has chosen to do with their site; you can't do anything about that from your web site.

WebView.loadDataWithBaseURL. Go exactly to #label

How to go EXACTLY to http://example.com/index.html#label if content to webview loading via WebView.loadDataWithBaseURL ?
By default webview go to root only. How go to label ?
WebView doesn't have such functionality from the box.
You can achieve this with the help of javascript, but this is a bit of ugly.
You should load your html page and then add javascript code to it.
After this you can load your webview and call javascript methods from current page.
Check this link for example how that can be done.
WebView jump to anchor using loadDataWithBaseUrl
Example goes here
webContents.setWebViewClient(new WebViewClient(){
#Override
public void onPageFinished(WebView view, String url) {
String id = "895884";
webContents.loadUrl("javascript:scrollAnchor(" + id + ");");
}
});

Multiwindow Apps in Android

I am developing android application to use multiple window in same window.
I am including multiple layouts with multiple purpose. For example one part of window will have browser and one part has to display Facebook or twitter news feed, and one more to display current news which can be get from rss feed.
For the browser I am using WebView in which user can search some thing in browser.
But if I use webview to search something it is opened in android browser.
Is there anyway to display webpages with in Webview and if I search anything It should also be displayed with in web view?
Guide me in right way.
Try this solution .
WebView view =(WebView)findViewById(R.id.webView1);
view.getSettings().setJavaScriptEnabled(true);
view.setWebViewClient(new WebViewClient() {
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return false;
}
});
Thanks

An alternative to Android's webview

Does anyone knows an alternative to Android's webview component ? For some reasons, it's functionality's are insufficient for me : I need to be able to catch every single request to some url, when i'm browsing a wml page (wap). Anyway, I need to be able to do stuff that Android's webview is not made for.
I thought "hey, let's play with the source code, I'm pretty sure that webviews are using apache.org librairies to access internet".
Oh boy was I mistaken. Webviews use native code, and that's where I'm stuck.
So I was wondering if anyone knew of another web browser view, in pure java, that would be open source and nice. It's not a problem if it's slow, i'm displaying some basic wap pages...
Thanks in advance.
You can extend WebView's functionality by using setWebViewClient & setWebChromeClient.
WebView.setWebViewClient(new MyWebViewClient());
WebView.setWebChromeClient(new WebChromeClient() {..}
You can handle each and every request sent/received from the WebView by overriding the below methods:
public boolean shouldOverrideUrlLoading(WebView view, String url) {..}
public void onPageStarted(WebView view, String url, Bitmap favicon) {..}
public void onPageFinished(WebView view, String url) {..}
The crosswalk project: https://crosswalk-project.org/ might be what you need. But beware, there are places where it differs from the stock webview. In some ways better, in some ways worse. For example, it supports WebGL (good), but currently the background cannot be transparent (bad). The really good news, it seems to be very actively supported, running it's own Jira to track and fix and Intel seems to be very involved.
Try to see how was Opera Mini programmed.
But I think you must program it if you want another one . But i would be surprised if it has a nice performance.
Try this:
goButton4.setOnClickListener(new OnClickListener() {
public void onClick(View view) {
Uri uri = Uri.parse("http://tory.com/");
Intent intent = new Intent(Intent.ACTION_VIEW, uri);
startActivity(intent);
}
});

How to display a website and a button in one activity?

I'm making an application that contains button's and those buttons control an embedded browser. My problem is that I want to see the button's and the web page in the same layout, but when i click on a button this will open a web page and don't show the button, can anyone help me?
If I understand correctly your problem is that following a link opens the standard browser not your WebView, right ?
Add this to your WebView to change that behavior
// this is to prevent that when clicking a new URL from the displayed
// page the default web browser launches
webView.setWebViewClient(new WebViewClient() {
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
});
You need to use a Layout that supports more than one child. Take a look here

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