I'm making an application that contains button's and those buttons control an embedded browser. My problem is that I want to see the button's and the web page in the same layout, but when i click on a button this will open a web page and don't show the button, can anyone help me?
If I understand correctly your problem is that following a link opens the standard browser not your WebView, right ?
Add this to your WebView to change that behavior
// this is to prevent that when clicking a new URL from the displayed
// page the default web browser launches
webView.setWebViewClient(new WebViewClient() {
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
});
You need to use a Layout that supports more than one child. Take a look here
Related
Good day!
Guys, I have a problem and want your help.
Through a WebView, how do I get when clicked by the user, do not open the options of standard browsers (eg chrome and internet). I saw an app by clicking the link to the page opens normally however, as if open in a custom browser. I found it very interesting, and I wonder how this mechanics.
If anyone know how to create an app that perform the same procedure I am grateful.
For better doubt the APP is this:
https://play.google.com/store/apps/details?id=com.tachanfil.jornaisdobrasil&hl=pt-BR
You have to set up WebViewClient like
this.mWebView.setWebViewClient(new WebViewClient(){
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url){
view.loadUrl(url);
return true;
}
});
Then your app will display all links in your WebView instead of opening browser
Perhaps you are missing setting your client as the webview client - Refer to
http://developer.android.com/reference/android/webkit/WebView.html#setWebViewClient%28android.webkit.WebViewClient%29
I am developing android application to use multiple window in same window.
I am including multiple layouts with multiple purpose. For example one part of window will have browser and one part has to display Facebook or twitter news feed, and one more to display current news which can be get from rss feed.
For the browser I am using WebView in which user can search some thing in browser.
But if I use webview to search something it is opened in android browser.
Is there anyway to display webpages with in Webview and if I search anything It should also be displayed with in web view?
Guide me in right way.
Try this solution .
WebView view =(WebView)findViewById(R.id.webView1);
view.getSettings().setJavaScriptEnabled(true);
view.setWebViewClient(new WebViewClient() {
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return false;
}
});
Thanks
When I type the url in the text box and click on the Go button the webview loads the required page but when I click on any link inside the webview the address bar which is the text box is not updated with the exact url? How do I go about doing this?
I am trying all varies ways on google not getting the solution - probably key words are wrong. :( - Help on this would be great.
Thanks!
You need to Override onPageFinished method
#Override
public void onPageFinished(WebView view, String url) {
urlEditText.setText(url, TextView.BufferType.NORMAL);
super.onPageFinished(view, url);
}
Hey everyone! Im pretty new to Android and I have a webView under 2 other widgets on the screen(Or w/e you call it). But when ever I navigate the webView, its changes to full screen and i cant see my other widgets. Ive looked all over Google but couldn't find anything, is there some way I can fix this?
Im using this code to navigate:
webView.loadUrl("http://www.example.com/");
Thank you.
webview.setWebViewClient(new WebViewClient() {
public boolean shouldOverrideUrlLoading(WebView view, String url){
view.loadUrl(url);
return true;
}
});
when you do webView.loadUrl("www.example.com") or if there is a redirection when a hyperlink is clicked or something similar, the android device browser is started. I believe you are stuck with this. Try pasting the above code before you call the webView.loadUrl("www.example.com")
What we are essentially doing is asking the webview to load the url, instead of opening it in the device browser.
I am new to Android WebView, in my application i need to display a web site conatins 3 web pages. In the first web page there will be a link to navigate to the second page and second to third page. I given the URL in the WebView, the first page is displayed perfectly, when i click the link it directly opens the browser application to display the second page. But i want to display the second page in the WebView itself. Please find my code below:
WebView forumView=(WebView)findViewById(R.id.forumView);
forumView.getSettings().setJavaScriptEnabled(true);
forumView.loadUrl("url");
As i said i am very new to WebView my code might be wrong, please help me to solve this problem.
Thanks in Advance,
Rajapandian
This piece of code will help you.
wbb = (WebView) findViewById(R.id.webView_tobe_loaded);
WebSettings wbset=wbb.getSettings();
wbset.setJavaScriptEnabled(true);
wbb.setWebViewClient(new MyWebViewClient());
String url="http://www.google.com";
System.out.println(getdeviceid());
wbb.getSettings().setJavaScriptEnabled(true);
wbb.loadUrl(url);
You'll have to intercept the clicks yourself if you don't want the default Android behavior.
You can monitor events in a WebView using a WebViewClient. The method you want is shouldOverrideUrlLoading(). This allows you to perform your own action when a particular URL is selected.
You set the WebViewClient of your WebView using the setWebViewClient() method.
If you look at the WebView sample in the SDK there's an example which does just what you want. It's as simple as:
private class HelloWebViewClient extends WebViewClient {
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
}