I am developing android application to use multiple window in same window.
I am including multiple layouts with multiple purpose. For example one part of window will have browser and one part has to display Facebook or twitter news feed, and one more to display current news which can be get from rss feed.
For the browser I am using WebView in which user can search some thing in browser.
But if I use webview to search something it is opened in android browser.
Is there anyway to display webpages with in Webview and if I search anything It should also be displayed with in web view?
Guide me in right way.
Try this solution .
WebView view =(WebView)findViewById(R.id.webView1);
view.getSettings().setJavaScriptEnabled(true);
view.setWebViewClient(new WebViewClient() {
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return false;
}
});
Thanks
Related
I have android app hosting a web site in WebView. It works fine, but has one issue. Whenever users search in Google and click on page of this site, the application is opening not at that page but on home page of the web site.
For example: they click on www.example.com/blog - WebView app is open but it shows homepage, not blog.
Links (navigation) works fine inside of application when it starts.
try these code
myWebView.setWebViewClient(new WebViewClient() {
#Override
public boolean shouldOverrideUrlLoading(WebView view, WebResourceRequest request) {
view.loadUrl(request.getUrl().toString());
return false;
}
});
when you click on any link on webview then view.loadurl() method again load new url.
Good day!
Guys, I have a problem and want your help.
Through a WebView, how do I get when clicked by the user, do not open the options of standard browsers (eg chrome and internet). I saw an app by clicking the link to the page opens normally however, as if open in a custom browser. I found it very interesting, and I wonder how this mechanics.
If anyone know how to create an app that perform the same procedure I am grateful.
For better doubt the APP is this:
https://play.google.com/store/apps/details?id=com.tachanfil.jornaisdobrasil&hl=pt-BR
You have to set up WebViewClient like
this.mWebView.setWebViewClient(new WebViewClient(){
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url){
view.loadUrl(url);
return true;
}
});
Then your app will display all links in your WebView instead of opening browser
Perhaps you are missing setting your client as the webview client - Refer to
http://developer.android.com/reference/android/webkit/WebView.html#setWebViewClient%28android.webkit.WebViewClient%29
I have an Android app with that displays a mobile website (WebView), in the mobile website there are links redirecting to a PDF, Excel and video files.
When try to open it in my regular browser my phone asks to open it with another app or it start a download, so I can open it afterwards.
But in my WebView app it either doesn't work, no response or it displays a "Page unavailable" error.
Is it even possible?
To handle links in WebView, you can use the shouldOverrideUrlLoading method of WebViewClient class. Consider the following example;
WebView webView = (WebView) findViewById(R.id.infoView);
webView.setWebViewClient(new WebViewClient() {
public boolean shouldOverrideUrlLoading(WebView view, String url) {
// Assuming you are giving link to some PDF file.
if (url.contains(".pdf")) {
// Now do what you want to with the url here
}
return true;
}
}
This way, you can intercept any link tapped in WebView and then do whatever you want.
I am new to Android WebView, in my application i need to display a web site conatins 3 web pages. In the first web page there will be a link to navigate to the second page and second to third page. I given the URL in the WebView, the first page is displayed perfectly, when i click the link it directly opens the browser application to display the second page. But i want to display the second page in the WebView itself. Please find my code below:
WebView forumView=(WebView)findViewById(R.id.forumView);
forumView.getSettings().setJavaScriptEnabled(true);
forumView.loadUrl("url");
As i said i am very new to WebView my code might be wrong, please help me to solve this problem.
Thanks in Advance,
Rajapandian
This piece of code will help you.
wbb = (WebView) findViewById(R.id.webView_tobe_loaded);
WebSettings wbset=wbb.getSettings();
wbset.setJavaScriptEnabled(true);
wbb.setWebViewClient(new MyWebViewClient());
String url="http://www.google.com";
System.out.println(getdeviceid());
wbb.getSettings().setJavaScriptEnabled(true);
wbb.loadUrl(url);
You'll have to intercept the clicks yourself if you don't want the default Android behavior.
You can monitor events in a WebView using a WebViewClient. The method you want is shouldOverrideUrlLoading(). This allows you to perform your own action when a particular URL is selected.
You set the WebViewClient of your WebView using the setWebViewClient() method.
If you look at the WebView sample in the SDK there's an example which does just what you want. It's as simple as:
private class HelloWebViewClient extends WebViewClient {
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
}
I'm making an application that contains button's and those buttons control an embedded browser. My problem is that I want to see the button's and the web page in the same layout, but when i click on a button this will open a web page and don't show the button, can anyone help me?
If I understand correctly your problem is that following a link opens the standard browser not your WebView, right ?
Add this to your WebView to change that behavior
// this is to prevent that when clicking a new URL from the displayed
// page the default web browser launches
webView.setWebViewClient(new WebViewClient() {
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
});
You need to use a Layout that supports more than one child. Take a look here