I must extract an image's url when reading RSS feeds. I was told to use regular expressions but I didn't manage to build a correct pattern.
You want to first
public class Utility {
public static Bitmap getBitmapFile(String str)
{
Bitmap bmImg=null;
URL myFileUrl;
try {
myFileUrl = new URL(str);
HttpURLConnection conn= (HttpURLConnection)myFileUrl.openConnection();
conn.setDoInput(true);
conn.connect();
InputStream is = conn.getInputStream();
bmImg = BitmapFactory.decodeStream(is);
} catch (Exception e) {
e.printStackTrace();
}
return bmImg;
}
}
After whatever you get like
String str="www.fifa.com/img.jpg"
ImageView img=(Imageview)findviewbyId(R.id.img);
Bitmap bmp=Utility.getBitmapFile(str);
img.setImageBitmap(bmp);
After you see parsed image in ImageView
Related
In my android project I would like to get a Bitmap image from given URL(htp://....) for this purpose I have used the below code to achieve this concept. But while running my code I am getting java.io.FileNotFoundException. So anyone please provide a better solution to solve this issue or else provide any code snippet to achieve this task.
public static Bitmap getBitmapFromURL(String src) {
try {
Log.e("src", src);
String stringURL = "http://.....";
URL url = new URL(stringURL);
HttpURLConnection connection = (HttpURLConnection) url
.openConnection();
connection.setDoInput(true);
connection.connect();
InputStream input = connection.getInputStream();
Bitmap myBitmap = BitmapFactory.decodeStream(input);
Log.e("Bitmap", "returned");
return myBitmap;
} catch (IOException e) {
e.printStackTrace();
Log.e("Exception", e.getMessage());
return null;
}
}
I am using a method to get the Image from URL when a button is clicked but it gets too much time, about 4-5 seconds to show an image sized only 6 kb using 3G not wi-fi.
My method is this;
public static Bitmap getBitmapFromURL(String src) {
try {
Log.e("src",src);
URL url = new URL(src);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.connect();
InputStream input = connection.getInputStream();
Bitmap myBitmap = BitmapFactory.decodeStream(input);
Log.e("Bitmap","returned");
return myBitmap;
} catch (IOException e) {
e.printStackTrace();
Log.e("Exception",e.getMessage());
return null;
}
}
and then;
Bitmap bimage = getBitmapFromURL("http://www.replikler.net/test2.jpg");
ImageView image = (ImageView)findViewById(R.id.movie_image);
image.setImageBitmap(bimage);
do you know another way (faster) to get an image from url ?
imageView.setImageDrawable(Drawable.createFromStream((InputStream)new URL(url).getContent(), "src"));
I need to download one file from an url that i give from an xml after connect to other url. My problem is that i need the same user agent and ip to do both actions.
To obtain the xml, i use a PHP code that is hosted on my server and i send it the user agent of my app:
String ua=new WebView(ct).getSettings().getUserAgentString().trim();
ua = ua.replaceAll(" ", "%20");
Then i parse the xml with a generic RssParserSax that gives me all i need.
After, i try to download the file to a drawable var and i do this:
Drawable dd = ImageOperations(url);
private Drawable ImageOperations(String url) {
try {
InputStream is = (InputStream) this.fetch(url);
Drawable d = Drawable.createFromStream(is, "src");
return d;
} catch (MalformedURLException e) {
return null;
} catch (IOException e) {
return null;
}
}
private Object fetch(String address) throws MalformedURLException,IOException {
URL url = new URL(address);
Object content = url.getContent();
return content;
}
But as i don't send the user agent, it does not give me anything.
Finally i did this to resolve:
Bitmap bmImg;
try {
URL url = new URL(addres);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.addRequestProperty("User-Agent", ua);
conn.setDoInput(true);
conn.connect();
InputStream is = conn.getInputStream();
bmImg = BitmapFactory.decodeStream(is);
imagen.setImageBitmap(bmImg);
imagen.setScaleType(ScaleType.FIT_XY);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
You can use AndroidHttpClient.newInstance(useragent).
See an example here AndroidHttpClient can not getEntity().getContent() after closed
How can I turn the static image
<ImageView
android:id="#+id/imageView1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_weight="0.67"
android:src="#drawable/static_image" />
into an ImageView whose source can be dynamically set to data that is not already in the res folder?
That is, my application has an icon on the screen but the actual image for the icon is downloaded from an outside server and can change dynamically. How do I update the ImageView with the desired image upon download? I want something functionally like:
Image selectedImage = //get from server
myImageView.setImage(selectedImage);
Ur question is not clear. If u just wanna have an image(that is in some url) set to an image view,
Bitmap bmp=getBitmapFromURL(ur url here);
imgview.setImageBitmap(bmp);
and write this function:
public static Bitmap getBitmapFromURL(String src) {
try {
URL url = new URL(src);
HttpURLConnection connection = (HttpURLConnection) url
.openConnection();
connection.setDoInput(true);
connection.connect();
InputStream input = connection.getInputStream();
Bitmap mybitmap = BitmapFactory.decodeStream(input);
return mybitmap;
} catch (Exception ex) {
return null;
}
yourImageView.setImageBitmap(bitmap);
to get Bitmap from server:
public static Bitmap loadBitmap(String url) {
Bitmap bitmap = null;
InputStream in = null;
BufferedOutputStream out = null;
try {
in = new BufferedInputStream(new URL(url).openStream(), IO_BUFFER_SIZE);
final ByteArrayOutputStream dataStream = new ByteArrayOutputStream();
out = new BufferedOutputStream(dataStream, IO_BUFFER_SIZE);
copy(in, out);
out.flush();
final byte[] data = dataStream.toByteArray();
BitmapFactory.Options options = new BitmapFactory.Options();
//options.inSampleSize = 1;
bitmap = BitmapFactory.decodeByteArray(data, 0, data.length,options);
} catch (IOException e) {
Log.e(TAG, "Could not load Bitmap from: " + url);
} finally {
closeStream(in);
closeStream(out);
}
return bitmap;
}
As per I understand your question something like,
ImageView selectedImage;
selectedImage = (ImageView)findViewById(R.id.imageView1);
Bitmap bmImg;
downloadFile(imageUrl);
And this is downloadFile() Method...
void downloadFile(String fileUrl){
URL myFileUrl =null;
try {
myFileUrl= new URL(fileUrl);
} catch (MalformedURLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
try {
HttpURLConnection conn= (HttpURLConnection)myFileUrl.openConnection();
conn.setDoInput(true);
conn.connect();
InputStream is = conn.getInputStream();
bmImg = BitmapFactory.decodeStream(is);
selectedImage.setImageBitmap(bmImg);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
You need to create a custom view and over-ride onDraw(). From there you are provided the drawing Canvas and you can do whatever you like. So assuming your dynamic image can be converted to a bitmap, there are numerous drawBitmap() methods you can use from Canvas.
Note that you must also override onMeasure() which allows your view to tell the layout manager how much space you need.
There's a lot of good info here:
http://developer.android.com/guide/topics/ui/custom-components.html
I want to read an image from a this URL photo
and I'm using the following code
public static Bitmap DownloadImage(String URL)
{
Bitmap bitmap=null;
InputStream in=null;
try {
in=networking.OpenHttpConnection("http://izwaj.com/"+URL);
BitmapFactory.Options options=new BitmapFactory.Options();
options.inSampleSize=8;
bitmap=BitmapFactory.decodeStream(in, null, options);
in.close();
} catch (Exception e) {
// TODO: handle exception
}
return bitmap;
}
public class Networking {
public InputStream OpenHttpConnection(String urlString)
throws IOException
{
InputStream in=null;
int response = -1;
URL url=new URL(urlString);
URLConnection conn=url.openConnection();
if(!(conn instanceof HttpURLConnection))
{
throw new IOException("Not an HTTP connection");
}
try {
HttpURLConnection httpconn=(HttpURLConnection)conn;
httpconn.setAllowUserInteraction(false);
httpconn.setInstanceFollowRedirects(true);
httpconn.setRequestMethod("GET");
httpconn.connect();
response=httpconn.getResponseCode();
if(response==HttpURLConnection.HTTP_OK)
{
in=httpconn.getInputStream();
}
}
catch (Exception ex) {
throw new IOException("Error connecting");
}
return in;
}
The bitmap always returned to me null.. I used also other functions found on the internet. all returned the bitmap as null value :S
use this function it may help you.
public Bitmap convertImage(String url)
{
URL aURL = null;
try
{
final String imageUrl =url.replaceAll(" ","%20");
Log.e("Image Url",imageUrl);
aURL = new URL(imageUrl);
URLConnection conn = aURL.openConnection();
InputStream is = conn.getInputStream();
//#SuppressWarnings("unused")
BufferedInputStream bis = new BufferedInputStream(is);
Bitmap bm = BitmapFactory.decodeStream(new PatchInputStream(bis));
if(bm==null)
{}
else
Bitmap bit=Bitmap.createScaledBitmap(bm,72, 72, true);//mention size here
return bit;
}
catch (IOException e)
{
Log.e("error in bitmap",e.getMessage());
return null;
}
}
I would check the %20 spacing on the picture
http://184.173.7.132/RealAds_Images/Apartment%20for%20sale,%20Sheikh%20Zayed%20_%201.jpg
To me the %20 will not render a space so ensure this is noted in your code
if you change the file to apartmentforsalesheikhzayed20201.jpg or something like as a test apartment.jpg it will work.
Personally instead of using spaces in your image names i would use an underscore between the spaces so no other code is needed try_renaming_your_photo_to_this.jpg :)