In my android project I would like to get a Bitmap image from given URL(htp://....) for this purpose I have used the below code to achieve this concept. But while running my code I am getting java.io.FileNotFoundException. So anyone please provide a better solution to solve this issue or else provide any code snippet to achieve this task.
public static Bitmap getBitmapFromURL(String src) {
try {
Log.e("src", src);
String stringURL = "http://.....";
URL url = new URL(stringURL);
HttpURLConnection connection = (HttpURLConnection) url
.openConnection();
connection.setDoInput(true);
connection.connect();
InputStream input = connection.getInputStream();
Bitmap myBitmap = BitmapFactory.decodeStream(input);
Log.e("Bitmap", "returned");
return myBitmap;
} catch (IOException e) {
e.printStackTrace();
Log.e("Exception", e.getMessage());
return null;
}
}
Related
I try to load a jpg image in a image view but I can't get the image, I debug the code and I guess to have some issue with permissions but when I try from another public web I have the same problem.
I use this 2 examples published here but I can find where is my error, very thanks for the help!
//option 1
private static Drawable fotoWeb(String address) {
try {
InputStream is = (InputStream) new URL(address).getContent();
//this line don't work crash on getContent()
Drawable d = Drawable.createFromStream(is, "Foto");
return d;
} catch (Exception e) {
return null;
}
}
//option 2
private static Bitmap fotoBMP (String address){
try {
URL url = new URL(address);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(60000 /* milliseconds */);
conn.setConnectTimeout(65000 /* milliseconds */);
conn.setRequestMethod("GET");
conn.setDoInput(true);
conn.connect(); //this line don't work crash on connect()
InputStream is = conn.getInputStream();
BufferedInputStream bufferedInputStream = new BufferedInputStream(is);
Bitmap bmpImage = BitmapFactory.decodeStream(bufferedInputStream);
return bmpImage;
} catch (Exception e) {
return null;
}
}
The code seems to be fine, just ensure to add the internet permission to your AndroidManifest.xml file:
<uses-permission android:name="android.permission.INTERNET" />
Much more simplified and enough:
public static Bitmap fotoBMP(String address) {
try {
URL url = new URL(address);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.connect();
return BitmapFactory.decodeStream(connection.getInputStream());
} catch (IOException ioEx) {
return null;
}
}
I better use the Picasso Library with the result I want very thanks GoRos for the help here is the link I use to see how to use http://javatechig.com/android/how-to-use-picasso-library-in-android
I am using a method to get the Image from URL when a button is clicked but it gets too much time, about 4-5 seconds to show an image sized only 6 kb using 3G not wi-fi.
My method is this;
public static Bitmap getBitmapFromURL(String src) {
try {
Log.e("src",src);
URL url = new URL(src);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.connect();
InputStream input = connection.getInputStream();
Bitmap myBitmap = BitmapFactory.decodeStream(input);
Log.e("Bitmap","returned");
return myBitmap;
} catch (IOException e) {
e.printStackTrace();
Log.e("Exception",e.getMessage());
return null;
}
}
and then;
Bitmap bimage = getBitmapFromURL("http://www.replikler.net/test2.jpg");
ImageView image = (ImageView)findViewById(R.id.movie_image);
image.setImageBitmap(bimage);
do you know another way (faster) to get an image from url ?
imageView.setImageDrawable(Drawable.createFromStream((InputStream)new URL(url).getContent(), "src"));
I'd like to know how I can download an Image from a given URL and display it inside an ImageView. And is there any permissions required to mention in the manifest.xml file?
You need to put this permission to access the Internet
<uses-permission android:name="android.permission.INTERNET" />
you can try this code.
String imageurl = "YOUR URL";
InputStream in = null;
try
{
Log.i("URL", imageurl);
URL url = new URL(imageurl);
URLConnection urlConn = url.openConnection();
HttpURLConnection httpConn = (HttpURLConnection) urlConn;
httpConn.connect();
in = httpConn.getInputStream();
}
catch (MalformedURLException e)
{
e.printStackTrace();
}
catch (IOException e)
{
e.printStackTrace();
}
Bitmap bmpimg = BitmapFactory.decodeStream(in);
ImageView iv = "YOUR IMAGE VIEW";
iv.setImageBitmap(bmpimg);
Use background thread to get image and after getting image set it in imageview using hanndler.
new Thread(){
public void run() {
try {
Bitmap bitmap = BitmapFactory.decodeStream(new URL("http://imageurl").openStream());
Message msg = new Message();
msg.obj = bitmap;
imageHandler.sendMessage(msg);
} catch (Exception e) {
e.printStackTrace();
}
}
}.start();
Handler code where we set downloaded image in imgaeview.
Handler imageHandler = new Handler(){
public void handleMessage(Message msg) {
if(msg.obj!=null && msg.obj instanceof Bitmap){
imageview.setBackgroundDrawable(new BitmapDrawable((Bitmap)msg.obj));
}
};
};
And ofcourse you need internet permission.
<uses-permission android:name="android.permission.INTERNET" />
You need to set usage permission of INTERNET in android manifest file and use java.net.URL and java.net.URLConnection classes to request the URL.
There is the BitmapFactory-class which can do that. It can create a Bitmap-object from an InputStream, which can then be displayed in an ImageView.
Something you should know is, that using a normal URLConnection to get an InputStream on a URL-object does not always work with the bitmap-factory. A work-around is presented here: Android: Bug with ThreadSafeClientConnManager downloading images
look this:
Option A:
public static Bitmap getBitmap(String url) {
Bitmap bm = null;
try {
URL aURL = new URL(url);
URLConnection conn = aURL.openConnection();
conn.connect();
InputStream is = conn.getInputStream();
BufferedInputStream bis = new BufferedInputStream(is);
bm = BitmapFactory.decodeStream(new FlushedInputStream(is));
bis.close();
is.close();
} catch (Exception e) {
e.printStackTrace();
}
return bm;
}
Option B:
public Bitmap getBitmapFromURL(String src) {
try {
URL url = new URL(src);
HttpURLConnection connection = (HttpURLConnection) url
.openConnection();
connection.setDoInput(true);
connection.connect();
InputStream input = connection.getInputStream();
Bitmap myBitmap = BitmapFactory.decodeStream(input);
input.close();
return myBitmap;
} catch (IOException e) {
e.printStackTrace();
return null;
}
}
Jus run the method in a background thread.
I want to read an image from a this URL photo
and I'm using the following code
public static Bitmap DownloadImage(String URL)
{
Bitmap bitmap=null;
InputStream in=null;
try {
in=networking.OpenHttpConnection("http://izwaj.com/"+URL);
BitmapFactory.Options options=new BitmapFactory.Options();
options.inSampleSize=8;
bitmap=BitmapFactory.decodeStream(in, null, options);
in.close();
} catch (Exception e) {
// TODO: handle exception
}
return bitmap;
}
public class Networking {
public InputStream OpenHttpConnection(String urlString)
throws IOException
{
InputStream in=null;
int response = -1;
URL url=new URL(urlString);
URLConnection conn=url.openConnection();
if(!(conn instanceof HttpURLConnection))
{
throw new IOException("Not an HTTP connection");
}
try {
HttpURLConnection httpconn=(HttpURLConnection)conn;
httpconn.setAllowUserInteraction(false);
httpconn.setInstanceFollowRedirects(true);
httpconn.setRequestMethod("GET");
httpconn.connect();
response=httpconn.getResponseCode();
if(response==HttpURLConnection.HTTP_OK)
{
in=httpconn.getInputStream();
}
}
catch (Exception ex) {
throw new IOException("Error connecting");
}
return in;
}
The bitmap always returned to me null.. I used also other functions found on the internet. all returned the bitmap as null value :S
use this function it may help you.
public Bitmap convertImage(String url)
{
URL aURL = null;
try
{
final String imageUrl =url.replaceAll(" ","%20");
Log.e("Image Url",imageUrl);
aURL = new URL(imageUrl);
URLConnection conn = aURL.openConnection();
InputStream is = conn.getInputStream();
//#SuppressWarnings("unused")
BufferedInputStream bis = new BufferedInputStream(is);
Bitmap bm = BitmapFactory.decodeStream(new PatchInputStream(bis));
if(bm==null)
{}
else
Bitmap bit=Bitmap.createScaledBitmap(bm,72, 72, true);//mention size here
return bit;
}
catch (IOException e)
{
Log.e("error in bitmap",e.getMessage());
return null;
}
}
I would check the %20 spacing on the picture
http://184.173.7.132/RealAds_Images/Apartment%20for%20sale,%20Sheikh%20Zayed%20_%201.jpg
To me the %20 will not render a space so ensure this is noted in your code
if you change the file to apartmentforsalesheikhzayed20201.jpg or something like as a test apartment.jpg it will work.
Personally instead of using spaces in your image names i would use an underscore between the spaces so no other code is needed try_renaming_your_photo_to_this.jpg :)
I have an image view in my app. when I try to make it show a jpg file exported from 3ds max, it works. But if it comes from Photoshop, it just does nothing. Why is that? If it is at all important my app gets the image from my server with the following code:
public static Bitmap getWebImage(String URL)
{
URL myImageURL = null;
Bitmap bitmap = null;
try {
myImageURL = new URL(URL);
} catch (MalformedURLException error) {
error.printStackTrace();
}
try {
HttpURLConnection connection = (HttpURLConnection)myImageURL .openConnection();
connection.setDoInput(true);
connection.connect();
InputStream input = connection.getInputStream();
bitmap = BitmapFactory.decodeStream(input);
} catch (IOException e) {
e.printStackTrace();
}
return bitmap;
}
Can you check the color settings of your JPG files? Most likely your JPG files from photoshop is in CMYK rather than RGB, and Android simply doesn't support CMYK.
Would it be possible for you to upload the two pictures for comparison?
public static Bitmap getWebImage(String URL)
{
URL myImageURL = null;
Bitmap bitmap = null;
try {
myImageURL = new URL(URL);
} catch (MalformedURLException error) {
error.printStackTrace();
}
try {
HttpURLConnection connection = (HttpURLConnection)myImageURL .openConnection();
connection.setDoInput(true);
connection.connect();
InputStream input = connection.getInputStream();
bitmap = BitmapFactory.decodeStream(input);
} catch (IOException e) {
e.printStackTrace();
}
return bitmap;
}