Pattern pattern = Pattern.compile("[a-zA-Z]+&");
myCustomLink.setText("press Linkify& or on Android& to search it on google");
Linkify.addLinks(myCustomLink,pattern, "http://www.google.ie/search?q=");
This code works perfectly but I cannot get it how patterns works and convert only Linkfy and Android as a link ???
It's a regular expression.
http://www.marksanborn.net/howto/learning-regular-expressions-for-beginners-the-basics/
http://www.regular-expressions.info/reference.html
it's saying get ' Letters followed by the &(ampersand) sign ' if you changed it to a . (fullstop) the . character has a special meaning in regex so you can't use it in this situation.
You could change it to:
[a-zA-Z]+L
then anything like:
press LinkifyL or on AndroidL to search it on google
will change to a link, get it?
Related
I've been trying to find a good way to be able to keep only emojis and letters in a given text, but every article I found, I didn't have success with .
I've tried to use regex, but seems that I can not make it work.
I've tried to use emoji4j but it seems that this library is working with emojis in this form ":)", which don't help me, because my emojis are groups of unicode characters.
The result I want is the following :
"This is. a text 👨👩👧👦,,1234" => "This is a text 👨👩👧👦"
"👨👩👧👦" => "👨👩👧👦"
"👨👩👧👦😃123abc👨👩👧👦" => "👨👩👧👦😃abc👨👩👧👦"
Here's the emoji regex : ?:[\u2700-\u27bf]|(?:[\ud83c\udde6-\ud83c\uddff]){2}|[\ud800\udc00-\uDBFF\uDFFF]|[\u2600-\u26FF])[\ufe0e\ufe0f]?(?:[\u0300-\u036f\ufe20-\ufe23\u20d0-\u20f0]|[\ud83c\udffb-\ud83c\udfff])?(?:\u200d(?:[^\ud800-\udfff]|(?:[\ud83c\udde6-\ud83c\uddff]){2}|[\ud800\udc00-\uDBFF\uDFFF]|[\u2600-\u26FF])[\ufe0e\ufe0f]?(?:[\u0300-\u036f\ufe20-\ufe23\u20d0-\u20f0]|[\ud83c\udffb-\ud83c\udfff])?)*|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|[\ud83c\udd70-\ud83c\udd71]|[\ud83c\udd7e-\ud83c\udd7f]|\ud83c\udd8e|[\ud83c\udd91-\ud83c\udd9a]|[\ud83c\udde6-\ud83c\uddff]|[\ud83c\ude01-\ud83c\ude02]|\ud83c\ude1a|\ud83c\ude2f|[\ud83c\ude32-\ud83c\ude3a]|[\ud83c\ude50-\ud83c\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff] .
If I try something like :
val regex = "the_whole_regex_above | [^a-zA-Z]".toRegex()
myText.replace(regex,""), it won't replace anything, basically every character will pass
Basically I want to achieve pretty much the same thing as in this question, but using Kotlin.
You want to remove all punctuation, symbols (other than those used to form emojis) and digits.
To do that, you may use
myText = myText.replace("""[\p{N}\p{P}\p{S}&&[^\p{So}]]+""".toRegex(), "")
See the online Kotlin demo.
Details
[ - start of a character class that matches:
\p{N} - any Unicode digit
\p{P} - any Unicode punctuation proper
\p{S} - any Unicode symbol
&&[^\p{So}] - BUT the Unicode symbols belonging to Symbol, other Unicode category that are mostly used to form emojis
]+ - 1 or more occurrences.
I have an Android application that uses Google Translate API.
Everything works great, including when I tried to translate phrases that include apostrophe like "We've eaten" to Spanish.
However, problems occur when the translation result I should be getting back contains an apostrophe. For example, when I translate a Spanish phrase, "A ver", into English, it returns "Let's see" with a ";" after "9". It seems like whenever I have a phrase that should return an apostrophe, it returns "'" with a ";" after "9". (Not placing ";" after "9" because it gets converted to an apostrophe by stackoverflow).
I can think of a way to solve it. After I get the translation result, I can match the string for ""'" + ";" and replace it with an apostrophe.
However, I don't feel like this is the way I should approach it. It's very unlikely that a user will actually type in "'" as an input for translation, but hard coding a manual conversion like this seems like it might cause problems down the road. I'll love to hear your thoughts on this.
Please let me know how I should fix/approach this issue.
Thank you!
The best solution is to add &format=text to your query.
You are correct hard codding is not solution,
But you can convert this HTML entity back to apostrophe, by Using HTML classes provided already.
Html.fromHtml((String) "Let's see").toString()
Above code will convert any valid HTML entity.
I Hope this is what you are looking for.
Thanks Guillaume. For those using php.
$translation = $translate->translate($stringToTranslate, ['target' => $target, 'format' => 'text']);
Thanks Guillaume. For those using go. (api v3)
req := &translatepb.TranslateTextRequest{
MimeType: "text/plain", // add this line to request
}
I have a sample message . I need to create a regular expression to validate using android pattern.
sample message :
ERR|any digit|any digit;
checking validation:
1.Starting fixed characters :ERR
separator character :|
digit after | character
Message termination ;
I have tried like this way:^{ERR}+{|}+\d+{|}+\d+{;}$
Am I right? Please help to solve my problem.
The corrected regex you gave would be ^(ERR)+(\\|)+\\d+(\\|)+\\d+;$. Brackets are used for grouping, not braces. Also, in regex, + is used to represent "one or more of the previous expression". So writing (ERR)+ means "one or more of the string 'ERR'", so strings like "ERRERR|123|456;" would be matched (same thing goes for the pipe characters) - this is not what you are trying to do, I assume.
Having said that, try this: "^ERR\\|\\d+\\|\\d+;$"
In my application users enters mobile number's country code with '+' symbol. Right now I am checking for + symbol. If they enter '+INDIA', according to my code this is correct. But according to logic this is wrong. They needs to enter '+91'. Means they can enter only 1, 2 or 3 digit number with '+' symbol. for example '+1', '+91' or '+234'. How I can achieve this type of validation in android?
You could write your own Pattern to check the format. I could give you the example, but I think the site I linked explains it much better.
It should probably start with something like \+\d\d?\d?
You could try using Google's own implementation of Phone Numbers or this xml list.
Hope it helps !
I am using solo.searchText function in my robotium testcases. I am passing the text as "$ testdata" for searching. But it is not detecting the text even if the text is there in the screen. Do we need to handle special charecters before using solo.searchText()? Please help me
Use Pattern.quote() as mentioned here to search for special characters that would otherwise be interpreted as regular expressions.
solo.searchText(Pattern.quote(stringWithSpecialCharacters))