solo.searchText does not identify "$" - android

I am using solo.searchText function in my robotium testcases. I am passing the text as "$ testdata" for searching. But it is not detecting the text even if the text is there in the screen. Do we need to handle special charecters before using solo.searchText()? Please help me

Use Pattern.quote() as mentioned here to search for special characters that would otherwise be interpreted as regular expressions.
solo.searchText(Pattern.quote(stringWithSpecialCharacters))

Related

Kotlin Android allow only emojis and letters in a text

I've been trying to find a good way to be able to keep only emojis and letters in a given text, but every article I found, I didn't have success with .
I've tried to use regex, but seems that I can not make it work.
I've tried to use emoji4j but it seems that this library is working with emojis in this form ":)", which don't help me, because my emojis are groups of unicode characters.
The result I want is the following :
"This is. a text ๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘งโ€๐Ÿ‘ฆ,,1234" => "This is a text ๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘งโ€๐Ÿ‘ฆ"
"๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘งโ€๐Ÿ‘ฆ" => "๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘งโ€๐Ÿ‘ฆ"
"๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘งโ€๐Ÿ‘ฆ๐Ÿ˜ƒ123abc๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘งโ€๐Ÿ‘ฆ" => "๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘งโ€๐Ÿ‘ฆ๐Ÿ˜ƒabc๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘งโ€๐Ÿ‘ฆ"
Here's the emoji regex : ?:[\u2700-\u27bf]|(?:[\ud83c\udde6-\ud83c\uddff]){2}|[\ud800\udc00-\uDBFF\uDFFF]|[\u2600-\u26FF])[\ufe0e\ufe0f]?(?:[\u0300-\u036f\ufe20-\ufe23\u20d0-\u20f0]|[\ud83c\udffb-\ud83c\udfff])?(?:\u200d(?:[^\ud800-\udfff]|(?:[\ud83c\udde6-\ud83c\uddff]){2}|[\ud800\udc00-\uDBFF\uDFFF]|[\u2600-\u26FF])[\ufe0e\ufe0f]?(?:[\u0300-\u036f\ufe20-\ufe23\u20d0-\u20f0]|[\ud83c\udffb-\ud83c\udfff])?)*|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|[\ud83c\udd70-\ud83c\udd71]|[\ud83c\udd7e-\ud83c\udd7f]|\ud83c\udd8e|[\ud83c\udd91-\ud83c\udd9a]|[\ud83c\udde6-\ud83c\uddff]|[\ud83c\ude01-\ud83c\ude02]|\ud83c\ude1a|\ud83c\ude2f|[\ud83c\ude32-\ud83c\ude3a]|[\ud83c\ude50-\ud83c\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff] .
If I try something like :
val regex = "the_whole_regex_above | [^a-zA-Z]".toRegex()
myText.replace(regex,""), it won't replace anything, basically every character will pass
Basically I want to achieve pretty much the same thing as in this question, but using Kotlin.
You want to remove all punctuation, symbols (other than those used to form emojis) and digits.
To do that, you may use
myText = myText.replace("""[\p{N}\p{P}\p{S}&&[^\p{So}]]+""".toRegex(), "")
See the online Kotlin demo.
Details
[ - start of a character class that matches:
\p{N} - any Unicode digit
\p{P} - any Unicode punctuation proper
\p{S} - any Unicode symbol
&&[^\p{So}] - BUT the Unicode symbols belonging to Symbol, other Unicode category that are mostly used to form emojis
]+ - 1 or more occurrences.

Create regular expression using android pattern

I have a sample message . I need to create a regular expression to validate using android pattern.
sample message :
ERR|any digit|any digit;
checking validation:
1.Starting fixed characters :ERR
separator character :|
digit after | character
Message termination ;
I have tried like this way:^{ERR}+{|}+\d+{|}+\d+{;}$
Am I right? Please help to solve my problem.
The corrected regex you gave would be ^(ERR)+(\\|)+\\d+(\\|)+\\d+;$. Brackets are used for grouping, not braces. Also, in regex, + is used to represent "one or more of the previous expression". So writing (ERR)+ means "one or more of the string 'ERR'", so strings like "ERRERR|123|456;" would be matched (same thing goes for the pipe characters) - this is not what you are trying to do, I assume.
Having said that, try this: "^ERR\\|\\d+\\|\\d+;$"

How to use solo.searchText for searching some text consisting of special characters

I am using robotium to test an android project.I have a testcase where i need to test a message consisting of special characters is posted correctly.
So I created a constant consisting of special characters :
public static final String PostMessageWithSpecialchars = "Hey hi,* Have a good day*.:()[]-=/&!?"'+;##";
and i am using following code to search it and assert that the posted message is exactly like the message in the constant PostMessageWithSpecialchars
assertTrue(solo.searchText(PostMessageWithSpecialchars));
but the test fails at assertTrue line.
What to do to search the PostMessageWithSpecialchars text?I dont want to use escape characters because that will ignore special characters.I want to make sure that the special characters in the PostMessageWithSpecialchars message are posted correctly.
The method solo.searchText() accept regex pattern. In your search string you are using special characters that is used for patters. You can quote them to find any text:
assertTrue(solo.searchText(Pattern.quote(PostMessageWithSpecialchars)));

android edittext limit to text and numbers

I am creating an android application. The first thing I'm creating is a login activity. I am trying to limit the username edittext just to text/numbers only (no special characters). Is there a way to adjust this in the xml file?
I dont think you can limit the characters from xml. You could always use a InputFilter, but specifically android provides UsernameFilterGeneric to filter valid user names. You could also use UsernameFilterGMail
As you already use in java Regular expression.called the same class here for checking for particular field.
let me know if you want some more if you didn't know about the RE.

Linkify using pattern

Pattern pattern = Pattern.compile("[a-zA-Z]+&");
myCustomLink.setText("press Linkify& or on Android& to search it on google");
Linkify.addLinks(myCustomLink,pattern, "http://www.google.ie/search?q=");
This code works perfectly but I cannot get it how patterns works and convert only Linkfy and Android as a link ???
It's a regular expression.
http://www.marksanborn.net/howto/learning-regular-expressions-for-beginners-the-basics/
http://www.regular-expressions.info/reference.html
it's saying get ' Letters followed by the &(ampersand) sign ' if you changed it to a . (fullstop) the . character has a special meaning in regex so you can't use it in this situation.
You could change it to:
[a-zA-Z]+L
then anything like:
press LinkifyL or on AndroidL to search it on google
will change to a link, get it?

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