In my application, I've developed to get a list of third party applications that the user installed. from that, what now I want is to add a button where, when clicked the user is directed to the inbuilt application details screen with the force stop and uninstall option, since I only take user installed application I don't need root permission and as well as system permission. is there a way to call that system intent inside my application.
try as:
Intent detailsIntent = new Intent();
detailsIntent.setClassName("com.android.settings",
"com.android.settings.InstalledAppDetails");
//ApiLevel greater than or equal to 8
detailsIntent.putExtra("pkg", "Appliction_Package_NAme");
//ApiLevel in less than 8
detailsIntent.putExtra("com.android.settings.ApplicationPkgName",
"Appliction_Package_NAme");
startActivity(detailsIntent);
try this
Intent intent = new Intent(Intent.ACTION_DELETE);
intent.setData(Uri.parse("package:app package name"));
startActivity(intent);
Related
I am looking for a way to create shortcuts from other apps.
Like launchs can query the apps that allow to create shortcuts and create them save them in thier program.
My API version is between M(21) to N7.1(25).
Even just a link or name of API it's fine. I just couldn't find it at all. All I found is about the new shortcut in android N.
Thx for ur time.
I found the way to do it. Since i don't see much info for this. I hope my share can help whoever is also looking for the answer.
So there will be 3 steps:
Get apps that can create shortcuts
Send Intent to the app that you want to create shortcut from
Get shortcut data in Activity.onActivityResult
1.
Since I just need to create shortcuts from certain apps. I skipped step one. But I guess using queryIntentActivities(...) or some other functions in PackageManager can get you the list.
Intent intent = new Intent("android.intent.action.CREATE_SHORTCUT");
PackageManager.queryIntentActitvies(intent,0);
2. Send intent to the app to create a shortcut.
Intent intent = new Intent("android.intent.action.CREATE_SHORTCUT");
intent.setComponent(...);
startActivityForResult(intent, requestCode);
3. Get data of shortcut:
Shortcut intent
Intent shortcutIntent = activityResultIntent.getParcelableExtra(Intent.EXTRA_SHORTCUT_INTENT);
Shortcut name
String shortcutName = intent.getStringExtra(Intent.EXTRA_SHORTCUT_NAME);
Shortcut icon
Bitmap shortcutIcon = intent.getParcelableExtra(Intent.EXTRA_SHORTCUT_ICON);
I have an android application that requires VPN. My users will be using Galaxy Note 3's and will be using the built in "VPN Client" (com.ipsec.vpnclient). I need to find a way to launch this application from my application, in the instance of the VPN dropping. I've already figured out a way to determine if the VPN dropped, but I still need a way to launch the application.
ANSWER:
Thanks to help from #Muthu I was able to get it working with the following method.
final Intent intent = new Intent("android.intent.action.VIEW");
intent.setComponent(new ComponentName("com.ipsec.vpnclient", "com.ipsec.vpnclient.MainActivity"));
EDIT:
To add to the confusion, I am easily able to add a shortcut to the activity (com.ipsec.vpnclient.MainActivity) via another Launcher like ADW or Nova. I also tried using com.ipsec.vpnclient.MainActivity instead of com.ipsec.vpnclient in the method below, to no avail.
Intent intent = getPackageManager().getLaunchIntentForPackage("com.ipsec.vpnclient");
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
The above method works with other packages, but I can't seem to get this one to launch.
Here is the application when viewed in Android System Info.
Any ideas on how to launch this application programmatically?
You can Start any installed application by using intent. in your case like this
Intent LaunchVPN = getPackageManager().getLaunchIntentForPackage("com.ipsec.vpnclient");
startActivity( LaunchVPN );
Edit
You can open pre installed apps that can be found inside settings page by
final Intent i = new Intent("android.intent.action.VIEW");
i.setComponent(new ComponentName("com.android.settings","com.android.settings.InstalledAppDetails"));
startActivity(i);
I developed a dial up application and I installed it to my phone. Now I want to "on click a button" in my app to set the built in dialer as the default dialing application "automatically" without giving the user to choose between my app and the default dialer application.
This code gives the user the choice,
startActivityForResult(new Intent("android.intent.action.DIAL",
Uri.parse("tel:" + someNumber)), 1);
I don't want this, I want to set the default application to be built in dialer without asking the user.
Note: Once the user is not using my app he will be given the choice, Howevre, if he clicked that button in my app .. it will set the default app automatically.
Try this. This should open default dialer .
Intent i = new Intent(Intent.ACTION_DIAL, Uri.parse("tel:0000000000"));
startActivity(i);
You can't force the default activity without user interaction. Why don't you just call your class directly on the button press?
Intent intent = new Intent(this, mydialer.class))
intent.putExtra("PHONENUMBER", _phoneNumber);
startActivityForResult(intent);
My boss asked me to prove that my application behaves properly when summoned by another application (dunno why he asked that).
So I have two apps here, one launches a second one. How I launch the specific app I want? Using Intent launch seemly any generic app that reaches a certain goal, not the app I really want.
Give this a try.
Intent secondIntent = new Intent();
secondIntent.setAction(Intent.ACTION_MAIN);
secondIntent.setClassName("com.example", "com.example.YourSecondApp");
startActivity(secondIntent);
I should point out that com.example should be the package of your second application (the one you want to call) and com.example.YourSecondapp is the class name where you have your onCreate() method.
Intent secondApp = new Intent("com.test.SecondApp");
startActivity(secondApp);
Check out for more examples
http://developer.android.com/resources/faq/commontasks.html#opennewscreen
Create one Intent using the following code
Explicit Intent
When you know the particular component(activity/service) to be loaded
Intent intent = new Intent();
intent.setClass("className/package name");
start<Activity/Service>(intent);
Imlicit Intent
When we do not have the idea which class to load and we know the Action to be perform by the launched application we can go with this intent.
Action needs to set, and the Android run time fallows the intent Resolution technique and list out(one or more components) the components to perform the action. from the list out components (if more than one), user will get the chance to launch his chosen application
I would like to launch an app the user selects from within my application. However, I'm not sure how I'd go about doing this. I've tried this:
Intent intent = new Intent();
intent.setAction(Contacts.Intents.SHOW_OR_CREATE_CONTACT);
startActivity(intent);
But this seems to throw an error and force close my application. I also tried adding:
<action android:name="Contacts.Intents.SHOW_OR_CREATE_CONTACT"/>
in the AndroidManifest file, but to no avail.
A look at Logcat shows that it's an "IOexception - no such file or directory". A couple of questions arise from this. I read through the Android docs and noticed that the Contact.Intents class is deprecated. However, it's successor, ContactContracts is aimed at API level 5 whereas I'm targeting API level 3. Could this be the problem? Also, I've hardcoded this application into the code. Is there a way to retrieve the intents of any application the user selects so that they can be launched?
You need to pass extra information into the intent to tell Android what you want to show or create. Otherwise Android doesn't know what activity to start and (presumably in your case) throws an ActivityNotFoundException.
For a contact, you use the generic Intent.ACTION_INSERT_OR_EDIT then use the MIME type of an individual contact (Contacts.People.CONTENT_ITEM_TYPE).
For example:
Intent intent = new Intent(Intent.ACTION_INSERT_OR_EDIT);
intent.setType(People.CONTENT_ITEM_TYPE);
intent.putExtra(Contacts.Intents.Insert.PHONE, "+1234567890");
intent.putExtra(Contacts.Intents.Insert.PHONE_TYPE, Contacts.PhonesColumns.TYPE_MOBILE);
That will bring up the contacts app, prompting you to select an existing contact to add the phone number to, or to create a new contact.
You don't need to add anything special to your manifest to start external activities. Only if you were to directly manipulate the contacts ContentProvider would you need to add the appropriate CONTACT permissions to your manifest.
I use this code for that purpose:
Intent intent = new Intent(Intent.ACTION_MAIN);
intent.setClassName("com.android.settings", "com.android.settings.Settings");
startActivity(intent);
This will launch the Settings app, you can use these also:
intent.setClassName("com.android.music", "com.android.music.MediaPlaybackActivityStarter");
intent.setClassName("com.android.contacts", "com.android.contacts.DialtactsContactsEntryActivity");
intent.setClassName("com.android.contacts", "com.android.contacts.DialtactsActivity");
The first starts the default music app, the second the contacts, and the third the dialer.
Hope this helps.
You need to pass in valid arguments to the apps you start. A lot of apps expect the data URI and / or certain extras to be valid.
Please try the following code:
Intent intent = new Intent(Contacts.Intents.SHOW_OR_CREATE_CONTACT);
this.startActivity(intent);
(sorry if there is something wrong on the syntax, I dont have android in this computer)
And remove the action from the manifest. that is not needed.
The action method is used for something else.
For more info, please look at the android site: http://developer.android.com/reference/android/content/Intent.html
Daniel
The activity you are calling should appear not only in the Manifest for its own package, but in the Manifest for the CALLING package, too.