I have an android application that requires VPN. My users will be using Galaxy Note 3's and will be using the built in "VPN Client" (com.ipsec.vpnclient). I need to find a way to launch this application from my application, in the instance of the VPN dropping. I've already figured out a way to determine if the VPN dropped, but I still need a way to launch the application.
ANSWER:
Thanks to help from #Muthu I was able to get it working with the following method.
final Intent intent = new Intent("android.intent.action.VIEW");
intent.setComponent(new ComponentName("com.ipsec.vpnclient", "com.ipsec.vpnclient.MainActivity"));
EDIT:
To add to the confusion, I am easily able to add a shortcut to the activity (com.ipsec.vpnclient.MainActivity) via another Launcher like ADW or Nova. I also tried using com.ipsec.vpnclient.MainActivity instead of com.ipsec.vpnclient in the method below, to no avail.
Intent intent = getPackageManager().getLaunchIntentForPackage("com.ipsec.vpnclient");
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
The above method works with other packages, but I can't seem to get this one to launch.
Here is the application when viewed in Android System Info.
Any ideas on how to launch this application programmatically?
You can Start any installed application by using intent. in your case like this
Intent LaunchVPN = getPackageManager().getLaunchIntentForPackage("com.ipsec.vpnclient");
startActivity( LaunchVPN );
Edit
You can open pre installed apps that can be found inside settings page by
final Intent i = new Intent("android.intent.action.VIEW");
i.setComponent(new ComponentName("com.android.settings","com.android.settings.InstalledAppDetails"));
startActivity(i);
Related
I am looking for a way to create shortcuts from other apps.
Like launchs can query the apps that allow to create shortcuts and create them save them in thier program.
My API version is between M(21) to N7.1(25).
Even just a link or name of API it's fine. I just couldn't find it at all. All I found is about the new shortcut in android N.
Thx for ur time.
I found the way to do it. Since i don't see much info for this. I hope my share can help whoever is also looking for the answer.
So there will be 3 steps:
Get apps that can create shortcuts
Send Intent to the app that you want to create shortcut from
Get shortcut data in Activity.onActivityResult
1.
Since I just need to create shortcuts from certain apps. I skipped step one. But I guess using queryIntentActivities(...) or some other functions in PackageManager can get you the list.
Intent intent = new Intent("android.intent.action.CREATE_SHORTCUT");
PackageManager.queryIntentActitvies(intent,0);
2. Send intent to the app to create a shortcut.
Intent intent = new Intent("android.intent.action.CREATE_SHORTCUT");
intent.setComponent(...);
startActivityForResult(intent, requestCode);
3. Get data of shortcut:
Shortcut intent
Intent shortcutIntent = activityResultIntent.getParcelableExtra(Intent.EXTRA_SHORTCUT_INTENT);
Shortcut name
String shortcutName = intent.getStringExtra(Intent.EXTRA_SHORTCUT_NAME);
Shortcut icon
Bitmap shortcutIcon = intent.getParcelableExtra(Intent.EXTRA_SHORTCUT_ICON);
I need to allow user to draw/sketch/paint something. There are already many apps(like Skitch, I will use this as an example) that accomplish this task. So I don't want to re-invent the wheel.
In Android, theoretically, we can launch other activity by intent. This is sort of like "pipe" in Unix.
The problem is, I don't know how to get the information for launching Skitch.
To integrate Skitch in my app, I need to know the Action it supports, the returning intent (if any) when it finishes.
I installed Skitch, photoshop, and lots of other touch drawing apps in my device, but this code doesn't work :
Uri data = Uri.fromFile(file);
Intent i = new Intent(Intent.ACTION_EDIT);
i.setData(data);
i.setType("image/*");
startActivityForResult(i, ACTIVITY_DRAW);
I can launch Skitch from my app in the following way: but obviously I can't get any returned result this way(code from here).
Intent i = new Intent(Intent.ACTION_MAIN);
PackageManager manager = getPackageManager();
i = manager.getLaunchIntentForPackage("com.evernote.skitch");
i.addCategory(Intent.CATEGORY_LAUNCHER);
startActivity(i);
My question: Is there a standard way to find information for launching a third party app?
Is this site the only way to share/get such information?
Or if you have any suggestions for my problem, please help me.
Thank you!
As you might already know how to call another application Activity from your app ..this way Mentioned Here.
Intent intent = new Intent(Intent.ACTION_RUN);
intent.setComponent(new ComponentName("<packet name>", "<class name>"));
List list = packageManager.queryIntentActivities(intent, packageManager.COMPONENT_ENABLED_STATE_DEFAULT);
if(list.size() > 0)
{
Log.i("Log", "Have application" + list.size());
startActivity(intent);
}
else
{
Log.i("Log", "None application");
}
All your require is Mainly Two Things to call any Activity
1) Package Name of that Activity
2) Activity Class Name
These two informations only can be available if they are opensource or made free to use .. like Zxing,Google Maps Application.
There is another way to start an application activity like,
Intent intent = new Intent();
intent.setAction(Intent.ACTION_CALL);
intent.setData(Uri.parse("tel:" + numberField.getText())); // set the Uri
startActivity(intent);
For this way to use need to know the correct Action for the Activity you want to call and the Correct parameter to pass with.
And again,These information only can be available if they are opensource or made free to use .. like Facebook and Gmail apps to share and post messages.
So If you are searching for anything like which can tell you what you will need to pass to call any specific comercial apps in your device, you wont find it directly.
It's an old question but perhaps it could help somebody to know that Sony's AppXplore application (free) shows the package and name of the activities of every app installed on your device, so you can eventually use them to do explicit Intents.
My boss asked me to prove that my application behaves properly when summoned by another application (dunno why he asked that).
So I have two apps here, one launches a second one. How I launch the specific app I want? Using Intent launch seemly any generic app that reaches a certain goal, not the app I really want.
Give this a try.
Intent secondIntent = new Intent();
secondIntent.setAction(Intent.ACTION_MAIN);
secondIntent.setClassName("com.example", "com.example.YourSecondApp");
startActivity(secondIntent);
I should point out that com.example should be the package of your second application (the one you want to call) and com.example.YourSecondapp is the class name where you have your onCreate() method.
Intent secondApp = new Intent("com.test.SecondApp");
startActivity(secondApp);
Check out for more examples
http://developer.android.com/resources/faq/commontasks.html#opennewscreen
Create one Intent using the following code
Explicit Intent
When you know the particular component(activity/service) to be loaded
Intent intent = new Intent();
intent.setClass("className/package name");
start<Activity/Service>(intent);
Imlicit Intent
When we do not have the idea which class to load and we know the Action to be perform by the launched application we can go with this intent.
Action needs to set, and the Android run time fallows the intent Resolution technique and list out(one or more components) the components to perform the action. from the list out components (if more than one), user will get the chance to launch his chosen application
I'm working on an app and I want to integrate the Last.fm app into it. Basically, when someone is looking at an artist in my app, I would like to have a button that they can tap to open up Last.fm application with the artist's information.
This intent works, but it loads a menu asking which app I would like to use (Browser or Last.fm):
Intent i = new Intent();
i.setData(Uri.parse("http://last.fm/music/" + headliner));
i.setAction("android.intent.action.VIEW");
startActivity(i);
However, I just want to start the Last.fm app and skip the dialog asking which app to use, I thought maybe using the setPackage() method would work like this:
i.setPackage("fm.last.android");
But it causes the app to crash:
android.content.ActivityNotFoundException: No Activity found to handle Intent { act=android.intent.action.VIEW dat=http://last.fm/music/Rihanna pkg=fm.last.android }
Is it possible to just start the Last.fm app? Here's a copy of Last.fm's AndroidManifest.xml for reference.
Thanks for reading,
Tony
Yes, it's possible but you need to know the correct component name. Launch the last.fm app regularly and check the logfile for the cmp=... information that's been used when the app is started. Use this as well in your app then.
I start the Z-DeviceTest app from the market from within my app without a problem like this:
final Intent intentDeviceTest = new Intent("android.intent.action.MAIN");
intentDeviceTest.setComponent(new ComponentName("zausan.zdevicetest","zausan.zdevicetest.zdevicetest"));
startActivity(intentDeviceTest);
in my case the info I took from the logcat was:
// dat=content://applications/applications/zausan.zdevicetest/zausan.zdevicetest.zdevicetest
// cmp=zausan.zdevicetest/.zdevicetest
in order to know how to start the app with the right component/class... do the same for the last.fm app
Edit:
I've tested to launch Last.fm from my own app, and this works fine without any errors:
final Intent intentDeviceTest = new Intent("android.intent.action.MAIN");
intentDeviceTest.setComponent(new ComponentName("fm.last.android","fm.last.android.LastFm"));
startActivity(intentDeviceTest);
In my tablet whenever i select the checkbox option for cell phone tethering iam observing
below line in my Eclipse logcat
07-09 07:28:18.279: INFO/ActivityManager(940): Starting activity: Intent { act=android.intent.action.MAIN cmp=com.android.settings/.tether.Tether }
I want to use this one in my application.Is it possible to use this component or can i see inbuilt application methods in my Application like API methods after including that component?Please give me sample code on this
You can start any intent from your app, which is Android's strength.
Off the top of my head:
ComponentName component = new ComponentName("com.android.settings", "com.android.settings/.tether.Tether");
Intent intent = new Intent(component);
intent.setAction(Intent.ACTION_MAIN);
startActivity(intent);
I may be a bit off with the component name (you may need to do some trial and error on the strings), but that should basically be it.