So ultimately I'm trying to upload images that I want Google to OCR. Then I want to be able to get the results of the OCR back to my Android app. I have my images uploading properly. I can loop through all the files in my google drive and I see that there are export links available, one of which is "text/plain". If I use one of these urls in a browser, it downloads the text. Is this the way I should be trying to access it?
I've tried to use the url I get from calling getExportLinks method on the file returned by the insert method
File file = drive.files().insert(body, mediaContent).setOcr(true).execute();
String imageAsTextUrl = getExportLinks.get("text/plain")
I end up getting HTML back that appears to be the Google Drive home page. To get the exported url document, I used google drive instance so it should have properly authenticated like the insert method I would think.
DriveRequest request = new DriveRequest(drive, HttpMethod.GET, imageAsTextUrl, null);
Has anyone tried to do this before? What am I doing wrong?
Well I answered my own question yet again, sort of. Basically since this seems to be a web url and not an API call I can make, then it's not responding with a 401 if it's unauthenticated. So basically the response I was getting is the HTML for the login page. Apparently using DriveRequest does not automatically handle authentication like I thought it would. So I have it working by adding authentication manually to an HttpClient GET call.
But is there a way to do what I'm trying to do with the actual API? So I can deal with response codes?
Here's what I did to download the text/plain representation of the file. Here's a caveat: given that the image I was uploading was taken on a cell phone camera using the default camera app, the default dpi and/or jpeg compression caused the OCR to not work very well. Anyway, here's the code I used. Just basic HttpClient stuff
String imageAsTextUrl = file.getExportLinks().get("text/plain");
HttpClient client = new DefaultHttpClient();
HttpGet get = new HttpGet(imageAsTextUrl);
get.setHeader("Authorization", "Bearer " + token);
HttpResponse response = client.execute(get);
StringBuffer sb = new StringBuffer();
BufferedReader in = null;
try {
in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
String str;
while ((str = in.readLine()) != null) {
sb.append(str);
}
}
finally {
if (in != null) {
in.close();
}
}
// Send data to new Intent to display:
Intent intent = new Intent(UploadImageService.this, VerifyTextActivity.class);
intent.putExtra("ocrText", sb.toString());
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
Related
How can I receive Pushbullet notes/images/profile details via API-Key on Android? My main problem is the SSL security in that point. (BTW: I'm pretty much a beginner in Android and only know the basics.)
The auth looks like this:
https://apikey#api.pushbullet.com/v2/users/me
I'm successfully requesting the content of a webpage (e.g. wikipedia.org) via
try {
URL url = new URL("https://www.wikipedia.org");
URLConnection urlConnection = url.openConnection();
InputStream in = urlConnection.getInputStream();
StringWriter writer = new StringWriter();
IOUtils.copy(in, writer);
theString = writer.toString();
textView.setText(theString);
} catch (Exception e) {
textView.setText("Error: "+e "String content: " +theString);
}
but when I'm requesting, for example, my profile details I'm always getting a
javaio FileNotFoundException
If you run your requests through https://www.runscope.com you can often see what the request is that your client is actually making (they have a free plan for trying it out).
If I had to guess I would say it's likely the authorization is not working correctly. Are you able to get that page using curl? It should look something like:
curl -u <apikey>: https://api.pushbullet.com/v2/users/me
Assuming that works, try something like
urlConnection.setRequestProperty("Authorization", "Bearer <apikey>");
or however it is you set headers on your HTTP requests. This is more explicit than relying on the https://password#domain url thing.
Im new to Android development but Im trying to do an application for Opencart to allow users to enter in their own store to administrate it.
Lets go to the point. In order to get the information from the store i created a page where all the information is presented in XML, so the idea is that the user login, and then redirects to this page and with the http response, parse the xml and voilá!.
I have already the xml parser, but Im having some difficulties with the http connection. Let me explain a little bit more:
Basically, to log into any store, you need to go to www.example.com/admin (I will be using my testing online address to see if someone is able to help me), in this case http://www.onlineshop.davisanchezplaza.com/admin . Once we arrive to the page we arrive to the login system. The login system uses post to send the username: admin and password:admin and redirects to http://onlineshop.davidsanchezplaza.com/admin/index.php?route=common/login and once it verify your identity, it gives you a Token (here I start having some problems). http://onlineshop.davidsanchezplaza.com/admin/index.php?route=common/home&token=8e64583e003a4eedf54aa07cb3e48150 . Well, till here, im very okay, and actually developed an app that can do till here, actually i can "hardcode" read the token from the http response it sends me (what is actually not very good).
Here comes my first question: HOW TO GET FROM THE HTTPresponse the token value? (by now, as I said, I can only get the token by reading all the response, and if we find the string token=, take what comes next ... not good).
HttpClient httpClient = new DefaultHttpClient();
HttpConnectionParams.setConnectionTimeout(httpClient.getParams(), TIMEOUT_MS);
HttpConnectionParams.setSoTimeout(httpClient.getParams(), TIMEOUT_MS);
HttpPost httpPost = new HttpPost("http://onlineshop.davidsanchezplaza.com/admin/index.php?route=common/login");
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("username", "admin"));
nameValuePairs.add(new BasicNameValuePair("password", "admin"));
try{
Log.d(DEBUG_TAG, "Try ");
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpClient.execute(httpPost);
BufferedReader br = new BufferedReader(new InputStreamReader(response.getEntity().getContent()), 8096);
Log.d(DEBUG_TAG, "br :" + br);
String line;
while ((line = br.readLine()) != null) {
Log.d(DEBUG_TAG, "br :" + line);
if(line.contains("token=")){
int index = line.indexOf("token=");
String aux = line.substring(index + "token=".length(), index + 32 + "token=".length());
token = aux; //Yes, I know, its not the best way.
break;
}
}
} catch (IOException e) {
Log.d(DEBUG_TAG, "Finally");
}
Second question, (and more important), now having the token (in the example 8e64583e003a4eedf54aa07cb3e48150), I need to go to the route android/home where is the xml information generated. (http://onlineshop.davidsanchezplaza.com/admin/index.php?route=android/home2&token=8e64583e003a4eedf54aa07cb3e48150). As I was reading, in httpget, we can either set the parameters, or directly send the url with the parameters already inside the url. Is in this step where it stops. Maybe is the internet connexion in China, maybe (most sure) im doing something wrong. Sometimes it just come the timeout connexion, others it just send me back to the login page.
Here is the code how i do (edit: I was a noob, and didnt create the httpclient to receive the answer, sorry!):
String s = "http://onlineshop.davidsanchezplaza.com/admin/index.php?route=common/home&token=";
String tot = s.concat(token);
HttpClient httpClient = new DefaultHttpClient();
HttpConnectionParams.setConnectionTimeout(httpClient.getParams(), TIMEOUT_MS);
HttpConnectionParams.setSoTimeout(httpClient.getParams(), TIMEOUT_MS);
HttpGet httpget = new HttpGet(tot);
try{
Log.d(DEBUG_TAG, "Try ");
HttpResponse response = httpClient.execute(httpget);
BufferedReader br = new BufferedReader(new InputStreamReader(response.getEntity().getContent()), 8096);
Log.d(DEBUG_TAG, "br :" + br);
} catch (IOException e) {
Log.d(DEBUG_TAG, "Finally");
}
I dont need someone to tell me how to do it, just need a little guidance to solve the issue, I really appreciate any comment or help you can offer, or extra documentation :).
As a bonus, if someone can give me further details about how can I test the http get, I will appreciate, I only know how to write it in the web browser, and works fine.
It's a while since I last did something for Android, but here is my advice:
for the login purpose from Android application into the OpenCart administration I recommend creating a new mobile login page, e.g. instead of accessing http://yourstore.com/admin/ which redirects You to http://.../admin/index.php?route=common/login create Your own action e.g. androidLogin() within this controller (admin/controller/common/login.php and You will access it directly via http://yourstore.com/admin/index.php?route=common/login/androidLogin. Why special action? Because the default login action redirects the user (using normal browser) to the home while setting the security token into the URL within the query string part. In Your own action You won't redirect but respond with XML containing this security token so that You can easily extract that token using Your XML parser.
I cannot address second problem exactly but from what I remember I was passing a query string in different way (now I cannot find any similar solution on the internet).
Here is my 5 cents for the second question :
After playing a bit with the browser I realized :
Set Cookies
Your request to ...?route=android/home2&token= seems to be rejected if you are missing cookies. That is, you probably need to extract cookies from first server response and set them for further requests either manually (via conn.setRequestProperty("Cookie", cookie); or using Android CookieManager
User agent
Some server may reject your request just because you are missing "User-Agent" property in request header. To be safe, you could set it to something like conn.setRequestProperty("User-Agent", "Mozilla/5.0");
Extra note - I suggest that you also handle redirects correctly, as for example when you POST your admin/admin credentials you get 302 response and redirected to ...?route=common/home page
Also, you don't need to set conn.setDoInput(true) for UrlConnection while doing GET request.
Hope that helps.
I don't see any catch statement for the try in the second question, this catch may have the info you need to know what's going on.
For the first question try to convert InputStreamReader to a String, and use the String for a
url constructor, with the url (or uri i'm not sure right now, and can't test it) object try .getQueryParameter("parameter").
For your second question when i tried to login using the token that you have provided, the web page replied with invalid token. Can you login with the token that you have provided? If not, try to get a new token. Maybe the token have expired.
I'm new to android programming. I'm looking for a simple way to send pictures to Picasa, I looked at a lot of projects on it. I'm just looking to send a JPEG or PNG button I click, sends and displays a message that it is OK.
I know that is required a Google API and client authentication, but a lot of people show the same Intention sent.
Please help (sorry for the english: P)
I found this:
http://code.google.com/p/google-api-java-client/source/browse?repo=samples#hg/picasa-android-sample
Someone knows how to use it? But from the basics, I'm lost.
The only existing code in online for uploading photos to Picasa is this one..
Picasa Photo Uploader
Try with this one whether it can meet your requirements.If it does,then engage it with a button click event and display message on notification.finished() event to ensure that the file has been uploaded.
Quite an old post, but just for future references, I was successful in directly using http post to upload my image to Picasa. Their own Java API keeps returning errors.
I've written about this method in detail here:
File image = new File("/path/to/image.jpg");
byte[] imageContent = null;
try {
imageContent = Files.toByteArray(image);
} catch (Exception e) {
// do something
}
HttpClient httpClient = HttpClientBuilder.create().build();
HttpPost httpPost = new HttpPost("https://picasaweb.google.com/data/feed/api/user/default/albumid/default");
httpPost.addHeader("Authorization", "Bearer " + mAccessToken);
httpPost.addHeader("Content-Type", "image/jpeg");
httpPost.setEntity(new ByteArrayEntity(imageContent));
try {
HttpResponse httpResponse = httpClient.execute(httpPost);
// log the response
logd(EntityUtils.toString(httpResponse.getEntity()));
} catch (IOException e){
// do something
}
This method uses Apache's HttpClient. If your Android version does not support it, you can still include this line in your Gradle file to compile it:
compile 'cz.msebera.android:httpclient:4.4.1.1'
In my browser, or in iOS, when I try to get the contents of a URL with encoded http authentication information in the form
http://myUser:myPassword#www.example.com/secure/area/index.html
It just works. I'm getting URLs from a web service, and I'd like to avoid trying to parse them up for their HTTP auth info if I can help it. Is there a way to do something similar in Android without actually parsing the URLs? Alternatively, what is the best way to go about that?
UPDATE:
I find that when I try to set the authentication information in an Authorization header, I get a very strange FileNotFoundException.
Here's the code I'm using:
URL url = new URL(urlString);
URLConnection connection;
String authority = url.getAuthority();
if (authority.contains("#")) {
String userPasswordString = authority.split("#")[0];
url = new URL(urlString.replace(userPasswordString + "#", ""));
connection = url.openConnection();
String encoded = new String(Base64.encode(userPasswordString.getBytes(), Base64.DEFAULT), "UTF-8");
connection.setRequestProperty("Authorization", "Basic " + encoded);
} else {
connection = url.openConnection();
}
InputStream responseStream = connection.getInputStream();
All the info seems to check out, I've verified the url is correct, the base64 string is correct, and the file is certainly on the server--I have no trouble at all opening it with Firefox, and Firebug shows all the right headers, matching what I've sent as far as I can tell. What I get though is the following error (url host changed to protect the innocent):
java.io.FileNotFoundException: http://a1b.example.com/grid/uploads/profile/avatar/user1/custom-avatar.jpg
at org.apache.harmony.luni.internal.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1061)
Any idea what this is all about?
I looked into using HttpClient, but saw that in Issue 16041 it is recommended that we prefer URLConnection.
That looks like your browser is applying some extra rules to parsing the URL. In Android you can use HTTP Client's authentication mechanism such as BASIC and DIGEST to do the same things. Which one you choose is dependent on the server you are trying to authenticate against.
Here is a good page to get you started.
Unfortunately, on Android you can't pass the user info (username/password) in that format to either java.net.URL or HttpClient and have it work like in a browser.
I'd recommend using URI (see http://download.oracle.com/javase/1.5.0/docs/api/index.html?java/net/URI.html) to do this: pass your URL to the URI constructor that takes a String and then you can extract the user info (using getUserInfo()). You can then either use HttpClient's authorization classes (see http://developer.android.com/reference/org/apache/http/auth/package-summary.html) or build the basic auth header yourself (an example is given at http://www.avajava.com/tutorials/lessons/how-do-i-connect-to-a-url-using-basic-authentication.html).
I am working in android sdk and using google maps api. I wanted to know if there is any way to find the nearest resturant or coffee shop or a grocery store from current location of the user.
There are many apps available for this purpose but i want to code my own application for learning purpose.
This may help, dont know if it works for android..
http://code.google.com/apis/maps/documentation/places/
I've had the same issue making a Navigation program for Android.
I ended up using Yahoo! Local Search web service, it worked pretty well.
You should understand how web services work, but basically you make an HTTP GET request with the parameters, such as Location, Query (restaurant, coffee, etc) and other parameters, and you get a response as XML or JSON (your choice).
What you do with the results is up to you
Additions:
Yahoo Local Search results are default to XML.
This is an example of how to make the request in Android:
public void doWebRequest()
{
try {
HttpClient client = new DefaultHttpClient();
String url = "http://local.yahooapis.com/LocalSearchService/V3/localSearch?appid=YahooDemo&query=pizza&zip=94306&results=2";
HttpGet request = new HttpGet(url);
HttpResponse response = client.execute(request);
BufferedInputStream bis = new BufferedInputStream(response.getEntity().getContent());
SAXReader reader = new SAXReader();
handleResponse(reader.read(bis));
} catch (Exception e) {
System.err.println(e);
}
}
private void handleResponse(Document doc) {
// doc is the XML response
// process the results here
}
There is no API for this in Android, sorry. There may be Web services you can use for this.
May be this could help..
Intent intent =new Intent(Intent.ACTION_VIEW,Uri.parse("geo:0,0?q=Cafe"));
startActivity(intent);