How can I receive Pushbullet notes/images/profile details via API-Key on Android? My main problem is the SSL security in that point. (BTW: I'm pretty much a beginner in Android and only know the basics.)
The auth looks like this:
https://apikey#api.pushbullet.com/v2/users/me
I'm successfully requesting the content of a webpage (e.g. wikipedia.org) via
try {
URL url = new URL("https://www.wikipedia.org");
URLConnection urlConnection = url.openConnection();
InputStream in = urlConnection.getInputStream();
StringWriter writer = new StringWriter();
IOUtils.copy(in, writer);
theString = writer.toString();
textView.setText(theString);
} catch (Exception e) {
textView.setText("Error: "+e "String content: " +theString);
}
but when I'm requesting, for example, my profile details I'm always getting a
javaio FileNotFoundException
If you run your requests through https://www.runscope.com you can often see what the request is that your client is actually making (they have a free plan for trying it out).
If I had to guess I would say it's likely the authorization is not working correctly. Are you able to get that page using curl? It should look something like:
curl -u <apikey>: https://api.pushbullet.com/v2/users/me
Assuming that works, try something like
urlConnection.setRequestProperty("Authorization", "Bearer <apikey>");
or however it is you set headers on your HTTP requests. This is more explicit than relying on the https://password#domain url thing.
Related
I'm about to code an Android app (using A.Studio 3.5.1) that should connect to a back-end using https. I'm quite new to the techniques so I looked at https://developer.android.com/training/articles/security-ssl.html#HttpsExample
I has four lines of code:
URL url = new URL("https://wikipedia.org");
URLConnection urlConnection = url.openConnection();
InputStream in = urlConnection.getInputStream();
copyInputStreamToOutputStream(in, System.out);
When I try it I get a red text;
new URL gives MalformedURLException
url.openConnection() gives IOException,
urlConnection.getInputStream() also
copyInputStreamToOutputStream is not found.
I have read about copyInputStreamToOutputStream, that it can be solved
copyInputStreamToOutputStream(in, System.out)
and
Easy way to write contents of a Java InputStream to an OutputStream
I tried the first way, using apache commons, with no success.
I'm mostly curious about the exceptions.
I will try another walk-through on
https://codelabs.developers.google.com/codelabs/android-network-security-config/
But it would be nice to learn about this...
I have faced similar situations many times. This occur because the webpage you are trying to reach doesn't return anything as a response after connection is established. So the parsing returns IOException as there is nothing to read in the response of URL after connection.
newURL is returning MalformedURLException because your url contains -- " -- which should be escaped as these are special characters.
Hope this helps.
here is url ...
https://api.thingspeak.com/update?api_key=R3LQP7IXIXEQ1OIV&field1=0
Actually..I don't want to get the content of url.
I just want to update the value of field1 to 1 and 0.
If I just type this url in any broswer,my thingspeak data will be update.All I need to do is to write code like typing in any broswer of this url.
In that way I think I can turn on and off my led through android application for my IOT project.I think all I need to do is to make connection between apk and thingspeak from this url.I am new to android studio.I have tried many ways.Help me please.
Thanks a lot.
You can simply use a HTTP GET method (that is what your browser does).
To answer your question:
try {
// create the HttpURLConnection
url = new URL(yourUrl);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
// just want to do an HTTP GET here like your browser would
connection.setRequestMethod("GET");
// give it 15 seconds to respond
connection.setReadTimeout(15*1000);
connection.connect();
} catch (Exception e) {
e.printStackTrace();
throw e;
} finally {
connection.disconnect();
}
There are better (cleaner) ways to do his, but this should answers your question.
PS: Be aware that in Android you will not be able to do this on the main thread! You should do this in a AsyncTask, AsyncTaskLoader, ...
I am almost dead doing this.Need help.
My Requirement :-
I am developing an android app and want to use the cookies(/session) from webview in my java code. I basically want to get the html of other pages of an url after login in webview without opening those pages in webview but through my java code.
What I tried :-
For this I tried HttpClient and HttpURLConnection referring many SO questions but failed.
Can anybody please give me a sample code?
Say I have cookies in a hashmap cookies. How Can I use HttpClient and HttpURLConnection or anything else to get the other page html. The website I am trying with is https:
Please give a sample code
If I am right u are trying to use your webview's cookies to get other pages of site in your activity java code.if yes try this:
BufferedReader reader = null;
try {
URL url2 = new URL("url");
URLConnection con = (URLConnection) url2.openConnection();
CookieManager.getInstance().setAcceptCookie(true);
con.setRequestProperty("Cookie",CookieManager.getInstance().getCookie("logged in url in webview"));
con.setDoOutput(true);
con.connect();
reader = new BufferedReader(new InputStreamReader(con.getInputStream()));
StringBiffer html;
String line = "";
while ((line = reader.readLine()) != null) {
html.append(line);
}
} catch (Exception e) {
e.printStackTrace();
}
It worked for me.
Have you tried to add the cookie as a HTTP header? I am not sure if I have understood you right but you can consider these:
Cookies: If you want to load some resource (no matter if it is a web page, image, css, js or something else) you are making a HTTP request. If the server keeps a session for your user, you are probably given a session cookie. The cookie must be sent with each request to the server as e COOKIE header. So if you want to pass the cookie to your request, add it as a header. Android provides you an easy way to do this with the CookieManager class. You can refer to this.
SSL: If you are trying to access a secured web site (https) you have to use an SSL certificate. Android comes up with a bunch of predistributed certificates for most of the popular web cites (e.g Facebook, Google, Twitter, etc.). You can use them out of the box. If your SSL certificate is not presented, you have to add it manually. Read this for more information.
I hope this was useful :)
I'm trying to PUT some XML to a server, but the gist of it is that no matter what I do, HttpPut simply won't put anything in the Http body. The server always comes back saying that the body is missing, and looking at it through Wireshark, nothing is there! Here's the code I'm using to set up and run the request:
HttpPut putRequest = new HttpPut(urlString]);
StringEntity stringEntity = new StringEntity(xmlString, HTTP.ISO_8859_1);
stringEntity.setContentType("text/xml");
putRequest.setEntity(stringEntity);
putRequest.addHeader("Host", formatUrlForHostHeader(broadsoftUrl));
putRequest.addHeader("Authorization", authorizationString);
putRequest.addHeader("Content-Type", "text/xml");
putRequest.addHeader("Accept", "text/xml");
response = httpClient.execute(putRequest);
I'm not sure what else to include here. I tried it on 4.2 and 4.0.3. This code is running in the doInBackground of an AsyncTask. The response code I get is a 409 Conflict, and the body is the server's application-specific message, telling me the body is missing. I confirmed that it's missing with Wireshark.
EDIT:
An interesting note is that I ran the same code standalone on my desktop, and it worked. So, is there something up with the Android versions of HttpClient, or the system? I tried a few different API levels, too, just to check.
Any thoughts?
Thanks!
Alright, so the solution was to just give up on HttpPut and all that, and use HttpURLConnection. Here's how we ended up doing it:
URL url = new URL(theUrl);
HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();
httpCon.setRequestProperty("Host", formatUrlForHostHeader(broadsoftUrl));
httpCon.setRequestProperty("Authorization", authorizationString);
httpCon.setRequestProperty("Content-Type", "text/xml; charset=ISO_8859_1");
httpCon.setRequestProperty("Accept", "text/xml");
httpCon.setDoInput(true);
httpCon.setDoOutput(true);
httpCon.setRequestMethod("PUT");
OutputStreamWriter out = new OutputStreamWriter(httpCon.getOutputStream(), "ISO_8859_1");
out.write(xmlData);
out.close();
if(httpCon.getErrorStream() == null) {
return "";
} else {
return "ERROR";
}
We didn't need to get the response from our PUT request, but you check if it failed by seeing if the error stream exists. If you wanted to get the response, you would do something like this:
StringWriter writer = new StringWriter();
IOUtils.copy(httpCon.getInputStream(), writer, encoding);
String responseString = writer.toString();
Of course, you would have to include Apache's IOTools in your app.
409 Conflict is usually an Edit Conflict error, usually associated with wikis, but it could be any type of conflict with the request.
http://en.wikipedia.org/wiki/List_of_HTTP_status_codes
http://www.w3.org/Protocols/rfc2616/rfc2616-sec10.html
What type of data are you trying to post and is it possible that the host has existing data that cannot be changed?
In my browser, or in iOS, when I try to get the contents of a URL with encoded http authentication information in the form
http://myUser:myPassword#www.example.com/secure/area/index.html
It just works. I'm getting URLs from a web service, and I'd like to avoid trying to parse them up for their HTTP auth info if I can help it. Is there a way to do something similar in Android without actually parsing the URLs? Alternatively, what is the best way to go about that?
UPDATE:
I find that when I try to set the authentication information in an Authorization header, I get a very strange FileNotFoundException.
Here's the code I'm using:
URL url = new URL(urlString);
URLConnection connection;
String authority = url.getAuthority();
if (authority.contains("#")) {
String userPasswordString = authority.split("#")[0];
url = new URL(urlString.replace(userPasswordString + "#", ""));
connection = url.openConnection();
String encoded = new String(Base64.encode(userPasswordString.getBytes(), Base64.DEFAULT), "UTF-8");
connection.setRequestProperty("Authorization", "Basic " + encoded);
} else {
connection = url.openConnection();
}
InputStream responseStream = connection.getInputStream();
All the info seems to check out, I've verified the url is correct, the base64 string is correct, and the file is certainly on the server--I have no trouble at all opening it with Firefox, and Firebug shows all the right headers, matching what I've sent as far as I can tell. What I get though is the following error (url host changed to protect the innocent):
java.io.FileNotFoundException: http://a1b.example.com/grid/uploads/profile/avatar/user1/custom-avatar.jpg
at org.apache.harmony.luni.internal.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1061)
Any idea what this is all about?
I looked into using HttpClient, but saw that in Issue 16041 it is recommended that we prefer URLConnection.
That looks like your browser is applying some extra rules to parsing the URL. In Android you can use HTTP Client's authentication mechanism such as BASIC and DIGEST to do the same things. Which one you choose is dependent on the server you are trying to authenticate against.
Here is a good page to get you started.
Unfortunately, on Android you can't pass the user info (username/password) in that format to either java.net.URL or HttpClient and have it work like in a browser.
I'd recommend using URI (see http://download.oracle.com/javase/1.5.0/docs/api/index.html?java/net/URI.html) to do this: pass your URL to the URI constructor that takes a String and then you can extract the user info (using getUserInfo()). You can then either use HttpClient's authorization classes (see http://developer.android.com/reference/org/apache/http/auth/package-summary.html) or build the basic auth header yourself (an example is given at http://www.avajava.com/tutorials/lessons/how-do-i-connect-to-a-url-using-basic-authentication.html).