I use HttpClient in android to send post request:
HttpClient client = new DefaultHttpClient();
HttpPost request = new HttpPost(hostNameCollection);
StringEntity se = new StringEntity(jsonObj.toString());
request.setHeader("Accept", "application/json");
request.setHeader("Content-type", "application/json");
request.setEntity(se);
HttpResponse response = client.execute(request);
Log.v("HttpLogClient.logJSONObject", "wyslano JSON");
and I'dont know how I can receive JSON object on my Java EE servlet.
you need to read the response body text, then parse as JSON,
String result = EntityUtils.toString(response.getEntity());
JSONObject jo = new JSONObject(result);
read the body of the http post ( server-side ) by getting the a stream object on the body and then reading it.
Once youve read it , convert the bytes to chars and that will be json which you can use to build a json object like a jsonNode using 'jackson' libs.
If you are using plain servlets the json stream is located in the body of the HttpServletRequest : request.getReader() or request.getInputStream();
To make things easier you could use a library handling databinding for you.
Have a look at Genson http://code.google.com/p/genson/.
YouClass object = new Genson().deserialize(request.getReader(), YourClass.class);
// or to a plain map
Map<String, Object> map = genson.deserialize(request.getReader(), Map.class);
Related
Scenario:
REST API: PHP Slim Framework
Android HTTP client library: loopj
I am storing an ITEM as json string in sqlite.
I want to POST this JSON on server. Each item is a record in my SQLite database.
What I am currently doing?
I have JSON with list of objects. I want to POST it to my PHP based REST API.
Here is the code
if (cursor != null && cursor.getCount() > 0) {
if (cursor.moveToFirst()) {
do {
Item item = new Item();
try {
item.setOfflineId(Long.parseLong(cursor.getString(0)));
item.setName(cursor.getString(1));
item.setImageLocalPath(itemPayload.getImageLocalPath());
item.setToUpdate(Boolean.parseBoolean(cursor.getString(3).toString()));
item.setDeviceID(cursor.getString(4));
item.setCreatedDate(cursor.getString(5));
//item.setImageBlob(cursor.getBlob(5));
String imageURL = itemPayload.getImageLocalPath();
File imageFile = new File(imageURL);
} catch (Exception e) {
Log.d("Ex", e.getMessage().toString());
}
itemList.add(item);
} while (cursor.moveToNext());
}
}
}catch(SQLException ex){
Log.d("DB", ex.getMessage().toString());
}
The challenge?
When I put the params for post, I also set one Param to File as I want to upload an image file as well. I know how to send one object as JSON. I want to POST the list of items (items having image Files). How to achieve this?
One way is that I do an API POST for each object in the list. Not sure if it is a good way to do it.
Looking for advice.
You can post json using this way
JSONObject json = new JSONObject();
json.put("obj", "obj value");
StringEntity entity = new StringEntity(json.toString());
client.post(context, url, entity, "application/json",
responseHandler);
Use this code to send Json data
try{
JSONObject jsonObject = new JSONObject();
jsonObject.accumulate("projectid","1");
jsonObject.accumulate("cnumber", "8983899383");
jsonObject.accumulate("address","IN");
jsonObject.accumulate("companyid","5");
jsonObject.accumulate("uploadimage","");
jsonObject.accumulate("id","9")
data = jsonObject.toString();
Log.d("json data",data);
// 1. create HttpClient
HttpClient httpclient = new DefaultHttpClient();
// 2. make POST request to the given URL
HttpPost httpPost = new HttpPost(CHECK_WEBSERVICE_URL);
StringEntity se = new StringEntity(data);
// 6. set httpPost Entity
httpPost.setEntity(se);
// 7. Set some headers to inform server about the type of the content
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
// 8. Execute POST request to the given URL
HttpResponse httpResponse = httpclient.execute(httpPost);
// 9. receive response as inputStream
inputStream = httpResponse.getEntity().getContent();
I want to perform following task :
1 > accept input from user and save it
2 > Send this input value with whole json object to server
This is log cat result
see this
http://hmkcode.com/android-send-json-data-to-server/
How to send a JSON object over Request with Android?
USe The following code..
// 1. create HttpClient
HttpClient httpclient = new DefaultHttpClient();
// 2. make POST request to the given URL
HttpPost httpPost = new HttpPost(url);
String json = "";
// 3. build jsonObject
JSONObject jsonObject = new JSONObject();
jsonObject.accumulate("name", person.getName());
jsonObject.accumulate("country", person.getCountry());
jsonObject.accumulate("twitter", person.getTwitter());
// 4. convert JSONObject to JSON to String
json = jsonObject.toString();
// ** Alternative way to convert Person object to JSON string usin Jackson Lib
// ObjectMapper mapper = new ObjectMapper();
// json = mapper.writeValueAsString(person);
// 5. set json to StringEntity
StringEntity se = new StringEntity(json);
// 6. set httpPost Entity
httpPost.setEntity(se);
// 7. Set some headers to inform server about the type of the content
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
// 8. Execute POST request to the given URL
HttpResponse httpResponse = httpclient.execute(httpPost);
// 9. receive response as inputStream
inputStream = httpResponse.getEntity().getContent();
I am trying to get an android app to interact with a server in Django.
The app is trying to POST "json" data to Django. However, I am unable to receive the object on the Django end.
The value of request.POST is <QueryDict: {}> although the data sent isn't blank. Following is the code snippet for POST request from android.
public static String POST(String url,JSONObject obj){
InputStream inputStream = null;
String result = "";
try{
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
String json = obj.toString();
StringEntity se = new StringEntity(json);
httpPost.setEntity(se);
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type","application/json");
HttpResponse httpResponse = httpClient.execute((HttpUriRequest)httpPost);
inputStream = httpResponse.getEntity().getContent();
if(inputStream!=null){
result = convertInputStreamToString(inputStream);
}else{
result = "Did not work!";
}
}catch(Exception e){
}
return result;
}
EDIT:
Earlier, I was getting CSRF error and handled it this way (I haven't worked with Django enough to know if this is correct way to handle CSRF error)
#csrf_exempt
def search(request):
logger.debug(request.POST)
"""Code for JSON object processing"""
Any help with rectifying the problem would be highly appreciated.
OK I'm not very fluent in java but it seems to me that your request is well formed.
I think the issue is that you are sending the data as a json string instead of as if it was a raw form. When you do it this way, the data is not displayed in request.POST but in request.body as what it is: a json string, not form-like data.
So I think you have to take one of these ways:
send the data from the Android app as a form (not json-like). This way you'll see it in request.POST or
translate request.body into a dict and work with it instead of request.POST
Hope this helps! :)
I am working with JSON Restful web serivces where I have to pass JSON object in the Service URL. I have created the JSON object successfully but getting exception when my URL created the HTTP connection with the SERVER.
Below I have mention my URL:
http://72.5.167.50:8084/UpdateProfileInfo?{"ProfileEditId":"917","ContactsEmail":[{"Email":"dsfs","ContactId":""}],"ContactsPhone":[{"CountryId":"+1","Type":"2","Phone":"345345"}],"ProfileId":"290","LastName":"demo","GroupId":"1212","Title":"sdf","City":"dsf","TemplateId":"1212","State":"dsf","AuthCode":"9bcc6f63-2050-4c5b-ba44-b8103fbc377a","Address":"sdf","FirstName":"demo","ContactId":"","Zip":"23","Company":"tv"}
Getting java.lang.IllegalArgumentException: Illegal character in query in code :
int TIMEOUT_MILLISEC = 100000; // 1000 milisec = 1 seconds
int SOCKET_TIMEOUT_MILISEC = 120000; // 2 minutes
HttpParams httpParams = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(httpParams, TIMEOUT_MILLISEC);
HttpConnectionParams.setSoTimeout(httpParams, SOCKET_TIMEOUT_MILISEC);
HttpClient client = new DefaultHttpClient(httpParams);
HttpPost request = new HttpPost(url);
HttpResponse response = client.execute(request);
responseString = request(response);
Please suggest me If I am doing something wrong with my URL.
*EDITED:*Tried with a key still getting Exeception:
http://72.5.167.50:8084/UpdateProfileInfo?profileinof={"ProfileEditId":"917","ContactsEmail":[{"Email":"sdf","ContactId":""}],"ContactsPhone":[{"CountryId":"+1","Type":"2","Phone":"345345345"}],"ProfileId":"290","LastName":"demo","GroupId":"1212","Title":"dsf","City":"dsf","TemplateId":"1212","State":"dsf","AuthCode":"d968273a-0110-461b-8ecf-3f9c456d17ac","Address":"dsf","FirstName":"demo","ContactId":"","Zip":"23","Company":"tv"}
There is different format of HTTP request that we needed to make for this kind of REQUEST.
I have mention my code below for this.
public JSONObject getJSONObject(){
return jsonObj;
}
ABove method returns me a JSON String which is passed in the below method.
public static HttpResponse makeRequest(String url) throws Exception
{
//instantiates httpclient to make request
DefaultHttpClient httpclient = new DefaultHttpClient();
//url with the post data
HttpPost httpost = new HttpPost(url);
//convert parameters into JSON object
JSONObject holder = getJSONObject();
//passes the results to a string builder/entity
StringEntity se = new StringEntity(holder.toString());
//sets the post request as the resulting string
httpost.setEntity(se);
httpost.setHeader("Accept", "application/json");
httpost.setHeader("Content-type", "application/json");
//Handles what is returned from the page
ResponseHandler responseHandler = new BasicResponseHandler();
return httpclient.execute(httpost, responseHandler);
}
Stack post helped me for doing this task...!!!
The IP is not correct.
IP is formed with 4 bytes. Every byte is a value from 0 to 255, can't be 7 thousand.
http://7232.25.1617.50:1084
Edit: Okay, you edited your question. You're sending a JSON as parameter. But this parameter has no "key".
Should be:
/UpdateProfileInfo?info={"ProfileEditId":"917",[.......]
Edit: I think this should be like this:
/UpdateProfileInfo?info="{'ProfileEditId':'917',[.......]}"
Notice that the value is surrounded by ", and the inner " are replaced now by '
Probably the issue is that you are trying to POST a JSON object as an url param.
If it really has to be an url param, that it has to be urlencoded.
If it rather should be a normal POST request, I's suggest to use a high level helper:
new RESTClient2(ctx).post("http://72.5.167.50:8084", jsonObject);
I can see a need to work with POJOs , converting them to JSON strings and conveying that string info over HTTP. There are lots of good android/java/apache/volley type libs that permit that.
However, i do not understand, in fact i disagree with your requirement to use GET and the URL parms for transport of your JSON string?
Its really easy to do the following:
POJO -> to JSON -> toString -> to http.string.entity -> POST
Why not re-examine your architecture and consider using POST not GET.
Then its easy , 2 step:
see example "request.setEntity( ... "
your code will look like this:
httpPost.setEntity(new StringEntity(pojo.toJSON().toString()));
Here is the code I'm using inside my AsyncTask
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet request = new HttpGet(url);
request.setHeader("Accept", "application/json");
request.setHeader("Content-type", "application/json");
HttpResponse response = httpClient.execute(request);
HttpEntity responseEntity = response.getEntity();
char[] buffer = new char[(int)responseEntity.getContentLength()];
InputStream stream = responseEntity.getContent();
InputStreamReader reader = new InputStreamReader(stream);
reader.read(buffer);
stream.close();
result = new String(buffer);
return result;
This returns a string result and in my onPostExecute method I try to parse that input string:
JSONObject vehicle = new JSONObject(new String(result));
makeEdit.setText(vehicle.getString("make"));
plateEdit.setText(vehicle.getString("plate"));
modelEdit.setText(vehicle.getString("model"));
yearEdit.setText(vehicle.getString("year"));
As soon as it reaches makeEdit.setText it throws an error - no value for make. I'm still very new to android, so don't send death threats if there was some obvious error. The input text is the following JSON string:
{"GetJSONObjectResult":{"make":"Ford","model":"Focus","plate":"XXO123GP","year":2006}}
No value for x error message is pretty common when dealing with JSON. This usually resulted by overlooked code.
usually, when dong JSON, I try to see the human readable structure first. For that, I usually use JSONViewer.
In your case, the structure is something like this:
You see that make is within another object called GetJSONObjectResult. Therefore, to get it, you must first get the container object first:
JSONObject vehicle = ((JSONObject)new JSONObject(result)).getJSONObject("GetJSONObjectResult");
//a more easy to read
JSONObject container = new JSONObject(result);
JSONObject vehicle = container.getJSONObject("GetJSONObjectResult");
and finally use the object to get make:
makeEdit.setText(vehicle.getString("make"));
plateEdit.setText(vehicle.getString("plate"));
modelEdit.setText(vehicle.getString("model"));
yearEdit.setText(vehicle.getString("year"));
Your JSON Object contains itself a JSONObject. To acces to your data, you have to do like this:
vehicle.getJSONObject("GetJSONObjectResult").getString("make");