Develop Reference

How to truncate decimal value in a text

So, I need to show a string in UI which has both numbers and text together.
Something like this,
10.289 Mbps
and I wanted to remove .289 and just show 10 Mbps
I tried a lot of options like setting text as
String rounded = String.format("%.0f", speedValue);
But nothing seems to be working for me.
Appreciate any help.

This can be possible in many ways.
Split String
String inputStr = "10.289 Mbps";
String[] splited = inputStr.split(" ");
Double val = Double.parseDouble(splited[0]);
System.out.println("Value : "+val.intValue()+" "+splited[1]);
Regx
Pattern pattern = Pattern.compile("(([0-9]+)(.)?([0-9]+)?) ([A-Z,a-z]+)", Pattern.MULTILINE);
Matcher matcher = pattern.matcher(inputStr);
if(matcher.find())
{
System.out.println("Value : "+matcher.group(2)+" "+matcher.group(5));
}

something like this can work:
string = "10.289 Mbps"
string_list = string.split(" ")
number = string_list[0]
number = float(number)
print(round(number))
basically isolate the number bu removing 'Mbps' then cast it to a float value and round it to get an integer.

try this
String str = "10.289 Mbps";
String[] strArray = str.split(" ");
Long roundedValue = Math.round(Double.valueOf(strArray[0]));
String resultStr = roundedValue.toString() + " " + strArray[1];
System.out.println(resultStr);

TalkBack decimal announcements

I'm having a problem with Talkback. In my string I have the following number.
1,827
it's a Dutch number so the number means:
1 euro and 82,7 cents.
But Talkback is saying:
18 hundred and 27 euro.
So this problem only occurs when I have a number with more than 2 decimals. How to fix this issue?
---EDIT---
When I'm reading this page: https://english.stackexchange.com/questions/62397/reading-out-decimal-numbers-in-english
it seems I must pronounce the number 1,827 as the following:
one point eight two seven instead to act if it is a number. How to do this?
---EDIT---
I included the following:
StringTokenizer stringTokenizer = new StringTokenizer(value, ".");
String currencyBeforeComma = null;
String currencyAfterComma = null;
while (stringTokenizer.hasMoreTokens()) {
currencyBeforeComma = stringTokenizer.nextToken();
currencyAfterComma = stringTokenizer.nextToken();
}
result = currencyBeforeComma + " point " + currencyAfterComma;
So now its pronouncing: one point eighthunderd twentyseven. So this is still now what i want.
---EDIT---
String value = 1,827;
String result = "";
for (Character chars : value.toCharArray()) {
result = result + chars + " ";
}
String replace = result.replace(getResources().getString(R.string.accessibility_decimal_separator), getResources().getString(R.string.accessibility_decimal_separator_text));
return replace;
This is what i did. I created a whitespace for every char in the value string and for the , or . I replaced it with a comma or point text.
This works for now but it isn't a clean solution. If anybody else has a better solution, please share

Try this and modify your as per your requirement
TextView currencylbl = (TextView) findViewById(R.id.currencylbl);
boolean countryCurrency = true;
String currency = "1,827";
if(countryCurrency==true && currency.contains(",")){
StringTokenizer stringTokenizer = new StringTokenizer(currency, ",");
String currencyBeforeComma = null;
String currencyAfterComma = null;
while (stringTokenizer.hasMoreTokens()) {
currencyBeforeComma = stringTokenizer.nextToken();
currencyAfterComma = stringTokenizer.nextToken();
currencylbl.setText(currency);
}
Double double1 = Double.parseDouble(currencyAfterComma);
double1 = Double.parseDouble(currencyBeforeComma)+double1/1000;
currencylbl.setContentDescription(double1+"");
}
countryCurrency refers to particular Country currency boolean.
Also modify as per your requirement.
Double double1 = Double.parseDouble(currencyAfterComma);
double1 = Double.parseDouble(currencyBeforeComma)+double1/1000;
currencylbl.setContentDescription(double1+"");
xml is
<TextView
android:id="#+id/currencylbl"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:textSize="24sp"
/>

How to get specific word in a whole string?

I am creating and android app that randomly generates any category, I would like to get the given random category word. This is the example string
String="The category Animals that starts with a letter J";
or
String="The category Colors that starts with a letter V";
I need to get the word Animals or Colors every random String is generated

A not so advanced solution, but easy to understand:
public void findCategory() {
String string = "The category Colors that starts with a letter V";
String[] split = string.split(" ");
int i;
for (i = 0; i < split.length; i++) {
if ("category".equals(split[i])) {
break;
}
}
System.out.println(split[i + 1]);
}

You may use regex.
Matcher m = Pattern.compile("\\bcategory\\s+(\\S+)").matcher(str);
while(m.find()) {
System.out.println(m.group(1));
}
OR
Matcher m = Pattern.compile("(?<=\\bcategory\\s)\\S+").matcher(str);
while(m.find()) {
System.out.println(m.group());
}

Please use Matcher and Pattern -
String input = "The category Animals that starts with a letter J";
Matcher m1 = Pattern.compile("^The category (.*) that starts with a letter (.*)$").matcher(input);
if(m1.find()) {
String _thirdWord = m1.group(1); // Animals
String _lastWord = m1.group(2); // J
System.out.println("Third word : "+_thirdWord);
System.out.println("Last Word : "+_lastWord);
}

Use this, it might fix your issue
String string = "The category Colors that starts with a letter V";
String[] ar = string.split(" ");
System.out.println(ar[2]);

Multiply Integers Inside A String By An Individual Value Using Regex

I currently have the code below and it successfully returns all the numbers that are present in a string I have.
An example of the string would be say: 1 egg, 2 rashers of bacon, 3 potatoes.
Pattern intsOnly = Pattern.compile("\\d+");
Matcher matcher = intsOnly.matcher(o1.getIngredients());
while (matcher.find()) {
Toast.makeText(this, "" + matcher.group(), Toast.LENGTH_LONG).show();
}
However, I would like to multiply these numbers by say four and then place them back in the original string. How can I achieve this?
Thanks in advance!

I've never tried this, but I think appendReplacement should solve your problem

Doing arithmetic is a little complicated while doing the find()
Pattern intsOnly = Pattern.compile("\\d+");
Matcher matcher = intsOnly.matcher(test);
int start = 0;
int end = 0;
StringBuffer resultString = new StringBuffer();
while (matcher.find()) {
start = matcher.start();
// Copy the string from the previous end to the start of this match
resultString.append(test.substring(end, start));
// Append the desired new value
resultString.append(4 * Integer.parseInt(matcher.group()));
end = matcher.end();
}
// Copy the string from the last match to the end of the string
resultString.append(test.substring(end));
This StringBuffer will hold the result you are expecting.

How to split a string and get a specific string in android?

I want to split a string and get a word finally. My data in database is as follows.
Mohandas Karamchand Gandhi (1869-1948), also known as Mahatma Gandhi, was born in Porbandar in the present day state of Gujarat in India on October 2, 1869.
He was raised in a very conservative family that had affiliations with the ruling family of Kathiawad. He was educated in law at University College, London.
src="/Leaders/gandhi.png"
From the above paragraph I want get the image name "gandhi". I am getting the index of "src=". But now how can I get the image name i.e "gandhi" finally.
My Code:
int index1;
public static String htmldata = "src=";
if(paragraph.contains("src="))
{
index1 = paragraph.indexOf(htmldata);
System.out.println("index1 val"+index1);
}
else
System.out.println("not found");

You can use the StringTokenizer class (from java.util package ):
StringTokenizer tokens = new StringTokenizer(CurrentString, ":");
String first = tokens.nextToken();// this will contain one word
String second = tokens.nextToken();// this will contain rhe other words
// in the case above I assumed the string has always that syntax (foo: bar)
// but you may want to check if there are tokens or not using the hasMoreTokens method

Try this code. Check if it working for you..
public String getString(String input)
{
Pattern pt = Pattern.compile("src=.*/(.*)\\..*");
Matcher mt = pt.matcher(input);
if(mt.find())
{
return mt.group(1);
}
return null;
}
Update:
Change for multiple item -
public ArrayList<String> getString(String input)
{
ArrayList<String> ret = new ArrayList<String>();
Pattern pt = Pattern.compile("src=.*/(.*)\\..*");
Matcher mt = pt.matcher(input);
while(mt.find())
{
ret.add(mt.group(1));
}
return ret;
}
Now you'll get an arraylist with all the name. If there is no name then you'll get an empty arraylist (size 0). Always make a check for size.