Develop Reference

How to truncate decimal value in a text

So, I need to show a string in UI which has both numbers and text together.
Something like this,
10.289 Mbps
and I wanted to remove .289 and just show 10 Mbps
I tried a lot of options like setting text as
String rounded = String.format("%.0f", speedValue);
But nothing seems to be working for me.
Appreciate any help.

This can be possible in many ways.
Split String
String inputStr = "10.289 Mbps";
String[] splited = inputStr.split(" ");
Double val = Double.parseDouble(splited[0]);
System.out.println("Value : "+val.intValue()+" "+splited[1]);
Regx
Pattern pattern = Pattern.compile("(([0-9]+)(.)?([0-9]+)?) ([A-Z,a-z]+)", Pattern.MULTILINE);
Matcher matcher = pattern.matcher(inputStr);
if(matcher.find())
{
System.out.println("Value : "+matcher.group(2)+" "+matcher.group(5));
}

something like this can work:
string = "10.289 Mbps"
string_list = string.split(" ")
number = string_list[0]
number = float(number)
print(round(number))
basically isolate the number bu removing 'Mbps' then cast it to a float value and round it to get an integer.

try this
String str = "10.289 Mbps";
String[] strArray = str.split(" ");
Long roundedValue = Math.round(Double.valueOf(strArray[0]));
String resultStr = roundedValue.toString() + " " + strArray[1];
System.out.println(resultStr);

ReplaceAll not working

I'm using google volley to retrieve source code from website. Some looping was done to capture the value in the code. I've successfully captured the data I wanted, but error was shown: NumberFormatException: Invalid float: "2,459.00"
My intention was to store the value after the class=ListPrice>
Sample:
RM 2,899.00
The example value of the source code I wanted to save is "RM2,459.00 "
Below is the code I've written:
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_lazada_result);
lelongResult = (TextView) findViewById(R.id.lelong_result);
RequestQueue lelong = MyVolley.getRequestQueue(this);
StringRequest myLel = new StringRequest(
Method.GET,
"http://list.lelong.com.my/Auc/List/List.asp?DA=A&TheKeyword=iphone&x=0&y=0&CategoryID=&PriceLBound=&PriceUBound=",
RetrieveLelong(), createMyReqErrorListener());
lelong.add(myLel);
}
private Response.Listener<String> RetrieveLelong() {
return new Response.Listener<String>() {
#Override
public void onResponse(String response) {
ArrayList<Float> integers = new ArrayList<>();
String to = "class=ListPrice>";
String remainingText = response;
String showP = "";
while (remainingText.indexOf(to) >= 0) {
String tokenString = remainingText.substring(remainingText
.indexOf(to) + to.length());
String priceString = tokenString.substring(0,
tokenString.indexOf("<"));
float price = Float.parseFloat(priceString.replaceAll("[^\\d,]+", "").trim());
integers.add((price / 100));
remainingText = tokenString;
}
for (int i = 0; i < integers.size(); i++) {
String test1 = Float.toString(integers.get(i));
showP += test1 + "\n";
}
lelongResult.setText(showP);
}
};
}
The problem was as below:
I've tried all sort of replaceAll(),
1)replaceAll("[^\d,]+","") result:2,89900
replace all character except digits and comma works.
2)replaceAll("[^\d]+","") result:Invalid int""
replace all character include comma and dot ,not working
3)replaceAll("[^\d.]+,"") result:Invalid int""
replace all character exclude digits and dot, not working
From the experiment 2&3 coding above,I've noticed that if the comma were removed,i cant parseFloat as the value received by it is: "".NumberFormatException:Invalid Float:"" shown.
From the experiment 1,NumberFormatException:Invalid Float "2,45900" is showned.
The problem was replacing comma ,the code will not work but with the presence of comma ,the value cannot be stored into string

try this:
float price = Float.parseFloat(priceString.replaceAll("RM", "").trim());

use `replaceAll(Pattern.quote(","), "");
EDIT
if you want only numbers then use this
String s1= s.replaceAll("\D+","");

Try to parse the number by specifying the Locale.
NumberFormat format = NumberFormat.getInstance(Locale.KOREAN);
Number number = format.parse(priceString.replaceAll("RM", ""));
double d = number.doubleValue();
I'm just guessing the locale, don't know what you should use, depends on country

You need to do it one by one
priceString=priceString.replaceAll("\\D", "");
priceString=priceString.replaceAll("\\s", "");
now
priceString=priceString.trim();
float price = Float.parseFloat(priceString);

the problem is that in your code:
priceString.replaceAll(Pattern.quote(","), "");
float price = Float.parseFloat(priceString.replaceAll("\\D+\\s+", "").trim());
You are replacing coma but not storing the value!
you have to do:
priceString = priceString.replaceAll(",", "");
float price = Float.parseFloat(priceString.replaceAll("\\D+\\s+", "").trim());
I'm not sure of the pattern "\D+\s" because if you remove the coma you don't need to replace anything else (except "RM" that i assume you already removed)
Update: set locale and parse a number:
NumberFormat format = NumberFormat.getInstance(Locale.KOREAN);
Number number = format.parse(priceString.replaceAll("RM", ""));
double d = number.doubleValue();

How can I effectively replace one or more characters

I have a String separated by commas as follows
1,2,4,6,8,11,14,15,16,17,18
This string is generated upon user input. Suppose the user wants to remove any of the numbers, I have to rebuild the string without the specified number.
If the current string is:
1,2,4,6,8,11,14,15,16,17,18
User intents to remove 1, the final string has to be:
2,4,6,8,11,14,15,16,17,18
I tried to achieve this using the following code:
//String num will be the number to be removed
old = tv.getText().toString(); //old string
newString = old.replace(num+",",""); //will be the new string
This might be working sometimes but it is sure that it won't work for the above example I have shown, if I try to remove the 1, it also removes the last part of 11, because there also exists 1.

well you can use this. Its the most simplest approach i can think of:
//String num will be the number to be removed
old=","+tv.getText().toString()+",";//old string commas added to remove trailing entries
newString=old.replace(","+num+",",",");// will be the new string
newString=newString.substring(1,newString.length()-1); // removing the extra commas added
This would work for what you want to do. I have added a comma at the start and end of your string so that you can also remove the first and last entries too.

You can split the string first and check for the number where you append those value that is not equivalent to the number that will get deleted;
sample:
String formated = "1,2,4,6,8,11,14,15,16,17,18";
String []s = formated.split(",");
StringBuilder newS = new StringBuilder();
for(String s2 : s)
{
if(!s2.equals("1"))
newS.append(s2 + ",");
}
if(newS.length() >= 1)
newS.deleteCharAt(newS.length() - 1);
System.out.println(newS);
result:
2,4,6,8,11,14,15,16,17,18

static public String removeItemFromCommaDelimitedString(String str, String item)
{
StringBuilder builder = new StringBuilder();
int count = 0;
String [] splits = str.split(",");
for (String s : splits)
{
if (item.equals(s) == false)
{
if (count != 0)
{
builder.append(',');
}
builder.append(s);
count++;
}
}
return builder.toString();
}

String old = "1,2,4,6,8,11,14,15,16,17,18";
int num = 11;
String toRemove = "," + num + "," ;
String oldString = "," + old + ",";
int index = oldString.indexOf(toRemove);
System.out.println(index);
String newString = null;
if(index > old.length() - toRemove.length() + 1){
newString = old.substring(0, index - 1);
}else{
newString = old.substring(0, index) + old.substring(index + toRemove.length() -1 , old.length());
}
System.out.println(newString);

How to split this String?

I want to split this string
String info = "0.542008835 meters height from ground";
from this i want to get only two decimals like this 0.54.
by using this i am getting that
String[] _new = rhs.split("(?<=\\G....)");
But i am facing problem here, if string does't contain any decimals like this string
String info = "1 meters height from ground";
for this string i am getting those characters upto first 4 in the split string like 1 me.
i want only numbers to split if it has decimals, How to solve this problem.

if(info.contains("."))
{
String[] _new = rhs.split("(?<=\\G....)");
}

I think you can check by white space after first value. see this
If you get the space then get first character only.
For checking if a string contains whitespace use a Matcher and call it's find method.
Pattern pattern = Pattern.compile("\\s");
Matcher matcher = pattern.matcher(s);
boolean found = matcher.find();
If you want to check if it only consists of whitespace then you can use String.matches:
boolean isWhitespace = s.matches("^\\s*$");

You could use a regex to do this as an alternative to Deepzz's method, this will handle the case where there is a '.' in the later part of the String, I've included an example below. It's not clear from your question is you actually want to remaining part of the String, but you could add a second group to the reg ex to capture this.
public static void main(String[] args) {
final String test1 = "1.23 foo";
final String test2 = "1 foo";
final String test3 = "1.234 foo";
final String test4 = "1.234 fo.o";
final String test5 = "1 fo.o";
getStartingDecimal(test1);
getStartingDecimal(test2);
getStartingDecimal(test3);
getStartingDecimal(test4);
getStartingDecimal(test5);
}
private static void getStartingDecimal(final String s) {
System.out.print(s + " : ");
Pattern pattern = Pattern.compile("^(\\d+\\.\\d\\d)");
Matcher matcher = pattern.matcher(s);
if(matcher.find()) {
System.out.println(matcher.group(1));
} else {
System.out.println("Doesn't start with decimal");
}
}

Assuming the number is always the first part of the string:
String numStr = rhs.split(" ")[0];
Double num = Double.parseDouble(numStr);
After that you can use the String Formatter to get the desired representation of the number.

This will work when you know the String near the numbers, with int and double numbers as well.
String a ="0.542008835 meters height from ground";
String b = a.replace(" meters height from ground", "");
int c = (int) ((Double.parseDouble(b))*100);
double d = ((double)c/100);

How to split a string and get a specific string in android?

I want to split a string and get a word finally. My data in database is as follows.
Mohandas Karamchand Gandhi (1869-1948), also known as Mahatma Gandhi, was born in Porbandar in the present day state of Gujarat in India on October 2, 1869.
He was raised in a very conservative family that had affiliations with the ruling family of Kathiawad. He was educated in law at University College, London.
src="/Leaders/gandhi.png"
From the above paragraph I want get the image name "gandhi". I am getting the index of "src=". But now how can I get the image name i.e "gandhi" finally.
My Code:
int index1;
public static String htmldata = "src=";
if(paragraph.contains("src="))
{
index1 = paragraph.indexOf(htmldata);
System.out.println("index1 val"+index1);
}
else
System.out.println("not found");

You can use the StringTokenizer class (from java.util package ):
StringTokenizer tokens = new StringTokenizer(CurrentString, ":");
String first = tokens.nextToken();// this will contain one word
String second = tokens.nextToken();// this will contain rhe other words
// in the case above I assumed the string has always that syntax (foo: bar)
// but you may want to check if there are tokens or not using the hasMoreTokens method

Try this code. Check if it working for you..
public String getString(String input)
{
Pattern pt = Pattern.compile("src=.*/(.*)\\..*");
Matcher mt = pt.matcher(input);
if(mt.find())
{
return mt.group(1);
}
return null;
}
Update:
Change for multiple item -
public ArrayList<String> getString(String input)
{
ArrayList<String> ret = new ArrayList<String>();
Pattern pt = Pattern.compile("src=.*/(.*)\\..*");
Matcher mt = pt.matcher(input);
while(mt.find())
{
ret.add(mt.group(1));
}
return ret;
}
Now you'll get an arraylist with all the name. If there is no name then you'll get an empty arraylist (size 0). Always make a check for size.