Develop Reference

How to create a new content in Google Sites by sending a POST request using Android or Curl?

Currently, I am working on creating a Android app to read and create google sites content. It seems like the java api doesn't work for Android, so I use google protocol
https://developers.google.com/google-apps/sites/docs/1.0/developers_guide_protocol#ContentFeedPOST.
I can get all the content on google site by this GET request
https://sites.google.com/feeds/site/domainName.
But I have no idea how to send a POST request to create a content beside on the google api guide.
Hope anyone could help me with this. All I need is how to send the request in curl.
Thanks!

you can try curl command like this:
curl -H "Content-Type: your-content-type" -X POST -d 'your-data' https://localhost:8080/api/login
And to post data using HttpUrlConnection class use following:
HttpURLConnection connection = null;
try {
//Create connection
url = new URL(targetURL);
connection = (HttpURLConnection)url.openConnection();
connection.setRequestMethod("POST");
connection.setRequestProperty("Content-Type",
"your-content-type");//set required content type
connection.setRequestProperty("Content-Length", "" +
data.getBytes().length);//set Content-Length header using your data length in bytes
connection.setRequestProperty("Content-Language", "en-US");
connection.setDoInput(true);
connection.setDoOutput(true);
//Send request
DataOutputStream wr = new DataOutputStream (
connection.getOutputStream ());
wr.writeBytes (data);//write data to o/p stream
wr.flush ();
wr.close ();
//Get Response
InputStream is = connection.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
String line;
StringBuffer response = new StringBuffer();
while((line = rd.readLine()) != null) {
response.append(line);
response.append('\r');
}
rd.close();
return response.toString();
} catch (Exception e) {
} finally {
if(connection != null) {
connection.disconnect();
}
}

Not able to POST to REST API

Today I'm making my first attempt of sending a POST request with a JSON to save some data, and I'm not being able to do so.
My app works by signing in, and then save, modify and delete data. It's already done in iOS, but since I'm new to Android, I'm not sure how to do it.
Here's my POST function:
public String POST(String targetURL, String urlParameters, String user, String pwd) {
URL url;
String u = targetURL;
HttpURLConnection connection = null;
try {
// Create connection
// u=URLEncoder.encode(u, "UTF-8");
url = new URL(u);
connection = (HttpURLConnection) url.openConnection();
// cambiarlo luego al usuario q esta logeado
String login = user + ":" + pwd;
String encoding = new String(org.apache.commons.codec.binary.Base64.encodeBase64(org.apache.commons.codec.binary.StringUtils.getBytesUtf8(login)));
connection.setRequestMethod("POST");
connection.setRequestProperty("Authorization", "Basic " + encoding);
connection.setRequestProperty("Content-Type", "plain/text");// hace q sirva con el string de json
connection.setRequestProperty("Content-Length", "" + Integer.toString(urlParameters.getBytes().length));
connection.setRequestProperty("Content-Language", "en-US");
connection.setUseCaches(false);
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setReadTimeout(120000);
// Send request
DataOutputStream wr = new DataOutputStream(connection.getOutputStream());
wr.writeBytes(urlParameters);
wr.flush();
wr.close();
// Get Response
InputStream is = connection.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
String line;
StringBuffer response = new StringBuffer();
this.setResponseCode(connection.getResponseCode());
while ((line = rd.readLine()) != null) {
response.append(line);
response.append('\r');
}
rd.close();
return response.toString();
} catch (Exception e) {
e.printStackTrace();
return null;
} finally {
if (connection != null) {
connection.disconnect();
}
}
}
The method above is executed with Asynctask, and even if I use it to Login using Spring security, it works, and even I can save for internal usage the username, password, and secret token.
I dunno if I need to put the token in a header or something, because I already did that, with no positive results.
I'm supposing that the only permission I need to execute this is the internet one, so in my manifest file I specified that permission.
I'm going crazy with this issue, please help!
Thanks in advance.
EDIT:
Sorry guys, I'm kinda new to this way of asking, and also, not an English native speaker :P
The output I receive after sending the request, is the HTML of the page that handles logging in into the web app... I need like a json response or something like that to make sure the request was saved correctly

Try handling your cookies
CookieManager cookieManager = new CookieManager();
CookieHandler.setDefault(cookieManager);
This should be a singleton.

how to send unicode charcters in http post request from asyncTask

I saw this post How to send unicode characters in an HttpPost on Android but I usaully do request in this way in AsyncTask class.My log is also printing local language in urlParameters but server is returning no result while it is perfect for english Strings:
#Override
protected String doInBackground(String... URLs) {
StringBuffer response = new StringBuffer();
try {
URL obj = new URL(URLs[0]);
HttpURLConnection con = (HttpURLConnection) obj.openConnection();
// add request header
con.setRequestMethod("POST");
if (URLs[0].equals(URLHelper.get_preleases)) {
urlCall = 1;
} else
urlCall = 2;
// String urlParameters = "longitude=" + longitude + "&latitude="+latitude;
// Send post request
con.setDoOutput(true);
DataOutputStream wr = new DataOutputStream(con.getOutputStream());
wr.writeBytes(urlParameters);
wr.flush();
wr.close();
int responseCode = con.getResponseCode();
if (responseCode == 200) {
BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
}
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return response.toString();
}
Is there a way to set character set UTF-8 to request parameters coding this way?

String urlParameters = "longitude=" + longitude + "&latitude="+latitude;
You need to URL-encode components you are injecting into an application/x-www-form-urlencoded context. (Even aside from non-ASCII characters, characters like the ampersand will break otherwise.)
Specify the string-to-bytes encoding that you are using for your request in that call, for example:
String urlParameters = "longitude=" + URLEncoder.encode(longitude, "UTF-8")...
...
DataOutputStream wr = new DataOutputStream(con.getOutputStream());
A DataOutputStream is for sending struct-like Java-typed binary data down a stream. It doesn't give you anything you need for writing HTTP request bodies. Maybe you meant OutputStreamWriter?
But since you already have the string all in memory you could simply do:
con.getOutputStream().write(urlParameters.getBytes("UTF-8"))
(Note the UTF-8 here is somewhat superfluous. Because you will already have URL-encoded all the non-ASCII characters into %xx escapes, there will be nothing to UTF-8-encoded. However in general it is almost always better to specify a particular encoding than omit it and revert to the unreliable system default encoding.)
new InputStreamReader(con.getInputStream())
is also omitting the encoding and reverting to the default encoding which is probably not the encoding of the response. So you will probably find non-ASCII characters get read incorrectly in the response too.

Why connection is not establishing on first time?

I want to send my id & password to server and get the response from server. Here is my code. It is not working for the first time. But iam getting the response from server if i execute my application on second time. It is throwing "Post method failed: -1 null" on first time. Where iam wrong?? Why if() block is executing on first time?? could you please tell me.
HttpsURLConnection con = null;
String httpsURL = "https://www.abc.com/login";
String query = "id=xyz&password=pqr";
URL url = new URL(httpsURL);
con = (HttpsURLConnection) url.openConnection();
con.setRequestMethod("POST");
con.setRequestProperty("Content-length", String.valueOf(query.length()));
con.setRequestProperty("Content-Type","application/x-www-form-urlencoded");
con.setRequestProperty("User-Agent","Mozilla/4.0(compatible; MSIE 5.0; Windows 98; DigExt)");
con.setDoInput(true);
con.setDoOutput(true);
DataOutputStream output = new DataOutputStream(con.getOutputStream());
output.writeBytes(query);
output.close();
int respCode = con.getResponseCode();
if (respCode != HttpsURLConnection.HTTP_OK)
{
throw new Exception("POST method failed: " + con.getResponseCode()+ "\t" + con.getResponseMessage()); }
else {
//read the content from server
}

1/ It is recommanded to use apache HttpClient rather than URLConnection (see http://developer.android.com/reference/org/apache/http/impl/client/DefaultHttpClient.html)
2/ for login and password, why not use Http Authentication ? both basic and digest are supported by android.
3/ as for you problem, you don't close the underlying outputStream.
you should do:
OutputStream os = con.getOutputStream();
DataOutputStream output = new DataOutputStream(os);
output.writeBytes(query);
output.close();
os.close();

Check Server service validity with other technology and/or classic java. You didn say in your question if you succeed to discriminate the server from the issue.
from java doc ...getResponseCode returns -1 if no code can be discerned from the response (i.e., the response is not valid HTTP).
Java https post request example : http://www.java-samples.com/java/POST-toHTTPS-url-free-java-sample-program.htm
try to close your outputstream after querying the status and not before...that may help

Here is how you should send POST requests in Android
HttpPost httpGet = new HttpPost(server + "/login?email="+username+"&password="+password);
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpResponse response = httpClient.execute(httpGet);
You can read response using:
response.getEntity().getContent()

Basic authentication to access assembla rest apis from android

I want to use assembla apis from android environment for my project.
I am trying to do basic authentication as follow :
String authentication = "username:password";
String encoding = Base64.encodeToString(authentication.getBytes(), 0);
URL url = new URL("https://www.assembla.com/");
conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
conn.setRequestProperty("Authorization", "Basic " + encoding);
conn.setDoOutput(true);
conn.connect();
System.out.println(conn.getResponseCode());
System.out.println(conn.getResponseMessage());
I am getting 400 and Bad Request in output.
is there something wrong with URL that i am using or some other thing is going wrong?

It looks like the question was answered here. You need to use Base64.NO_WRAP flag when encoding username-password pair:
String encoding = Base64.encodeToString(authentication.getBytes(), Base64.NO_WRAP);
By default the Android Base64 util adds a newline character to the end of the encoded string. This invalidates the HTTP headers and causes the "Bad request".
The Base64.NO_WRAP flag tells the util to create the encoded string without the newline character thus keeping the HTTP headers intact.

REST API with HTTP Authentication Output:- I got the result
String authentication = "username:password";
String encoding = Base64.encodeToString(authentication.getBytes(), Base64.NO_WRAP);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
conn.setDoOutput(true);
conn.setRequestProperty ("Authorization", "Basic " + encoding);
conn.connect();
OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
wr.write( data );
wr.flush();
reader = new BufferedReader(new InputStreamReader(conn.getInputStream()));
StringBuilder sb = new StringBuilder();
String line = null;
while((line = reader.readLine()) != null)
{
// Append server response in string
sb.append(line + "\n");
}
Content = sb.toString();