Not able to POST to REST API - android

Today I'm making my first attempt of sending a POST request with a JSON to save some data, and I'm not being able to do so.
My app works by signing in, and then save, modify and delete data. It's already done in iOS, but since I'm new to Android, I'm not sure how to do it.
Here's my POST function:
public String POST(String targetURL, String urlParameters, String user, String pwd) {
URL url;
String u = targetURL;
HttpURLConnection connection = null;
try {
// Create connection
// u=URLEncoder.encode(u, "UTF-8");
url = new URL(u);
connection = (HttpURLConnection) url.openConnection();
// cambiarlo luego al usuario q esta logeado
String login = user + ":" + pwd;
String encoding = new String(org.apache.commons.codec.binary.Base64.encodeBase64(org.apache.commons.codec.binary.StringUtils.getBytesUtf8(login)));
connection.setRequestMethod("POST");
connection.setRequestProperty("Authorization", "Basic " + encoding);
connection.setRequestProperty("Content-Type", "plain/text");// hace q sirva con el string de json
connection.setRequestProperty("Content-Length", "" + Integer.toString(urlParameters.getBytes().length));
connection.setRequestProperty("Content-Language", "en-US");
connection.setUseCaches(false);
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setReadTimeout(120000);
// Send request
DataOutputStream wr = new DataOutputStream(connection.getOutputStream());
wr.writeBytes(urlParameters);
wr.flush();
wr.close();
// Get Response
InputStream is = connection.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
String line;
StringBuffer response = new StringBuffer();
this.setResponseCode(connection.getResponseCode());
while ((line = rd.readLine()) != null) {
response.append(line);
response.append('\r');
}
rd.close();
return response.toString();
} catch (Exception e) {
e.printStackTrace();
return null;
} finally {
if (connection != null) {
connection.disconnect();
}
}
}
The method above is executed with Asynctask, and even if I use it to Login using Spring security, it works, and even I can save for internal usage the username, password, and secret token.
I dunno if I need to put the token in a header or something, because I already did that, with no positive results.
I'm supposing that the only permission I need to execute this is the internet one, so in my manifest file I specified that permission.
I'm going crazy with this issue, please help!
Thanks in advance.
EDIT:
Sorry guys, I'm kinda new to this way of asking, and also, not an English native speaker :P
The output I receive after sending the request, is the HTML of the page that handles logging in into the web app... I need like a json response or something like that to make sure the request was saved correctly

Try handling your cookies
CookieManager cookieManager = new CookieManager();
CookieHandler.setDefault(cookieManager);
This should be a singleton.

Related

How can I share database android application and a .net web application?

I want to share database between an android application and a web application build using Asp.net (my database is based on an IIS server.)
I just want to find the possible ways available to do it, and if I could use php services with IIS server.
I would be so thankful if someone could help me.
Million ways. I can advise you this one: create REST or SOAP service which will have access to database with all methods you need. Now in android application and in ASP.NET application you can "ask" your service to create/update/delete/do something.
try with below code.Hope it will resolved your query.
/**
* This method is used for getting user response after sending request to server.
* It returns the response after executing url request.
* #param params
* #return
*/
public String getJSONObject(String params)
{
try
{
URL url = null;
String response = null;
String parameters = "param1=value1&param2=value2";
//url = new URL("http://www.somedomain.com/sendGetData.php");
url = new URL(params);
//create the connection
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setReadTimeout(40000);
connection.setRequestProperty("Content-Type","application/x-www-form-urlencoded");
//set the request method to GET
connection.setRequestMethod("GET");
//get the output stream from the connection you created
OutputStreamWriter request = new OutputStreamWriter(connection.getOutputStream());
//write your data to the ouputstream
request.write(parameters);
request.flush();
request.close();
String line = "";
//create your inputsream
InputStreamReader isr = new InputStreamReader(
connection.getInputStream());
//read in the data from input stream, this can be done a variety of ways
BufferedReader reader = new BufferedReader(isr);
StringBuilder sb = new StringBuilder();
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
//get the string version of the response data
response = sb.toString();
//do what you want with the data now
//always remember to close your input and output streams
isr.close();
reader.close();
}
catch (Exception e)
{
Log.e("HTTP GET:", e.toString());
response="";
}
return response;
}

Why am I getting 500 response code on passing wrong email or password to service in android?

I have been running into a very strange problem. I am trying to implement log in service in my app. When I pass right email and password service returns response as expected(means no error comes) but when I delibrately pass wrong email or password geInputStream() method throws FileNotFoundException. I don't know what is the reason behind this.Further more, before calling getInputStream() method i checked status code as well(this is the case when I am passing wrong email and password intentionally).The status code was 500. I checked for 500 and that was internal server error. My question is why is that so? I mean when intentionally passing wrong email or password why internal server occurred? One more thing I would like to mention that I have checked the same service on post man it is working fine as expected. If i pass wrong email or password postman returns the expected error. Below is the code I am using
private String invokeWebservice() {
String data = null;
HttpURLConnection conn = null;
BufferedReader in = null;
try {
String webservice = Constants.BASE_URL + serviceName;
LogUtility.debugLog("webservice just called "+ webservice);
URL url = new URL(webservice);
conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(10000);
conn.setConnectTimeout(15000);
conn.setUseCaches(false);
if (isPost) {
conn.setDoOutput(true);
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/json");
conn.setRequestProperty("Accept", "application/json");
Writer writer = new BufferedWriter(new OutputStreamWriter(conn.getOutputStream(), "UTF-8"));
if (jsonObject != null)
writer.write(jsonObject.toString());
writer.close();
}
in = new BufferedReader(new InputStreamReader(conn.getInputStream()));
StringBuffer sb = new StringBuffer("");
String l = "";
String nl = System.getProperty("line.separator");
while ((l = in.readLine()) != null)
sb.append(l + nl);
in.close();
data = sb.toString();
return data;
} catch (Exception e) {
LogUtility.errorLog("exception while calling web service");
} finally {
try {
if (conn != null)
conn.disconnect();
if (in != null)
in.close();
} catch (Exception ex) {
// LogUtility.errorLogWithException(ex, ex.getMessage());
}
}
return data;
}
Any help?
After spending some time now I was able to solve my problem.Posting my answer for others. Passing wrong email and password to the service was right and server was consuming those parameters as well and because there was an error(because email and password) that is why it was returning 500 code. So, I checked for status code if it was 200 then I used getInputStream() method and else i called getErrorStream() method. By this way i got the stream that has property for error(this property contains error detail). Below is the code i used
if (conn.getResponseCode() != HttpURLConnection.HTTP_OK) {
in = new BufferedReader(new InputStreamReader(conn.getErrorStream()));
} else {
in = new BufferedReader(new InputStreamReader(conn.getInputStream()));
}
Hope it helps other as well.

how to send unicode charcters in http post request from asyncTask

I saw this post How to send unicode characters in an HttpPost on Android but I usaully do request in this way in AsyncTask class.My log is also printing local language in urlParameters but server is returning no result while it is perfect for english Strings:
#Override
protected String doInBackground(String... URLs) {
StringBuffer response = new StringBuffer();
try {
URL obj = new URL(URLs[0]);
HttpURLConnection con = (HttpURLConnection) obj.openConnection();
// add request header
con.setRequestMethod("POST");
if (URLs[0].equals(URLHelper.get_preleases)) {
urlCall = 1;
} else
urlCall = 2;
// String urlParameters = "longitude=" + longitude + "&latitude="+latitude;
// Send post request
con.setDoOutput(true);
DataOutputStream wr = new DataOutputStream(con.getOutputStream());
wr.writeBytes(urlParameters);
wr.flush();
wr.close();
int responseCode = con.getResponseCode();
if (responseCode == 200) {
BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
}
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return response.toString();
}
Is there a way to set character set UTF-8 to request parameters coding this way?
String urlParameters = "longitude=" + longitude + "&latitude="+latitude;
You need to URL-encode components you are injecting into an application/x-www-form-urlencoded context. (Even aside from non-ASCII characters, characters like the ampersand will break otherwise.)
Specify the string-to-bytes encoding that you are using for your request in that call, for example:
String urlParameters = "longitude=" + URLEncoder.encode(longitude, "UTF-8")...
...
DataOutputStream wr = new DataOutputStream(con.getOutputStream());
A DataOutputStream is for sending struct-like Java-typed binary data down a stream. It doesn't give you anything you need for writing HTTP request bodies. Maybe you meant OutputStreamWriter?
But since you already have the string all in memory you could simply do:
con.getOutputStream().write(urlParameters.getBytes("UTF-8"))
(Note the UTF-8 here is somewhat superfluous. Because you will already have URL-encoded all the non-ASCII characters into %xx escapes, there will be nothing to UTF-8-encoded. However in general it is almost always better to specify a particular encoding than omit it and revert to the unreliable system default encoding.)
new InputStreamReader(con.getInputStream())
is also omitting the encoding and reverting to the default encoding which is probably not the encoding of the response. So you will probably find non-ASCII characters get read incorrectly in the response too.

POST with Basic Auth fails on Android but works in C#

I have an app I am developing that requires me to post data to a 3rd party API. I have been struggling with authentication since the beginning and kept putting off further and further, and now I'm stuck.
I have tried using an Authenticator, but have read all about how there appears to be a bug in certain Android versions: Authentication Example
I have tried several different options, including the Apache Commons HTTP Library with no success. After all of this, I decided to make sure that the API wasn't the pain point. So I wrote a quick WinForms program to test the API, which worked perfectly on the first try. So, the idea that I'm working from and the API I working with both seem fine, but I am in desperate need of some guidance as to why the Java code isn't working.
Examples follow:
C# Code that works everytime:
System.Net.ServicePointManager.Expect100Continue = false;
// Create a request using a URL that can receive a post.
WebRequest request = WebRequest.Create(addWorkoutUrl);
// Set the Method property of the request to POST.
request.Method = "POST";
// Create POST data and convert it to a byte array.
string postData = "distance=4000&hours=0&minutes=20&seconds=0&tenths=0&month=08&day=01&year=2011&typeOfWorkout=standard&weightClass=H&age=28";
byte[] byteArray = Encoding.UTF8.GetBytes(postData);
// Set the ContentType property of the WebRequest.
request.Headers["X-API-KEY"] = apiKey;
request.Headers["Authorization"] = "Basic " + Convert.ToBase64String(Encoding.Default.GetBytes("username:password"));
request.ContentType = "application/x-www-form-urlencoded";
// Set the ContentLength property of the WebRequest.
request.ContentLength = byteArray.Length;
// Get the request stream.
Stream dataStream = request.GetRequestStream();
// Write the data to the request stream.
dataStream.Write(byteArray, 0, byteArray.Length);
// Close the Stream object.
dataStream.Close();
// Get the response.
WebResponse response = request.GetResponse();
// Display the status.
MessageBox.Show(((HttpWebResponse)response).StatusDescription);
// Get the stream containing content returned by the server.
dataStream = response.GetResponseStream();
// Open the stream using a StreamReader for easy access.
StreamReader reader = new StreamReader(dataStream);
// Read the content.
string responseFromServer = reader.ReadToEnd();
// Display the content.
MessageBox.Show(responseFromServer);
// Clean up the streams.
reader.Close();
dataStream.Close();
response.Close();
Java code for Android that currently returns a 500:Internal Server Error, though I believe this is my fault.
URL url;
String data = "distance=4000&hours=0&minutes=20&seconds=0&tenths=0&month=08&day=01&year=2011&typeOfWorkout=standard&weightClass=H&age=28";
HttpURLConnection connection = null;
//Create connection
url = new URL(urlBasePath);
connection = (HttpURLConnection)url.openConnection();
connection.setConnectTimeout(10000);
connection.setUseCaches(false);
connection.setRequestProperty("User-Agent","Mozilla/5.0 ( compatible ) ");
connection.setRequestProperty("Accept","*/*");
connection.setRequestProperty("X-API-KEY", apiKey);
connection.setRequestProperty("Authorization", "Basic " +
Base64.encode((username + ":" + password).getBytes("UTF-8"), Base64.DEFAULT));
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
connection.setRequestProperty("Content-Length", "" + Integer.toString(data.getBytes("UTF-8").length));
DataOutputStream wr = new DataOutputStream(connection.getOutputStream());
wr.write(data.getBytes("UTF-8"));
wr.flush();
wr.close();
statusCode = connection.getResponseCode();
statusReason = connection.getResponseMessage();
//At this point, I have the 500 error...
I figured out the problem, and the solution finally after stumbling across the root cause as mentioned in the comment above.
I was using Base64.encode() in my example, but I needed to be using Base64.encodeToString().
The difference being that encode() returns a byte[] and encodeToString() returns the string I was expecting.
Hopefully this will help somebody else who is caught by this.
Here's a nicer method to do to the POST.
install-package HttpClient
Then:
public void DoPost()
{
var httpClient = new HttpClient();
var creds = string.Format("{0}:{1}", _username, _password);
var basicAuth = string.Format("Basic {0}", Convert.ToBase64String(Encoding.UTF8.GetBytes(creds)));
httpClient.DefaultRequestHeaders.Add("Authorization", basicAuth);
var post = httpClient.PostAsync(_url,
new FormUrlEncodedContent(new Dictionary<string, string>
{
{ "name", "Henrik" },
{ "age", "99" }
}));
post.Wait();
}
I have tried this in java
import java.io.*;
import java.net.*;
class download{
public static void main(String args[]){
try{
String details = "API-Key=e6d871be90a689&orderInfo={\"booking\":{\"restaurantinfo\":{\"id\":\"5722\"},\"referrer\":{\"id\": \"9448476530\" }, \"bookingdetails\":{\"instructions\":\"Make the stuff spicy\",\"bookingtime\": \"2011-11-09 12:12 pm\", \"num_guests\": \"5\"}, \"customerinfo\":{\"name\":\"Ramjee Ganti\", \"mobile\":\"9345245530\", \"email\": \"sajid#pappilon.in\", \"landline\":{ \"number\":\"0908998393\",\"ext\":\"456\"}}}}";
Authenticator.setDefault(new Authenticator() {
protected PasswordAuthentication getPasswordAuthentication() {
return new PasswordAuthentication("admin", "1234".toCharArray());
}
});
HttpURLConnection conn = null;
//URL url = new URL("http://api-justeat.in/ma/orders/index");
URL url = new URL("http://api.geanly.in/ma/order_ma/index");
conn = (HttpURLConnection) url.openConnection();
conn.setDoOutput(true);
conn.setDoInput (true);
conn.setRequestMethod("POST");
//conn.setRequestMethod(HttpConnection.POST);
DataOutputStream outStream = new DataOutputStream(conn.getOutputStream());
outStream.writeBytes(details);
outStream.flush();
outStream.close();
//Get Response
InputStream is = conn.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
String line;
StringBuffer response = new StringBuffer();
while((line = rd.readLine()) != null) {
System.out.println(line);
}
rd.close();
System.out.println(conn.getResponseCode() + "\n\n");
}catch(Exception e){
System.out.println(e);
}
}
}
this could help.

How do I send a request to different page on the logged site

First, I want to connect to the site.
After, I want to get a data from different page with this connection
sample:
1- connect to http://site.com/Login with user pass
2- get a secret data from http://site.com/Secret
How do I do this, pleas help me...
OutputStreamWriter request = null;
url = new URL("http://site.com/Login");
String response = null;
EditText user = (EditText)this.findViewById(R.id.user);
EditText pass = (EditText)this.findViewById(R.id.pass);
String parameters ;
try {
System.setProperty("http.keepAlive", "true");
url = new URL("http://site.com/Home/Login");
httppost = (HttpURLConnection) url.openConnection();
httppost.setDoInput(true);
httppost.setDoOutput(true);
httppost.setRequestMethod("POST");
httppost.setRequestProperty("User-Agent", "Mozilla/5.0 Linux U Android 2.3.3 tr-tr HTC_DesireHD_A9191 Build/GRI40 AppleWebKit/533.1 KHTML, like Gecko Version/4.0 Mobile Safari/533.1");
httppost.setRequestProperty("Accept_Language", "en-US");
httppost.setRequestProperty("Connection", "Keep-Alive");
httppost.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
request = new OutputStreamWriter(httppost.getOutputStream());
parameters = "username="+user.getText()+"&password="+pass.getText();
request.write(parameters);
request.flush();
request.close();
String line = "";
InputStreamReader isr = new InputStreamReader(httppost.getInputStream());
BufferedReader reader = new BufferedReader(isr);
StringBuilder sb = new StringBuilder();
while ((line = reader.readLine()) != null)
{
sb.append(line + "\n");
}
response = sb.toString();
Toast.makeText(this,response, Toast.LENGTH_LONG).show();
isr.close();
reader.close();
} catch (Exception e) {
e.printStackTrace();
Toast.makeText(getApplicationContext(), e.toString(), Toast.LENGTH_LONG).show();
}
You should use WebView and sorry but you can not get the webview content.
If you own the server-side code and you want to access from java then you should use an access token for more secure connection and get data by using JSON or XML. Or there is a much more secure connection type which is OAuth2.
If you don't own server, you should show the http://site.com/Login url in webview. When the user logins than you have cookie in your webview. You can use CookieManager http://developer.android.com/reference/android/webkit/CookieManager.html and send the data by using this cookie and get the result. This method is not easy and can differentiate according to server-side implementation.

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