Develop Reference

change hex of integer resource to String

I am new in android.
in my value resource i create an xml layout and put this line in to it:
<integer name="mode_happy"> 0x1F60A</integer>
in my activity I want convert 0x1F60A to String. for this i create a method:
private String getStringOfEmojiCode(int emogiCode) {
StringBuilder sb = new StringBuilder();
//convert hex to char
sb.append(Character.toChars(emogiCode));
return sb.toString();
}
when I pass mode_happyto my method:
mSelectedMode =
getStringOfEmojiCode(getResources().getInteger(R.integer.mode_happy));
I receive this :
mSelectedMode: ��
but i want to get like this:0x1F60A
where is my mistake?

A formatter may be used to build the string from hex characters in a particular format:
String mSelectedMode
= String.format("0x%05X", getResources().getInteger(R.integer.mode_happy));
This worked for me, the hex which you stored as an integer was being converted to a decimal for me, but using the formatter worked. This also meant I did not have to use any other method.
Explanation:
The format 0x%05X takes in a 5 digit hex character signified by %05X with 'X' indicating hex. A lowercase x may be used which in this case would give out the output in lower case: 0x1f60a. The 0x is added to the format so as to have it as a prefix for each string. Refer to this for further details on formatting.

Getting invalid double, but the error shows a proper one

My application does some basic arithmetic processes and then adds them to a TextView. Because I want them the result be shown up to XX,XX I format my string with %.2f. Now, when I try to retrieve this result and use it in another arithmetic process, it gives me an error of:
java.lang.NumberFormatException: Invalid double: "8,86" (or any number for that matter)
How can I make the second process convert the string from the TextViewwithout getting an error?
process 1
int newProductQuantity = Integer.valueOf(productQuantity.getText().toString());
double newProductPrice = Double.valueOf(productPrice.getText().toString());
double newProductVAT = Double.valueOf(productVat.getText().toString());
double newProductPriceSum = ((newProductPrice + (newProductPrice * (newProductVAT / 100))) * newProductQuantity);
String newProductPriceSumTexta = String.format("%.2f", newProductPriceSum);
productPriceSum.setText(newProductPriceSumTexta);
process 2
double newOrderFinalLastSum = Double.parseDouble(newOrderFinalSum.getText().toString());
double newOrderFinalNewSum = Double.parseDouble(productPriceSum.getText().toString());
double newOrderFinalOmegaSum = newOrderFinalLastSum + newOrderFinalNewSum; //error is here
String newOrderFinalOmegaSumText = String.format("%.2f", newOrderFinalOmegaSum);
newOrderFinalSum.setText(newOrderFinalOmegaSumText);

your issue is Locale related. If you want always a dot . as separator, you should specify a Locale that use it. You can use format method that takes as first parameter a Locale object. For instance
String.format(Locale.UK,...
From the documentation of public static String format(Locale l, String format, Object... args)
Returns a formatted string using the specified locale, format string,
and arguments.
where
l - The locale to apply during formatting. If l is null then no
localization is applied.

How to roud off a String value "5571.329849243164" in android

I'm getting below error while converting String array to Long array.
java.lang.NumberFormatException: Invalid long: "5571.329849243164". How to round off this value like 5571.

Use this
String.format("%.2f", d)

//try this way, hope this will help you...
String value = "5571.329849243164";
Toast.makeText(MyActivity.this,""+Math.round(Double.parseDouble(value)),Toast.LENGTH_SHORT).show();

round(Double value)`
see here
String string = "5571.329849243164";
Double value1 = Double.parseDouble(string);
tv.setText(Math.round(value1) + "/");

I understand you want to convert a String representing a floating point value to an Integer with rounding, not truncation. Perfectly reasonable.
Two choices.
Convert the string to a Double first (Double.valueOf()), then convert to Integer (intValue()) using a rounding algorithm. Usually it's enough to just add 0.5 to the Double.
Round the String using string operations, then convert to Integer. Split the string at the first ".", convert it to Integer (getInteger()). If the digit after the "." is in the range 5-9 then add one.
I'm sure you can write the code.

Android How to convert Hex String to int but remain 0x

I has a Hex String like "0xff"
I want to convert the String to int
but remain the part of "0x"
such as
String hex = "0x32";
int convert = Integer.parseInt(hex, 16);
the result of convert = 50
but what i want is directly convert the hex to int like:
convert = 0x32
How should i do?
Edit:
I have an variable hex like
String Hex = "0x32"
Now I want to parse it to int value but i want the int result is
int convert = 0x32
My question is which method can help me convert the hex String directly to int like
String hex = "0x32"
int convert = hex do some thing but result will be convert = 0x32

You seem to confuse the value of an integer with its representation as a string. For example the integer value twelve can be represented in various ways, decimal 12, octal 14, hex c, binary 1100, roman XII, are just a few of the possible representations.
An int in Java just stores the value. Representations come into play when you convert the value to a string or vice versa.

Android convert color int to hexa String

public static int RGB(float[] hsv) {
return Color.HSVToColor(hsv);
}
this function add an int, froma color. how can i convert that int to a hexa string: #efefef

The answer of st0le is not correct with respect to colors. It does not work if first color components are 0. So toHexString is useless.
However this code will work as expected:
String strColor = String.format("#%06X", 0xFFFFFF & intColor);

Here are 2 ways to convert Integer to Hex Strings...
int n = 123456;
System.out.println(String.format("#%X", n)); //use lower case x for lowercase hex
System.out.println("#"+Integer.toHexString(n));

If you want to convert to javascript format:
val hexColor = String.format("%06X", 0xFFFFFFFF.and(R.color.text.toColorInt(context).toLong()))
val javascriptHexColor = "#" + hexColor.substring(2) + hexColor.substring(0, 2)

Use this way
Java:
String hexColor = "#" + Integer.toHexString(ContextCompat.getColor(context, R.color.colorTest))
Kotlin:
var hexColor = "#${Integer.toHexString(ContextCompat.getColor(context, R.color.colorTest))}"