I am setting text using setText() by following way.
prodNameView.setText("" + name);
prodOriginalPriceView.setText("" + String.format(getString(R.string.string_product_rate_with_ruppe_sign), "" + new BigDecimal(price).setScale(2, RoundingMode.UP)));
In that First one is simple use and Second one is setting text with formatting text.
Android Studio is so much interesting, I used Menu Analyze -> Code Cleanup and i got suggestion on above two lines like.
Do not concatenate text displayed with setText. Use resource string
with placeholders. less... (Ctrl+F1)
When calling TextView#setText:
Never call Number#toString() to format numbers; it will not handle fraction separators and locale-specific digits properly. Consider
using String#format with proper format specifications (%d or %f)
instead.
Do not pass a string literal (e.g. "Hello") to display text. Hardcoded text can not be properly translated to other languages.
Consider using Android resource strings instead.
Do not build messages by concatenating text chunks. Such messages can not be properly translated.
What I can do for this? Anyone can help explain what the thing is and what should I do?
Resource has the get overloaded version of getString which takes a varargs of type Object: getString(int, java.lang.Object...). If you setup correctly your string in strings.xml, with the correct place holders, you can use this version to retrieve the formatted version of your final String. E.g.
<string name="welcome_messages">Hello, %1$s! You have %2$d new messages.</string>
using getString(R.string.welcome_message, "Test", 0);
android will return a String with
"Hello Test! you have 0 new messages"
About setText("" + name);
Your first Example, prodNameView.setText("" + name); doesn't make any sense to me. The TextView is able to handle null values. If name is null, no text will be drawn.
Don't get confused with %1$s and %2$d in the accepted answer.Here is a few extra information.
The format specifiers can be of the following syntax:
%[argument_index$]format_specifier
The optional argument_index is specified as a number ending with a “$” after the “%” and selects the specified argument in the argument list. The first argument is referenced by "1$", the second by "2$", etc.
The required format specifier is a character indicating how the argument should be formatted. The set of valid conversions for a given argument depends on the argument's data type.
Example
We will create the following formatted string where the gray parts are inserted programmatically.
Hello Test! you have 0 new messages
Your string resource:
< string name="welcome_messages">Hello, %1$s! You have %2$d new
messages< /string >
Do the string substitution as given below:
getString(R.string.welcome_message, "Test", 0);
Note:
%1$s will be substituted by the string "Test"
%2$d will be substituted by the string "0"
I ran into the same lint error message and solved it this way.
Initially my code was:
private void displayQuantity(int quantity) {
TextView quantityTextView = (TextView) findViewById(R.id.quantity_text_view);
quantityTextView.setText("" + quantity);
}
I got the following error
Do not concatenate text displayed with setText. Use resource string with placeholders.
So, I added this to strings.xml
<string name="blank">%d</string>
Which is my initial "" + a placeholder for my number(quantity).
Note: My quantity variable was previously defined and is what I wanted to append to the string. My code as a result was
private void displayQuantity(int quantity) {
TextView quantityTextView = (TextView) findViewById(R.id.quantity_text_view);
quantityTextView.setText(getString(R.string.blank, quantity));
}
After this, my error went away. The behavior in the app did not change and my quantity continued to display as I wanted it to now without a lint error.
Do not concatenate text inside your setText() method, Concatenate what ever you want in a String and put that String value inside your setText() method.
ex: correct way
int min = 120;
int sec = 200;
int hrs = 2;
String minutes = String.format("%02d", mins);
String seconds = String.format("%02d", secs);
String newTime = hrs+":"+minutes+":"+seconds;
text.setText(minutes);
Do not concatenate inside setText() like
text.setText(hrs+":"+String.format("%02d", mins)+":"+String.format("%02d", secs));
You should check this thread and use a placeholder like his one (not tested)
<string name="string_product_rate_with_ruppe_sign">Price : %1$d</string>
String text = String.format(getString(R.string.string_product_rate_with_ruppe_sign),new BigDecimal(price).setScale(2, RoundingMode.UP));
prodOriginalPriceView.setText(text);
Don't Mad, It's too Simple.
String firstname = firstname.getText().toString();
String result = "hi "+ firstname +" Welcome Here";
mytextview.setText(result);
the problem is because you are appending "" at the beginning of every string.
lint will scan arguments being passed to setText and will generate warnings, in your case following warning is relevant:
Do not build messages by
concatenating text chunks. Such messages can not be properly
translated.
as you are concatenating every string with "".
remove this concatenation as the arguments you are passing are already text. Also, you can use .toString() if at all required anywhere else instead of concatenating your string with ""
I fixed it by using String.format
befor :
textViewAddress.setText("Address"+address+"\n"+"nCountry"+"\n"+"City"+"city"+"\n"+"State"+"state")
after :
textViewAddress.setText(
String.format("Address:%s\nCountry:%s\nCity:%s\nState:%s", address, country, city, state));
You can use this , it works for me
title.setText(MessageFormat.format("{0} {1}", itemList.get(position).getOppName(), itemList.get(position).getBatchNum()));
If you don't need to support i18n, you can disable this lint check in Android Studio
File -> Settings -> Editor -> Inspections -> Android -> Lint -> TextView Internationalization(uncheck this)
prodNameView.setText("" + name); //this produce lint error
val nameStr="" + name;//workaround for quick warning fix require rebuild
prodNameView.setText(nameStr);
I know I am super late for answering this but I think you can store the data in a varible first then you can provide the variable name. eg:-
// Java syntax
String a = ("" + name);
String b = "" + String.format(getString(R.string.string_product_rate_with_ruppe_sign);
String c = "" + new BigDecimal(price).setScale(2, RoundingMode.UP));
prodNameView.setText(a);
prodOriginalPriceView.setText(b, c);
if it is textView you can use like that : myTextView.text = ("Hello World")
in editText you can use myTextView.setText("Hello World")
I've got a String filled with hex values like this:
received_Value = fffec780
The string isn't declared as a hex string, it is declared as a normal string and filled with this characters. But I must define it as a Hex string to make the conversion to int.
int_value_receive = Integer.parseInt(received_Value, 16)
Because when doing this i'm getting an error.
fffec780's value as an int is greater than MAX_INTEGER.
Try this
Long.parseLong(received_Value, 16);
In my Android Application when I am reading the particular data from NFC chip it's giving garbage values as show follows which is printed on Log
����������������
I used following line to remove garbage value
str.replaceAll("[^\\p{ASCII}]", "")
but it is not working.
Please provide me solution.
That is because � is not an ASCII character. It is a unicode character with (int) � returning 65533.
And your code str.replaceAll("[^\\p{ASCII}]", "") works perfectly fine.
scala> val str ="����������������"
str: String = ����������������
scala> str.replaceAll("[^\\p{ASCII}]", "")
res8: String = ""
You need to show more code and explain what exactly you are trying to do.
Better to retrieve the data in the form of UTF-8 format then it helps. try it out.
or convert the string to UTF-8 format
i.e, String _data=new String(str.getBytes(),"UTF-8");
it returns the data in UTF-8 format
One solution using this method .replaceAll("[^\\x00-\\x7F]", "")
String str = "jorgesys���������������� was here!";
str = str.replaceAll("[^\\x00-\\x7F]", ""));
so the result of str is:
jorgesys was here!
I have a UTF-16LE encoded string that comes from a server. I would like to print that string in Textview of my activity. However, the string prints with spaces in between them. So, "Hello" prints as "H e l l o" and doesn't look all that nice in my screen.
Any help is appreciated.
Thanks
Assuming you have a stream (or array of bytes) containing a UTF-16LE encoded string.
String str0 = "Hello, I am a UTF-16LE encoded String";
byte[] utf16le = str.getBytes("UTF-16LE");
If you do not convert these back & stating the character set used you will be producing a string containing a lot of 0-bytes (UTF-16LE is, obviously, 16-bit) in your resulting String.
String wrong = new String(utf16le); // This will produce crap with \0:s in it.
String correct = new String(utf16le, "UTF-16LE"); // This will be the actual string.
Note: If you dump crap String:s like these into a TextView in ICS it will remove the garbage for you and not print "H e l l o".
What I'm trying to do is find a way I can take the word "camel" for example from a EditText field and make for instance c=2 a=1 m=4 e=5 l=3. Is there anyway I can pull the individual characters from a string and convert them to numbers?
I've tried using "split" to separate each character into an array but I can't figure out how to convert the letters into numbers
so I can do something like:
a=1
b=2
c=3
int temp = (int)(array[1]+array[2]+array[3]+etc...)
using the example of "camel" would equal 15
This is what I have so far:
String name = inputarea.getText().toString();
String[] array = name.split("");
for(int i =0; i < array.length ; i++)
The biggest problem I keep having is if I try to pull from the 7th position in the array and nothing is there. (camel only has 5 characters) then I get a nice big error.
Thank you for any help that can be provided.
Edit: I figured it out after a few hours of playing with it here is my working code:
String firstname = inputarea.getText().toString();
char[] array = firstname.toCharArray();
final char[] array2 = new char[15];
System.arraycopy(array, 0, array2, 0, array.length);
if (array2[0] == 'A' ) {
array2[0] = '1';
}
suggestion:
first, need define all letter, from a-z (A-Z), the ASCII code 'a' to 'z' is 97 to 122, if you want support the upper letter, you need add A-Z.
then, get the letter in the string, u can use this:
for(int i=0;i<string.length();i++){
int number = string.charAt(i);
}
when you get the number size, you can reduce to the base number('a' is 97), you will get the individual number
Does String.charAt() works for you?
As for converting to number, if the numbers are consecutive you can define a fixed string with all the characters you want to map and use String.indexOf(). If not, you can have a parallel array with ints or use a Map.