Im getting the following error on trying to use an web service from google api maps:
{
"error_message" : "Requests to this API must be over SSL.",
"results" : [],
"status" : "REQUEST_DENIED"
}
the url used to invoke the web service:
http://maps.googleapis.com/maps/api/geocode/json?key=my_key=Rua+Vergueiro,+1883,+S%C3%A3o+Paulo,+Brazil&sensor=true
method used to call the web service:
enter code here
public static String httpPost(String urlStr) throws Exception {
String novaUrl = urlStr.trim();
novaUrl = urlStr.replaceAll(" ", "+");
novaUrl = novaUrl.replaceAll("\r", "");
novaUrl = novaUrl.replaceAll("\t", "");
novaUrl = novaUrl.replaceAll("\n", "");
URL url = new URL(novaUrl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
conn.setDoOutput(true);
conn.setDoInput(true);
conn.setUseCaches(false);
conn.setAllowUserInteraction(false);
conn.setRequestProperty("Content-Type", "application/x-www-form-urldecoded");
// Create the form content
OutputStream out = conn.getOutputStream();
Writer writer = new OutputStreamWriter(out, "UTF-8");
writer.close();
out.close();
// Buffer the result into a string
BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream()));
StringBuilder sb = new StringBuilder();
String line;
while ((line = rd.readLine()) != null) {
sb.append(line);
}
rd.close();
conn.disconnect();
Spanned retorno = Html.fromHtml(sb.toString());
return retorno.toString();
}
How to solve this problem?
Thanks.
Try using this URL. Error just because of http and https. https is used for secure line.
https://maps.googleapis.com/maps/api/geocode/json?key=my_key=Rua+Vergueiro,+1883,+S%C3%A3o+Paulo,+Brazil&sensor=true
Now when you click on this you will get some error like this .. The provided API key is invalid.
For that just provide correct API key that you retrieved from Google Console.
Your given URL :: https://maps.googleapis.com/maps/api/geocode/json?key=my_key=Rua+Vergueiro,+1883,+S%C3%A3o+Paulo,+Brazil&sensor=true
here key=my_key Here is the problem, please provide correct API key and you problem will be solved.
Related
Today I'm making my first attempt of sending a POST request with a JSON to save some data, and I'm not being able to do so.
My app works by signing in, and then save, modify and delete data. It's already done in iOS, but since I'm new to Android, I'm not sure how to do it.
Here's my POST function:
public String POST(String targetURL, String urlParameters, String user, String pwd) {
URL url;
String u = targetURL;
HttpURLConnection connection = null;
try {
// Create connection
// u=URLEncoder.encode(u, "UTF-8");
url = new URL(u);
connection = (HttpURLConnection) url.openConnection();
// cambiarlo luego al usuario q esta logeado
String login = user + ":" + pwd;
String encoding = new String(org.apache.commons.codec.binary.Base64.encodeBase64(org.apache.commons.codec.binary.StringUtils.getBytesUtf8(login)));
connection.setRequestMethod("POST");
connection.setRequestProperty("Authorization", "Basic " + encoding);
connection.setRequestProperty("Content-Type", "plain/text");// hace q sirva con el string de json
connection.setRequestProperty("Content-Length", "" + Integer.toString(urlParameters.getBytes().length));
connection.setRequestProperty("Content-Language", "en-US");
connection.setUseCaches(false);
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setReadTimeout(120000);
// Send request
DataOutputStream wr = new DataOutputStream(connection.getOutputStream());
wr.writeBytes(urlParameters);
wr.flush();
wr.close();
// Get Response
InputStream is = connection.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
String line;
StringBuffer response = new StringBuffer();
this.setResponseCode(connection.getResponseCode());
while ((line = rd.readLine()) != null) {
response.append(line);
response.append('\r');
}
rd.close();
return response.toString();
} catch (Exception e) {
e.printStackTrace();
return null;
} finally {
if (connection != null) {
connection.disconnect();
}
}
}
The method above is executed with Asynctask, and even if I use it to Login using Spring security, it works, and even I can save for internal usage the username, password, and secret token.
I dunno if I need to put the token in a header or something, because I already did that, with no positive results.
I'm supposing that the only permission I need to execute this is the internet one, so in my manifest file I specified that permission.
I'm going crazy with this issue, please help!
Thanks in advance.
EDIT:
Sorry guys, I'm kinda new to this way of asking, and also, not an English native speaker :P
The output I receive after sending the request, is the HTML of the page that handles logging in into the web app... I need like a json response or something like that to make sure the request was saved correctly
Try handling your cookies
CookieManager cookieManager = new CookieManager();
CookieHandler.setDefault(cookieManager);
This should be a singleton.
I'm trying to do a post method for a REST service, but I'm not getting any response from server:
public JSONObject postValues (String strUrl, String strJsonArray) throws Exception{
JSONObject jsonObject = null;
URL url = new URL(strUrl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(10000);
conn.setConnectTimeout(15000);
conn.setDoOutput(true);
conn.setDoInput(true);
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
strJsonArray = "data=" + strJsonArray;
Log.e("result",""+strJsonArray);
OutputStream os = conn.getOutputStream();
os.write(strJsonArray.getBytes());
os.flush();
conn.connect();
if (conn.getResponseCode() != 200) {
throw new RuntimeException("Failed : HTTP error code : "
+ conn.getResponseCode());
}
BufferedReader br = new BufferedReader(new InputStreamReader(
(conn.getInputStream())));
String output;
StringBuilder sb = new StringBuilder();
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null) {
Log.e("output",output);
sb.append(output);
}
Log.e("output",sb.toString());
jsonObject = new JSONObject(sb.toString());
conn.disconnect();
return jsonObject;
}
When I see my logCat a get:
output {}
I know that the server is working right because I'm using the "advanced REST client" plugin of google chrome. If I call the URL manually (using the plugin of course)I get the desired answer:
{"message":"OK","code":200}
But if I try to use my function, my strJsonArray is inserted but I get an empty respond from server.
Is there anything wrong with my code?.
Everything looks good...
You could use Wireshark to capture the packets sent to and received from the server using an emulator and the chrome rest client. Then you can compare them and maybe find out what's wrong.
You could also check if theres something in the error stream (conn.getErrorStream()).
i want to upload a file from my android phone to server URL. but the server required login first. how can i do this to upload the file to this server URL with also login URL.
for example:
uploading url:
http://api.someapi.net/v1/medium/14
parameters required: file and title
login url:
http://api.someapi.net/v1/user/login
parameters required: email and password
Check the login credentials by using the code below. If the response is OK send the file to the url using the same code below with different parameters. Else do whatever you want.
URL siteUrl;
try {
siteUrl = new URL("yoururl");
HttpURLConnection conn = (HttpURLConnection) siteUrl
.openConnection();
conn.setRequestMethod("POST");
conn.setDoOutput(true);
conn.setDoInput(true);
DataOutputStream out = new DataOutputStream(conn.getOutputStream());
String content1 = "";
//Here param is the Map<String,String> which holds the value of email and password
Set getkey = param.keySet();
Iterator keyIter = getkey.iterator();
String content = "";
for (int i = 0; keyIter.hasNext(); i++) {
Object key = keyIter.next();
if (i != 0) {
content += "&";
}
content += key + "=" + param.get(key);
}
//Check by printing here
System.out.println(content);
out.writeBytes(content.trim());
out.flush();
out.close();
BufferedReader in = new BufferedReader(new InputStreamReader(
conn.getInputStream()));
String line = "";
while ((line = in.readLine()) != null) {
System.out.println(line);
}
in.close();
} catch (MalformedURLException e) {
e.printStackTrace();
}
Hope it helps
You need Apache's Mime4J jar file on your project (here - http://james.apache.org/download.cgi#Apache_Mime4J )
And do:
MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
entity.addPart("file", new InputStreamBody(file, "UPLOAD.jpg"));
request.setEntity(entity);
Tada!
I want to use assembla apis from android environment for my project.
I am trying to do basic authentication as follow :
String authentication = "username:password";
String encoding = Base64.encodeToString(authentication.getBytes(), 0);
URL url = new URL("https://www.assembla.com/");
conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
conn.setRequestProperty("Authorization", "Basic " + encoding);
conn.setDoOutput(true);
conn.connect();
System.out.println(conn.getResponseCode());
System.out.println(conn.getResponseMessage());
I am getting 400 and Bad Request in output.
is there something wrong with URL that i am using or some other thing is going wrong?
It looks like the question was answered here. You need to use Base64.NO_WRAP flag when encoding username-password pair:
String encoding = Base64.encodeToString(authentication.getBytes(), Base64.NO_WRAP);
By default the Android Base64 util adds a newline character to the end of the encoded string. This invalidates the HTTP headers and causes the "Bad request".
The Base64.NO_WRAP flag tells the util to create the encoded string without the newline character thus keeping the HTTP headers intact.
REST API with HTTP Authentication Output:- I got the result
String authentication = "username:password";
String encoding = Base64.encodeToString(authentication.getBytes(), Base64.NO_WRAP);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
conn.setDoOutput(true);
conn.setRequestProperty ("Authorization", "Basic " + encoding);
conn.connect();
OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
wr.write( data );
wr.flush();
reader = new BufferedReader(new InputStreamReader(conn.getInputStream()));
StringBuilder sb = new StringBuilder();
String line = null;
while((line = reader.readLine()) != null)
{
// Append server response in string
sb.append(line + "\n");
}
Content = sb.toString();
I have an app I am developing that requires me to post data to a 3rd party API. I have been struggling with authentication since the beginning and kept putting off further and further, and now I'm stuck.
I have tried using an Authenticator, but have read all about how there appears to be a bug in certain Android versions: Authentication Example
I have tried several different options, including the Apache Commons HTTP Library with no success. After all of this, I decided to make sure that the API wasn't the pain point. So I wrote a quick WinForms program to test the API, which worked perfectly on the first try. So, the idea that I'm working from and the API I working with both seem fine, but I am in desperate need of some guidance as to why the Java code isn't working.
Examples follow:
C# Code that works everytime:
System.Net.ServicePointManager.Expect100Continue = false;
// Create a request using a URL that can receive a post.
WebRequest request = WebRequest.Create(addWorkoutUrl);
// Set the Method property of the request to POST.
request.Method = "POST";
// Create POST data and convert it to a byte array.
string postData = "distance=4000&hours=0&minutes=20&seconds=0&tenths=0&month=08&day=01&year=2011&typeOfWorkout=standard&weightClass=H&age=28";
byte[] byteArray = Encoding.UTF8.GetBytes(postData);
// Set the ContentType property of the WebRequest.
request.Headers["X-API-KEY"] = apiKey;
request.Headers["Authorization"] = "Basic " + Convert.ToBase64String(Encoding.Default.GetBytes("username:password"));
request.ContentType = "application/x-www-form-urlencoded";
// Set the ContentLength property of the WebRequest.
request.ContentLength = byteArray.Length;
// Get the request stream.
Stream dataStream = request.GetRequestStream();
// Write the data to the request stream.
dataStream.Write(byteArray, 0, byteArray.Length);
// Close the Stream object.
dataStream.Close();
// Get the response.
WebResponse response = request.GetResponse();
// Display the status.
MessageBox.Show(((HttpWebResponse)response).StatusDescription);
// Get the stream containing content returned by the server.
dataStream = response.GetResponseStream();
// Open the stream using a StreamReader for easy access.
StreamReader reader = new StreamReader(dataStream);
// Read the content.
string responseFromServer = reader.ReadToEnd();
// Display the content.
MessageBox.Show(responseFromServer);
// Clean up the streams.
reader.Close();
dataStream.Close();
response.Close();
Java code for Android that currently returns a 500:Internal Server Error, though I believe this is my fault.
URL url;
String data = "distance=4000&hours=0&minutes=20&seconds=0&tenths=0&month=08&day=01&year=2011&typeOfWorkout=standard&weightClass=H&age=28";
HttpURLConnection connection = null;
//Create connection
url = new URL(urlBasePath);
connection = (HttpURLConnection)url.openConnection();
connection.setConnectTimeout(10000);
connection.setUseCaches(false);
connection.setRequestProperty("User-Agent","Mozilla/5.0 ( compatible ) ");
connection.setRequestProperty("Accept","*/*");
connection.setRequestProperty("X-API-KEY", apiKey);
connection.setRequestProperty("Authorization", "Basic " +
Base64.encode((username + ":" + password).getBytes("UTF-8"), Base64.DEFAULT));
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
connection.setRequestProperty("Content-Length", "" + Integer.toString(data.getBytes("UTF-8").length));
DataOutputStream wr = new DataOutputStream(connection.getOutputStream());
wr.write(data.getBytes("UTF-8"));
wr.flush();
wr.close();
statusCode = connection.getResponseCode();
statusReason = connection.getResponseMessage();
//At this point, I have the 500 error...
I figured out the problem, and the solution finally after stumbling across the root cause as mentioned in the comment above.
I was using Base64.encode() in my example, but I needed to be using Base64.encodeToString().
The difference being that encode() returns a byte[] and encodeToString() returns the string I was expecting.
Hopefully this will help somebody else who is caught by this.
Here's a nicer method to do to the POST.
install-package HttpClient
Then:
public void DoPost()
{
var httpClient = new HttpClient();
var creds = string.Format("{0}:{1}", _username, _password);
var basicAuth = string.Format("Basic {0}", Convert.ToBase64String(Encoding.UTF8.GetBytes(creds)));
httpClient.DefaultRequestHeaders.Add("Authorization", basicAuth);
var post = httpClient.PostAsync(_url,
new FormUrlEncodedContent(new Dictionary<string, string>
{
{ "name", "Henrik" },
{ "age", "99" }
}));
post.Wait();
}
I have tried this in java
import java.io.*;
import java.net.*;
class download{
public static void main(String args[]){
try{
String details = "API-Key=e6d871be90a689&orderInfo={\"booking\":{\"restaurantinfo\":{\"id\":\"5722\"},\"referrer\":{\"id\": \"9448476530\" }, \"bookingdetails\":{\"instructions\":\"Make the stuff spicy\",\"bookingtime\": \"2011-11-09 12:12 pm\", \"num_guests\": \"5\"}, \"customerinfo\":{\"name\":\"Ramjee Ganti\", \"mobile\":\"9345245530\", \"email\": \"sajid#pappilon.in\", \"landline\":{ \"number\":\"0908998393\",\"ext\":\"456\"}}}}";
Authenticator.setDefault(new Authenticator() {
protected PasswordAuthentication getPasswordAuthentication() {
return new PasswordAuthentication("admin", "1234".toCharArray());
}
});
HttpURLConnection conn = null;
//URL url = new URL("http://api-justeat.in/ma/orders/index");
URL url = new URL("http://api.geanly.in/ma/order_ma/index");
conn = (HttpURLConnection) url.openConnection();
conn.setDoOutput(true);
conn.setDoInput (true);
conn.setRequestMethod("POST");
//conn.setRequestMethod(HttpConnection.POST);
DataOutputStream outStream = new DataOutputStream(conn.getOutputStream());
outStream.writeBytes(details);
outStream.flush();
outStream.close();
//Get Response
InputStream is = conn.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
String line;
StringBuffer response = new StringBuffer();
while((line = rd.readLine()) != null) {
System.out.println(line);
}
rd.close();
System.out.println(conn.getResponseCode() + "\n\n");
}catch(Exception e){
System.out.println(e);
}
}
}
this could help.