I used below code for launching Twitter through intent but it's not working. I have twitter app installed on my phone.
Intent shareIntent = new Intent(android.content.Intent.ACTION_SEND);
shareIntent.setType("text/plain");
shareIntent.putExtra(android.content.Intent.EXTRA_TEXT, "Content to share");
PackageManager pm = contexto.getPackageManager();
List<ResolveInfo> activityList = pm.queryIntentActivities(shareIntent, 0);
for (final ResolveInfo app : activityList) {
if ("com.twitter.android.PostActivity".equals(app.activityInfo.name)) {
final ActivityInfo activity = app.activityInfo;
final ComponentName name = new ComponentName(activity.applicationInfo.packageName, activity.name);
shareIntent.addCategory(Intent.CATEGORY_LAUNCHER);
shareIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED);
shareIntent.setComponent(name);
contexto.startActivity(shareIntent);
break;
}
}
Getting exception when I try to calling the activity:
android.content.ActivityNotFoundException: Unable to find explicit
activity class {com.twitter.android/com.twitter.android.PostActivity};
have you declared this activity in your AndroidManifest.xml?
Typically for launching a user's feed
Intent intent = null;
try {
// get the Twitter app if possible
this.getPackageManager().getPackageInfo("com.twitter.android", 0);
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?screen_name=USERID"));
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
} catch (Exception e) {
// no Twitter app, revert to browser
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/USERID_OR_PROFILENAME"));
}
this.startActivity(intent);
For Post Intent
Intent tweetIntent = new Intent(Intent.ACTION_SEND);
tweetIntent.putExtra(Intent.EXTRA_TEXT, "This is a Test.");
tweetIntent.setType("text/plain");
PackageManager packManager = getPackageManager();
List<ResolveInfo> resolvedInfoList = packManager.queryIntentActivities(tweetIntent, PackageManager.MATCH_DEFAULT_ONLY);
boolean resolved = false;
for(ResolveInfo resolveInfo: resolvedInfoList){
if(resolveInfo.activityInfo.packageName.startsWith("com.twitter.android")){
tweetIntent.setClassName(
resolveInfo.activityInfo.packageName,
resolveInfo.activityInfo.name );
resolved = true;
break;
}
}
if(resolved){
startActivity(tweetIntent);
}else{
Toast.makeText(this, "Twitter app isn't found", Toast.LENGTH_LONG).show();
}
Slightly corrected (thanks to Taranfx) an user's feed intent (change user_id=>screen_name):
public static void startTwitter(Context context) {
Intent intent = null;
try {
// get the Twitter app if possible
context.getPackageManager().getPackageInfo("com.twitter.android", 0);
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?screen_name=<place_user_name_here>"));
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
return intent;
} catch (Exception e) {
// no Twitter app, revert to browser
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/<place_user_name_here>"));
}
startActivity(intent);
}
I was using the com.twitter.android.composer.ComposerActivity to post text and images since 2016. But started to receive crash reports from users some time ago:
Fatal Exception: android.content.ActivityNotFoundException Unable to
find explicit activity class
{com.twitter.android/com.twitter.android.composer.ComposerActivity};
have you declared this activity in your AndroidManifest.xml?
The issue was caused by renaming
com.twitter.android.composer.ComposerActivity
to
com.twitter.composer.ComposerActivity
inside Twitter app.
The issue was resolved since I changed activity name to com.twitter.composer.ComposerActivity.
And I use the following code to post images with text to Twitter:
ShareCompat.IntentBuilder.from(activity)
.setText(getTextToShare())
.setStream(getImageUriToShare())
.setType("image/png")
.getIntent().addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION)
.setClassName("com.twitter.android", "com.twitter.composer.ComposerActivity");
Related
private void shareonfb(){
Intent shareIntent = new Intent(Intent.ACTION_SEND);
shareIntent.setType("text/plain");
shareIntent.putExtra(Intent.EXTRA_TEXT, "Content to share");
PackageManager pm = getPackageManager();
List<ResolveInfo> activityList = pm.queryIntentActivities(shareIntent, 0);
for (final ResolveInfo app : activityList) {
if ((app.activityInfo.name).contains("facebook")) {
final ActivityInfo activity = app.activityInfo;
final ComponentName name = new ComponentName(activity.applicationInfo.packageName, activity.name);
shareIntent.addCategory(Intent.CATEGORY_LAUNCHER);
shareIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED);
shareIntent.setComponent(name);
startActivity(shareIntent);
break;
}
}
}
the data cannot be post it comes empty when i try the Extra text to post on fb
You cannot prefill a user message as that's against Facebook's Platform Policies. Any message you try to add will be stripped out by the app.
https://developers.facebook.com/policy#control
I am creating an home replacement app for android(Launcher) and I want to place the sms , call, contacts ,gallery and browser apps in the home screen. How can I know the package name for them.
If the user is using a custom contact app as the default one , I need to get the package name of that one and not the android contact app.
How can I achieve this?Thanks.
You can use this code to get Intent to those thing. The problomatic one is the SMS one.
For sms:
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT) {
String defaultSmsPackageName = Telephony.Sms.getDefaultSmsPackage(ctx);
Intent lunchIntent;
if (defaultSmsPackageName != null) {
launchIntent = pm.getLaunchIntentForPackage(defaultSmsPackageName);
} else {
String SMS_MIME_TYPE = "vnd.android-dir/mms-sms";
launchIntent = new Intent(Intent.ACTION_MAIN);
launchIntent.setType(SMS_MIME_TYPE);
}
} else {
String SMS_MIME_TYPE = "vnd.android-dir/mms-sms";
launchIntent = new Intent(Intent.ACTION_MAIN);
launchIntent.setType(SMS_MIME_TYPE);
}
For call:
Intent intent = new Intent(Intent.ACTION_DIAL);
For browser:
Intent intent;
Intent queryIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("http://www.google.com"));
ActivityInfo af = queryIntent.resolveActivityInfo(pm, 0);
intent = new Intent(Intent.ACTION_MAIN);
intent.setClassName(af.packageName, af.name);
For photos:
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("content://media/internal/images/media"));
try {
context.startActivity(intent);
} catch (ActivityNotFoundException eee){
try {
intent = new Intent(Intent.ACTION_VIEW);
intent.setType(android.provider.MediaStore.Images.Media.CONTENT_TYPE);
} catch (Exception err){
Toast.makeText(context, "This app not supported in your device", Toast.LENGTH_LONG).show();
}
}
You could try getting the default launch activity for a specific Intent, for example for SMS you do an Intent with an sms:-URI, and from there check the 'default'-Activity its launching, on the way getting its package name and other details.
Get Preferred/Default app on Android
Good day!
Are there some tools in Android SDK, that i can use to remove application from activity. In particular, i need activity method, that removes other application with the same app-name, but other package.
If you mean with "same name app" to app with same label that define in XML menifest as the label of your app, this snippest should work:
private void deleteAppByActivityName(#NonNull String myAppLabel,#NonNull Context context){
try {
PackageManager pm = context.getPackageManager();
Intent mainIntent = new Intent(Intent.ACTION_MAIN, null);
mainIntent.addCategory(Intent.CATEGORY_LAUNCHER);
List<ResolveInfo> dataInDevice = pm.queryIntentActivities(mainIntent, 0);
for (ResolveInfo resolveInfo : dataInDevice){
String label = resolveInfo.loadLabel(pm).toString();
if (label.equals(myAppLabel)) { //we find app with same name as ours
Intent intent = new Intent(Intent.ACTION_DELETE);
intent.setData(Uri.parse("package:" + resolveInfo.activityInfo.packageName));
context.startActivity(intent);
break;
}
}
}catch (ActivityNotFoundException e){
e.printStackTrace();
}
}
I am trying to remove all shortcuts from all screens in android. I succeed it once but somehow it stopped working after next execute. Could I ask you to help me find out what would be the problem? There is not stack, there is no error, just I click and nothing happens. When I first managed to success I got many toasts describing that "X was removed".
Here is my code:
private void method0() {
final Intent anyIntent = new Intent(Intent.ACTION_MAIN, null);
List<ResolveInfo> pkgAppsList = this.getPackageManager().queryIntentActivities(anyIntent, 0);
for (final ResolveInfo resolveInfo : pkgAppsList) {
method(resolveInfo);
}
}
private void method(ResolveInfo resolveInfo) {
try {
final PackageManager pm = getPackageManager();
String packageName = ((ActivityInfo) resolveInfo.activityInfo).packageName;
String appName = (String) resolveInfo.loadLabel(pm);
ComponentName componentName = new ComponentName(resolveInfo.activityInfo.applicationInfo.packageName, resolveInfo.activityInfo.name);
if (packageName.startsWith("com.google") || (packageName.startsWith("com.android")))
return;
final Intent shortcutIntent = new Intent(Intent.ACTION_MAIN);
shortcutIntent.setComponent(new ComponentName(packageName, componentName.getClassName()));
Intent intent = new Intent();
intent.putExtra(Intent.EXTRA_SHORTCUT_INTENT, shortcutIntent);
intent.putExtra(Intent.EXTRA_SHORTCUT_NAME, appName);
intent.setComponent(new ComponentName(packageName, componentName.getClassName()));
intent.setAction("com.android.launcher.action.UNINSTALL_SHORTCUT");
sendBroadcast(intent, null);
} catch (Exception e) {
e.printStackTrace();
}
}
I added also permission
<uses-permission android:name="com.android.launcher.permission.UNINSTALL_SHORTCUT" />
I am using standard launcher for Nexus 4 - original image ROM from google site.
Looks like you are not using default Stock android launcher.
Please check this example.Hope that helps.
I was looking for some way to launch Twitter app and open a specified page from my application, without webview.
I found the solution for Facebook here:
Opening facebook app on specified profile page
I need something similar.
[EDIT]
I've just found a solution:
try {
Intent intent = new Intent(Intent.ACTION_VIEW,
Uri.parse("twitter://user?screen_name=[user_name]"));
startActivity(intent);
} catch (ActivityNotFoundException e) {
startActivity(new Intent(Intent.ACTION_VIEW,
Uri.parse("https://twitter.com/#!/[user_name]")));
}
Based on fg.radigales answer, this is what I used to launch the app if possible, but fall back to the browser otherwise:
Intent intent = null;
try {
// get the Twitter app if possible
this.getPackageManager().getPackageInfo("com.twitter.android", 0);
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=USERID"));
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
} catch (Exception e) {
// no Twitter app, revert to browser
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/PROFILENAME"));
}
this.startActivity(intent);
UPDATE
Added intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK); to fix an issue where twitter was opening inside my app instead of as a new activity.
This worked for me: twitter://user?user_id=id_num
Open page on Twitter app from other app using Android in 2 Steps:
1.Just paste the below code (on button click or anywhere you need)
Intent intent = null;
try{
// Get Twitter app
this.getPackageManager().getPackageInfo("com.twitter.android", 0);
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=USER_ID"));
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
} catch () {
// If no Twitter app found, open on browser
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/USERNAME"));
}
2.intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=USER_ID"));
To get USER_ID just write username https://tweeterid.com/ and get Twitter User ID in there
Reference: https://solutionspirit.com/open-page-twitter-application-android/
My answer builds on top of the widely-accepted answers from fg.radigales and Harry.
If the user has Twitter installed but disabled (for example by using App Quarantine), this method will not work. The intent for the Twitter app will be selected but it will not be able to process it as it is disabled.
Instead of:
getPackageManager().getPackageInfo("com.twitter.android", 0);
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=2343965036"));
You can use the following to decide what to do:
PackageInfo info = getPackageManager().getPackageInfo("com.twitter.android", 0);
if(info.applicationInfo.enabled)
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=2343965036"));
else
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/wrkoutapp"));
Just try this code snippet. It will help you.
//Checking If the app is installed, according to the package name
Intent intent = new Intent();
intent.setType("text/plain");
intent.setAction(Intent.ACTION_SEND);
final PackageManager packageManager = getPackageManager();
List<ResolveInfo> list = packageManager.queryIntentActivities(intent, PackageManager.MATCH_DEFAULT_ONLY);
for (ResolveInfo resolveInfo : list)
{
String packageName = resolveInfo.activityInfo.packageName;
//In case that the app is installed, lunch it.
if (packageName != null && packageName.equals("com.twitter.android"))
{
try
{
String formattedTwitterAddress = "twitter://user/" ;
Intent browseTwitter = new Intent(Intent.ACTION_VIEW, Uri.parse(formattedTwitterAddress));
long twitterId = <Here is the place for the twitter id>
browseTwitter.putExtra("user_id", twitterId);
startActivity(browseTwitter);
return;
}
catch (Exception e)
{
}
}
}
//If it gets here it means that the twitter app is not installed. Therefor, lunch the browser.
try
{
String twitterName = <Put the twitter name here>
String formattedTwitterAddress = "http://twitter.com/" + twitterName;
Intent browseTwitter = new Intent(Intent.ACTION_VIEW, Uri.parse(formattedTwitterAddress));
startActivity(browseTwitter);
}
catch (Exception e)
{
}
For me this did the trick it opens Twitter app if you have it or goes to web browser:
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/"+"USERID"));
startActivity(intent);
try {
Intent intent = new Intent(Intent.ACTION_VIEW,
Uri.parse("twitter://user?screen_name=[user_name]"));
startActivity(intent);
} catch (Exception e) {
startActivity(new Intent(Intent.ACTION_VIEW,
Uri.parse("https://twitter.com/#!/[user_name]")));
}
This answer was posted as an edit to the question Open page in Twitter app from other app - Android by the OP jbc25 under CC BY-SA 3.0.