I was looking for some way to launch Twitter app and open a specified page from my application, without webview.
I found the solution for Facebook here:
Opening facebook app on specified profile page
I need something similar.
[EDIT]
I've just found a solution:
try {
Intent intent = new Intent(Intent.ACTION_VIEW,
Uri.parse("twitter://user?screen_name=[user_name]"));
startActivity(intent);
} catch (ActivityNotFoundException e) {
startActivity(new Intent(Intent.ACTION_VIEW,
Uri.parse("https://twitter.com/#!/[user_name]")));
}
Based on fg.radigales answer, this is what I used to launch the app if possible, but fall back to the browser otherwise:
Intent intent = null;
try {
// get the Twitter app if possible
this.getPackageManager().getPackageInfo("com.twitter.android", 0);
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=USERID"));
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
} catch (Exception e) {
// no Twitter app, revert to browser
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/PROFILENAME"));
}
this.startActivity(intent);
UPDATE
Added intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK); to fix an issue where twitter was opening inside my app instead of as a new activity.
This worked for me: twitter://user?user_id=id_num
Open page on Twitter app from other app using Android in 2 Steps:
1.Just paste the below code (on button click or anywhere you need)
Intent intent = null;
try{
// Get Twitter app
this.getPackageManager().getPackageInfo("com.twitter.android", 0);
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=USER_ID"));
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
} catch () {
// If no Twitter app found, open on browser
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/USERNAME"));
}
2.intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=USER_ID"));
To get USER_ID just write username https://tweeterid.com/ and get Twitter User ID in there
Reference: https://solutionspirit.com/open-page-twitter-application-android/
My answer builds on top of the widely-accepted answers from fg.radigales and Harry.
If the user has Twitter installed but disabled (for example by using App Quarantine), this method will not work. The intent for the Twitter app will be selected but it will not be able to process it as it is disabled.
Instead of:
getPackageManager().getPackageInfo("com.twitter.android", 0);
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=2343965036"));
You can use the following to decide what to do:
PackageInfo info = getPackageManager().getPackageInfo("com.twitter.android", 0);
if(info.applicationInfo.enabled)
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=2343965036"));
else
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/wrkoutapp"));
Just try this code snippet. It will help you.
//Checking If the app is installed, according to the package name
Intent intent = new Intent();
intent.setType("text/plain");
intent.setAction(Intent.ACTION_SEND);
final PackageManager packageManager = getPackageManager();
List<ResolveInfo> list = packageManager.queryIntentActivities(intent, PackageManager.MATCH_DEFAULT_ONLY);
for (ResolveInfo resolveInfo : list)
{
String packageName = resolveInfo.activityInfo.packageName;
//In case that the app is installed, lunch it.
if (packageName != null && packageName.equals("com.twitter.android"))
{
try
{
String formattedTwitterAddress = "twitter://user/" ;
Intent browseTwitter = new Intent(Intent.ACTION_VIEW, Uri.parse(formattedTwitterAddress));
long twitterId = <Here is the place for the twitter id>
browseTwitter.putExtra("user_id", twitterId);
startActivity(browseTwitter);
return;
}
catch (Exception e)
{
}
}
}
//If it gets here it means that the twitter app is not installed. Therefor, lunch the browser.
try
{
String twitterName = <Put the twitter name here>
String formattedTwitterAddress = "http://twitter.com/" + twitterName;
Intent browseTwitter = new Intent(Intent.ACTION_VIEW, Uri.parse(formattedTwitterAddress));
startActivity(browseTwitter);
}
catch (Exception e)
{
}
For me this did the trick it opens Twitter app if you have it or goes to web browser:
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/"+"USERID"));
startActivity(intent);
try {
Intent intent = new Intent(Intent.ACTION_VIEW,
Uri.parse("twitter://user?screen_name=[user_name]"));
startActivity(intent);
} catch (Exception e) {
startActivity(new Intent(Intent.ACTION_VIEW,
Uri.parse("https://twitter.com/#!/[user_name]")));
}
This answer was posted as an edit to the question Open page in Twitter app from other app - Android by the OP jbc25 under CC BY-SA 3.0.
Related
There is a way of knowing the id of the specific twitter that you want to open, to be able to open it in the official app.
I remember I found it long ago, but I can not remember.
I think it was a similar thing, but I'm not remembering.
Intent appIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://...?tweet_id=" + id));
appIntent.setPackage("com.twitter.android");
For launching a twitter user feed:
Intent intent = null;
try {
// get the Twitter app if possible
this.getPackageManager().getPackageInfo("com.twitter.android", 0);
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=USERID"));
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
} catch (Exception e) {
// no Twitter app, revert to browser
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/USERID_OR_PROFILENAME"));
}
this.startActivity(intent);
I am creating an home replacement app for android(Launcher) and I want to place the sms , call, contacts ,gallery and browser apps in the home screen. How can I know the package name for them.
If the user is using a custom contact app as the default one , I need to get the package name of that one and not the android contact app.
How can I achieve this?Thanks.
You can use this code to get Intent to those thing. The problomatic one is the SMS one.
For sms:
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT) {
String defaultSmsPackageName = Telephony.Sms.getDefaultSmsPackage(ctx);
Intent lunchIntent;
if (defaultSmsPackageName != null) {
launchIntent = pm.getLaunchIntentForPackage(defaultSmsPackageName);
} else {
String SMS_MIME_TYPE = "vnd.android-dir/mms-sms";
launchIntent = new Intent(Intent.ACTION_MAIN);
launchIntent.setType(SMS_MIME_TYPE);
}
} else {
String SMS_MIME_TYPE = "vnd.android-dir/mms-sms";
launchIntent = new Intent(Intent.ACTION_MAIN);
launchIntent.setType(SMS_MIME_TYPE);
}
For call:
Intent intent = new Intent(Intent.ACTION_DIAL);
For browser:
Intent intent;
Intent queryIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("http://www.google.com"));
ActivityInfo af = queryIntent.resolveActivityInfo(pm, 0);
intent = new Intent(Intent.ACTION_MAIN);
intent.setClassName(af.packageName, af.name);
For photos:
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("content://media/internal/images/media"));
try {
context.startActivity(intent);
} catch (ActivityNotFoundException eee){
try {
intent = new Intent(Intent.ACTION_VIEW);
intent.setType(android.provider.MediaStore.Images.Media.CONTENT_TYPE);
} catch (Exception err){
Toast.makeText(context, "This app not supported in your device", Toast.LENGTH_LONG).show();
}
}
You could try getting the default launch activity for a specific Intent, for example for SMS you do an Intent with an sms:-URI, and from there check the 'default'-Activity its launching, on the way getting its package name and other details.
Get Preferred/Default app on Android
I am trying to open certain Facebook profile page in my android app with specific user ID.
My code opens facebook app if it is installed otherwise open webbrowser.
It works fine except when facebook app is installed and it is closed.
In that situation it just opens newsfeed page instead of the profile page. When the facebook app is open at background, it successfully redirect to desired profile page. How can I solve this ? Also is there an official facebook document which describes about the way to access facebook app URI ?
try{
this.getPackageManager()
.getPackageInfo("com.facebook.katana", 0); //Checks if FB is even installed.
final String facebookScheme = String.format("fb://profile/%s", user2FbID);
final Intent facebookIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(facebookScheme));
facebookIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_NO_HISTORY
| Intent.FLAG_ACTIVITY_CLEAR_WHEN_TASK_RESET);
startActivity(facebookIntent);
}catch (Exception e) {
String facebookScheme = "https://m.facebook.com/" + user2FbID;
Intent facebookIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(facebookScheme));
startActivity(facebookIntent);
}
Try this, Works for me
try
{
Intent followIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("fb://profile/<your profile_id>"));
startActivity(followIntent);
final Handler handler = new Handler();
handler.postDelayed(new Runnable()
{
#Override
public void run() {
Intent followIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("fb://profile/<your profile_id>"));
startActivity(followIntent);
}
}, 1000 * 2);
}
catch (Exception e)
{
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://www.facebook.com/<user_name>")));
String errorMessage = (e.getMessage()==null)?"Message is empty":e.getMessage();
Log.e("Unlock_ScreenActivity:FacebookAppNotFound" ,errorMessage);
}
This was happening with me too. Updated the Facebook app and it's solved now, seems it was something to do in with Facebook. It's working properly now.
Here's the code I'm using:
public static Intent getOpenFacebookIntent(Context context) {
try{
// open in Facebook app
context.getPackageManager().getPackageInfo("com.facebook.katana", 0);
return new Intent(Intent.ACTION_VIEW, Uri.parse("fb://page/<profile_id>"));
} catch (Exception e) {
// open in browser
return new Intent(Intent.ACTION_VIEW, Uri.parse("https://www.facebook.com/<profile_id>"));
}
}
I'm able to start Twitter application (if it exists on the phone), yet I can't find how to automatically display a specific user profile.
Something like this works for Google+:
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setClassName("com.google.android.apps.plus", "com.google.android.apps.plus.phone.UrlGatewayActivity");
intent.putExtra("customAppUri", "USER_ID");
Here is the Facebook way:
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("fb://profile/USER_ID"));
startActivity(intent);
There should be the same kind of solution when I start Twitter app ?
Intent intent = getPackageManager().getLaunchIntentForPackage("com.twitter.android");
intent.putExtra("WHAT_TO_PUT_HERE?", "USER_ID");
startActivity(intent);
try {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?screen_name=" + twitter_user_name)));
}catch (Exception e) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/#!/" + twitter_user_name)));
}
This is working fine with the new Twitter app. Solution provided by #Baptiste Costa didn't work for me.
try
{
// Check if the Twitter app is installed on the phone.
getPackageManager().getPackageInfo("com.twitter.android", 0);
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setClassName("com.twitter.android", "com.twitter.android.ProfileActivity");
// Don't forget to put the "L" at the end of the id.
intent.putExtra("user_id", 01234567L);
startActivity(intent);
}
catch (NameNotFoundException e)
{
// If Twitter app is not installed, start browser.
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/AndroTesteur")));
}
This is a very old question, I would like to shed some light into it. I have done it using either the user id or the username if that fails.
Intent intent;
try {
// Check if the Twitter app is installed on the phone.
context.getPackageManager().getPackageInfo("com.twitter.android", 0);
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=813679215195410432"));
} catch (Exception e) {
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/LynxMods"));
}
context.startActivity(intent);
How can I start an intent to open a Facebook application on a phone and navigate to the prefered page in Facebook?
I tried:
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setClassName("com.facebook.katana", "com.facebook.katana.ProfileTabHostActivity");
intent.putExtra("extra_user_id", "123456789l");
this.startActivity(intent);
Well, whatever I write to "1234567891", it is always navigating to my page. Always to me and not else.
How could I do this?
Here is the best and simple way to do it.
Just follow the code
public final void Facebook() {
final String urlFb = "fb://page/"+yourpageid;
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse(urlFb));
// If Facebook application is installed, use that else launch a browser
final PackageManager packageManager = getPackageManager();
List<ResolveInfo> list =
packageManager.queryIntentActivities(intent,
PackageManager.MATCH_DEFAULT_ONLY);
if (list.size() == 0) {
final String urlBrowser = "https://www.facebook.com/pages/"+pageid;
intent.setData(Uri.parse(urlBrowser));
}
startActivity(intent);
}
I had the exactly same problem, sent the user id but for some reason, my profile always opened instead of the friend's profile.
The problem is that if you pass the String of the Long object that represents the Facebook UID, or even a long primitive type, the intent won't be able to read it later. You need to pass a real Long.
So the complete code is:
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setClassName("com.facebook.katana", "com.facebook.katana.ProfileTabHostActivity");
Long uid = new Long("123456789");
intent.putExtra("extra_user_id", uid);
startActivity(intent);
Ok enjoy and hope this helps :-)
Maxim
try this code :
String facebookUrl = "https://www.facebook.com/<id_here>";
try {
int versionCode = getPackageManager().getPackageInfo("com.facebook.katana", 0).versionCode;
if (versionCode >= 3002850) {
Uri uri = Uri.parse("fb://facewebmodal/f?href=" + facebookUrl);
startActivity(new Intent(Intent.ACTION_VIEW, uri));
} else {
Uri uri = Uri.parse("fb://page/<id_here>");
startActivity(new Intent(Intent.ACTION_VIEW, uri));
}
} catch (PackageManager.NameNotFoundException e) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(facebookUrl)));
}
This solution won't work any more. The new version of the facebook app doesn't support anymore those kind of intents. See here the bug report
The new solution is to use the iPhone scheme mechanism (Yes, facebook decided to support the iPhone mechanism in Android instead of the implicit intent mechanism of Android).
So in order to open the facebook app with a user profile all you need to do is:
String facebookScheme = "fb://profile/" + facebookId;
Intent facebookIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(facebookScheme));
startActivity(facebookIntent);
If you are looking for other actions you can use the following page for all available actions (/you have to test it though, since I didn't find an official publication of facebook about this)