Is it possible to specify the filename of the generated *.apk through gradle? So that I automatically could get MyApp-1.0.0.apk instead of the default app-release.apk.
You can do this by adding the following line to your build.gradle file inside the android{...} part:
android.applicationVariants.all { variant ->
variant.outputFile = file("$project.buildDir/${defaultConfig.versionName}-${defaultConfig.versionCode}.apk")
}
Notes:
Everything inside the file(...) is arbitrary, of course
This code will output the *.apk to your project/module/build directory, no matter what path you've specified when Building the Signed APK.
The output-file will take the Name and Version-Code from your build.gradle file.
Android Studio may complain that it "cannot resolve symbol applicationVariants/defaultConfig" - ignore it. ;)
Got it working! Used this answer
android {
applicationVariants.all { variant ->
variant.outputs.each { output ->
output.outputFile = new File(
output.outputFile.parent,
output.outputFile.name.replace(".apk", "-${variant.versionName}.apk"))
}
}
}
Related
I am struggling with writing a task which will unzip an apk. I have several Build Variants, and I want to dynamically create a task for each of them.
applicationVariants.all { variant -> variant.outputs.all { output ->
def assembleTaskName = 'assemble' + variant.getName().capitalize()
def outputDir = new File(output.packageApplication.outputDirectory.toString() + "\\tmp")
def apk = output.outputFile //there is some code which generates correct apk name based on Build Variant
tasks.getByName(assembleTaskName).finalizedBy(task("unzip" + apk.name, type: Zip) {
outputDir.mkdirs()
from zipTree(apk)
into outputDir
})
}}
While this code creates tmp folder where I need it, apk doesn't get extracted, and this code seems to run on every build variant I have, but I only need it to run on the one I build right now. How can I do that?
I know that it is possible to specify APK name by using following command in Gradle build file:
setProperty("archivesBaseName", "something")
There are lots of questions here that deal with this. But doing this also results in APK that has flavor and build variant appended to the name. So using above command results in APK that's named something-dev-debug.apk.
Is there a way to completely specify file name without appending any suffixes. I already have appId in my flavors like this:
//...
productFlavors {
dev {
applicationId "com.myapp.dev"
setProperty("archivesBaseName", applicationId)
}
//...
So ideally I would like to produce APK named com.myapp.dev.apk without any extra suffixes or version numbers. Is this possible?
It seems that this shouldn't be done with setPropery. Rather you can define handler that changes output file name as final step by adding following code to the end of android { } section in gradle file:
applicationVariants.all { variant ->
variant.outputs.each { output ->
def file = output.outputFile
def appId = variant.applicationId
def fileName = appId +".apk"
output.outputFile = new File(file.parent, fileName)
}
}
I would like to change the APK output folder and this is what I used to do:
applicationVariants.all { variant ->
variant.outputs.all {
def filePath = "${rootProject.rootDir.absolutePath}/apks/${variant.name}"
println("My Path: " + filePath)
outputFileName = filePath
}
}
However, it didn't work in Gradle 4.1 (Android studio 3.0 preview). Instead of generating the folder as the path above, it generated the above path inside old debug folder like image below:
Does anyone have a solution for this? Thanks.
This is a workaround to keep the output path same after upgrade to gradle 4.x.
applicationVariants.all { variant ->
variant.outputs.all {
outputFileName = "../" + outputFileName
}
}
now apk is generated at platforms/android/build/outputs/apk/android-release.apk
From migration guide:
Using the Variant API to manipulate variant outputs is broken with the new plugin. It still works for simple tasks, such as changing the APK name during build time, as shown below:
android.applicationVariants.all { variant ->
variant.outputs.all {
outputFileName = "${variant.name}-${variant.versionName}.apk"
}
}
However, more complicated tasks that involve accessing outputFile objects no longer work. That's because variant-specific tasks are no longer created during the configuration stage. This results in the plugin not knowing all of its outputs up front, but it also means faster configuration times.
I had a similar issue, because I needed the output apk in a known folder and not in a folder depending on the computer user name. So I have fixed like this:
applicationVariants.all { variant ->
variant.outputs.all {
def apk = output.outputFile;
def newName = apk.name.replace(".apk", "-v" + variant.versionName + "-RELEASE.apk");
newName = newName.replace("-" + variant.buildType.name, "");
outputFileName = "./" + newName
}
}
With this I get the apk in:
".../outputs/apk/flavorName/buildTypeName/xxx.apk"
Hope it helps you.
Prior to Android plugin version 3.0.0-alpha4, I have been using the following for publishing different variants of my APKs to a specific file path:
def publish = project.tasks.create("publishAll")
android.applicationVariants.all { variant ->
def task = project.tasks.create("publish${variant.name}Apk", Copy)
task.from(variant.outputs[0].outputFile)
task.into(buildDir)
task.dependsOn variant.assemble
publish.dependsOn task
}
I originally got it from this answer from Xavier Ducrohet: Copying APK file in Android Gradle project
As of the new updates to Android Studio Preview which uses version 3.0.0-alpha4, variant.outputFile is deprecated. What is the new suggested way to achieve something like this?
EDIT:
Looks like there is no way to currently access the variant output file as pointed out here: https://developer.android.com/studio/preview/features/new-android-plugin-migration.html#variant_api
Looks like we'll have to wait until they introduce those apis
If you don't use abi splits next snippet works
project.afterEvaluate {
android.applicationVariants.all { variant ->
// create file where to copy
def backupFolder = rootProject.file("backup")
def backupFile = new File(backupFolder, String.format("%s_v%s.%d.apk", variant.flavorName, variant.versionName, variant.versionCode))
variant.outputs.all { output ->
Task copyAndRenameAPKTask = project.task("copyAndRename${variant.name.capitalize()}APK", type: Copy) {
from output.outputFile.getParent()
into backupFolder
include output.outputFileName
rename(output.outputFileName, backupFile.getName())
}
// if copyAndRenameAPKTask needs to automatically execute assemble before
copyAndRenameAPKTask.dependsOn(variant.assemble)
copyAndRenameAPKTask.mustRunAfter(variant.assemble)
// if assemble needs to automatically execute copyAndRenameAPKTask after
variant.assemble.finalizedBy(copyAndRenameAPKTask)
}
}
}
I have gradle task that depends on assembleRelease
sendReleaseCandidate.dependsOn assembleRelease
And I want to get resulted apk file path. From my task I've wrote:
def apk = android.applicationVariants.release.outputFile
But it doesn't work. What i'm doing wrong?
Thanks!
ps: android plugin 0.11.1, for now I stick with uri('./build/outputs/apk/<app_name>-release.apk').path but it seems aweful.
You can loop through the variants to find the one you need:
def apk = null
android.applicationVariants.all { variant ->
if ( (variant.name).equals("release") ) {
variant.outputs.each { output ->
apk = output.outputFile
}
}
}
println "Found output file: " + apk