I have 2 projects in Android Studio . I want to launch the activty of one of these projects in an other.
I searched a lot. Some says to create the library project of the project where the activity I want to launch is and then import this library in the other project.
However I don't even know how to create this library project since I want to create it from an existing project.
There is the option 'Import Module' , however i'm afraid it's modifying the whole project.
Help please
Thanks in advance
This is one way to do it
Intent i;
PackageManager manager = getPackageManager();
try {
i = manager.getLaunchIntentForPackage("com.exp.yourpackage");
if (i == null)
throw new PackageManager.NameNotFoundException();
i.addCategory(Intent.CATEGORY_LAUNCHER);
startActivity(i);
This will call the launcher activity of the other application. It is possible to start any activity you want with that method
I don't know why but the solution
Intent i;
PackageManager manager = getPackageManager();
try {
i = manager.getLaunchIntentForPackage("com.exp.yourpackage");
if (i == null)
throw new PackageManager.NameNotFoundException();
i.addCategory(Intent.CATEGORY_LAUNCHER);
startActivity(i);
didn't work for me. Maybe I used it in a wrong way, I don't know.
What works is using
<intent-filter>
in the manifest file of the app we want to trigger and then call the action name of the
<intent-filter>
in the main application.
All details here : http://hmkcode.com/android-start-another-activity-of-another-application/
Related
I have an android application that requires VPN. My users will be using Galaxy Note 3's and will be using the built in "VPN Client" (com.ipsec.vpnclient). I need to find a way to launch this application from my application, in the instance of the VPN dropping. I've already figured out a way to determine if the VPN dropped, but I still need a way to launch the application.
ANSWER:
Thanks to help from #Muthu I was able to get it working with the following method.
final Intent intent = new Intent("android.intent.action.VIEW");
intent.setComponent(new ComponentName("com.ipsec.vpnclient", "com.ipsec.vpnclient.MainActivity"));
EDIT:
To add to the confusion, I am easily able to add a shortcut to the activity (com.ipsec.vpnclient.MainActivity) via another Launcher like ADW or Nova. I also tried using com.ipsec.vpnclient.MainActivity instead of com.ipsec.vpnclient in the method below, to no avail.
Intent intent = getPackageManager().getLaunchIntentForPackage("com.ipsec.vpnclient");
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
The above method works with other packages, but I can't seem to get this one to launch.
Here is the application when viewed in Android System Info.
Any ideas on how to launch this application programmatically?
You can Start any installed application by using intent. in your case like this
Intent LaunchVPN = getPackageManager().getLaunchIntentForPackage("com.ipsec.vpnclient");
startActivity( LaunchVPN );
Edit
You can open pre installed apps that can be found inside settings page by
final Intent i = new Intent("android.intent.action.VIEW");
i.setComponent(new ComponentName("com.android.settings","com.android.settings.InstalledAppDetails"));
startActivity(i);
I am new to Android. Say, I open an app and I would like to open another App after clicking a button. How can I accomplish this task? Would appreciate if you can provide me some tutorial on this.
Intent intent = new Intent();
intent.setClassName("**package.name**", "**package.name.LauncherActivityName**");
startActivityForResult(intent,REQUEST_CODE);
You need to know the package and class names of the activity to call
Intent i = new Intent(Intent.ACTION_MAIN);
PackageManager manager = getPackageManager();
i = manager.getLaunchIntentForPackage("app package name");
i.addCategory(Intent.CATEGORY_LAUNCHER);
startActivity(i);
Use this code:
Intent launchIntent = getPackageManager().getLaunchIntentForPackage("com.example.package");
startActivity(launchIntent);
The app you want to launch must be on the device.
Intent appIntent = getPackageManager().getLaunchIntentForPackage("your app package name ");
startActivity(appIntent );
If the other application is a pre-packaged application mean, this tutorial may help you.
If the other application is going to be your application, then you need to learn Implicit Intent tutorials.
Also include the activity of the other application which you are planning to call in the Manifest file of the calling package also.
I need to allow user to draw/sketch/paint something. There are already many apps(like Skitch, I will use this as an example) that accomplish this task. So I don't want to re-invent the wheel.
In Android, theoretically, we can launch other activity by intent. This is sort of like "pipe" in Unix.
The problem is, I don't know how to get the information for launching Skitch.
To integrate Skitch in my app, I need to know the Action it supports, the returning intent (if any) when it finishes.
I installed Skitch, photoshop, and lots of other touch drawing apps in my device, but this code doesn't work :
Uri data = Uri.fromFile(file);
Intent i = new Intent(Intent.ACTION_EDIT);
i.setData(data);
i.setType("image/*");
startActivityForResult(i, ACTIVITY_DRAW);
I can launch Skitch from my app in the following way: but obviously I can't get any returned result this way(code from here).
Intent i = new Intent(Intent.ACTION_MAIN);
PackageManager manager = getPackageManager();
i = manager.getLaunchIntentForPackage("com.evernote.skitch");
i.addCategory(Intent.CATEGORY_LAUNCHER);
startActivity(i);
My question: Is there a standard way to find information for launching a third party app?
Is this site the only way to share/get such information?
Or if you have any suggestions for my problem, please help me.
Thank you!
As you might already know how to call another application Activity from your app ..this way Mentioned Here.
Intent intent = new Intent(Intent.ACTION_RUN);
intent.setComponent(new ComponentName("<packet name>", "<class name>"));
List list = packageManager.queryIntentActivities(intent, packageManager.COMPONENT_ENABLED_STATE_DEFAULT);
if(list.size() > 0)
{
Log.i("Log", "Have application" + list.size());
startActivity(intent);
}
else
{
Log.i("Log", "None application");
}
All your require is Mainly Two Things to call any Activity
1) Package Name of that Activity
2) Activity Class Name
These two informations only can be available if they are opensource or made free to use .. like Zxing,Google Maps Application.
There is another way to start an application activity like,
Intent intent = new Intent();
intent.setAction(Intent.ACTION_CALL);
intent.setData(Uri.parse("tel:" + numberField.getText())); // set the Uri
startActivity(intent);
For this way to use need to know the correct Action for the Activity you want to call and the Correct parameter to pass with.
And again,These information only can be available if they are opensource or made free to use .. like Facebook and Gmail apps to share and post messages.
So If you are searching for anything like which can tell you what you will need to pass to call any specific comercial apps in your device, you wont find it directly.
It's an old question but perhaps it could help somebody to know that Sony's AppXplore application (free) shows the package and name of the activities of every app installed on your device, so you can eventually use them to do explicit Intents.
hi Its been 2 days looking for this simple problem. I want to launch Android own launcher from my application EVEN if its not set as default.
final PackageManager packageManager=getPackageManager();
Intent intent = packageManager.getLaunchIntentForPackage("com.android.launcher");
this return null for Android own launcher but if I try custom launcher is give me successfully
Found the solution, after investigating source code of getLaunchIntentForPackage. As per documentation,
The current implementation will look first for a main activity in the
category CATEGORY_INFO, next for a main activity in the category
CATEGORY_LAUNCHER, or return null if neither are found.
So, the function don't look for CATEGORY_HOME, i rewrote it in following way, it worked perfectly.
Intent intentToResolve = new Intent(Intent.ACTION_MAIN);
intentToResolve.addCategory(Intent.CATEGORY_HOME);
intentToResolve.setPackage("com.android.launcher");
ResolveInfo ri = getPackageManager().resolveActivity(intentToResolve, 0);
if (ri != null)
{
Intent intent = new Intent(intentToResolve);
intent.setClassName(ri.activityInfo.applicationInfo.packageName, ri.activityInfo.name);
intent.setAction(Intent.ACTION_MAIN);
intent.addCategory(Intent.CATEGORY_HOME);
startActivity(intent);
}
Are you sure the default Google Android Launcher being installed on your device? If not, then it's truly NULL.
I need simple start an application from my code, like Skype, or other one.
I read some thread, on the internet, but I haven't solution.
I tried this methode:
Intent startApp = new Intent("com.android.gesture.builder");
startActivity(startApp);
I wrote this in try/catch blokk, and the LogCat told me: ApplicationNotFound exception handled by Intent. I read the "Hello" tutorial on the Android Developers site, but it's too comlicated, to my solution...
I can't register this application starting activity to my manifest file.
I think I need to implement a new class, that extends from Activity, and implement, the code above, and try again?
Please help me, how can I start other application from my main activity easy...
You were nearly there!:
You just need to supply the package and class of the app you want.
// Try
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setComponent(new ComponentName("com.htc.Camera", "com.htc.Camera.Camera"));
startActivity(intent);
// catch not found (only works on HTC phones)
ComponentName
I also just saw you can do it a second way:
PackageManager packageManager = getPackageManager();
startActivity(packageManager.getLaunchIntentForPackage("com.skype.android"));
See: SOQ Ref