Develop Reference

How to get split string with special characters in android?

I have a string named namely "-10.00","-100.00","-1000.00". I want to get value like "10","100","1000" from that string. I have tried to get substring but did not able to get.
code i have tried
String amount = "-10.00";
String trimwalletBalance = amount.substring(0, amount.indexOf('.'));
From above i only get "-10".

String trimwalletBalance = amount.substring(1, amoun.indexOf("."));

Its very simple.
Do it like String trimwalletBalance = amount.substring(1, amount.indexOf('.'));
Instead of position 0, You should get substring from position 1

Convert it into integer and then name it positive:
String amount = "-10.00";
int amountInt = (int) Double.parseDouble(amount);
if(amountInt<0)amountInt*=-1;

Try
String amount = "-10.00";
int value = (int) Double.parseDouble(amount);
if(value < 0) value *= -1;
//value will be 10
OR
String text = amount.substring(1, amount.indexOf('.'));

Remove digits which are in the decimal place

I get a double value (eg. -3.1234) which contains a value in decimals (0.1234 in this case). I want to remove the value in decimal value (in this case I wanted the value -3). How do I do it? I know how to remove the decimal if the decimal only has 0, but in this case I don't have the decimal value as 0.
Anyways here is the code for that:
DecimalFormat format = new DecimalFormat();
format.setDecimalSeparatorAlwaysShown(false);
Double asdf = 2.0;
Double asdf2 = 2.11;
Double asdf3 = 2000.11;
System.out.println( format.format(asdf) );
System.out.println( format.format(asdf2) );
System.out.println( format.format(asdf3) );
/*
prints-:
2
2.11
2000.11
*/

If you just want to print it :
String val = String.format("%.0f", 2.11)
// val == "2"
If you want to keep the double type but without decimals :
double val = Math.floor(2.11);
// val == 2.000
If you don't care about type you can cast the double into int :
int val = (int) 2.11;
// val == 2
//double as object
int val = myDouble.integerValue();

You can simply use the intValue() method of Double to get the integer part.

You can cast it to int
int i=(int)2.12
System.out.println(i); // Prints 2

Round up decimal value & convert it into integer;
Integer intValue = Integer.valueOf((int) Math.round(doubleValue)));

http://www.studytonight.com/java/type-casting-in-java check out type conversion in java
double asdf2 = 2.11;
int i = (int)asdf2;
System.out.println(asdf2);
System.out.println(i);
Output:
2.11`
2

number format exception invalid int

I have to add values to my sq lite from the list view. In my list view there are two edit texts and text view. I just want to get value from each edit text and multiply it to the corresponding text view value. when I am running the app, I need not to enter data to every edit text. due to this I am ending with a "number format exception : invalid int". From other examples I can understand that multiplication on null value may cause the error. how can I skip the null value contained edit texts from the iteration?
this is my code
protected void InsertDb() {
// TODO Auto-generated method stub
DatabaseHelper databasecontroller = new DatabaseHelper(Orders.this);
List<Map<String, String>> data = null;
data = new ArrayList<Map<String, String>>();
if(list != null){
for(int i = 0; i< list.getChildCount();i++){
View vie = list.getChildAt(i);
EditText ed1= (EditText) vie.findViewById(R.id.cases);
EditText ed2 = (EditText) vie.findViewById(R.id.pcs);
String qty = ed1.getText().toString();
TextView tv = (TextView)findViewById(R.id.srp);
String imsrpv= tv.getText().toString();
float srps = Float.valueOf(imsrpv);
int qtys = Integer.valueOf(qty);
float amts = srps * qtys;
String amount = Float.toString(amts);
datanum.put("A",qty );
datanum.put("B",ed2.getText().toString() );
datanum.put("L", amount);
Log.d("value of amnt",amount);
databasecontroller.entercustdetails(datanum);
}
}
Log.v("compleated", data.toString());
}
Thanks in advance..

Check either returning value from edittext is a proper number or it is not null.if a null value is there it may give exeception of numberformat.you have to handle this.
if both are correct then you can also you
float srps=0.0;
int qtys=0;
try
{
srps = Float.valueOf(imsrpv);
qtys = Integer.valueOf(qty);
}
catch (NumberFormatException e)
{
srps =//Default value you want;
qtys =//Default value you want;
}
Hope it works..

Your problem is not how You have parsed the values. For explanation:
parseFloat(), parseInt() will return a primitive type of int and float and valueOf() returns a new type of Integer and Float. Also, parseInt(), parseFloat() will recognize plus and minus signs, valueOf() doesn´t. That´s the difference between these two types/methods. Your problem seems to be, that the value is empty and You can simply get rid of this by:
//set a default float and int
float srps = 0.0;
int qtys = 0;
//now parse the values by checking if the strings are not null or empty
if(imsrpv!=null&&!imsrpv.isEmpty()){
srps = Float.valueOf(imsrpv);
}
if(qty!=null&&!qty.isEmpty()){
qtys = Integer.valueOf(qty);
}
Like I said, if these values have a plus or minus sign and it is important for Your needs, You should use the parse method. Also, You don´t need a new Integer or Float type, so more correct is using parse() method.

Convert String to double

Is there way to convert a string to double. This is how i did.
String s = b.getText().toString();
double d = Double.parseDouble(s);
It gives NumberFormatException

Try this
String s = b.getText().toString();
double d = Double.valueOf(s.trim()).doubleValue();

You are probably starting off with a zero-length string. Check the length before you parse it. It also wouldn't hurt to catch NumberFormatException, although that shouldn't be problem if you have android:inputType="number" in the view's layout.
double d = 0;
CharSequence cs = b.getText();
if(cs != null && cs.length() > 0) {
d = Double.parseDouble(cs.toString());
}

i have a similar problem.
for correct formatting EditText text content to double value i use this code:
try {
String eAm = etAmount.getText().toString();
DecimalFormat dF = new DecimalFormat("0.00");
Number num = dF.parse(eAm);
mPayContext.amount = num.doubleValue();
} catch (Exception e) {
mPayContext.amount = 0.0d;
}
this is independet from current phone locale and return correct double value.
hope it's help;

Why does Integer.parseInt("53.6") fail?

I got an exception "Unable to parse 53.6 as an integer". What is the proper format?
double dbval;
double temp_val=12;
double p = 1.8;
double fvalue =p;
temp_val = temp_val * fvalue;
temp_val = (temp_val + 32);
String dbcal1=Double.toString(temp_val);
dbval = Integer.parseInt(dbcal1);
System.out.println("dbval"+dbval);

You can't parse 53.6 as an integer because it is not an integer.
If you are just trying to change temp_val to an integer there is no need to convert it to a string and back. You can cast use a cast instead:
int result = (int)temp_val;