Develop Reference

string to int,causing app to stop

final EditText ed7 = (EditText)findViewById(R.id.Recycleweight);
final EditText ed8 = (EditText)findViewById(R.id.Nonweight);
final EditText ed11 = (EditText)findViewById(R.id.totalweight);
recy_wt=ed7.getText().toString();
nonrec_wt=ed8.getText().toString();
total_wt=ed11.getText().toString();
int rec = Integer.parseInt(recy_wt);
int nrec = Integer.parseInt(nonrec_wt);
ed11.setText(String.valueOf(rec + nrec));
The input I am giving is,ed7=10kg and ed8=20kg,and it will be displayed in ed11
as 30kg,but the app is unfortunately stopping.
If I am not writing 'kg',it is correctly displaying the totalwt.
But I want to display 'kg' in the answer.

There is already a solution here (can't flag as duplicate)
Find and extract a number from a string
Extract the digit part from the string and then parse it to an integer

Try this out
String regexp = "/^[0-9]+kg$/g"; //It accepts only '<number><kg>' format
int weight = 0;
if (recy_wt.matches(regexp) && nonrec_wt.matches(regex)) {
//It's valid input
Scanner scan = new Scanner(recy_wt);
weight = Integer.parseInt(scan.findInLine("\\d+(\\.\\d+)?"));
Scanner scan = new Scanner(nonrec_wt);
weight += Integer.parseInt(scan.findInLine("\\d+(\\.\\d+)?"));
}
ed11.setText(String.valueOf(weight + "Kg"));

If the only possible unit is kg, then try like this
final EditText ed7 = (EditText)findViewById(R.id.Recycleweight);
final EditText ed8 = (EditText)findViewById(R.id.Nonweight);
final EditText ed11 = (EditText)findViewById(R.id.totalweight);
int weight = 0;
recy_wt=ed7.getText().toString();
nonrec_wt=ed8.getText().toString();
recy_wt = recy_wt.replace("kg","");
nonrec_wt = nonrec_wt.replace("kg","");
weight += Integer.parseInt(recy_wt) + Integer.parseInt(nonrec_wt);
ed11.setText(weight + "kg");

This will work:-
recy_wt=ed7.getText().toString();
nonrec_wt=ed8.getText().toString();
String n=recy_wt.replace("kg","");
String n1=nonrec_wt.replace("kg","");
weight += Integer.parseInt(n) + Integer.parseInt(n1);
ed11.setText(weight + "kg");
storing the replaced one in a string and then converting to int will help.

Android - String to Integer then Integer to increase the String value - Json

String value comes like float value, then I need to convert it into integer after that I want increment integer value means string will automatically get new string from j-son. How to handle this problem ?

Try this :
String stringValue = "2.3";
int intValue = Integer.valueOf(stringValue);
intValue++;
stringValue = String.valueOf(intValue);
I don't my IDE with me so maybe you should have to add try/catch etc.

From String to float use
float f = Float.parseFloat("1235.00"); // replace with your string
From String to int use
int i = Integer.parseInt("741125"); // replace with your string
From int or float to String use
String s = String.valueOf(yourIntOrFloat);
For increment use
i++;
or
i=i+1;

How to show it point after two digit in java?

I am Android developer.I get from web service result 45.0000.i am stored ArrayList.But i want show it point after two digit only.
Example output 45.00 only .Please give me solution.

Use DecimalFormat class to achieve this.
DecimalFormat df=new DecimalFormat("##.##");
String formate = df.format(value);
double finalValue = (Double)df.parse(formate) ;

you can use String.format, it returns a formatted string using the specified format string and arguments
String.format("$%.2f", value);
also String.format uses your Locale
int index = 0;
for (; index < yourList.size (); index++) {
String tmpvalue = yourList.get(index);
String conValue = String.format("$%.2f", Float.parse(tmpvalue));
yourList.set(index, conValue);
index++;
}

How to split this String?

I want to split this string
String info = "0.542008835 meters height from ground";
from this i want to get only two decimals like this 0.54.
by using this i am getting that
String[] _new = rhs.split("(?<=\\G....)");
But i am facing problem here, if string does't contain any decimals like this string
String info = "1 meters height from ground";
for this string i am getting those characters upto first 4 in the split string like 1 me.
i want only numbers to split if it has decimals, How to solve this problem.

if(info.contains("."))
{
String[] _new = rhs.split("(?<=\\G....)");
}

I think you can check by white space after first value. see this
If you get the space then get first character only.
For checking if a string contains whitespace use a Matcher and call it's find method.
Pattern pattern = Pattern.compile("\\s");
Matcher matcher = pattern.matcher(s);
boolean found = matcher.find();
If you want to check if it only consists of whitespace then you can use String.matches:
boolean isWhitespace = s.matches("^\\s*$");

You could use a regex to do this as an alternative to Deepzz's method, this will handle the case where there is a '.' in the later part of the String, I've included an example below. It's not clear from your question is you actually want to remaining part of the String, but you could add a second group to the reg ex to capture this.
public static void main(String[] args) {
final String test1 = "1.23 foo";
final String test2 = "1 foo";
final String test3 = "1.234 foo";
final String test4 = "1.234 fo.o";
final String test5 = "1 fo.o";
getStartingDecimal(test1);
getStartingDecimal(test2);
getStartingDecimal(test3);
getStartingDecimal(test4);
getStartingDecimal(test5);
}
private static void getStartingDecimal(final String s) {
System.out.print(s + " : ");
Pattern pattern = Pattern.compile("^(\\d+\\.\\d\\d)");
Matcher matcher = pattern.matcher(s);
if(matcher.find()) {
System.out.println(matcher.group(1));
} else {
System.out.println("Doesn't start with decimal");
}
}

Assuming the number is always the first part of the string:
String numStr = rhs.split(" ")[0];
Double num = Double.parseDouble(numStr);
After that you can use the String Formatter to get the desired representation of the number.

This will work when you know the String near the numbers, with int and double numbers as well.
String a ="0.542008835 meters height from ground";
String b = a.replace(" meters height from ground", "");
int c = (int) ((Double.parseDouble(b))*100);
double d = ((double)c/100);

int to String in Android

I get the id of resource like so:
int test = (context.getResourceId("raw.testc3"));
I want to get it's id and put it into a string. How can I do this? .toString does not work.

String testString = Integer.toString(test);

Or you can use Use
String.valueOf()
eg.
int test=5;
String testString = String.valueOf(test);

Very fast to do it if you dnt remember or dnt have time to type long text :
int a= 100;
String s = ""+a;

What about:
int a = 100;
String s = String.format("%d", a);