Please tell me why am I getting this error?
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String lineEnd = "rn";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable = 0, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
String urlString = "http://thinksl.com/taughtable/audiopost.php";
try
{
//------------------ CLIENT REQUEST
FileInputStream fileInputStream = new FileInputStream(new File(path) );
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
conn.setRequestProperty("userfile",path);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"userfile\";filename=\"" +path+ "\"" + lineEnd);
Log.e("Debug", "Filename: " +path);
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
Log.e("Debug","File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.e("Debug", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("Debug", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("Debug","Server Response "+str);
}
inStream.close();
}
catch (IOException ioex){
Log.e("Debug", "error: " + ioex.getMessage(), ioex);
}
Log cat
Server Response
{"result":0,"post":[],"files":[],"filename":null,"message":"There was
an error uploading the file, please try again!"}
Use following method to upload audio file to server.
private String uploadAudio(final String filePath) {
String extension = filePath.substring(filePath.lastIndexOf("."));
Log.e(extension);
String response = null;
String final_upload_filename = "sample_audio"+ extension;
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "---------------------------14737809831466499882746641449";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
try {
FileInputStream fileInputStream = new FileInputStream(new File(filePath));
URL url = new URL("http://thinksl.com/taughtable/audiopost.php");
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true);
conn.setDoOutput(true);
conn.setUseCaches(false);
conn.setChunkedStreamingMode(1024);
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("uploaded_file", final_upload_filename);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"userfile\"; filename=\"" + final_upload_filename + "\"" + lineEnd);
dos.writeBytes("Content-Type: application/octet-stream" + lineEnd);
dos.writeBytes(lineEnd);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
fileInputStream.close();
dos.flush();
dos.close();
InputStream is = conn.getInputStream();
ByteArrayOutputStream baos = new ByteArrayOutputStream();
int bytessRead;
byte[] bytes = new byte[1024];
while ((bytessRead = is.read(bytes)) != -1) {
baos.write(bytes, 0, bytessRead);
}
byte[] bytesReceived = baos.toByteArray();
baos.close();
is.close();
response = new String(bytesReceived);
Log.e("Server Response" + response);
} catch (MalformedURLException ex) {
Log.e("Debug", "error: " + ex.getMessage(), ex);
} catch (IOException ioe) {
Log.e("Debug", "error: " + ioe.getMessage(), ioe);
}
return response;
}
I hope it helps!
Why don't you try like this,
try {
HttpClient httpClient = new DefaultHttpClient();
String url = "http://thinksl.com/taughtable/audiopost.php";
HttpPost httppost = new HttpPost(url);
MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart("file", new FileBody(new File(path)));
reqEntity.addPart("filename", final_upload_filename);
httppost.setEntity(reqEntity);
HttpResponse response = httpClient.execute(httppost);
BufferedReader reader = new BufferedReader(new InputStreamReader(
response.getEntity().getContent(), "UTF-8"));
String sResponse;
StringBuilder s = new StringBuilder();
while ((sResponse = reader.readLine()) != null) {
s = s.append(sResponse);
}
System.out.println("Response: " + s);
Log.e(TAG, "Response: " + s);
status = "" + s;
} catch (Exception e) {
e.printStackTrace();
}
Related
I'm uploading a file and want to display a progress dialog to see the upload progress. I already included a horizontal dialog which works incorrectly, because it goes to 100% in 1 second and then it waits (because it's still uploading).
I used the following function for uploading:
private void doFileUpload(String selectedPath){
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
String urlString = "https://xxxxxxxxxx.com";
try
{
//------------------ CLIENT REQUEST
File f = new File(selectedPath);
FileInputStream fileInputStream = new FileInputStream(f);
//calculate size of file
wholeFilesize = f.length(); //returns the length in Bytes
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"upfile\";filename=\"" + selectedPath + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
totalReadFilesize+=bytesRead;
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
int progress = (int)((totalReadFilesize*100)/(wholeFilesize));
//Log.i("Progress: ", (int)((totalReadFilesize*100)/(wholeFilesize))+"");
dialog.setProgress(progress);
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
//publishProgress(100);
Log.i("Size: ", wholeFilesize+"");
Log.i("Bytes read: ", totalReadFilesize+"");
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
Log.e("Debug","File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.e("Debug", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("Debug", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("Debug","Server Response "+str);
JSONObject jsonObj = new JSONObject(str);
//String status=(String) jsonObj.get("status");
Log.i("TEST", (String) jsonObj.get("message"));
uploadResultMessage = (String) jsonObj.get("message");
Log.i("TEST", uploadResultMessage);
}
inStream.close();
}
catch (IOException ioex){
Log.e("Debug", "error: " + ioex.getMessage(), ioex);
} catch (JSONException e) {
e.printStackTrace();
}
}
Does someone know, how should I modify the code to see the real progress of the file, which is being uploaded? I find it strange, because I'm doing the same as the user in his doInBackground() in this thread.
i want to send file from our app to sever through http post method.
My code is looking like as fallows
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String existingFileName = Environment.getExternalStorageDirectory().getAbsolutePath()
+ "/TamTrack/TamTrackDetails.xml";
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
String urlString = "http://192.158.1.7/Geo/myfilename";
try
{
//------------------ CLIENT REQUEST
FileInputStream fileInputStream = new FileInputStream(new File(existingFileName) );
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + existingFileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
//while (bytesRead > 0)
Log.v("info",".size."+bytesRead);
for(int n1=0;n1<bytesRead;n1++)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
Log.v("info","File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.v("info", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.v("info", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.v("info","Server Response "+str);
}
inStream.close();
}
catch (IOException ioex)
{
Log.v("info", "error: " + ioex.getMessage(), ioex);
}
return null;
It is working fine.but empty file is created in server.
If any one know the solution ,please help me .
Thanks in advance.
Try this code. It is using a class "SimpleMultipartEntity" using which you can easily send the file.
I'd prefer using Apache Http commons, it is part of android. I think this is a much simpler and cleaner approach. You need to do something like this:
AndroidHttpClient client = AndroidHttpClient.newInstance("useragent string");
URI uri = "something";
File file = new File("/tmp/data");
HttpPost post = new HttpPost(uri);
post.setEntity(new FileEntity(file, "text/html"));
HttpResponse httpResponse = client.execute(post);
int statusCode = httpResponse.getStatusLine().getStatusCode();
I'm trying to upload more than one image taken from the camera. I call the camera via Intent:
public void TakePicture(int actionCode)
{
Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
try
{
photo[0] = createTemporaryFile("spot", ".jpg");
}
catch(Exception e)
{
Log.v("ERROR SD!!", "Can't create file to take picture!");
Toast.makeText(this, "Please check SD card! Image shot is impossible!", 10000);
}
fileUri = Uri.fromFile(photo[0]);
intent.putExtra(MediaStore.EXTRA_OUTPUT, fileUri);
startActivityForResult(intent, CAPTURE_IMAGE_ACTIVITY_REQUEST_CODE);
}
And then I upload it to a PHP server:
public void UploadImg()
{
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
// String exsistingFileName = "/sdcard/prueba.png"; --> Used for local files!!
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String urlString = "http://myUrl.com/uploadimg.php";
try
{
FileInputStream fileInputStream = new FileInputStream(photo[0].toString());
// Open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true);
conn.setDoOutput(true);
conn.setUseCaches(false);
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + photo[0] +"\"" + lineEnd);
dos.writeBytes(lineEnd);
// Create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// Read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// Send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Close streams
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex) { Log.e("MediaPlayer", "error: " + ex.getMessage(), ex); }
catch (IOException ioe) { Log.e("MediaPlayer", "error: " + ioe.getMessage(), ioe); }
try {
inStream = new DataInputStream (conn.getInputStream());
String str;
while ((str = inStream.readLine()) != null)
{
System.out.println("Server Response" + str);
}
inStream.close();
}
catch (IOException ioex) { Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex); }
}
I save 3 different images: photo[0], photo[1] and photo[2]. The problem is that when I take, for example, two pictures, it only uploads one of them and with size = 0.
In the code of the UploadImg() I show only the photo[0], but in the 'real' code I use a for loop after the first try so that it upload all of the images taken.
Any idea of what am I doing wrong?
Thank you very much in advance!
I've already solved my problem! I did the following: Instead of saving the photo File, I save the it in a String with the location of the image.
if (requestCode == CAPTURE_IMAGE_ACTIVITY_REQUEST_CODE) {
if (resultCode == RESULT_OK) {
for (int u = 0; u <= 2; u++)
{
if (savedImgs[u].equals(""))
{
// Saving important info to be used later
imgs = u + 1;
savedImgs[u] = photo.toString();
break;
}
} ...
And then, when uploading the images to the server, I make a for loop like this:
public void UploadImg()
{
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
// String exsistingFileName = "/sdcard/prueba.png"; --> Used for local files!!
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String urlString = "http://myUrl.com/uploadimg.php";
for (int n = 0; n < imgs; n++)
{
try
{
FileInputStream fileInputStream = new FileInputStream(savedImgs[n]);
// Open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true);
conn.setDoOutput(true);
conn.setUseCaches(false);
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + savedImgs[n] +"\"" + lineEnd);
dos.writeBytes(lineEnd);
// Create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// Read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// Send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Close streams
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex) { Log.e("MediaPlayer", "error: " + ex.getMessage(), ex); }
catch (IOException ioe) { Log.e("MediaPlayer", "error: " + ioe.getMessage(), ioe); }
try {
inStream = new DataInputStream (conn.getInputStream());
String str;
while ((str = inStream.readLine()) != null)
{
System.out.println("Server Response" + str);
}
inStream.close();
}
catch (IOException ioex) { Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex); }
}
}
I want to upload video on specific server in Android.
Is is possible ?
How I can achieve this ?
Thanks.
Had the same issue some time ago. Here's a code.
public static int upLoad2Server(String sourceFileUri)
{
String upLoadServerUri = "your remote server link";
// String [] string = sourceFileUri;
String fileName = sourceFileUri;
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
String responseFromServer = "";
File sourceFile = new File(sourceFileUri);
if (!sourceFile.isFile()) {
Log.e("Huzza", "Source File Does not exist");
return 0;
}
try { // open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
conn = (HttpURLConnection) url.openConnection(); // Open a HTTP connection to the URL
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("uploaded_file", fileName);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\""+ fileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
bytesAvailable = fileInputStream.available(); // create a buffer of maximum size
Log.i("Huzza", "Initial .available : " + bytesAvailable);
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("Upload file to server", "HTTP Response is : " + serverResponseMessage + ": " + serverResponseCode);
// close streams
Log.i("Upload file to server", fileName + " File is written");
fileInputStream.close();
dos.flush();
dos.close();
} catch (MalformedURLException ex) {
ex.printStackTrace();
Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
} catch (Exception e) {
e.printStackTrace();
}
//this block will give the response of upload link
try {
BufferedReader rd = new BufferedReader(new InputStreamReader(conn
.getInputStream()));
String line;
while ((line = rd.readLine()) != null) {
Log.i("Huzza", "RES Message: " + line);
}
rd.close();
} catch (IOException ioex) {
Log.e("Huzza", "error: " + ioex.getMessage(), ioex);
}
return serverResponseCode; // like 200 (Ok)
} // end upLoad2Server
I use this to upload the video to php server, when i try to upload the image ,it was working fine, but when i tried to upload the Video the following error occur,
"02-22 18:22:35.588: ERROR/dalvikvm-heap(780): Out of memory on a 14680278-byte allocation."
***
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String exsistingFileName = "/sdcard/Video/dance.wmv";
// Is this the place are you doing something wrong.
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
String urlString = "http://172.17.0.146/viddygo/upload.php";
try
{
//------------------ CLIENT REQUEST
Log.e("MediaPlayer","Inside second Method");
FileInputStream fileInputStream = new FileInputStream(new File(exsistingFileName) );
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + exsistingFileName +"\"" + lineEnd);
dos.writeBytes(lineEnd);
Log.e("MediaPlayer","Headers are written");
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
BufferedReader in = new BufferedReader(
new InputStreamReader(
conn.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null)
tv.append(inputLine);
// close streams
Log.e("MediaPlayer","File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.e("MediaPlayer", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("MediaPlayer", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("MediaPlayer","Server Response"+str);
}
inStream.close();
}
catch (IOException ioex){
Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex);
}
can anyone suggest some idea to solve this.
I think error happened in follow line because DataOutputStream size is exceeds VM budget when you write
dos.write(buffer, 0, bufferSize);