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How to get a random value from a string array without repetition?

How to get a random value from a string array in android without repetition?
I have array in String.xml file as below -
<string-array name="msg">
<item>Cow</item>
<item>Pig</item>
<item>Bird</item>
<item>Sheep</item>
</string-array>
I am selecting random string by using following code -
String[] array = Objects.requireNonNull(context).getResources().getStringArray(R.array.msg);
String Msg = array[new Random().nextInt(array.length)];
Can anyone help me please? Thanks is advance...!

Can you just do something like this:
Collections.shuffle(copyOfArray);
Then loop through that?
for (int i = 0; i < copyOfArray.size(); i++) {
println(copyOfArray.get(i))
}

try this -
array = Objects.requireNonNull(context).getResources().getStringArray(R.array.msg);
//String msg = array[new Random().nextInt(array.length)];
LinkedList<String> myList = new LinkedList<String>();
for (String i : array)
myList.add(i);
Collections.shuffle(myList);
for (int i = 0; i < myList.size(); i++) {
String msg=myList.get(i);
}

Try this solution,
LinkedList<String> myList = new LinkedList<String>();
String[] words = { "Cow", "Pig", "Bird", "Sheep" };
for (String i : words)
myList.add(i);
Collections.shuffle(myList);
Then,
sampleText.setText(myList.pollLast());
pollLast() in LinkedList will retrieves and removes the last element of this list, or returns null if this list is empty.

try this.
int max = array.length() - 1;
int min = 0;
String Msg = array[new Random().nextInt(max - min + 1) + min];

First convert your String resource array to ArrayList
Fill value from current ArrayList to HashSet and convert that HashSet to newly ArrayList
Now shuffle that new ArrayList

Split strings on string array

i have String Array like this:
String[] q1={"AAA-BBB","AAA-CCC","AAA-DDD"}
and i want result like this
temp={"BBB","CCC","DDD"}
i tried below code but the result is wrong
for(int i=0;i<q1.length;i++){
ArrayList<String> temp=new ArrayList<>(Arrays.asList(q1[i].split("AAA-")));
}

Try like this:
ArrayList<String> temp=new ArrayList<>();
for(int i=0;i<q1.length;i++){
String[] array = q1[i].split("-");
temp.add(array[1]);
}

You could use substring:
ArrayList<String> temp = new ArrayList<>();
for(int i=0; i<q1.length; i++){
temp.add(q[i].substring(q[i].indexOf('-') + 1, q[i].length()))
}

you find error Because you use split
Splits this string around matches of the given regular expression.
https://docs.oracle.com/javase/7/docs/api/java/lang/String.html
q1[i].split("AAA-")
in this line you got 2 result splited 0 = "" AND 1 = "BBB"
so you need to pick the sec result
you have multi Solution
like https://stackoverflow.com/a/50234408/6998825 said
String[] array = q1[i].split("-");
temp.add(array[1]);
//change this q1[i].split("AAA-") to
q1[0].substring(4)
if your AAA- is not going to change

Have you tried creating the ArrayList outside of the loop? As previously you were creating a new ArrayList for every element in your string array
ArrayList<String> temp = new ArrayList<>();
for(int i=0;i<q1.length;i++){
temp.add(q1[i].substring(4);
}
Assuming that "AAA-" is not going to change.

Handle comma separated string

Creating an app in which i want to get string from json but i have one key and multiple value so i don't know how to handle this.
"colours": "#fff600,#000000,#ffffff,#00000,#ff9900,#333333"
And want to use this color in different class:
final ValueAnimator colorAnimation = ValueAnimator.ofObject(new android.animation.ArgbEvaluator(), Color.RED, Color.BLUE,Color.WHITE,Color.YELLOW,Color.CYAN,Color.MAGENTA,Color.GREEN,Color.GRAY);
colorAnimation.setDuration(1400);

Put the value of colours in string variable and then split the string in following way and add it to an arraylist :
String[] arr = str.split(",");
ArrayList<String> arr1 = new ArrayList<String>();
for (int i=0; i<arr.length; i++){
arr1.add(arr[i]);
}

Get value of color and use string tokenizer with ',' delima like this:
StringTokenizer stringTokenizer = new StringTokenizer(colorValueString, ",");
Also it has stringTokenizer.nextToken to get the next color in string

You can get the value of colours as a string and then split the string into parts like this:
String colours = json.getString("colours");
Log.d(TAG, colours);
String items[] = colours.split(",");
for (String item : items) {
Log.d(TAG, item);
}

If you own the json
You should use JSONArray:
"colours": ["#fff600","#000000","#ffffff","#00000","#ff9900","#333333"]
And read it like
JSONObject json = ...;
JSONArray colorsArray = json.getJSONArray("colours");
for(int i = 0; i < colorsArray.length(); i++) {
String colorString = colorsArray.getString(i);
int color = Color.parseColor(colorString);
// you should probably also catch IllegalArgumentException for wrong input
}
If you don't own the json
You can read it as string and split around commas:
JSONObject json = ...;
String colorsString = json.getString("colours");
String[] colorStrings = colorsString.split(",");
for(String string : colorStrings) {
int color = Color.parseColor(string);
// you should probably also catch IllegalArgumentException for wrong input
}

Compare a value with all the values in arraylist in java

In my case Arraylist contains user define timings like{12:23,15:40,17:17...}.
how can i print message when system time is equal to user timings.

First make an array for this by below code
String s = "{12:23,15:40,17:17...}";
String newstring = s.replace("{").replace("}");
int size = StringUtils.countOccurrencesOf(newstring , ",");
String[] arrayString = new String[size];
Now Compare
for(int i=0; i<size; i++){
if(yoursystemtime.equals(newstring.split(",")[i])){
Toast.makeText(context, "equal", Toast.Lenght.Short).show();
}
}

Array integer Android

ok so i create an array that has integers. The array displays five number from the min and max. How can i display all five numbers in a textview or edittext ? I tried:
nameofile.setText(al.get(x).toString());
but it only displays one?
ArrayList<Integer> al = new ArrayList<Integer>();
for (int i = minint; i <= maxint; i++)
al.add(i);
Random ran = new Random();
for (int i = 0; i < 5; i++) {
int x = al.remove(ran.nextInt(al.size()));
String myString = TextUtils.join(", ", al);
lottonumbers.setText(myString);

ArrayList<Integer> al = new ArrayList<Integer>();
al.add(0);
al.add(1);
al.add(5);
al.add(4);
al.add(3);
java.util.Collections.sort(al);//for sorting Integer values
String listString = "";
for (int s : al)
{
listString += s + " ";
}
nameofile.setText(listString);

You're currently only printing out one element (the one at index x). If you want to print them all in order, you can just join them using TextUtils.join().
Update: After seeing your edit, I think there's a better way to go about what you're trying to do. Instead of trying to pull the values one at a time, and update the list, why not just shuffle them, then use the above method?
Update 2: Okay, I think I finally understand your problem. Just a simple change, then.
ArrayList<Integer> al = new ArrayList<Integer>();
for (int i = minint; i <= maxint; i++)
al.add(i);
Random ran = new Random();
StringBuilder text = new StringBuilder(); // Create a builder
for (int i = 0; i < 5; i++) {
int x = al.remove(ran.nextInt(al.size()));
if (i > 0)
text.append(", "); // Add a comma if we're not at the start
text.append(x);
}
lottonumbers.setText(text);

al.get(x).toString() will only get the value at index "x". If you want to display all values, you need to combine all of the values from the array into a single string then use setText on that string.

You are only showing one number of your array in the TextView, you must to concat the numbers to see the others results like:
for(Integer integer : al) {
nameofile.setText(nameofile.getText() + " " + al.get(x).toString());
}
Then i think you can show all number in one String.