Creating an app in which i want to get string from json but i have one key and multiple value so i don't know how to handle this.
"colours": "#fff600,#000000,#ffffff,#00000,#ff9900,#333333"
And want to use this color in different class:
final ValueAnimator colorAnimation = ValueAnimator.ofObject(new android.animation.ArgbEvaluator(), Color.RED, Color.BLUE,Color.WHITE,Color.YELLOW,Color.CYAN,Color.MAGENTA,Color.GREEN,Color.GRAY);
colorAnimation.setDuration(1400);
Put the value of colours in string variable and then split the string in following way and add it to an arraylist :
String[] arr = str.split(",");
ArrayList<String> arr1 = new ArrayList<String>();
for (int i=0; i<arr.length; i++){
arr1.add(arr[i]);
}
Get value of color and use string tokenizer with ',' delima like this:
StringTokenizer stringTokenizer = new StringTokenizer(colorValueString, ",");
Also it has stringTokenizer.nextToken to get the next color in string
You can get the value of colours as a string and then split the string into parts like this:
String colours = json.getString("colours");
Log.d(TAG, colours);
String items[] = colours.split(",");
for (String item : items) {
Log.d(TAG, item);
}
If you own the json
You should use JSONArray:
"colours": ["#fff600","#000000","#ffffff","#00000","#ff9900","#333333"]
And read it like
JSONObject json = ...;
JSONArray colorsArray = json.getJSONArray("colours");
for(int i = 0; i < colorsArray.length(); i++) {
String colorString = colorsArray.getString(i);
int color = Color.parseColor(colorString);
// you should probably also catch IllegalArgumentException for wrong input
}
If you don't own the json
You can read it as string and split around commas:
JSONObject json = ...;
String colorsString = json.getString("colours");
String[] colorStrings = colorsString.split(",");
for(String string : colorStrings) {
int color = Color.parseColor(string);
// you should probably also catch IllegalArgumentException for wrong input
}
Related
How to get a random value from a string array in android without repetition?
I have array in String.xml file as below -
<string-array name="msg">
<item>Cow</item>
<item>Pig</item>
<item>Bird</item>
<item>Sheep</item>
</string-array>
I am selecting random string by using following code -
String[] array = Objects.requireNonNull(context).getResources().getStringArray(R.array.msg);
String Msg = array[new Random().nextInt(array.length)];
Can anyone help me please? Thanks is advance...!
Can you just do something like this:
Collections.shuffle(copyOfArray);
Then loop through that?
for (int i = 0; i < copyOfArray.size(); i++) {
println(copyOfArray.get(i))
}
try this -
array = Objects.requireNonNull(context).getResources().getStringArray(R.array.msg);
//String msg = array[new Random().nextInt(array.length)];
LinkedList<String> myList = new LinkedList<String>();
for (String i : array)
myList.add(i);
Collections.shuffle(myList);
for (int i = 0; i < myList.size(); i++) {
String msg=myList.get(i);
}
Try this solution,
LinkedList<String> myList = new LinkedList<String>();
String[] words = { "Cow", "Pig", "Bird", "Sheep" };
for (String i : words)
myList.add(i);
Collections.shuffle(myList);
Then,
sampleText.setText(myList.pollLast());
pollLast() in LinkedList will retrieves and removes the last element of this list, or returns null if this list is empty.
try this.
int max = array.length() - 1;
int min = 0;
String Msg = array[new Random().nextInt(max - min + 1) + min];
First convert your String resource array to ArrayList
Fill value from current ArrayList to HashSet and convert that HashSet to newly ArrayList
Now shuffle that new ArrayList
I am trying to remove special character from arraylist.
Not getting click how to do this?
I have 3 editfield and filling text after certain conditions
means when 1 is filled then another can be filled. now when i click to save this. this returns an array like [hello,abc,zbz] for fields
private List<String> hashtagData;
hashtagData = new ArrayList<String>();
String status_message = status.getText().toString();
String status_message2 = status2.getText().toString();
String status_message3 = status3.getText().toString();
hashtagData.add(status_message);
hashtagData.add(status_message2);
hashtagData.add(status_message3);
But I am trying to remove "[]".
Thank you if anybody can help.
Here try this:
ArrayList<String> strCol = new ArrayList<String>();
strCol.add("[a,b,c,d,e]");
strCol.add(".a.a.b");
strCol.add("1,2,].3]");
for (String string : strCol) {
System.out.println(removeCharacter(string));
}
private String removeCharacter(String word) {
String[] specialCharacters = { "[", "}" ,"]",",","."};
StringBuilder sb = new StringBuilder(word);
for (int i = 0;i < sb.toString().length() - 1;i++){
for (String specialChar : specialCharacters) {
if (sb.toString().contains(specialChar)) {
int index = sb.indexOf(specialChar);
sb.deleteCharAt(index);
}
}
}
return sb.toString();
}
Create regex which matches with your criteria, then loop through your list.
String myRegex = "[^a-zA-Z0-9]";
int index = 0;
for (String your_string : list)
list.set(index++, s.replaceAll(myRegex, ""));
can use below function to remove special character from string using regular expressions.
using System.Text;
using System.Text.RegularExpressions;
public string RemoveSpecialCharacters(string str)
{
return Regex.Replace(str, "[^a-zA-Z0-9_.]+", "", RegexOptions.Compiled);
}
I have got an array through Vector addittion like
[1!,2!,3!,4!]
I have to convert it into a string like
{1!2!3!4!}
..can you please tell me the name of few methods by which i can make it? Thanks all..
String getElement = null;
for(int j = 0;j<5;j++){
getElement = dynamicViewtagNames.elementAt(j);
}
I can get elements of this array like this..then I have to convert it into a string.
I'm not sure if I understand your question correctly, but if you just want to turn this:
[1!,2!,3!,4!]
into
{1!2!3!4!}
you can for example make use of the String.replace() or String.replaceAll() method.
String str = "[1!,2!,3!,4!]";
str = str.replace("[", "{");
str = str.replace("]", "}");
str = str.replace(",", "");
If [1!,2!,3!,4!] is a Vector containing the Strings you showed us above, you could do it like this using a StringBuffer:
// letz assume this vector has the following content: [1!,2!,3!,4!]
Vector<String> dynamicViewtagNames = new Vector<String>();
StringBuffer b = new StringBuffer();
b.append("{");
for(int i = 0; i < dynamicViewtagNames.size(); i++) {
b.append(dynamicViewtagNames.get(i))
}
b.append("}");
String mystring = b.toString();
Simple Solution
String names = names.replaceAll(",","");
names = names.replaceAll("[", "{");
names = names.replaceAll("]", "}");
Use this code,
StringBuilder str = new StringBuilder();
for (int i = 0; i<dynamicViewtagNames.length;i++){
str.append(dynamicViewtagNames[i])
}
str.toString();
or you can use:
Arrays.toString(dynamicViewtagNames);
Thanks
I am trying to get the data from database table via php file and displaying it in android. In php file I seperated each column with "#".
So now I am getting values like 4#2012-11-06#test1#test2. But for some columns there is not data. So the values are comng like 5###.
Here when I splitting with # and displaying the data it is throwing out of bounds exception. How can I resolve this issue?
Code:
String st="1#2012-10-30#test1#2#2012-10-30#test2#3#2012-11-06#test3#9##test1#21###22###23###";
String[] val = st.trim().split("#");
for (int i = 0; i < val.length; i++)
{
String str = val[i];
String arr[] = str.split("#");
System.out.println("arr0" + arr[0]);
System.out.println("arr1" + arr[1]);
System.out.println("arr2" + arr[2]);
}
try as using Pattern.compile to split your current string :
String your_string = "4#2012-11-06#test1#test2";
Pattern pattern = Pattern.compile("#");
String[] strarray =pattern.split(your_string);
for Handling if array index contain empty string change your code as:
for (int i = 0; i < val.length; i++)
{
String your_string =val[i];
Pattern pattern = Pattern.compile("#");
String[] strarray =pattern.split(your_string);
for(int j=0;j<strarray.length;j++){
if(strarray[j].trim().length() >0){
System.out.println("arr"+j+"::" + strarray[j]);
}
else{
}
}
}
In my project I need to store the values dynamically in a string and need to split that string with ",". How can I do that ? Please help me..
My Code:
static ArrayList<ArrayList<String>> listhere;
ArrayList<String> arropids;
String arropids1;
for(int q=0;q<listhere.size();q++)
{
arropids = listhere.get(q);
if(arropids.get(3).equals("1"))
{
arropids1 += arropids.get(0) + ",";
System.out.println("arropids1"+arropids1);
}
}
You must be getting NullPointerException as you havent initialized the String, initialize it as
String arropids1="";
It will resolve your issue, but I dont Recommend String for this task, as String is Immutable type, you can use StringBuffer for this purpose, so I recommend following code:
static ArrayList<ArrayList<String>> listhere;
ArrayList<String> arropids;
StringBuffer buffer=new StringBuffer();
for(int q=0;q<listhere.size();q++)
{
arropids = listhere.get(q);
if(arropids.get(3).equals("1"))
{
buffer.append(arropids.get(0));
buffer.append(",");
System.out.println("arropids1"+arropids1);
}
}
and finally get String from that buffer by:
String arropids1=buffer.toString();
In order to split the results after storing your parse in the for loop, you use the split method on your stored string and set that equal to a string array like this:
static ArrayList<ArrayList<String>> listhere;
ArrayList<String> arropids;
String arropids1 = "";
for(int q=0;q<listhere.size();q++) {
arropids = listhere.get(q);
if(arropids.get(3).equals("1"))
{
arropids1 += arropids.get(0) + ",";
System.out.println("arropids1"+arropids1);
}
}
String[] results = arropids1.split(",");
for (int i =0; i < results.length; i++) {
System.out.println(results[i]);
}
I hope that this is what you're looking for.