its may be silly but am confused on that this i want to start count up to one and if press comma(,)then i want to count comma only, here how i am try.
String conCount;
conCount = "1";
int countComma = conCount.length() - conCount.replace(",", "").length();
String lenVar;
lenVar = conCount;
convert = String.valueOf(countComma);
if (conCount.length() == 0) {
lenVar = "0";
} else {
textViewConCount.setText(convert);
}
String editTextString = "abc,efg,pqr,xyz";
if (editTextString.contains(",")) {
int countStringsSeperatedByComma = 0;
countStringsSeperatedByComma = editTextString.split(",").length;
System.out.println("Count of strings seperated by comma : " + countStringsSeperatedByComma);
int commaCount = countStringsSeperatedByComma - 1;
System.out.println("Count of commas : " + commaCount);
} else {
System.out.println("Count of characters in editText string : " + editTextString.length());
}
Output for above condition will be :
Count of strings seperated by comma : 4
Count of commas : 3
Suppose if your string is "abcefgpqrxyz" i.e. without comma then it will execute else part and print characters count as 12 in this case
Count of characters in editText string : 12
Your question statement is so ambiguous. Elaborate it completely and explain your end result with example. It's regarding string functions, I can give you the answer about it if I understand it :) :D
thanks for that i got that answer like that.
String varStr = editextContact.getText().toString();
//int VarCount = editextContact.getText().length();
int countStringsSeperatedByComma = varStr.split(",").length;
String convet=String.valueOf(countStringsSeperatedByComma);
textViewConCount.setText(varStr);
if (varStr.length() == 0){
textViewConCount.setText("0");
}else {
textViewConCount.setText(convet);
}
I'm having a problem with Talkback. In my string I have the following number.
1,827
it's a Dutch number so the number means:
1 euro and 82,7 cents.
But Talkback is saying:
18 hundred and 27 euro.
So this problem only occurs when I have a number with more than 2 decimals. How to fix this issue?
---EDIT---
When I'm reading this page: https://english.stackexchange.com/questions/62397/reading-out-decimal-numbers-in-english
it seems I must pronounce the number 1,827 as the following:
one point eight two seven instead to act if it is a number. How to do this?
---EDIT---
I included the following:
StringTokenizer stringTokenizer = new StringTokenizer(value, ".");
String currencyBeforeComma = null;
String currencyAfterComma = null;
while (stringTokenizer.hasMoreTokens()) {
currencyBeforeComma = stringTokenizer.nextToken();
currencyAfterComma = stringTokenizer.nextToken();
}
result = currencyBeforeComma + " point " + currencyAfterComma;
So now its pronouncing: one point eighthunderd twentyseven. So this is still now what i want.
---EDIT---
String value = 1,827;
String result = "";
for (Character chars : value.toCharArray()) {
result = result + chars + " ";
}
String replace = result.replace(getResources().getString(R.string.accessibility_decimal_separator), getResources().getString(R.string.accessibility_decimal_separator_text));
return replace;
This is what i did. I created a whitespace for every char in the value string and for the , or . I replaced it with a comma or point text.
This works for now but it isn't a clean solution. If anybody else has a better solution, please share
Try this and modify your as per your requirement
TextView currencylbl = (TextView) findViewById(R.id.currencylbl);
boolean countryCurrency = true;
String currency = "1,827";
if(countryCurrency==true && currency.contains(",")){
StringTokenizer stringTokenizer = new StringTokenizer(currency, ",");
String currencyBeforeComma = null;
String currencyAfterComma = null;
while (stringTokenizer.hasMoreTokens()) {
currencyBeforeComma = stringTokenizer.nextToken();
currencyAfterComma = stringTokenizer.nextToken();
currencylbl.setText(currency);
}
Double double1 = Double.parseDouble(currencyAfterComma);
double1 = Double.parseDouble(currencyBeforeComma)+double1/1000;
currencylbl.setContentDescription(double1+"");
}
countryCurrency refers to particular Country currency boolean.
Also modify as per your requirement.
Double double1 = Double.parseDouble(currencyAfterComma);
double1 = Double.parseDouble(currencyBeforeComma)+double1/1000;
currencylbl.setContentDescription(double1+"");
xml is
<TextView
android:id="#+id/currencylbl"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:textSize="24sp"
/>
I have a String separated by commas as follows
1,2,4,6,8,11,14,15,16,17,18
This string is generated upon user input. Suppose the user wants to remove any of the numbers, I have to rebuild the string without the specified number.
If the current string is:
1,2,4,6,8,11,14,15,16,17,18
User intents to remove 1, the final string has to be:
2,4,6,8,11,14,15,16,17,18
I tried to achieve this using the following code:
//String num will be the number to be removed
old = tv.getText().toString(); //old string
newString = old.replace(num+",",""); //will be the new string
This might be working sometimes but it is sure that it won't work for the above example I have shown, if I try to remove the 1, it also removes the last part of 11, because there also exists 1.
well you can use this. Its the most simplest approach i can think of:
//String num will be the number to be removed
old=","+tv.getText().toString()+",";//old string commas added to remove trailing entries
newString=old.replace(","+num+",",",");// will be the new string
newString=newString.substring(1,newString.length()-1); // removing the extra commas added
This would work for what you want to do. I have added a comma at the start and end of your string so that you can also remove the first and last entries too.
You can split the string first and check for the number where you append those value that is not equivalent to the number that will get deleted;
sample:
String formated = "1,2,4,6,8,11,14,15,16,17,18";
String []s = formated.split(",");
StringBuilder newS = new StringBuilder();
for(String s2 : s)
{
if(!s2.equals("1"))
newS.append(s2 + ",");
}
if(newS.length() >= 1)
newS.deleteCharAt(newS.length() - 1);
System.out.println(newS);
result:
2,4,6,8,11,14,15,16,17,18
static public String removeItemFromCommaDelimitedString(String str, String item)
{
StringBuilder builder = new StringBuilder();
int count = 0;
String [] splits = str.split(",");
for (String s : splits)
{
if (item.equals(s) == false)
{
if (count != 0)
{
builder.append(',');
}
builder.append(s);
count++;
}
}
return builder.toString();
}
String old = "1,2,4,6,8,11,14,15,16,17,18";
int num = 11;
String toRemove = "," + num + "," ;
String oldString = "," + old + ",";
int index = oldString.indexOf(toRemove);
System.out.println(index);
String newString = null;
if(index > old.length() - toRemove.length() + 1){
newString = old.substring(0, index - 1);
}else{
newString = old.substring(0, index) + old.substring(index + toRemove.length() -1 , old.length());
}
System.out.println(newString);
I have a string (length 3-8) assigned to a variable (text). I want to check whether the 2nd and 3rd characters are NOT numeric (a letter or symbol or space..or anything other than numbers).
Elementary way to do this could be:
if(((text.charAt(1)-'0')>=0)&&(text.charAt(1)-'0')<10))||((text.charAt(2)-'0')>=0)&&(text.charAt(2)-'0')<10)))
{
//do nothing, since this means 2nd and/or 3rd characters in the string are numeric
}
else
{
// Your condition is met
}
You could also use REGEX's , if your checking is still more complicated.
Here is Another way to achieve this:
boolean isNumeric = true;
String test = "testing";
char second = test.charAt(1);
char third = test.charAt(2);
try {
Integer.parseInt(String.valueOf(second));
Integer.parseInt(String.valueOf(third));
} catch(NumberFormatException e) {
isNumeric = false;
}
System.out.println("Contains Number in 2nd and 3rd or both position: " + isNumeric);
You might make use of the String.IndexOf(String) method, like:
String digits = "0123456789";
String s2 = text.substring(2,3);
String s3 = text.substring(3,4);
boolean valid = (digits.indexOf(s2) > -1) && (digits.indexOf(s3) > -1);
I want to split a string and get a word finally. My data in database is as follows.
Mohandas Karamchand Gandhi (1869-1948), also known as Mahatma Gandhi, was born in Porbandar in the present day state of Gujarat in India on October 2, 1869.
He was raised in a very conservative family that had affiliations with the ruling family of Kathiawad. He was educated in law at University College, London.
src="/Leaders/gandhi.png"
From the above paragraph I want get the image name "gandhi". I am getting the index of "src=". But now how can I get the image name i.e "gandhi" finally.
My Code:
int index1;
public static String htmldata = "src=";
if(paragraph.contains("src="))
{
index1 = paragraph.indexOf(htmldata);
System.out.println("index1 val"+index1);
}
else
System.out.println("not found");
You can use the StringTokenizer class (from java.util package ):
StringTokenizer tokens = new StringTokenizer(CurrentString, ":");
String first = tokens.nextToken();// this will contain one word
String second = tokens.nextToken();// this will contain rhe other words
// in the case above I assumed the string has always that syntax (foo: bar)
// but you may want to check if there are tokens or not using the hasMoreTokens method
Try this code. Check if it working for you..
public String getString(String input)
{
Pattern pt = Pattern.compile("src=.*/(.*)\\..*");
Matcher mt = pt.matcher(input);
if(mt.find())
{
return mt.group(1);
}
return null;
}
Update:
Change for multiple item -
public ArrayList<String> getString(String input)
{
ArrayList<String> ret = new ArrayList<String>();
Pattern pt = Pattern.compile("src=.*/(.*)\\..*");
Matcher mt = pt.matcher(input);
while(mt.find())
{
ret.add(mt.group(1));
}
return ret;
}
Now you'll get an arraylist with all the name. If there is no name then you'll get an empty arraylist (size 0). Always make a check for size.