I have a URL that I want the user to open in OneNote or a web browser using an Android intent. With web browser it's easy. I just use ACTION_SEND and set the intent data with the url.
How do I add OneNote app (if available) to the list of apps to choose from as well as send this URL data?
Look at this other question, it should have all your answers
Launch OneNote using Share Intent in Android
Edit
String onPackageName = "com.microsoft.office.onenote";
Intent launchIntent = getPackageManager().
getLaunchIntentForPackage(onPackageName);
launchIntent.setAction(Intent.ACTION_SEND);
launchIntent.putExtra(Intent.EXTRA_TITLE,"Hello world");
launchIntent.putExtra(Intent.EXTRA_TEXT,"Hello world");
launchIntent.putExtra(Intent.EXTRA_SUBJECT,"htttp://www.google.com");
startActivity(launchIntent);
I solved it using the following code:
String url = link.Uri;
Uri uri = Uri.parse(url);
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse(url));
if (intent.resolveActivity(context.getPackageManager()) != null) {
context.startActivity(intent);
}
Related
I want to share an image from android activity to facebook messenger app which is already opened in my device and reside in recent tasks of the android device.
I am using the below code to share the image but it is opening a new activity in messenger 'share seperately' but I want to share it to the already opened chat.
String mimeType = "image/*";
Intent intent = new Intent(Intent.ACTION_SEND);
intent.setPackage("com.facebook.orca");
intent.setType(mimeType);
intent.putExtra(Intent.EXTRA_STREAM, contentUri);
intent.putExtra(EXTRA_PROTOCOL_VERSION, PROTOCOL_VERSION);
intent.putExtra(EXTRA_APP_ID, YOUR_APP_ID);
activity.startActivityForResult(shareIntent, SHARE_TO_MESSENGER_REQUEST_CODE);
Facebook has restricted the text sharing over the post. It will either support a valid URL link sharing or Image Sharing. So I've posted the code which is referenced from https://stackoverflow.com/a/22994833/8331006
private void shareAppLinkViaFacebook(String urlToShare) {
try {
Intent intent1 = new Intent();
intent1.setClassName("com.facebook.katana", "com.facebook.katana.activity.composer.ImplicitShareIntentHandler");
intent1.setAction("android.intent.action.SEND");
intent1.setType("text/plain");
intent1.putExtra("android.intent.extra.TEXT", urlToShare);
startActivity(intent1);
} catch (Exception e) {
// If we failed (not native FB app installed), try share through SEND
String sharerUrl = "https://www.facebook.com/sharer/sharer.php?u=" + urlToShare;
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(sharerUrl));
startActivity(intent);
}
}
I am doing an android share intent for Pinterest but is not fully working. I am able to attach the image but I can't send text to the "description" field in the share window. I've tried different types (text/plain, image/*, image/png) and also tried the ACTION_SEND_MULTIPLE intent type but still no luck. Google chrome share intent works perfectly so I'm sure Pinterest supports this functionality. Here is my code:
Intent intent = new Intent(Intent.ACTION_SEND);
intent.setType("*/*");
intent.putExtra(Intent.EXTRA_TEXT, text);
if(file != null) intent.putExtra(Intent.EXTRA_STREAM, Uri.fromFile(file));
intent.setClassName(packageName, name);
this.startActivity(intent);
Any idea? thanks!
I found a way to share to Pinterest with plain Android intents (without using the Pinterest SDK), with help from Pin It button developer docs.
Basically you just open an URL like this with Intent.ACTION_VIEW; the official Pinterest app kindly supports these URLs. (I've earlier used a very similar approach for sharing to Twitter.)
https://www.pinterest.com/pin/create/button/
?url=http%3A%2F%2Fwww.flickr.com%2Fphotos%2Fkentbrew%2F6851755809%2F
&media=http%3A%2F%2Ffarm8.staticflickr.com%2F7027%2F6851755809_df5b2051c9_z.jpg
&description=Next%20stop%3A%20Pinterest
And for smoother user experience, set the intent to open directly in Pinterest app, if installed.
A complete example:
String shareUrl = "https://stackoverflow.com/questions/27388056/";
String mediaUrl = "http://cdn.sstatic.net/stackexchange/img/logos/so/so-logo.png";
String description = "Pinterest sharing using Android intents"
String url = String.format(
"https://www.pinterest.com/pin/create/button/?url=%s&media=%s&description=%s",
urlEncode(shareUrl), urlEncode(mediaUrl), urlEncode(description));
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
filterByPackageName(context, intent, "com.pinterest");
context.startActivity(intent);
Util methods used above:
public static void filterByPackageName(Context context, Intent intent, String prefix) {
List<ResolveInfo> matches = context.getPackageManager().queryIntentActivities(intent, 0);
for (ResolveInfo info : matches) {
if (info.activityInfo.packageName.toLowerCase().startsWith(prefix)) {
intent.setPackage(info.activityInfo.packageName);
return;
}
}
}
public static String urlEncode(String s) {
try {
return URLEncoder.encode(s, "UTF-8");
}
catch (UnsupportedEncodingException e) {
Log.wtf("", "UTF-8 should always be supported", e);
return "";
}
}
This is the result on a Nexus 5 with Pinterest app installed:
And if Pinterest app is not installed, sharing works just fine via a browser too:
for some reason pinterest app doesn't comply to the standard (Intent.EXTRA_TEXT) so we have to add it separately
if(appInfo.activityInfo.packageName.contains("com.pinterest"){
shareIntent.putExtra("com.pinterest.EXTRA_DESCRIPTION","your description");
}
File imageFileToShare = new File(orgimagefilePath);
Uri uri = Uri.fromFile(imageFileToShare);
Intent sharePintrestIntent = new Intent(Intent.ACTION_SEND);
sharePintrestIntent.setPackage("com.pinterest");
sharePintrestIntent.putExtra("com.pinterest.EXTRA_DESCRIPTION", text);
sharePintrestIntent.putExtra(Intent.EXTRA_STREAM, uri);
sharePintrestIntent.setType("image/*");
startActivityForResult(sharePintrestIntent, PINTEREST);
How can I open a url in the android web browser from my application on clicking a button.
I tried this :
Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(strURL));
startActivity(myIntent);
but I am getting exception:
but I got an Exception :
"No activity found to handle Intent{action=android.intent.action.VIEW data =www.google.com"
You are doing it fundamentally correct, you just need to include the full url.
String strURL="http://www.google.com";
Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(strURL));
startActivity(myIntent);
Basically, the http is the protocol. It is the computer's way of trying to figure out how you want to open it. You might also be interested in https, if you want a secure connection over SSL.
Almost seems like this would be useful to read... from the page:
Uri uri = Uri.parse("http://androidbook.blogspot.com");
Intent launchBrowser = new Intent(Intent.ACTION_VIEW, uri);
startActivity(launchBrowser);
There is a second way, involving the WebView, but that seems like it's not your question. Hope this helped.
String url = "http://www.example.com";
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(url));
startActivity(i);
Try this:
String strURL = "http://www.google.com";
Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(strURL));
startActivity(myIntent);
As for the missing "http://" I'd just do something like this:
if (!url.startsWith("http://") && !url.startsWith("https://"))
url = "http://" + url;
Hello I just want to call Facebook app with the link below (on my android project):
String url_facebook_prixo = "https://www.facebook.com/pages/Prixo/468580313168290";
I tried this :
Uri uri = Uri.parse("facebook://facebook.com/page{468580313168290}");
Intent viewIntent = new Intent(Intent.ACTION_VIEW, uri);
startActivity(viewIntent);
I tried with others link but its only displaying my wall..
Someone?
You should use the id to open the page.
Intent facebookIntent = new Intent(
Intent.ACTION_VIEW,
Uri.parse("fb://profile/468580313168290"));
startActivity(facebookIntent);
I would advice you to encapsulate this in a try catch. Inside the catch open a normal browser intent
How can I start an intent to open a Facebook application on a phone and navigate to the prefered page in Facebook?
I tried:
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setClassName("com.facebook.katana", "com.facebook.katana.ProfileTabHostActivity");
intent.putExtra("extra_user_id", "123456789l");
this.startActivity(intent);
Well, whatever I write to "1234567891", it is always navigating to my page. Always to me and not else.
How could I do this?
Here is the best and simple way to do it.
Just follow the code
public final void Facebook() {
final String urlFb = "fb://page/"+yourpageid;
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse(urlFb));
// If Facebook application is installed, use that else launch a browser
final PackageManager packageManager = getPackageManager();
List<ResolveInfo> list =
packageManager.queryIntentActivities(intent,
PackageManager.MATCH_DEFAULT_ONLY);
if (list.size() == 0) {
final String urlBrowser = "https://www.facebook.com/pages/"+pageid;
intent.setData(Uri.parse(urlBrowser));
}
startActivity(intent);
}
I had the exactly same problem, sent the user id but for some reason, my profile always opened instead of the friend's profile.
The problem is that if you pass the String of the Long object that represents the Facebook UID, or even a long primitive type, the intent won't be able to read it later. You need to pass a real Long.
So the complete code is:
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setClassName("com.facebook.katana", "com.facebook.katana.ProfileTabHostActivity");
Long uid = new Long("123456789");
intent.putExtra("extra_user_id", uid);
startActivity(intent);
Ok enjoy and hope this helps :-)
Maxim
try this code :
String facebookUrl = "https://www.facebook.com/<id_here>";
try {
int versionCode = getPackageManager().getPackageInfo("com.facebook.katana", 0).versionCode;
if (versionCode >= 3002850) {
Uri uri = Uri.parse("fb://facewebmodal/f?href=" + facebookUrl);
startActivity(new Intent(Intent.ACTION_VIEW, uri));
} else {
Uri uri = Uri.parse("fb://page/<id_here>");
startActivity(new Intent(Intent.ACTION_VIEW, uri));
}
} catch (PackageManager.NameNotFoundException e) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(facebookUrl)));
}
This solution won't work any more. The new version of the facebook app doesn't support anymore those kind of intents. See here the bug report
The new solution is to use the iPhone scheme mechanism (Yes, facebook decided to support the iPhone mechanism in Android instead of the implicit intent mechanism of Android).
So in order to open the facebook app with a user profile all you need to do is:
String facebookScheme = "fb://profile/" + facebookId;
Intent facebookIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(facebookScheme));
startActivity(facebookIntent);
If you are looking for other actions you can use the following page for all available actions (/you have to test it though, since I didn't find an official publication of facebook about this)