How can I open a url in the android web browser from my application on clicking a button.
I tried this :
Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(strURL));
startActivity(myIntent);
but I am getting exception:
but I got an Exception :
"No activity found to handle Intent{action=android.intent.action.VIEW data =www.google.com"
You are doing it fundamentally correct, you just need to include the full url.
String strURL="http://www.google.com";
Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(strURL));
startActivity(myIntent);
Basically, the http is the protocol. It is the computer's way of trying to figure out how you want to open it. You might also be interested in https, if you want a secure connection over SSL.
Almost seems like this would be useful to read... from the page:
Uri uri = Uri.parse("http://androidbook.blogspot.com");
Intent launchBrowser = new Intent(Intent.ACTION_VIEW, uri);
startActivity(launchBrowser);
There is a second way, involving the WebView, but that seems like it's not your question. Hope this helped.
String url = "http://www.example.com";
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(url));
startActivity(i);
Try this:
String strURL = "http://www.google.com";
Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(strURL));
startActivity(myIntent);
As for the missing "http://" I'd just do something like this:
if (!url.startsWith("http://") && !url.startsWith("https://"))
url = "http://" + url;
Related
What I want to achieve is to display PDFs directly in browser.
private void openPDF(String url) {
Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
startActivity(browserIntent);
}
With this method the PDF is downloaded, but I have to manually open it in order to see it.
I remember this method worked just fine a while a go, did something change in the intent or chrome maybe?
String format = "https://drive.google.com/viewerng/viewer?embedded=true&url=%s";
String fullPath = String.format(Locale.ENGLISH, format, "PDF_URL_HERE");
Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(fullPath));
startActivity(browserIntent);
If this can help.
I am trying to put a simple Google Search in my app. I found this code but it's not exactly what I am searching for. Below the search comes from a given url.
String url = "http://www.google.com";
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(url));
startActivity(i);
The thing is that I would like to get the search text from user and if possible without starting a new Activity like this one:
Intent intent = new Intent(Intent.ACTION_WEB_SEARCH);
String term = editTextInput.getText().toString();
intent.putExtra(SearchManager.QUERY, term);
startActivity(intent);
Get the text from the user and place that in the URI, then start the intent.
String url = "http://www.google.com/search?q=" + userText;
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(url));
startActivity(i);
Hi I'm testing on encryption & decryption of a web url & trying to develop intent to web browser.
String decrypted = DecodeAES.decrypt(AESkey, encrypted);
decryptedValue.setText(decrypted);
here i want to retrieve "decryptedValue" and to be placed in the Uri.parse
actually here the "decryptedValue" contains some website to be opened in webbrowser.
Intent browserIntent = new Intent(Intent.ACTION_VIEW,Uri.parse("http://www.google.com"));
startActivity(browserIntent);
Please tell me how to use Uri.parse & what to be used.
Thanks in advance.
Change -
Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("www.google.com"));
to -
Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("http://www.google.com"));
Hello I just want to call Facebook app with the link below (on my android project):
String url_facebook_prixo = "https://www.facebook.com/pages/Prixo/468580313168290";
I tried this :
Uri uri = Uri.parse("facebook://facebook.com/page{468580313168290}");
Intent viewIntent = new Intent(Intent.ACTION_VIEW, uri);
startActivity(viewIntent);
I tried with others link but its only displaying my wall..
Someone?
You should use the id to open the page.
Intent facebookIntent = new Intent(
Intent.ACTION_VIEW,
Uri.parse("fb://profile/468580313168290"));
startActivity(facebookIntent);
I would advice you to encapsulate this in a try catch. Inside the catch open a normal browser intent
String url = "<html><body>hello World</body></html>";
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(url));
startActivity(i);
how can i load the HTML source code in the browser? Please kindly explain with an example.
Intent i = new Intent();
// MUST instantiate android browser, otherwise it won't work
i.setComponent(new ComponentName("com.android.browser", "com.android.browser.BrowserActivity"));
i.setAction(Intent.ACTION_VIEW);
String html = "<html><body>hello World</body></html>";
// May work without url encoding, but I think is advisable
// URLEncoder.encode replace space with "+", must replace again with %20
String dataUri = "data:text/html," + URLEncoder.encode(html).replaceAll("\\+","%20");
i.setData(Uri.parse(dataUri));
startActivity(i);