Develop Reference

How do I convert decimal input into an int?

I have an EditText field where the user can enter his weight in Kilogram, i.e. 11.7. I want to store that in the database as gramms, i.e. 11700.
How do I convert the String "11.7" to the Integer 11700?

To get the value from an EditText use http://developer.android.com/reference/android/widget/EditText.html#getText()
String userInput = editText.getText().toString();
To convert a String into a double use the code from #govindpatel http://developer.android.com/reference/java/lang/Double.html#parseDouble(java.lang.String)
try {
double kg = Double.parseDouble(userInput)
}
catch (NumberFormatException nfe) {
editText.setError(R.string.invalid_double); // Or whatever you want to show the user
}
To convert from KG to g:
long gramms = Math.round(kg * 1000);
You could replace the double and long with float and int if you know you don't need the precision or range of the larger variables.

you have to parse it to int,long or double.
I think In your case you can do this
double grams = Double.parseDouble("11.7") * 1000;
double variable_name = Double.parseDouble(string_name) * number_you_want_to_multiply_with;
and this will give a double value. So you can convert that to integer, long or keep as it is in your db.
to convert double to long you can do something like this:
long value = (long)(grams);
Hope this helps you,

I'm not sure what it has to do with Android?
int grams = (int)(kg * 1000);
To get text from EditText
EditText mEdit = (EditText)findViewById(R.id.edittext);
double kg = Double.parseDouble(mEdit.getText().toString());

ReplaceAll not working

I'm using google volley to retrieve source code from website. Some looping was done to capture the value in the code. I've successfully captured the data I wanted, but error was shown: NumberFormatException: Invalid float: "2,459.00"
My intention was to store the value after the class=ListPrice>
Sample:
RM 2,899.00
The example value of the source code I wanted to save is "RM2,459.00 "
Below is the code I've written:
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_lazada_result);
lelongResult = (TextView) findViewById(R.id.lelong_result);
RequestQueue lelong = MyVolley.getRequestQueue(this);
StringRequest myLel = new StringRequest(
Method.GET,
"http://list.lelong.com.my/Auc/List/List.asp?DA=A&TheKeyword=iphone&x=0&y=0&CategoryID=&PriceLBound=&PriceUBound=",
RetrieveLelong(), createMyReqErrorListener());
lelong.add(myLel);
}
private Response.Listener<String> RetrieveLelong() {
return new Response.Listener<String>() {
#Override
public void onResponse(String response) {
ArrayList<Float> integers = new ArrayList<>();
String to = "class=ListPrice>";
String remainingText = response;
String showP = "";
while (remainingText.indexOf(to) >= 0) {
String tokenString = remainingText.substring(remainingText
.indexOf(to) + to.length());
String priceString = tokenString.substring(0,
tokenString.indexOf("<"));
float price = Float.parseFloat(priceString.replaceAll("[^\\d,]+", "").trim());
integers.add((price / 100));
remainingText = tokenString;
}
for (int i = 0; i < integers.size(); i++) {
String test1 = Float.toString(integers.get(i));
showP += test1 + "\n";
}
lelongResult.setText(showP);
}
};
}
The problem was as below:
I've tried all sort of replaceAll(),
1)replaceAll("[^\d,]+","") result:2,89900
replace all character except digits and comma works.
2)replaceAll("[^\d]+","") result:Invalid int""
replace all character include comma and dot ,not working
3)replaceAll("[^\d.]+,"") result:Invalid int""
replace all character exclude digits and dot, not working
From the experiment 2&3 coding above,I've noticed that if the comma were removed,i cant parseFloat as the value received by it is: "".NumberFormatException:Invalid Float:"" shown.
From the experiment 1,NumberFormatException:Invalid Float "2,45900" is showned.
The problem was replacing comma ,the code will not work but with the presence of comma ,the value cannot be stored into string

try this:
float price = Float.parseFloat(priceString.replaceAll("RM", "").trim());

use `replaceAll(Pattern.quote(","), "");
EDIT
if you want only numbers then use this
String s1= s.replaceAll("\D+","");

Try to parse the number by specifying the Locale.
NumberFormat format = NumberFormat.getInstance(Locale.KOREAN);
Number number = format.parse(priceString.replaceAll("RM", ""));
double d = number.doubleValue();
I'm just guessing the locale, don't know what you should use, depends on country

You need to do it one by one
priceString=priceString.replaceAll("\\D", "");
priceString=priceString.replaceAll("\\s", "");
now
priceString=priceString.trim();
float price = Float.parseFloat(priceString);

the problem is that in your code:
priceString.replaceAll(Pattern.quote(","), "");
float price = Float.parseFloat(priceString.replaceAll("\\D+\\s+", "").trim());
You are replacing coma but not storing the value!
you have to do:
priceString = priceString.replaceAll(",", "");
float price = Float.parseFloat(priceString.replaceAll("\\D+\\s+", "").trim());
I'm not sure of the pattern "\D+\s" because if you remove the coma you don't need to replace anything else (except "RM" that i assume you already removed)
Update: set locale and parse a number:
NumberFormat format = NumberFormat.getInstance(Locale.KOREAN);
Number number = format.parse(priceString.replaceAll("RM", ""));
double d = number.doubleValue();

Convert String to double

Is there way to convert a string to double. This is how i did.
String s = b.getText().toString();
double d = Double.parseDouble(s);
It gives NumberFormatException

Try this
String s = b.getText().toString();
double d = Double.valueOf(s.trim()).doubleValue();

You are probably starting off with a zero-length string. Check the length before you parse it. It also wouldn't hurt to catch NumberFormatException, although that shouldn't be problem if you have android:inputType="number" in the view's layout.
double d = 0;
CharSequence cs = b.getText();
if(cs != null && cs.length() > 0) {
d = Double.parseDouble(cs.toString());
}

i have a similar problem.
for correct formatting EditText text content to double value i use this code:
try {
String eAm = etAmount.getText().toString();
DecimalFormat dF = new DecimalFormat("0.00");
Number num = dF.parse(eAm);
mPayContext.amount = num.doubleValue();
} catch (Exception e) {
mPayContext.amount = 0.0d;
}
this is independet from current phone locale and return correct double value.
hope it's help;

unable to parse "" as integer[FC]

I have this code to control if a EditTextPreference is null or not:
case R.id.prochain_vidange:
settings = PreferenceManager.getDefaultSharedPreferences(getBaseContext());
String choix_huile = settings.getString("listPref_huile_moteur", "0");
km = settings.getString("km", "");
Log.d("TAG",km);
int x= Integer.valueOf(km);
if (km != "")
{
if (Integer.valueOf(choix_huile) == 0) {
............
The problem is in this line:
int x= Integer.valueOf(km);
What could be the problem ?
Thanks.

If you give Integer.valueOf(String s) a string that is not a valid number, it throws a NumberFormatException. Change the default value to 0:
km = settings.getString("km", "0");
Alternatively, you can catch the exception, and set x to 0:
km = settings.getString("km", "");
int x;
try {
x = Integer.valueOf(km);
} catch(NumberFormatException e) {
x = 0;
}

Integer.valueOf trys to make a new Integer with .parseInteger(String s), "" cant be parsed to a valid number so you get a NumberFormatException
You can catch it with a try catch block or you can simply dont try to make a Integer with the String "".
before:
int x= Integer.valueOf(km);
if (km != "") {
after:
if (km != "") {
int x= Integer.valueOf(km);

Integer.valueOf(km) can throw an exception if the the km string is not able to be parsed as an integer.
However, wrapping it in a try { } catch() block is not an approach I would recommend.
The whole purpose of having a default value on the getString() method in SharedPreferences is that there can be a default value to fall back on if the preference doesn't exist. So the better way to solve this is to modify your settings.getString(...) call to be like this:
km = settings.getString("km", "0");
Then your subsequent call to Integer.valueOf(km) will not have a blank to fail upon.
Is the input string coming from a blank text field where the user can enter any value? If so, it's at that point that you can validate the value that the user entered. By validating the input early on, you won't need to scatter the checking/validating mechanism to other areas of your code.

Android: converting String to int

I'm simply trying to convert a string that is generated from a barcode scanner to an int so that I can manipulate it by taking getting the remainder to generate a set number of integers. So far I have tried:
int myNum = 0;
try {
myNum = Integer.parseInt(myString.getText().toString());
} catch(NumberFormatException nfe) {
}
and
Integer.valueOf(mystr);
and
int value = Integer.parseInt(string);
The first one gives me the error :The method getText() is undefined for the type String
while the last two don't have any compile errors but the app crashes immediately when those are called. I thought it had to do with my barcode scanning intent method but I put it into the OnCreate and still got the error.

Change
try {
myNum = Integer.parseInt(myString.getText().toString());
} catch(NumberFormatException nfe) {
to
try {
myNum = Integer.parseInt(myString);
} catch(NumberFormatException nfe) {

It's already a string? Remove the getText() call.
int myNum = 0;
try {
myNum = Integer.parseInt(myString);
} catch(NumberFormatException nfe) {
// Handle parse error.
}

You just need to write the line of code to convert your string to int.
int convertedVal = Integer.parseInt(YOUR STR);

Use regular expression:
int i=Integer.parseInt("hello123".replaceAll("[\\D]",""));
int j=Integer.parseInt("123hello".replaceAll("[\\D]",""));
int k=Integer.parseInt("1h2el3lo".replaceAll("[\\D]",""));
output:
i=123;
j=123;
k=123;

Use regular expression:
String s="your1string2contain3with4number";
int i=Integer.parseInt(s.replaceAll("[\\D]", ""))
output: i=1234;
If you need first number combination then you should try below code:
String s="abc123xyz456";
int i=((Number)NumberFormat.getInstance().parse(s)).intValue()
output: i=123;

barcode often consist of large number so i think your app crashes because of the size of the string that you are trying to convert to int. you can use BigInteger
BigInteger reallyBig = new BigInteger(myString);

You can not convert to string if your integer value is zero or starts with zero (in which case 1st zero will be neglected).
Try change.
int NUM=null;

try this
String t1 = name.getText().toString();
Integer t2 = Integer.parseInt(mynum.getText().toString());
boolean ins = myDB.adddata(t1,t2);
public boolean adddata(String name, Integer price)

// Convert String to Integer
// String s = "fred"; // use this if you want to test the exception below
String s = "100";
try
{
// the String to int conversion happens here
int i = Integer.parseInt(s.trim());
// print out the value after the conversion
System.out.println("int i = " + i);
}
catch (NumberFormatException nfe)
{
System.out.println("NumberFormatException: " + nfe.getMessage());
}