Develop Reference

Android ScrollView loses clip on rotation animation

I'm using Rotate3dAnimation to flip a card view which contains a ScrollView. But during animation ScrollView loses a clip somehow so I see top and bottom of ScrollView content outside the card view (and ScrollView) bounds until animation is done.
Why is that and how to beat this behaviour?

This unfortunately happens due to the way the bounds for the ScrollView are calculated. It seems the bounds are not "rotated" along with the view.
One work around is to take a snapshot of each view - both the front and the back of the card - and then to animate between these snapshots above the actual views.
The code would look something like this:
firstView.setDrawingCacheEnabled(true);
firstAnimationView.setBackgroundDrawable(new BitmapDrawable(firstView.getDrawingCache()));
secondView.setDrawingCacheEnabled(true);
secondAnimationView.setBackgroundDrawable(new BitmapDrawable(secondView.getDrawingCache()));
Animation flipOutAnimation = createFlipOutAnimation();
flipOutAnimation.setAnimationListener(new Animation.AnimationListener() {
#Override
public void onAnimationEnd(Animation animation) {
firstAnimationView.setVisibility(View.GONE);
}
...
});
Animation flipInAnimation = createFlipInAnimation();
flipInAnimation.setAnimationListener(new Animation.AnimationListener() {
#Override
public void onAnimationEnd(Animation animation) {
animationBackgroundView.setVisibility(View.GONE);
secondAnimationView.setVisibility(View.GONE);
}
...
});
firstAnimationView.startAnimation(flipOutAnimation);
secondAnimationView.startAnimation(flipInAnimation);
animationBackgroundView.setVisibility(View.VISIBLE);
firstAnimationView.setVisibility(View.VISIBLE);
secondAnimationView.setVisibility(View.VISIBLE);
For backwards compatible flip animations, I use http://genzeb.github.io/flip/

Android fragment animation first time stuck

I am doing an animation inside a fragment.
I have 2 views on top of each other, one of them set on View.GONE.
when I press a button I want my 2nd fragment to translate animation from the bottom to top.
I am doing it fine and it's working great,
the problem is that in my first run, the xml view is gone, but he is in the same Y he is suppose to be.
so the first animation I do isn't doing anything, just switch from GONE to VISIBLE, after that, I press dismiss and the fragment goes away and comes back just like I want too.
my problem is just the first run.
how can I set my view Y to be 100% below my screen?
here's the code I use :
private void moreCustomAnimation() {
int yOffset = moreMenuFrameLayout.getMeasuredHeight();
TranslateAnimation moveAnim = new TranslateAnimation(0, 0, yOffset, 0);
moveAnim.setDuration(500);
moveAnim.setFillAfter(true);
blackView.setVisibility(View.VISIBLE);
moreMenuFrameLayout.setVisibility(View.VISIBLE);
moreMenuFrameLayout.startAnimation(moveAnim);
moveAnim.setAnimationListener(new Animation.AnimationListener() {
#Override
public void onAnimationStart(Animation animation) {
}
#Override
public void onAnimationEnd(Animation animation) {
}
#Override
public void onAnimationRepeat(Animation animation) {
}
});
}
on the way out of the screen I use the same code just switch the
yOffset to the other Y integer, and set the view to GONE at animation end.
thanks a lot in advance for any help !

You can use the onGlobalLayout event to set the position of the view.
Like this:
moreMenuFrameLayout.getViewTreeObserver().addOnGlobalLayoutListener(new OnGlobalLayoutListener() {
#Override
public void onGlobalLayout() {
moreMenuFrameLayout.setTranslationY(moreMenuFrameLayout.getMeasuredHeight());
moreMenuFrameLayout.getViewTreeObserver().removeOnGlobalLayoutListener(this);
}
});
This event happens when your views get their actual size and position before being drawn to the screen. However, they happen every time the view is drawn so you must remember to remove the listener right after the first time.
HTH

First time you can add the 'yOffset' value to the view orginal points
moreMenuFrameLayout.setY(currentYpostition + yOffset)
and this will place the view to the bottom of the screen. You can enable the visibility when the animation starts.

How do I animate expansion of a ListView?

I'm looking to implement an animation that will slide open or expand a ListView in android. At the moment, I'm using a scale animation (shown below)
Animation slideDown = new ScaleAnimation(1.0f, 1.0f, 0.0f, 1.0f);
slideDown.setDuration(1000);
but this doesn't work for 2 reasons:
1) I want the first item to fade in, and then the list to drop down. If I do a fade in animation, the entire list shows up and then jumps back up to the top and scales down to full size
2) I'm not really looking to scale, I would like to just reveal the ListView by animating down the bottom (if that makes sense).
Is there a way that I can do a TranslateAnimation on just the bottom margin or something similar? I looked into the drawable Clip resource, but that didn't seem to fit my needs here (I'm not sure how to apply it to a ListView). And I'm using a normal ListView, not an ExpandableListView, because I just have one group of items.

So I started searching for different things and it turns out that animating the height was my solution. Essentially I start with a dummy object in the list (so that it has at least 1 row), then I animate it from the height of that row to the height of the full list. Below is the code for the runnable that I am now calling.
private Runnable slideDownList1 = new Runnable() {
#Override
public void run() {
final ListView detail = (ListView)getView().findViewById(R.id.detail_menu_1);
ValueAnimator va = ValueAnimator.ofInt(detail.getHeight(), detail.getHeight()*mItem.containedObjects.size());
va.addUpdateListener(new ValueAnimator.AnimatorUpdateListener() {
public void onAnimationUpdate(ValueAnimator animation) {
Integer value = (Integer) animation.getAnimatedValue();
detail.getLayoutParams().height = value.intValue();
detail.requestLayout();
}
});
va.setDuration(1000);
va.start();
}
};
The XML is just a basic ListView with the id of detail_menu_1.

The new element Recycler View include animations. You can use it with Support Library
https://developer.android.com/training/material/lists-cards.html

Buttons on an animated view respond to clicks even when off screen?

I have a LinearLayout, I'm applying a translation animation to it. I'm filling the animation before and after. Visually it works fine. The animation ends by translating the view off screen. But if I click an x,y coordinate on screen that happens to be where the view was at some point during its animation, a button on the view has its click listener fire.
The only solution I've found is to add an animation listener, and when the animation ends, mark the buttons on the (now out of view) layout to visibility=gone, enabled=false. This seems bizarre - the view is no longer on screen, but it's still responding to click events. Is this a known thing, I'm probably not setting the animation up correctly?
Thanks
----- Update --------
I refactored my animation a little. Instead of using animation.setFillAfter(true), I set the layout's visibility to GONE when the animation is complete. Now it doesn't register clicks when off-screen. Still interested to know if this is a known thing, as it'd be easier to simply not have to add an animation listener etc.

Translate Animations on lower level API( below honey comb) changes where the button is drawn, but not where the button physically exists within the container. So, you are on your own to handle this situation. For more information about this you can refer to this link. One way is to actually change the location of the button in the layout(not by animation). Here is how you can achieve this:
params = (LayoutParams) mBtn.getLayoutParams();
TranslateAnimation animation = new TranslateAnimation(0, 0, 0, 400);
animation.setDuration(2000);
animation.setAnimationListener(mAnimationListener);
mBtn.startAnimation(animation);
....
....
private AnimationListener mAnimationListener = new AnimationListener() {
#Override
public void onAnimationStart(Animation animation) {
}
#Override
public void onAnimationRepeat(Animation animation) {
}
#Override
public void onAnimationEnd(Animation animation) {
params.topMargin = params.topMargin + 400;
mButton.setLayoutParams(params);
}
};
Here by changing the layout params we are changing the physical position of the button.
In your case as view is going off the screen so you just need to change the visibility of the button(View.GONE) on animation end.

Android Layout Animation won't work

I have a LinearLayout (LayoutContentView) which can contain one or two view (SubView1 and SubView2) (they are eitherTextView or ImageView).
This layout is in another LinearLayout (MyScreenLayout).
I want to make an animation on LayoutContentView so it can move and show just a part of it in MyScreenLayout.
Both of these layouts have setClipChildren(false); so it can let it's children draw outside it-self.
Depending on different parameters, I can change the size of the content, and the size of the content I will show.
Basically, I expend from top to bottom to show the two subviews and unexpend for bottom to top to show only the second subview. Before I expend, I increase the size of the LayoutContentView, so it can show the two subviews, and after I unexpend, I decrease the size of the LayoutContentView, so it can only show the second subview, and it let space on the screen for other elements.
Here is my method for expending and un-expending LayoutContentView :
mLayoutContentView.clearAnimation();
float yFrom = 0.0F;
float yTo = 0.0F;
float xFrom = 0.0F;
float xTo = 0.0F;
if (expend) { // if we expend
// I change the height of my LayoutContentView so it we can show it's two subviews
final android.view.ViewGroup.LayoutParams lp = mLayoutContentView.getLayoutParams();
lp.height = subView1H + subView2H;
setLayoutParams(lp);
invalidate();
// we start the animation so it shows only the second subview
yFrom = -subView1H;
// and we animate from top to bottom until it shows the two subviews
yTo = 0;
} else { // if we un-expend
// we animate from bottom to top starting by showing the two subviews
yFrom = 0;
// and progressively hiding the first subview and showing only the second subview
yTo = -subView1H;
}
Animation anim = new TranslateAnimation(xFrom, xTo, yFrom, yTo);
anim.setDuration(1000);
anim.setFillAfter(true);
anim.setFillEnabled(true);
anim.setAnimationListener(new AnimationListener() {
#Override
public void onAnimationStart(Animation animation) {
}
#Override
public void onAnimationRepeat(Animation animation) {
}
#Override
public void onAnimationEnd(Animation animation) {
if (!expend) {
// if we un expend at the end of the animation we can set the size of LayoutContentView to the size of the second subview again
final android.view.ViewGroup.LayoutParams lp = mLayoutContentView.getLayoutParams();
lp.height = subView2H;
mLayoutContentView.setLayoutParams(lp);
invalidate();
}
}
});
mLayoutContentView.startAnimation(anim);
The way I made my animation I need it to apply on LayoutContentView, the layout which contain two subview, and with startAnimation() it doesn't do the animation.
I tried to use a LayoutAnimationController, but instead of doing the animation on the LayoutContentView, it does it on each of its children...
I also tried to do the animation on each children myself, but I don't know why, the second subview isn't shown.
Each time I've tried to use HierarchyViewer, but it's does see the change made by the animation.
Does anyone know a solution or have faced the same problem and found a good solution ?
EDIT :
Well it seems that if you set a background color to your TextView and move them with animation, the background move but even if you have set the fill after parameter to your animation, the background moves back to it's original position or something like that, and therefore as I set a background color to both of my SubViews, somewhat one of the SubView's background hide the background of the other...
And there also a problem if after the animation, one of the SubView is still outside the its layout, there is also a problem during the animation, so I add a limitation to what I intended to here too.