Intent not opening playstore

Intent not opening playstore - android

When I tried to open play store listing of my app via intent, it is opening playstore app and shows this message, "to view this content, install and setup a web browsing app". Please see the screenshot.
I have set chrome as default browsing app. this is the code
private void launchRateUS() {
try {
Intent rateIntent = rate("market://details?id=" + getPackageName());
startActivity(rateIntent);
} catch (ActivityNotFoundException e) {
Intent rateIntent = rate("https://play.google.com/store/apps/details?id=" + getPackageName());
startActivity(rateIntent);
}
}
private Intent rate(String url) {
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(String.format("%s?id=%s", url, getPackageName())));
int flags = Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_ACTIVITY_MULTIPLE_TASK;
if (Build.VERSION.SDK_INT >= 21) {
flags |= Intent.FLAG_ACTIVITY_NEW_DOCUMENT;
} else {
flags |= Intent.FLAG_ACTIVITY_CLEAR_WHEN_TASK_RESET;
}
intent.addFlags(flags);
return intent;
}
What is wrong with the code? How to show playstore listing instead of this message?

You are doubling up your ?id=packagename in your rate function.
Just use the url you pass in.
private Intent rate(String url) {
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
...

Try it
Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("http://www.google.com"));
startActivity(browserIntent);

Related

Opening facebook profile page in facebook native app from my android app

I'm trying to open a specific profile page from my android app, in the native facebook app. I've seen many answers about this topic, but none of them worked for me currently (maybe because some new versions)
Right now, I'm trying to open it like that:
public static Intent getFacebookIntent(PackageManager pm, String url ,String fbID) {
Intent intent;
try {
int versionCode = pm.getPackageInfo("com.facebook.katana", 0).versionCode;
boolean activated = pm.getApplicationInfo("com.facebook.katana", 0).enabled;
if(activated){
if ((versionCode >= 3002850)) {
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("fb://facewebmodal/f?href=" + url));
return intent;
} else {
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("fb://page/" + fbID));
return intent;
}
}else{
intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
return intent;
}
} catch (PackageManager.NameNotFoundException e) {
intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
return intent;
}
}
where fbID its the user id, and url is the "link" from user graph request.
I've tried to change the url, to a specific url like
"https://www.facebook.com/some_user_name" but not luck.
the result of that code, is that the facebook app opens and crashes.
I do able to open it with webpage link.
Thanks

How to get default sms,gallery,call,contacts and browser app and package name in android?

I am creating an home replacement app for android(Launcher) and I want to place the sms , call, contacts ,gallery and browser apps in the home screen. How can I know the package name for them.
If the user is using a custom contact app as the default one , I need to get the package name of that one and not the android contact app.
How can I achieve this?Thanks.

You can use this code to get Intent to those thing. The problomatic one is the SMS one.
For sms:
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT) {
String defaultSmsPackageName = Telephony.Sms.getDefaultSmsPackage(ctx);
Intent lunchIntent;
if (defaultSmsPackageName != null) {
launchIntent = pm.getLaunchIntentForPackage(defaultSmsPackageName);
} else {
String SMS_MIME_TYPE = "vnd.android-dir/mms-sms";
launchIntent = new Intent(Intent.ACTION_MAIN);
launchIntent.setType(SMS_MIME_TYPE);
}
} else {
String SMS_MIME_TYPE = "vnd.android-dir/mms-sms";
launchIntent = new Intent(Intent.ACTION_MAIN);
launchIntent.setType(SMS_MIME_TYPE);
}
For call:
Intent intent = new Intent(Intent.ACTION_DIAL);
For browser:
Intent intent;
Intent queryIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("http://www.google.com"));
ActivityInfo af = queryIntent.resolveActivityInfo(pm, 0);
intent = new Intent(Intent.ACTION_MAIN);
intent.setClassName(af.packageName, af.name);
For photos:
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("content://media/internal/images/media"));
try {
context.startActivity(intent);
} catch (ActivityNotFoundException eee){
try {
intent = new Intent(Intent.ACTION_VIEW);
intent.setType(android.provider.MediaStore.Images.Media.CONTENT_TYPE);
} catch (Exception err){
Toast.makeText(context, "This app not supported in your device", Toast.LENGTH_LONG).show();
}
}

You could try getting the default launch activity for a specific Intent, for example for SMS you do an Intent with an sms:-URI, and from there check the 'default'-Activity its launching, on the way getting its package name and other details.
Get Preferred/Default app on Android

How to open Google play store app directly without chooser intent [duplicate]

I have open the Google Play store using the following code
Intent i = new Intent(android.content.Intent.ACTION_VIEW);
i.setData(Uri.parse("https://play.google.com/store/apps/details?id=my packagename "));
startActivity(i);.
But it shows me a Complete Action View as to select the option (browser/play store). I need to open the application in Play Store directly.

You can do this using the market:// prefix.
Java
final String appPackageName = getPackageName(); // getPackageName() from Context or Activity object
try {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=" + appPackageName)));
} catch (android.content.ActivityNotFoundException anfe) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + appPackageName)));
}
Kotlin
try {
startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=$packageName")))
} catch (e: ActivityNotFoundException) {
startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=$packageName")))
}
We use a try/catch block here because an Exception will be thrown if the Play Store is not installed on the target device.
NOTE: Any app can register as capable of handling the market://details?id=<appId> URI. If you want to specifically target Google Play, the solution in Berťák's answer is a good alternative.

Many answers here suggest to use Uri.parse("market://details?id=" + appPackageName)) to open Google Play, but I think it is insufficient in fact:
Some third-party applications can use its own intent-filters with "market://" scheme defined, thus they can process supplied Uri instead of Google Play (I experienced this situation with e.g.SnapPea application). The question is "How to open the Google Play Store?", so I assume, that you do not want to open any other application. Please also note, that e.g. app rating is only relevant in GP Store app etc...
To open Google Play AND ONLY Google Play I use this method:
public static void openAppRating(Context context) {
// you can also use BuildConfig.APPLICATION_ID
String appId = context.getPackageName();
Intent rateIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("market://details?id=" + appId));
boolean marketFound = false;
// find all applications able to handle our rateIntent
final List<ResolveInfo> otherApps = context.getPackageManager()
.queryIntentActivities(rateIntent, 0);
for (ResolveInfo otherApp: otherApps) {
// look for Google Play application
if (otherApp.activityInfo.applicationInfo.packageName
.equals("com.android.vending")) {
ActivityInfo otherAppActivity = otherApp.activityInfo;
ComponentName componentName = new ComponentName(
otherAppActivity.applicationInfo.packageName,
otherAppActivity.name
);
// make sure it does NOT open in the stack of your activity
rateIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
// task reparenting if needed
rateIntent.addFlags(Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED);
// if the Google Play was already open in a search result
// this make sure it still go to the app page you requested
rateIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
// this make sure only the Google Play app is allowed to
// intercept the intent
rateIntent.setComponent(componentName);
context.startActivity(rateIntent);
marketFound = true;
break;
}
}
// if GP not present on device, open web browser
if (!marketFound) {
Intent webIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("https://play.google.com/store/apps/details?id="+appId));
context.startActivity(webIntent);
}
}
The point is that when more applications beside Google Play can open our intent, app-chooser dialog is skipped and GP app is started directly.
UPDATE:
Sometimes it seems that it opens GP app only, without opening the app's profile. As TrevorWiley suggested in his comment, Intent.FLAG_ACTIVITY_CLEAR_TOP could fix the problem. (I didn't test it myself yet...)
See this answer for understanding what Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED does.

Go on Android Developer official link as tutorial step by step see and got the code for your application package from play store if exists or play store apps not exists then open application from web browser.
Android Developer official link
https://developer.android.com/distribute/tools/promote/linking.html
Linking to a Application Page
From a web site: https://play.google.com/store/apps/details?id=<package_name>
From an Android app: market://details?id=<package_name>
Linking to a Product List
From a web site: https://play.google.com/store/search?q=pub:<publisher_name>
From an Android app: market://search?q=pub:<publisher_name>
Linking to a Search Result
From a web site: https://play.google.com/store/search?q=<search_query>&c=apps
From an Android app: market://search?q=<seach_query>&c=apps

While Eric's answer is correct and Berťák's code also works. I think this combines both more elegantly.
try {
Intent appStoreIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=" + appPackageName));
appStoreIntent.setPackage("com.android.vending");
startActivity(appStoreIntent);
} catch (android.content.ActivityNotFoundException exception) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + appPackageName)));
}
By using setPackage, you force the device to use the Play Store. If there is no Play Store installed, the Exception will be caught.

try this
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse("market://details?id=com.example.android"));
startActivity(intent);

All of the above answers open Google Play in a new view of the same app, if you actually want to open Google Play (or any other app) independently:
Intent launchIntent = getPackageManager().getLaunchIntentForPackage("com.android.vending");
// package name and activity
ComponentName comp = new ComponentName("com.android.vending",
"com.google.android.finsky.activities.LaunchUrlHandlerActivity");
launchIntent.setComponent(comp);
// sample to open facebook app
launchIntent.setData(Uri.parse("market://details?id=com.facebook.katana"));
startActivity(launchIntent);
The important part is that actually opens google play or any other app independently.
Most of what I have seen uses the approach of the other answers and it was not what I needed hopefully this helps somebody.
Regards.

You can check if the Google Play Store app is installed and, if this is the case, you can use the "market://" protocol.
final String my_package_name = "........." // <- HERE YOUR PACKAGE NAME!!
String url = "";
try {
//Check whether Google Play store is installed or not:
this.getPackageManager().getPackageInfo("com.android.vending", 0);
url = "market://details?id=" + my_package_name;
} catch ( final Exception e ) {
url = "https://play.google.com/store/apps/details?id=" + my_package_name;
}
//Open the app page in Google Play store:
final Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_CLEAR_WHEN_TASK_RESET);
startActivity(intent);

use market://
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=" + my_packagename));

As the official docs use https:// instead of market://, this combines Eric's and M3-n50's answer with code reuse (don't repeat yourself):
Intent intent = new Intent(Intent.ACTION_VIEW)
.setData(Uri.parse("https://play.google.com/store/apps/details?id=" + getPackageName()));
try {
startActivity(new Intent(intent)
.setPackage("com.android.vending"));
} catch (android.content.ActivityNotFoundException exception) {
startActivity(intent);
}
It tries to open with the GPlay app if it exists and falls back to default.

Some of the answers to this question are outdated.
What worked for me (in 2020) was to explicitly tell the intent to skip the chooser and directly open the play store app, according to this link:
"If you want to link to your products from an Android app, create an
Intent that opens a URL. As you configure this intent, pass
"com.android.vending" into Intent.setPackage() so that users see your
app's details in the Google Play Store app instead of a chooser."
This is the Kotlin code I used to direct users to viewing the app containing the package name com.google.android.apps.maps in Google Play:
val intent = Intent(Intent.ACTION_VIEW).apply {
data = Uri.parse("http://play.google.com/store/apps/details?id=com.google.android.apps.maps")
setPackage("com.android.vending")
}
startActivity(intent)
I hope that helps someone!

Kotlin:
Extension:
fun Activity.openAppInGooglePlay(){
val appId = BuildConfig.APPLICATION_ID
try {
this.startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=$appId")))
} catch (anfe: ActivityNotFoundException) {
this.startActivity(
Intent(
Intent.ACTION_VIEW,
Uri.parse("https://play.google.com/store/apps/details?id=$appId")
)
)
}}
Method:
fun openAppInGooglePlay(activity:Activity){
val appId = BuildConfig.APPLICATION_ID
try {
activity.startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=$appId")))
} catch (anfe: ActivityNotFoundException) {
activity.startActivity(
Intent(
Intent.ACTION_VIEW,
Uri.parse("https://play.google.com/store/apps/details?id=$appId")
)
)
}
}

You can do:
final Uri marketUri = Uri.parse("market://details?id=" + packageName);
startActivity(new Intent(Intent.ACTION_VIEW, marketUri));
get Reference here:
You can also try the approach described in the accepted answer of this question:
Cannot determine whether Google play store is installed or not on Android device

Very late in the party Official docs are here. And code described is
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse(
"https://play.google.com/store/apps/details?id=com.example.android"));
intent.setPackage("com.android.vending");
startActivity(intent);
As you configure this intent, pass "com.android.vending" into Intent.setPackage() so that users see your app's details in the Google Play Store app instead of a chooser.
for KOTLIN
val intent = Intent(Intent.ACTION_VIEW).apply {
data = Uri.parse(
"https://play.google.com/store/apps/details?id=com.example.android")
setPackage("com.android.vending")
}
startActivity(intent)
If you have published an instant app using Google Play Instant, you can launch the app as follows:
Intent intent = new Intent(Intent.ACTION_VIEW);
Uri.Builder uriBuilder = Uri.parse("https://play.google.com/store/apps/details")
.buildUpon()
.appendQueryParameter("id", "com.example.android")
.appendQueryParameter("launch", "true");
// Optional parameters, such as referrer, are passed onto the launched
// instant app. You can retrieve these parameters using
// Activity.getIntent().getData().
uriBuilder.appendQueryParameter("referrer", "exampleCampaignId");
intent.setData(uriBuilder.build());
intent.setPackage("com.android.vending");
startActivity(intent);
For KOTLIN
val uriBuilder = Uri.parse("https://play.google.com/store/apps/details")
.buildUpon()
.appendQueryParameter("id", "com.example.android")
.appendQueryParameter("launch", "true")
// Optional parameters, such as referrer, are passed onto the launched
// instant app. You can retrieve these parameters using Activity.intent.data.
uriBuilder.appendQueryParameter("referrer", "exampleCampaignId")
val intent = Intent(Intent.ACTION_VIEW).apply {
data = uriBuilder.build()
setPackage("com.android.vending")
}
startActivity(intent)

Ready-to-use solution:
public class GoogleServicesUtils {
public static void openAppInGooglePlay(Context context) {
final String appPackageName = context.getPackageName();
try {
context.startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=" + appPackageName)));
} catch (android.content.ActivityNotFoundException e) { // if there is no Google Play on device
context.startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + appPackageName)));
}
}
}
Based on Eric's answer.

Kotlin
fun openAppInPlayStore(appPackageName: String) {
try {
startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=$appPackageName")))
} catch (exception: android.content.ActivityNotFoundException) {
startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=$appPackageName")))
}
}

This link will open the app automatically in market:// if you are on Android and in browser if you are on PC.
https://play.app.goo.gl/?link=https://play.google.com/store/apps/details?id=com.app.id&ddl=1&pcampaignid=web_ddl_1

If you want to open Google Play store from your app then use this command directy: market://details?gotohome=com.yourAppName, it will open your app's Google Play store pages.
Web: http://play.google.com/store/apps/details?id=
App: market://details?id=
Show all apps by a specific publisher
Web: http://play.google.com/store/search?q=pub:
App: market://search?q=pub:
Search for apps that using the Query on its title or description
Web: http://play.google.com/store/search?q=
App: market://search?q=
Reference: https://tricklio.com/market-details-gotohome-1/

Here is the final code from the answers above that first attempts to open the app using the Google play store app and specifically play store, if it fails, it will start the action view using the web version:
Credits to #Eric, #Jonathan Caballero
public void goToPlayStore() {
String playStoreMarketUrl = "market://details?id=";
String playStoreWebUrl = "https://play.google.com/store/apps/details?id=";
String packageName = getActivity().getPackageName();
try {
Intent intent = getActivity()
.getPackageManager()
.getLaunchIntentForPackage("com.android.vending");
if (intent != null) {
ComponentName androidComponent = new ComponentName("com.android.vending",
"com.google.android.finsky.activities.LaunchUrlHandlerActivity");
intent.setComponent(androidComponent);
intent.setData(Uri.parse(playStoreMarketUrl + packageName));
} else {
intent = new Intent(Intent.ACTION_VIEW, Uri.parse(playStoreMarketUrl + packageName));
}
startActivity(intent);
} catch (ActivityNotFoundException e) {
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(playStoreWebUrl + packageName));
startActivity(intent);
}
}

I have combined both Berťák and Stefano Munarini answer to creating a hybrid solution which handles both Rate this App and Show More App scenario.
/**
* This method checks if GooglePlay is installed or not on the device and accordingly handle
* Intents to view for rate App or Publisher's Profile
*
* #param showPublisherProfile pass true if you want to open Publisher Page else pass false to open APp page
* #param publisherID pass Dev ID if you have passed PublisherProfile true
*/
public void openPlayStore(boolean showPublisherProfile, String publisherID) {
//Error Handling
if (publisherID == null || !publisherID.isEmpty()) {
publisherID = "";
//Log and continue
Log.w("openPlayStore Method", "publisherID is invalid");
}
Intent openPlayStoreIntent;
boolean isGooglePlayInstalled = false;
if (showPublisherProfile) {
//Open Publishers Profile on PlayStore
openPlayStoreIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("market://search?q=pub:" + publisherID));
} else {
//Open this App on PlayStore
openPlayStoreIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("market://details?id=" + getPackageName()));
}
// find all applications who can handle openPlayStoreIntent
final List<ResolveInfo> otherApps = getPackageManager()
.queryIntentActivities(openPlayStoreIntent, 0);
for (ResolveInfo otherApp : otherApps) {
// look for Google Play application
if (otherApp.activityInfo.applicationInfo.packageName.equals("com.android.vending")) {
ActivityInfo otherAppActivity = otherApp.activityInfo;
ComponentName componentName = new ComponentName(
otherAppActivity.applicationInfo.packageName,
otherAppActivity.name
);
// make sure it does NOT open in the stack of your activity
openPlayStoreIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
// task reparenting if needed
openPlayStoreIntent.addFlags(Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED);
// if the Google Play was already open in a search result
// this make sure it still go to the app page you requested
openPlayStoreIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
// this make sure only the Google Play app is allowed to
// intercept the intent
openPlayStoreIntent.setComponent(componentName);
startActivity(openPlayStoreIntent);
isGooglePlayInstalled = true;
break;
}
}
// if Google Play is not Installed on the device, open web browser
if (!isGooglePlayInstalled) {
Intent webIntent;
if (showPublisherProfile) {
//Open Publishers Profile on web browser
webIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("http://play.google.com/store/search?q=pub:" + getPackageName()));
} else {
//Open this App on web browser
webIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("https://play.google.com/store/apps/details?id=" + getPackageName()));
}
startActivity(webIntent);
}
}
Usage
To Open Publishers Profile
#OnClick(R.id.ll_more_apps)
public void showMoreApps() {
openPlayStore(true, "Hitesh Sahu");
}
To Open App Page on PlayStore
#OnClick(R.id.ll_rate_this_app)
public void openAppInPlayStore() {
openPlayStore(false, "");
}

public void launchPlayStore(Context context, String packageName) {
Intent intent = null;
try {
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("market://details?id=" + packageName));
context.startActivity(intent);
} catch (android.content.ActivityNotFoundException anfe) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + packageName)));
}
}

My kotlin entension function for this purpose
fun Context.canPerformIntent(intent: Intent): Boolean {
val mgr = this.packageManager
val list = mgr.queryIntentActivities(intent, PackageManager.MATCH_DEFAULT_ONLY)
return list.size > 0
}
And in your activity
val uri = if (canPerformIntent(Intent(Intent.ACTION_VIEW, Uri.parse("market://")))) {
Uri.parse("market://details?id=" + appPackageName)
} else {
Uri.parse("https://play.google.com/store/apps/details?id=" + appPackageName)
}
startActivity(Intent(Intent.ACTION_VIEW, uri))

KOTLIN :
create extension in context.
fun Context.openPlayStoreApp(pkgName:String?){
if(!pkgName.isNullOrEmpty()) {
try {
startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=$pkgName")))
} catch (e: ActivityNotFoundException) {
startActivity(
Intent(
Intent.ACTION_VIEW,
Uri.parse("https://play.google.com/store/apps/details?id=$pkgName")
)
)
}
}
}
Hope it should work.

Peoples, dont forget that you could actually get something more from it. I mean UTM tracking for example. https://developers.google.com/analytics/devguides/collection/android/v4/campaigns
public static final String MODULE_ICON_PACK_FREE = "com.example.iconpack_free";
public static final String APP_STORE_URI =
"market://details?id=%s&referrer=utm_source=%s&utm_medium=app&utm_campaign=plugin";
public static final String APP_STORE_GENERIC_URI =
"https://play.google.com/store/apps/details?id=%s&referrer=utm_source=%s&utm_medium=app&utm_campaign=plugin";
try {
startActivity(new Intent(
Intent.ACTION_VIEW,
Uri.parse(String.format(Locale.US,
APP_STORE_URI,
MODULE_ICON_PACK_FREE,
getPackageName()))).addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP));
} catch (android.content.ActivityNotFoundException anfe) {
startActivity(new Intent(
Intent.ACTION_VIEW,
Uri.parse(String.format(Locale.US,
APP_STORE_GENERIC_URI,
MODULE_ICON_PACK_FREE,
getPackageName()))).addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP));
}

A kotlin verison with fallback and current syntax
fun openAppInPlayStore() {
val uri = Uri.parse("market://details?id=" + context.packageName)
val goToMarketIntent = Intent(Intent.ACTION_VIEW, uri)
var flags = Intent.FLAG_ACTIVITY_NO_HISTORY or Intent.FLAG_ACTIVITY_MULTIPLE_TASK or Intent.FLAG_ACTIVITY_NEW_TASK
flags = if (Build.VERSION.SDK_INT >= 21) {
flags or Intent.FLAG_ACTIVITY_NEW_DOCUMENT
} else {
flags or Intent.FLAG_ACTIVITY_CLEAR_TASK
}
goToMarketIntent.addFlags(flags)
try {
startActivity(context, goToMarketIntent, null)
} catch (e: ActivityNotFoundException) {
val intent = Intent(Intent.ACTION_VIEW,
Uri.parse("http://play.google.com/store/apps/details?id=" + context.packageName))
startActivity(context, intent, null)
}
}

Tested. This should work fine.
val context = LocalContext.current
val onOpenPlayStore: () -> Unit = {
try {
LOG.d(tag, "onOpenPlayStore ${context.packageName}")
val intent = Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=${context.packageName}"))
startActivity(context, intent, null)
} catch (e: ActivityNotFoundException) {
var intent = Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=${context.packageName}"))
startActivity(context, intent, null)
}
}

For Rate Application: Redirect to Playstore.
In Flutter, you can do it through a Platform channel Like this
Flutter Part:-
static const platform = const MethodChannel('rateApp'); // initialize
onTap: platform.invokeMethod('urls', {'android_id': 'com.xyz'}),
Now Android Native Part(Java):
private static final String RATEAPP = "rateApp"; // initialize variable
// Now in ConfigureFlutterEngine funtion:
new MethodChannel(flutterEngine.getDartExecutor().getBinaryMessenger(), RATEAPP)
.setMethodCallHandler(
(call, result) -> {
if (call.method.equals("urls") && call.hasArgument("android_id")) {
String id = call.argument("android_id").toString();
try {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("$uri" + id)));
} catch (android.content.ActivityNotFoundException anfe) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + id)));
}
result.success("Done");
} else {
result.notImplemented();
}
}
);

How to open the Google Play Store directly from my Android application?

I have open the Google Play store using the following code
Intent i = new Intent(android.content.Intent.ACTION_VIEW);
i.setData(Uri.parse("https://play.google.com/store/apps/details?id=my packagename "));
startActivity(i);.
But it shows me a Complete Action View as to select the option (browser/play store). I need to open the application in Play Store directly.

You can do this using the market:// prefix.
Java
final String appPackageName = getPackageName(); // getPackageName() from Context or Activity object
try {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=" + appPackageName)));
} catch (android.content.ActivityNotFoundException anfe) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + appPackageName)));
}
Kotlin
try {
startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=$packageName")))
} catch (e: ActivityNotFoundException) {
startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=$packageName")))
}
We use a try/catch block here because an Exception will be thrown if the Play Store is not installed on the target device.
NOTE: Any app can register as capable of handling the market://details?id=<appId> URI. If you want to specifically target Google Play, the solution in Berťák's answer is a good alternative.

Many answers here suggest to use Uri.parse("market://details?id=" + appPackageName)) to open Google Play, but I think it is insufficient in fact:
Some third-party applications can use its own intent-filters with "market://" scheme defined, thus they can process supplied Uri instead of Google Play (I experienced this situation with e.g.SnapPea application). The question is "How to open the Google Play Store?", so I assume, that you do not want to open any other application. Please also note, that e.g. app rating is only relevant in GP Store app etc...
To open Google Play AND ONLY Google Play I use this method:
public static void openAppRating(Context context) {
// you can also use BuildConfig.APPLICATION_ID
String appId = context.getPackageName();
Intent rateIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("market://details?id=" + appId));
boolean marketFound = false;
// find all applications able to handle our rateIntent
final List<ResolveInfo> otherApps = context.getPackageManager()
.queryIntentActivities(rateIntent, 0);
for (ResolveInfo otherApp: otherApps) {
// look for Google Play application
if (otherApp.activityInfo.applicationInfo.packageName
.equals("com.android.vending")) {
ActivityInfo otherAppActivity = otherApp.activityInfo;
ComponentName componentName = new ComponentName(
otherAppActivity.applicationInfo.packageName,
otherAppActivity.name
);
// make sure it does NOT open in the stack of your activity
rateIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
// task reparenting if needed
rateIntent.addFlags(Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED);
// if the Google Play was already open in a search result
// this make sure it still go to the app page you requested
rateIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
// this make sure only the Google Play app is allowed to
// intercept the intent
rateIntent.setComponent(componentName);
context.startActivity(rateIntent);
marketFound = true;
break;
}
}
// if GP not present on device, open web browser
if (!marketFound) {
Intent webIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("https://play.google.com/store/apps/details?id="+appId));
context.startActivity(webIntent);
}
}
The point is that when more applications beside Google Play can open our intent, app-chooser dialog is skipped and GP app is started directly.
UPDATE:
Sometimes it seems that it opens GP app only, without opening the app's profile. As TrevorWiley suggested in his comment, Intent.FLAG_ACTIVITY_CLEAR_TOP could fix the problem. (I didn't test it myself yet...)
See this answer for understanding what Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED does.

Go on Android Developer official link as tutorial step by step see and got the code for your application package from play store if exists or play store apps not exists then open application from web browser.
Android Developer official link
https://developer.android.com/distribute/tools/promote/linking.html
Linking to a Application Page
From a web site: https://play.google.com/store/apps/details?id=<package_name>
From an Android app: market://details?id=<package_name>
Linking to a Product List
From a web site: https://play.google.com/store/search?q=pub:<publisher_name>
From an Android app: market://search?q=pub:<publisher_name>
Linking to a Search Result
From a web site: https://play.google.com/store/search?q=<search_query>&c=apps
From an Android app: market://search?q=<seach_query>&c=apps

While Eric's answer is correct and Berťák's code also works. I think this combines both more elegantly.
try {
Intent appStoreIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=" + appPackageName));
appStoreIntent.setPackage("com.android.vending");
startActivity(appStoreIntent);
} catch (android.content.ActivityNotFoundException exception) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + appPackageName)));
}
By using setPackage, you force the device to use the Play Store. If there is no Play Store installed, the Exception will be caught.

try this
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse("market://details?id=com.example.android"));
startActivity(intent);

All of the above answers open Google Play in a new view of the same app, if you actually want to open Google Play (or any other app) independently:
Intent launchIntent = getPackageManager().getLaunchIntentForPackage("com.android.vending");
// package name and activity
ComponentName comp = new ComponentName("com.android.vending",
"com.google.android.finsky.activities.LaunchUrlHandlerActivity");
launchIntent.setComponent(comp);
// sample to open facebook app
launchIntent.setData(Uri.parse("market://details?id=com.facebook.katana"));
startActivity(launchIntent);
The important part is that actually opens google play or any other app independently.
Most of what I have seen uses the approach of the other answers and it was not what I needed hopefully this helps somebody.
Regards.

You can check if the Google Play Store app is installed and, if this is the case, you can use the "market://" protocol.
final String my_package_name = "........." // <- HERE YOUR PACKAGE NAME!!
String url = "";
try {
//Check whether Google Play store is installed or not:
this.getPackageManager().getPackageInfo("com.android.vending", 0);
url = "market://details?id=" + my_package_name;
} catch ( final Exception e ) {
url = "https://play.google.com/store/apps/details?id=" + my_package_name;
}
//Open the app page in Google Play store:
final Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_CLEAR_WHEN_TASK_RESET);
startActivity(intent);

use market://
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=" + my_packagename));

As the official docs use https:// instead of market://, this combines Eric's and M3-n50's answer with code reuse (don't repeat yourself):
Intent intent = new Intent(Intent.ACTION_VIEW)
.setData(Uri.parse("https://play.google.com/store/apps/details?id=" + getPackageName()));
try {
startActivity(new Intent(intent)
.setPackage("com.android.vending"));
} catch (android.content.ActivityNotFoundException exception) {
startActivity(intent);
}
It tries to open with the GPlay app if it exists and falls back to default.

Some of the answers to this question are outdated.
What worked for me (in 2020) was to explicitly tell the intent to skip the chooser and directly open the play store app, according to this link:
"If you want to link to your products from an Android app, create an
Intent that opens a URL. As you configure this intent, pass
"com.android.vending" into Intent.setPackage() so that users see your
app's details in the Google Play Store app instead of a chooser."
This is the Kotlin code I used to direct users to viewing the app containing the package name com.google.android.apps.maps in Google Play:
val intent = Intent(Intent.ACTION_VIEW).apply {
data = Uri.parse("http://play.google.com/store/apps/details?id=com.google.android.apps.maps")
setPackage("com.android.vending")
}
startActivity(intent)
I hope that helps someone!

Kotlin:
Extension:
fun Activity.openAppInGooglePlay(){
val appId = BuildConfig.APPLICATION_ID
try {
this.startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=$appId")))
} catch (anfe: ActivityNotFoundException) {
this.startActivity(
Intent(
Intent.ACTION_VIEW,
Uri.parse("https://play.google.com/store/apps/details?id=$appId")
)
)
}}
Method:
fun openAppInGooglePlay(activity:Activity){
val appId = BuildConfig.APPLICATION_ID
try {
activity.startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=$appId")))
} catch (anfe: ActivityNotFoundException) {
activity.startActivity(
Intent(
Intent.ACTION_VIEW,
Uri.parse("https://play.google.com/store/apps/details?id=$appId")
)
)
}
}

You can do:
final Uri marketUri = Uri.parse("market://details?id=" + packageName);
startActivity(new Intent(Intent.ACTION_VIEW, marketUri));
get Reference here:
You can also try the approach described in the accepted answer of this question:
Cannot determine whether Google play store is installed or not on Android device

Very late in the party Official docs are here. And code described is
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse(
"https://play.google.com/store/apps/details?id=com.example.android"));
intent.setPackage("com.android.vending");
startActivity(intent);
As you configure this intent, pass "com.android.vending" into Intent.setPackage() so that users see your app's details in the Google Play Store app instead of a chooser.
for KOTLIN
val intent = Intent(Intent.ACTION_VIEW).apply {
data = Uri.parse(
"https://play.google.com/store/apps/details?id=com.example.android")
setPackage("com.android.vending")
}
startActivity(intent)
If you have published an instant app using Google Play Instant, you can launch the app as follows:
Intent intent = new Intent(Intent.ACTION_VIEW);
Uri.Builder uriBuilder = Uri.parse("https://play.google.com/store/apps/details")
.buildUpon()
.appendQueryParameter("id", "com.example.android")
.appendQueryParameter("launch", "true");
// Optional parameters, such as referrer, are passed onto the launched
// instant app. You can retrieve these parameters using
// Activity.getIntent().getData().
uriBuilder.appendQueryParameter("referrer", "exampleCampaignId");
intent.setData(uriBuilder.build());
intent.setPackage("com.android.vending");
startActivity(intent);
For KOTLIN
val uriBuilder = Uri.parse("https://play.google.com/store/apps/details")
.buildUpon()
.appendQueryParameter("id", "com.example.android")
.appendQueryParameter("launch", "true")
// Optional parameters, such as referrer, are passed onto the launched
// instant app. You can retrieve these parameters using Activity.intent.data.
uriBuilder.appendQueryParameter("referrer", "exampleCampaignId")
val intent = Intent(Intent.ACTION_VIEW).apply {
data = uriBuilder.build()
setPackage("com.android.vending")
}
startActivity(intent)

Ready-to-use solution:
public class GoogleServicesUtils {
public static void openAppInGooglePlay(Context context) {
final String appPackageName = context.getPackageName();
try {
context.startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=" + appPackageName)));
} catch (android.content.ActivityNotFoundException e) { // if there is no Google Play on device
context.startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + appPackageName)));
}
}
}
Based on Eric's answer.

Kotlin
fun openAppInPlayStore(appPackageName: String) {
try {
startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=$appPackageName")))
} catch (exception: android.content.ActivityNotFoundException) {
startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=$appPackageName")))
}
}

This link will open the app automatically in market:// if you are on Android and in browser if you are on PC.
https://play.app.goo.gl/?link=https://play.google.com/store/apps/details?id=com.app.id&ddl=1&pcampaignid=web_ddl_1

If you want to open Google Play store from your app then use this command directy: market://details?gotohome=com.yourAppName, it will open your app's Google Play store pages.
Web: http://play.google.com/store/apps/details?id=
App: market://details?id=
Show all apps by a specific publisher
Web: http://play.google.com/store/search?q=pub:
App: market://search?q=pub:
Search for apps that using the Query on its title or description
Web: http://play.google.com/store/search?q=
App: market://search?q=
Reference: https://tricklio.com/market-details-gotohome-1/

Here is the final code from the answers above that first attempts to open the app using the Google play store app and specifically play store, if it fails, it will start the action view using the web version:
Credits to #Eric, #Jonathan Caballero
public void goToPlayStore() {
String playStoreMarketUrl = "market://details?id=";
String playStoreWebUrl = "https://play.google.com/store/apps/details?id=";
String packageName = getActivity().getPackageName();
try {
Intent intent = getActivity()
.getPackageManager()
.getLaunchIntentForPackage("com.android.vending");
if (intent != null) {
ComponentName androidComponent = new ComponentName("com.android.vending",
"com.google.android.finsky.activities.LaunchUrlHandlerActivity");
intent.setComponent(androidComponent);
intent.setData(Uri.parse(playStoreMarketUrl + packageName));
} else {
intent = new Intent(Intent.ACTION_VIEW, Uri.parse(playStoreMarketUrl + packageName));
}
startActivity(intent);
} catch (ActivityNotFoundException e) {
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(playStoreWebUrl + packageName));
startActivity(intent);
}
}

I have combined both Berťák and Stefano Munarini answer to creating a hybrid solution which handles both Rate this App and Show More App scenario.
/**
* This method checks if GooglePlay is installed or not on the device and accordingly handle
* Intents to view for rate App or Publisher's Profile
*
* #param showPublisherProfile pass true if you want to open Publisher Page else pass false to open APp page
* #param publisherID pass Dev ID if you have passed PublisherProfile true
*/
public void openPlayStore(boolean showPublisherProfile, String publisherID) {
//Error Handling
if (publisherID == null || !publisherID.isEmpty()) {
publisherID = "";
//Log and continue
Log.w("openPlayStore Method", "publisherID is invalid");
}
Intent openPlayStoreIntent;
boolean isGooglePlayInstalled = false;
if (showPublisherProfile) {
//Open Publishers Profile on PlayStore
openPlayStoreIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("market://search?q=pub:" + publisherID));
} else {
//Open this App on PlayStore
openPlayStoreIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("market://details?id=" + getPackageName()));
}
// find all applications who can handle openPlayStoreIntent
final List<ResolveInfo> otherApps = getPackageManager()
.queryIntentActivities(openPlayStoreIntent, 0);
for (ResolveInfo otherApp : otherApps) {
// look for Google Play application
if (otherApp.activityInfo.applicationInfo.packageName.equals("com.android.vending")) {
ActivityInfo otherAppActivity = otherApp.activityInfo;
ComponentName componentName = new ComponentName(
otherAppActivity.applicationInfo.packageName,
otherAppActivity.name
);
// make sure it does NOT open in the stack of your activity
openPlayStoreIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
// task reparenting if needed
openPlayStoreIntent.addFlags(Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED);
// if the Google Play was already open in a search result
// this make sure it still go to the app page you requested
openPlayStoreIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
// this make sure only the Google Play app is allowed to
// intercept the intent
openPlayStoreIntent.setComponent(componentName);
startActivity(openPlayStoreIntent);
isGooglePlayInstalled = true;
break;
}
}
// if Google Play is not Installed on the device, open web browser
if (!isGooglePlayInstalled) {
Intent webIntent;
if (showPublisherProfile) {
//Open Publishers Profile on web browser
webIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("http://play.google.com/store/search?q=pub:" + getPackageName()));
} else {
//Open this App on web browser
webIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("https://play.google.com/store/apps/details?id=" + getPackageName()));
}
startActivity(webIntent);
}
}
Usage
To Open Publishers Profile
#OnClick(R.id.ll_more_apps)
public void showMoreApps() {
openPlayStore(true, "Hitesh Sahu");
}
To Open App Page on PlayStore
#OnClick(R.id.ll_rate_this_app)
public void openAppInPlayStore() {
openPlayStore(false, "");
}

public void launchPlayStore(Context context, String packageName) {
Intent intent = null;
try {
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("market://details?id=" + packageName));
context.startActivity(intent);
} catch (android.content.ActivityNotFoundException anfe) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + packageName)));
}
}

My kotlin entension function for this purpose
fun Context.canPerformIntent(intent: Intent): Boolean {
val mgr = this.packageManager
val list = mgr.queryIntentActivities(intent, PackageManager.MATCH_DEFAULT_ONLY)
return list.size > 0
}
And in your activity
val uri = if (canPerformIntent(Intent(Intent.ACTION_VIEW, Uri.parse("market://")))) {
Uri.parse("market://details?id=" + appPackageName)
} else {
Uri.parse("https://play.google.com/store/apps/details?id=" + appPackageName)
}
startActivity(Intent(Intent.ACTION_VIEW, uri))

KOTLIN :
create extension in context.
fun Context.openPlayStoreApp(pkgName:String?){
if(!pkgName.isNullOrEmpty()) {
try {
startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=$pkgName")))
} catch (e: ActivityNotFoundException) {
startActivity(
Intent(
Intent.ACTION_VIEW,
Uri.parse("https://play.google.com/store/apps/details?id=$pkgName")
)
)
}
}
}
Hope it should work.

Peoples, dont forget that you could actually get something more from it. I mean UTM tracking for example. https://developers.google.com/analytics/devguides/collection/android/v4/campaigns
public static final String MODULE_ICON_PACK_FREE = "com.example.iconpack_free";
public static final String APP_STORE_URI =
"market://details?id=%s&referrer=utm_source=%s&utm_medium=app&utm_campaign=plugin";
public static final String APP_STORE_GENERIC_URI =
"https://play.google.com/store/apps/details?id=%s&referrer=utm_source=%s&utm_medium=app&utm_campaign=plugin";
try {
startActivity(new Intent(
Intent.ACTION_VIEW,
Uri.parse(String.format(Locale.US,
APP_STORE_URI,
MODULE_ICON_PACK_FREE,
getPackageName()))).addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP));
} catch (android.content.ActivityNotFoundException anfe) {
startActivity(new Intent(
Intent.ACTION_VIEW,
Uri.parse(String.format(Locale.US,
APP_STORE_GENERIC_URI,
MODULE_ICON_PACK_FREE,
getPackageName()))).addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP));
}

A kotlin verison with fallback and current syntax
fun openAppInPlayStore() {
val uri = Uri.parse("market://details?id=" + context.packageName)
val goToMarketIntent = Intent(Intent.ACTION_VIEW, uri)
var flags = Intent.FLAG_ACTIVITY_NO_HISTORY or Intent.FLAG_ACTIVITY_MULTIPLE_TASK or Intent.FLAG_ACTIVITY_NEW_TASK
flags = if (Build.VERSION.SDK_INT >= 21) {
flags or Intent.FLAG_ACTIVITY_NEW_DOCUMENT
} else {
flags or Intent.FLAG_ACTIVITY_CLEAR_TASK
}
goToMarketIntent.addFlags(flags)
try {
startActivity(context, goToMarketIntent, null)
} catch (e: ActivityNotFoundException) {
val intent = Intent(Intent.ACTION_VIEW,
Uri.parse("http://play.google.com/store/apps/details?id=" + context.packageName))
startActivity(context, intent, null)
}
}

Tested. This should work fine.
val context = LocalContext.current
val onOpenPlayStore: () -> Unit = {
try {
LOG.d(tag, "onOpenPlayStore ${context.packageName}")
val intent = Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=${context.packageName}"))
startActivity(context, intent, null)
} catch (e: ActivityNotFoundException) {
var intent = Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=${context.packageName}"))
startActivity(context, intent, null)
}
}

For Rate Application: Redirect to Playstore.
In Flutter, you can do it through a Platform channel Like this
Flutter Part:-
static const platform = const MethodChannel('rateApp'); // initialize
onTap: platform.invokeMethod('urls', {'android_id': 'com.xyz'}),
Now Android Native Part(Java):
private static final String RATEAPP = "rateApp"; // initialize variable
// Now in ConfigureFlutterEngine funtion:
new MethodChannel(flutterEngine.getDartExecutor().getBinaryMessenger(), RATEAPP)
.setMethodCallHandler(
(call, result) -> {
if (call.method.equals("urls") && call.hasArgument("android_id")) {
String id = call.argument("android_id").toString();
try {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("$uri" + id)));
} catch (android.content.ActivityNotFoundException anfe) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + id)));
}
result.success("Done");
} else {
result.notImplemented();
}
}
);

Open page in Twitter app from other app - Android

I was looking for some way to launch Twitter app and open a specified page from my application, without webview.
I found the solution for Facebook here:
Opening facebook app on specified profile page
I need something similar.
[EDIT]
I've just found a solution:
try {
Intent intent = new Intent(Intent.ACTION_VIEW,
Uri.parse("twitter://user?screen_name=[user_name]"));
startActivity(intent);
} catch (ActivityNotFoundException e) {
startActivity(new Intent(Intent.ACTION_VIEW,
Uri.parse("https://twitter.com/#!/[user_name]")));
}

Based on fg.radigales answer, this is what I used to launch the app if possible, but fall back to the browser otherwise:
Intent intent = null;
try {
// get the Twitter app if possible
this.getPackageManager().getPackageInfo("com.twitter.android", 0);
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=USERID"));
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
} catch (Exception e) {
// no Twitter app, revert to browser
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/PROFILENAME"));
}
this.startActivity(intent);
UPDATE
Added intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK); to fix an issue where twitter was opening inside my app instead of as a new activity.

This worked for me: twitter://user?user_id=id_num

Open page on Twitter app from other app using Android in 2 Steps:
1.Just paste the below code (on button click or anywhere you need)
Intent intent = null;
try{
// Get Twitter app
this.getPackageManager().getPackageInfo("com.twitter.android", 0);
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=USER_ID"));
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
} catch () {
// If no Twitter app found, open on browser
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/USERNAME"));
}
2.intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=USER_ID"));
To get USER_ID just write username https://tweeterid.com/ and get Twitter User ID in there
Reference: https://solutionspirit.com/open-page-twitter-application-android/

My answer builds on top of the widely-accepted answers from fg.radigales and Harry.
If the user has Twitter installed but disabled (for example by using App Quarantine), this method will not work. The intent for the Twitter app will be selected but it will not be able to process it as it is disabled.
Instead of:
getPackageManager().getPackageInfo("com.twitter.android", 0);
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=2343965036"));
You can use the following to decide what to do:
PackageInfo info = getPackageManager().getPackageInfo("com.twitter.android", 0);
if(info.applicationInfo.enabled)
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?user_id=2343965036"));
else
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/wrkoutapp"));

Just try this code snippet. It will help you.
//Checking If the app is installed, according to the package name
Intent intent = new Intent();
intent.setType("text/plain");
intent.setAction(Intent.ACTION_SEND);
final PackageManager packageManager = getPackageManager();
List<ResolveInfo> list = packageManager.queryIntentActivities(intent, PackageManager.MATCH_DEFAULT_ONLY);
for (ResolveInfo resolveInfo : list)
{
String packageName = resolveInfo.activityInfo.packageName;
//In case that the app is installed, lunch it.
if (packageName != null && packageName.equals("com.twitter.android"))
{
try
{
String formattedTwitterAddress = "twitter://user/" ;
Intent browseTwitter = new Intent(Intent.ACTION_VIEW, Uri.parse(formattedTwitterAddress));
long twitterId = <Here is the place for the twitter id>
browseTwitter.putExtra("user_id", twitterId);
startActivity(browseTwitter);
return;
}
catch (Exception e)
{
}
}
}
//If it gets here it means that the twitter app is not installed. Therefor, lunch the browser.
try
{
String twitterName = <Put the twitter name here>
String formattedTwitterAddress = "http://twitter.com/" + twitterName;
Intent browseTwitter = new Intent(Intent.ACTION_VIEW, Uri.parse(formattedTwitterAddress));
startActivity(browseTwitter);
}
catch (Exception e)
{
}

For me this did the trick it opens Twitter app if you have it or goes to web browser:
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/"+"USERID"));
startActivity(intent);

try {
Intent intent = new Intent(Intent.ACTION_VIEW,
Uri.parse("twitter://user?screen_name=[user_name]"));
startActivity(intent);
} catch (Exception e) {
startActivity(new Intent(Intent.ACTION_VIEW,
Uri.parse("https://twitter.com/#!/[user_name]")));
}
This answer was posted as an edit to the question Open page in Twitter app from other app - Android by the OP jbc25 under CC BY-SA 3.0.

Develop Reference

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