Dotted dash vertical line with gradient color - android

I want to make dotted line vertically with the gradient color effect. But I'm unable to do that. How can I approach. I am using this code on drawable for the dotted line
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item
android:left="3px"
android:right="-5px"
android:top="-5px"
android:bottom="-5px">
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle">
<stroke
android:width="4px"
android:color="#color/colorPrimary"
android:dashGap="20px"
android:dashWidth="20px" />
</shape>
</item>
</layer-list>
Anyone knows please help
Thanks in advance

create a drawable like below
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item
android:bottom="-5px"
android:left="3px"
android:right="-5px"
android:top="-5px">
<shape>
<gradient
android:angle="270"
android:centerColor="#00ff00"
android:endColor="#ff0000"
android:startColor="#0000ff"/>
<stroke
android:width="2dp"
android:color="#fff"
android:dashWidth="8dp"
android:dashGap="16dp"/>
</shape>
</item>
</layer-list>
now in layout you need to use a view and set this shape as background to it.
<View
android:layout_width="4dp"
android:layout_height="match_parent"
android:background="#drawable/your_shape"/>
you might need to change widht settings as per your requirements. Here is what I got

You can use shape Try this...
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="line">
<stroke
android:color="#000000"
android:dashWidth="10px"
android:dashGap="10px"
android:width="1dp"/>
</shape>

Related

How to have bottom line programmatically just like in default edittext with gradientdrawable in android

It will draw a bottom underline and i want to simply achieve below xml code by using gradientdrawable, I am trying to have custom edit text class which used in xml and set some property like bottom line color or others.
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item
android:left="-6dp"
android:right="-6dp"
android:top="-6dp">
<shape>
<stroke
android:width="1dp"
android:color="#000" />
</shape>
</item>
</layer-list>
First create gradient file
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android">
<gradient android:angle="180" android:startColor="#7c0000" android:endColor="#ff9a9a"/>
</shape>
and than add it here :
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item>
<shape android:shape="rectangle">
<solid android:color="#android:color/white"/>
</shape>
</item>
<item android:drawable="#drawable/gradient" android:gravity="bottom" android:height="2dp"/>
</layer-list>

How can i draw a shape circular but zigzag in android?

I want to draw a shape circular but zigzag in android as per attached image
trying this type
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item android:id="#android:id/progress">
<shape
android:innerRadius="#dimen/circleProgressRadius"
android:shape="ring"
android:thickness="#dimen/circleProgressThickness">
<gradient
android:startColor="#color/circleProgressIncompleteStartGradient"
android:endColor="#color/circleProgressIncompleteEndGradient"
android:type="sweep" />
</shape>
</item>
</layer-list>
But not getting shape as per attached image How can i do this ?
edged_circle.xml
<?xml version="1.0" encoding="utf-8"?>
<shape android:shape="oval"
xmlns:android="http://schemas.android.com/apk/res/android">
<size android:height="50dp" android:width="50dp" />
<stroke android:width="10dp"
android:dashGap="4dp"
android:dashWidth="1dp"
android:color="#000"/>
<solid android:color="#00000000" />
</shape>
Hope this helps, do some customizations according to your need.
P.S. size tag is just to maintain aspect ratio. Its only the stroke tag that you need to change.
To draw this image we can go like this
circle_progress_background.xml:
<?xml version="1.0" encoding="utf-8"?>
<shape android:shape="oval"
xmlns:android="http://schemas.android.com/apk/res/android">
<size android:height="10dp" android:width="10dp" />
<stroke android:width="7dp"
android:dashGap="3dp"
android:dashWidth="0.5dp"
android:color="#000"/>
<solid android:color="#00000000" />
</shape>
in main activity
android:layout_width="178dp"
android:layout_height="178dp"
android:background="#drawable/circle_progress_background"
image is coming like attached snapshot

How can I create a vertical line in a drawable xml? Android

Is there a way to make a drawable that draws a vertical line? So far I have a horizontal line that draws this:
current code is as follows:
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item android:drawable="#drawable/object_switcher_background" />
<item android:left="0dp"
android:right="250dp">
<shape android:shape="line">
<stroke android:color="#color/c19"
android:width="2dp"/>
<size android:width="40dp"/>
</shape>
</item>
<item android:left="50dp"
android:bottom="50dp"
android:top="75dp"
android:right="150dp">
<shape android:shape="line">
<stroke android:color="#color/c19"
android:width="2dp"
android:rotation="90"/>
<size android:width="40dp"/>
</shape>
</item>
</layer-list>
How can I manipulate this to make it look like this?
You could do this by nesting your second item inside a rotate item.
you can do that using rotate item: the below code defines a white background with a vertical divider using only xml drawable
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item>
<shape android:shape="rectangle">
<solid android:color="#android:color/white" />
</shape>
</item>
<item>
<rotate android:fromDegrees="90">
<shape android:shape="line">
<stroke
android:width="1dp"
android:color="#android:color/darker_gray" />
</shape>
</rotate>
</item>
I'm not sure why you need a drawable for this.
This can also be done by using a simple view and adjusting its height, width and position according to your needs. For example:
<View
android:layout_width="1dp"
android:background="#color/grey_text_color"
android:layout_height="match_parent"/>

Add only top and bottom border on LinearLayout [duplicate]

This question already has answers here:
Is there an easy way to add a border to the top and bottom of an Android View?
(25 answers)
Closed 1 year ago.
I would like to add only a bottom and a top border on my Linearlayout.
I have tried to do this :
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item
android:bottom="1dp"
android:top="1dp">
<shape android:shape="rectangle">
<solid android:color="#FFFFFF" />
<stroke
android:width="1dp"
android:color="#000" />
</shape>
</item>
</layer-list>
But it add a border around the shape..
Could you help me please ?
I think you can create this drawable and use it as background:
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item>
<shape android:shape="rectangle" >
<solid android:color="#000"/>
</shape>
</item>
<item android:bottom="1dp" android:top="1dp">
<shape android:shape="rectangle" >
<solid android:color="#FFFFFF" />
</shape>
</item>
</layer-list>
Think of is as drawing a rectangle with border color first and then lay on top of it a rectangle with your background color leaving out 1dp on top and at the bottom.
Make this two file and put this code. you can set border top and bottom border,
main.xml
<TextView
android:text="This is textline"
android:background="#drawable/border_set"
/>
border_set.xml
This file located into full path project_root/res/drawable/border_set.xml
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item>
<shape
android:shape="rectangle">
<stroke android:width="1dp" android:color="#FF000000" />
<solid android:color="#FFDDDDDD" />
</shape>
</item>
<item android:top="1dp" android:bottom="1dp">
<shape
android:shape="rectangle">
<stroke android:width="1dp" android:color="#000" />
<solid android:color="#FFFFFF" />
</shape>
</item>
</layer-list>
Here is the solution. It works even with transparent background.
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item android:left="-2dp" android:right="-2dp">
<shape android:shape="rectangle">
<stroke android:width="2dp" android:color="#color/borderColor" />
<solid android:color="#color/backgroundColor" />
</shape>
</item>
</layer-list>
I believe this is the simplest way:
<View
android:layout_width="match_parent"
android:layout_height="2dp"
android:background="#000000" />
This is my version; top border and bottom border are visible, not showing the left or right borders. And the background is transparent.
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="1dp">
<item
android:left="-1dp"
android:right="-1dp"
android:top="-1dp"
android:bottom="1dp">
<shape
android:shape="rectangle">
<stroke
android:width="1dp"
android:color="#color/BlueGrey_colorPrimary" />
<solid android:color="#android:color/transparent" />
</shape>
</item>
</layer-list>
A quick way to achieve this:
Add a Text View to the bottom and/or top of your layout.
Set the TextView's width to "match_parent"
Set the TextView's height to about "1dp" or find the thickness you would like
Set the TextView's background to the color you would like the border to be
I hope this helps!
You can follow this link Is there an easy way to add a border to the top and bottom of an Android View?
I expect that you are solve from this link.
also you can solve How to add border around linear layout except at the bottom?
Its simple. Draw 3 shapes like this.
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item>
<shape android:shape="rectangle" >
<solid android:color="#color/menu_line_separator_in" />
</shape>
</item>
<item android:bottom="1.5dp">
<shape android:shape="rectangle" >
<solid android:color="#color/menu_line_separator_out" />
</shape>
</item>
<item android:top="1.5dp">
<shape android:shape="rectangle" >
<solid android:color="#color/menu_line_separator_out" />
</shape>
</item>
</layer-list>

Square shaped layout border with round inside edges

I’m attempting to create a layout border with corners that are square on the outside and round on the inside. I’ve gathered that I need to create an .xml drawable definition composed of two shapes: one with a stroke width and corner radius and another with a stroke width only:
The drawables
round_border.xml
<shape xmlns:android="http://schemas.android.com/apk/res/android">
<stroke android:width="4dp" android:color="#FF000000" />
<padding android:left="7dp" android:top="7dp"
android:right="7dp" android:bottom="7dp" />
<corners android:radius="4dp" />
<solid android:color="#FFC0C0C0" />
</shape>
square_border.xml
<shape xmlns:android="http://schemas.android.com/apk/res/android">
<stroke android:width="2dp" android:color="#FF000000" />
<solid android:color="#FFC0C0C0" />
</shape>
Each of these works independantly as a border when appliedby itself like so:
android:background="#drawable/round_border"
but when they either or both are added to an item-list drawable like so:
composite_border.xml
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android">
<layer-list>
<item android:drawable="#drawable/round_border"/>
<!-- <item android:drawable="#drawable/square_border"/> -->
</layer-list>
</shape>
and:
android:background="#drawable/composite_border"
The layout's background is completely black instead of just a black border.
Does anyone know how to make the layer list work for this task?
From Shape Drawable Doc you can see that shape can't have layer-list inside so you should define your composite_border.xml like this
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item android:drawable="#drawable/square_border"/>
<item android:drawable="#drawable/round_border"/>
</layer-list>
note that I changed the order of your items inside the layer-list as stated in the documentation of layer-list
Each drawable in the list is drawn in the order of the list—the last drawable in the list is drawn on top and you want it to be squared from outside
Try this will work fine enough:
solid is background color
stroke is border
<?xml version="1.0" encoding="utf-8"?>
<shape
xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle">
<solid
android:color="#color/white"/>
<stroke android:width="1dp" android:color="#ffaaaaaa" />
<size
android:width="15dp"
android:height="15dp"/>
</shape>
Create a xml file like round_background.xml:
<?xml version="1.0" encoding="utf-8"?>
<shape
xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="oval">
<solid
android:color="#CCCC33"/>
<size
android:width="35dp"
android:height="35dp"/>
</shape>
In the layout set as background
<LinearLayout
android:id="#+id/layout_wellbeing"
android:layout_width="wrap_content"
android:layout_height="match_parent"
android:layout_weight="1"
android:gravity="center"
android:background="#drawable/rounded_corner_leuvan"
android:orientation="horizontal" >
</LinearLayout>
square_border.xml
<shape xmlns:android="http://schemas.android.com/apk/res/android">
<stroke android:width="2dp"
android:color="#FF000000"
/>
<solid android:color="#FFC0C0C0" />
</shape>
composite_border.xml
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android">
<layer-list>
<item android:drawable="#drawable/round_border"/>
<!-- <item android:drawable="#drawable/square_border"/> -->
</layer-list>
</shape>
watch out the comments and the quotation marks! =]

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