How can i draw a shape circular but zigzag in android? - android

I want to draw a shape circular but zigzag in android as per attached image
trying this type
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item android:id="#android:id/progress">
<shape
android:innerRadius="#dimen/circleProgressRadius"
android:shape="ring"
android:thickness="#dimen/circleProgressThickness">
<gradient
android:startColor="#color/circleProgressIncompleteStartGradient"
android:endColor="#color/circleProgressIncompleteEndGradient"
android:type="sweep" />
</shape>
</item>
</layer-list>
But not getting shape as per attached image How can i do this ?


edged_circle.xml
<?xml version="1.0" encoding="utf-8"?>
<shape android:shape="oval"
xmlns:android="http://schemas.android.com/apk/res/android">
<size android:height="50dp" android:width="50dp" />
<stroke android:width="10dp"
android:dashGap="4dp"
android:dashWidth="1dp"
android:color="#000"/>
<solid android:color="#00000000" />
</shape>
Hope this helps, do some customizations according to your need.
P.S. size tag is just to maintain aspect ratio. Its only the stroke tag that you need to change.


To draw this image we can go like this
circle_progress_background.xml:
<?xml version="1.0" encoding="utf-8"?>
<shape android:shape="oval"
xmlns:android="http://schemas.android.com/apk/res/android">
<size android:height="10dp" android:width="10dp" />
<stroke android:width="7dp"
android:dashGap="3dp"
android:dashWidth="0.5dp"
android:color="#000"/>
<solid android:color="#00000000" />
</shape>
in main activity
android:layout_width="178dp"
android:layout_height="178dp"
android:background="#drawable/circle_progress_background"
image is coming like attached snapshot

Related

How can I create the following shape in Android?

I am trying to create a following shape in android.
I tried following code but it's only for changing the corners
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle" >
<solid android:color="#ffffff" />
<gradient
android:startColor="#00EBCF"
android:endColor="#00BEEC"
android:angle="180"
android:type="linear" />
<corners
android:bottomLeftRadius="80dp"
android:bottomRightRadius="80dp"
android:topLeftRadius="0dp"
android:topRightRadius="0dp" />
What do I need to make changes in code to achieve the above shape?
Edit1
As per the answer I used following code (modifications in layout height):
<?xml version="1.0" encoding="utf-8"?>
</shape>
</item>
<item
android:width="1500dp"
android:height="200dp"
android:top="95dp">
<shape android:shape="oval">
<solid android:color="#36D6E9" />
</shape>
</item>
But when I am using this layout as a background for LinearLayout. It's showing me this:
<LinearLayout
android:layout_width="match_parent"
android:layout_height="0dp"
android:layout_weight="1"
android:background="#drawable/header_shape_rect">

use this as an example
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item android:height="200dp">
<shape android:shape="rectangle">
<solid android:color="#ccc"/>
</shape>
</item>
<item android:height="200dp" android:top="95dp" android:width="1500dp" >
<shape android:shape="oval">
<solid android:color="#ccc"/>
</shape>
</item>
</layer-list>

Android: how to create shape with skewed two-tone color?

I am attempting to create a drawable shape that will become the background of a search bar. I know how to create a rectangle with two colors but I do not know how to tilt the color at an angle, like in the second image. Can someone help me with this? Thanks.

Take a Toolbar...code is here...
<android.support.v7.widget.Toolbar
android:layout_width="500dp"
android:layout_height="wrap_content"
android:background="#drawable/custom_background" />
create a drawable res file custom_background.xml and
In that toolbar set drawable like this....code is here
<?xml version="1.0" encoding="UTF-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item>
<shape android:shape="rectangle">
<size
android:width="500dp"
android:height="50dp" />
<solid android:color="#0072BC" />
<corners android:radius="0dp"/>
</shape>
</item>
<item
android:top="8dp"
android:bottom="0dp"
android:left="-400dp"
android:right="128dp">
<rotate
android:fromDegrees="160">
<shape android:shape="rectangle">
<solid android:color="#FFF" />
</shape>
</rotate>
</item>

How can I create a vertical line in a drawable xml? Android

Is there a way to make a drawable that draws a vertical line? So far I have a horizontal line that draws this:
current code is as follows:
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item android:drawable="#drawable/object_switcher_background" />
<item android:left="0dp"
android:right="250dp">
<shape android:shape="line">
<stroke android:color="#color/c19"
android:width="2dp"/>
<size android:width="40dp"/>
</shape>
</item>
<item android:left="50dp"
android:bottom="50dp"
android:top="75dp"
android:right="150dp">
<shape android:shape="line">
<stroke android:color="#color/c19"
android:width="2dp"
android:rotation="90"/>
<size android:width="40dp"/>
</shape>
</item>
</layer-list>
How can I manipulate this to make it look like this?

You could do this by nesting your second item inside a rotate item.

you can do that using rotate item: the below code defines a white background with a vertical divider using only xml drawable
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item>
<shape android:shape="rectangle">
<solid android:color="#android:color/white" />
</shape>
</item>
<item>
<rotate android:fromDegrees="90">
<shape android:shape="line">
<stroke
android:width="1dp"
android:color="#android:color/darker_gray" />
</shape>
</rotate>
</item>

I'm not sure why you need a drawable for this.
This can also be done by using a simple view and adjusting its height, width and position according to your needs. For example:
<View
android:layout_width="1dp"
android:background="#color/grey_text_color"
android:layout_height="match_parent"/>

How to define a rectangle with a circle at the end using Android XML definitions

Is it possible to define a shape like shown on the following image:
I tried a layer-list but I could not find a solution close to what I am looking for.
I want to use the resulting shape as a background image to a RelativeLayout with a transparency.
Any hints are appreciated! Thank you.

Here is the shape you asked for:
<?xml version="1.0" encoding="UTF-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item>
<shape android:shape="rectangle">
<size
android:width="250dp"
android:height="100dp" />
<solid android:color="#ffffff" />
</shape>
</item>
<item
android:top="0dp">
<shape android:shape="line">
<stroke
android:width="25dp"
android:color="#000000" />
</shape>
</item>
<item
android:right="0dp"
android:left="150dp">
<shape android:shape="oval">
<solid android:color="#000000" />
</shape>
</item>
</layer-list>
Screenshot:

How to draw border on just one side of a linear layout?

I'm able to draw border to a linear layout, but it is getting drawn on all sides. I want to restrict it to right side only, like you do in CSS (border-right:1px solid red;).
I've tried this, but it still draws on all sides:
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item>
<shape android:shape="rectangle" >
<stroke
android:height="2dp"
android:width="2dp"
android:color="#FF0000" />
<solid android:color="#000000" />
<padding
android:bottom="0dp"
android:left="0dp"
android:right="1dp"
android:top="0dp" />
<corners
android:bottomLeftRadius="0dp"
android:bottomRightRadius="5dp"
android:radius="1dp"
android:topLeftRadius="5dp"
android:topRightRadius="0dp" />
</shape>
</item>
Any suggestions on how to accomplish this?
BTW, I do not want to use the hack of putting a view of width 1dp on the required side.

You can use this to get border on one side
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item>
<shape android:shape="rectangle">
<solid android:color="#FF0000" />
</shape>
</item>
<item android:left="5dp">
<shape android:shape="rectangle">
<solid android:color="#000000" />
</shape>
</item>
</layer-list>
EDITED
As many including me wanted to have a one side border with transparent background, I have implemented a BorderDrawable which could give me borders with different size and color in the same way as we use css. But this could not be used via xml. For supporting XML, I have added a BorderFrameLayout in which your layout can be wrapped.
See my github for the complete source.

Easy as pie, allowing a transparent bg:
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle">
<gradient
android:angle="0"
android:startColor="#f00"
android:centerColor="#android:color/transparent"
android:centerX="0.01" />
</shape>
Change the angle to change border location:
0 = left
90 = bottom
180 = right
270 = top

it is also possible to implement what you want using a single layer
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item
android:bottom="-5dp"
android:right="-5dp"
android:top="-5dp">
<shape android:shape="rectangle" >
<solid android:color="#color/color_of_the_background" />
<stroke
android:width="5dp"
android:color="#color/color_of_the_border" />
</shape>
</item>
</layer-list>
this way only left border is visible but you can achieve any combination you want by playing with bottom, left, right and top attributes of the item element

To get a border on just one side of a drawable, apply a negative inset to the other 3 sides (causing those borders to be drawn off-screen).
<?xml version="1.0" encoding="utf-8"?>
<inset xmlns:android="http://schemas.android.com/apk/res/android"
android:insetTop="-2dp"
android:insetBottom="-2dp"
android:insetLeft="-2dp">
<shape android:shape="rectangle">
<stroke android:width="2dp" android:color="#FF0000" />
<solid android:color="#000000" />
</shape>
</inset>
This approach is similar to naykah's answer, but without the use of a layer-list.

An other great example
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<inset xmlns:android="http://schemas.android.com/apk/res/android"
android:insetRight="-2dp">
<shape android:shape="rectangle">
<corners
android:bottomLeftRadius="4dp"
android:bottomRightRadius="0dp"
android:topLeftRadius="4dp"
android:topRightRadius="0dp" />
<stroke
android:width="1dp"
android:color="#70b23f" />
<solid android:color="#android:color/transparent" />
</shape>
</inset>

As an alternative (if you don't want to use background), you can easily do it by making a view as follows:
<View
android:layout_width="2dp"
android:layout_height="match_parent"
android:background="#000000" />
For having a right border only, place this after the layout (where you want to have the border):
<View
android:layout_width="2dp"
android:layout_height="match_parent"
android:background="#000000" />
For having a left border only, place this before the layout (where you want to have the border):
Worked for me...Hope its of some help....

I was able to achieve the effect with the following code
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item android:left="0dp" android:right="-5dp" android:top="-5dp" android:bottom="-5dp">
<shape
android:shape="rectangle">
<stroke android:width="1dp" android:color="#123456" />
</shape>
</item>
</layer-list>
You can adjust to your needs for border position by changing the direction of displacement

<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:state_pressed="true" >
<shape>
<solid
android:color="#f28b24" />
<stroke
android:width="1dp"
android:color="#f28b24" />
<corners
android:radius="0dp"/>
<padding
android:left="0dp"
android:top="0dp"
android:right="0dp"
android:bottom="0dp" />
</shape>
</item>
<item>
<shape>
<gradient
android:startColor="#f28b24"
android:endColor="#f28b24"
android:angle="270" />
<stroke
android:width="0dp"
android:color="#f28b24" />
<corners
android:bottomLeftRadius="8dp"
android:bottomRightRadius="0dp"
android:topLeftRadius="0dp"
android:topRightRadius="0dp"/>
<padding
android:left="10dp"
android:top="10dp"
android:right="10dp"
android:bottom="10dp" />
</shape>
</item>
</selector>

There is no mention about nine-patch files here. Yes, you have to create the file, however it's quite easy job and it's really "cross-version and transparency supporting" solution. If the file is placed to the drawable-nodpi directory, it works px based, and in the drawable-mdpi works approximately as dp base (thanks to resample).
Example file for the original question (border-right:1px solid red;) is here:
http://ge.tt/517ZIFC2/v/3?c
Just place it to the drawable-nodpi directory.

Borders of different colors. I used 3 items.
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item>
<shape android:shape="rectangle">
<solid android:color="#color/colorAccent" />
</shape>
</item>
<item android:top="3dp">
<shape android:shape="rectangle">
<solid android:color="#color/light_grey" />
</shape>
</item>
<item
android:bottom="1dp"
android:left="1dp"
android:right="1dp"
android:top="3dp">
<shape android:shape="rectangle">
<solid android:color="#color/colorPrimary" />
</shape>
</item>
</layer-list>

You can wrap into container and define margins for start left bottom top.
Suppose you want to provide margin for left side you can do this
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:background="#color/light_blue"
>
<TextView
android:marginStart="2dp" // This is Your border
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:background="#color/white"
android:padding="16dp"
android:text="a"
android:textColor="#color/light_blue"
android:textSize="25dp" />
</RelativeLayout>

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