I want to open chooser for both whatsapp and gb-whatsapp so the user can choose any of one from them. This code is only opening whatsapp only.
Intent intentWhatsapp = new Intent(Intent.ACTION_VIEW);
String url = "https://chat.whatsapp.com/JPJSkaiqmDu5gLKqUPAfMM";
intentWhatsapp.setData(Uri.parse(url));
intentWhatsapp.setPackage("com.whatsapp");
startActivity(intentWhatsapp);
To handle business whatsapp, GB-Whatsapp and normal whatsapp, the url scheme intent needs to be used, since the normal method of using package "com.whatsapp" only works for normal whatsapp.
Here's the code sample to handle gb, normal and business whatsapp :
try {
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse("whatsapp://send?phone="+ "+92300xxxxxxx" +"&text=" + URLEncoder.encode("Message\n", "UTF-8")));
context.startActivity(i);
} catch (Exception e){
Toast.makeText(context, "Whatsapp not installed!", Toast.LENGTH_LONG).show();
}
Simple answer you can't.
More detailed answer: You can only create an Intent targeting one specific app. I would suggest building a dialogue inside your app, showing the app images of whatsapp and gb-whatsapp, and then putting specific intents behind those two images so that it "looks" like the Android chooser.
I'm trying to launch the Amazon Kindle app from my android application but based on a specific book that the user clicks.
I'm able to determine the books available and which book the user has selected but I have only been able to launch the kindle application (using the package name com.amazon.kindle) to launch the kindle app.
Does anyone know of any additional commands I can send to specify a book to open? I know this is possible as there is a widget on the google play store where the user selects a boo and it creates a button on the homescreen that launches the kindle app and opens the book.
Thanks in advance!
First we need to set the intent to an ACTION_VIEW intent.
Then we need to define an Uri for the data which is actually a link that looks something like: kindle://book/?action=open&book_id=AMZNID0/B000FC1GHO/0/, where in this case the section B000FC1GHO corresponds to the ID of the book.
Finally we can then start the activity. In my case I had to set some flags on the intent to launch a new activity.
The code I'm using is as follows:
if(intent.getAction().contains("BOOK_ACTION_"))
{
Log.w("LOG", "We have a book selected");
bookID = intent.getAction().substring(12);
Log.w("LOG", bookID);
Intent readbook = new Intent(Intent.ACTION_VIEW);
readbook.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
Uri file = Uri.parse("kindle://book/?action=open&book_id=AMZNID0/" + bookID + "/0/");
readbook.setData(file);
context.startActivity(readbook);
}
I'm overriding the onReceive method in this case so that I can perform some additional steps on each book. Presumably because I'm just setting an ACTION_VIEW intent this could have been handles in the other class that does the onClickListener for the imageview that holds the book I want.
I would like to start a default application: browser, contact-book, phone, email, music app, etc. I have found many q/a, like browser opening a specific URL or blank, and here the answer is even "No not possible". But I would like to just open/launch it without telling it to go to a specific URL or sending a mail to someone, etc.
However, I also saw some Home applications where this seems to be working (at least for some apps). On my colleague's device there is for example a different contact-book (no google) which is detected and opened correctly.
I have seen in the Android documentation some intent categories that point to these problems, but these are only >= API.11. So I can't use/test them on my device.
Question: Is it not somehow possible to launch a default application (having the app chooser is of course ok) without providing extra data? If no, what do you think are these Home apps doing (perhaps workarounds are somehow possible).
PS: for the phone app I think, I have a workaround using Intent.ACTION_DIAL without any other information which will open simply the dialer.
UPDATE: I modified the title. Some applications like the address book may not be the same on different devices. So in this case I would like to start the address-book app, whichever this is.
This answer is not a 100% answer, but some workarounds on some typical applications.
Still open are: music player, address book
Browser: I get a list of applications that handle "http"-data intents, and then I look if one is available in the list of preferred applications.
Intent appFilter = new Intent(Intent.ACTION_VIEW);
appFilter.setData(Uri.parse("http://www.google.com"));
List<ResolveInfo> browserInfoList = pm.queryIntentActivities(appFilter, 0);
List<IntentFilter> outFilters = new ArrayList<IntentFilter>();
List<ComponentName> outActivities = new ArrayList<ComponentName>();
pm.getPreferredActivities(outFilters, outActivities, null);
if(outActivities.size() > 0) {
for(ComponentName cn : outActivities) {
String cnClass = cn.getClassName();
String cnPkg = cn.getPackageName();
for (ResolveInfo info : browserInfoList) {
if(info.activityInfo.name.equals(cnClass) &&
info.activityInfo.packageName.equals(cnPkg)) {
return cn;
}
}
}
}
In case no default is found, I open a browser chooser dialog, see here.
Phone: as described in the question:
Intent intent = new Intent(Intent.ACTION_DIAL);
startActivity(intent);
You can start apps by the function "startActivity" if you know about the canonical app name
like "android.com.browser". Do this simple by searching for AndroidManifest.xml in the app
source code (look at Codeaurora.com or at github/Cyanogenmod) and grab the app name you want.
After you know about the App name ("Activity") implement the code as follows:
Intent intent = new Intent();
intent.setClassName(this, "com.android.browser");
intent.setCategory(Intent.ACTION_MAIN);
startActivity(intent);
THIS is only a example, sometimes you have to put intent extras or data values, this information can be found in the app's AndroidManifest.xml too.
in my android application i want to add the functionality the user to buy song from amazon. The easiest way to do is i think to use amazon mp3 application to communicate with amazon store. I found this piece of code from default music player
Intent i = new Intent();
i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
i.setAction(MediaStore.INTENT_ACTION_MEDIA_SEARCH);
i.putExtra(SearchManager.QUERY, mSong.getArtits() + " " + mSong.getName());
i.putExtra(MediaStore.EXTRA_MEDIA_ARTIST, "artist");
i.putExtra(MediaStore.EXTRA_MEDIA_ALBUM, "album");
i.putExtra(MediaStore.EXTRA_MEDIA_TITLE, mSong.getName());
i.putExtra(MediaStore.EXTRA_MEDIA_FOCUS, "audio/*");
startActivity(Intent.createChooser(i, "Search for " + mSong.getName()));
which shows menu to select where to search for your song (browser, youtube, amazon mp3). But here are some things i want to do -
I don't want to show the whole pop up screen but only amazon search, what intent i should use to search directly in amazon mp3.
How can i send my affiliate partner key to amazon mp3 so it can included it when querying amazon.
Shazam is using directly amazon mp3 but i couldn't find any information what intent i should use. Thanks in advance any help will be very helpful.
It's not a public API; Shazam apparently have a private arrangement with Amazon. It might be worth contacting Amazon directly, since they have a lot of public APIs, and this one would certainly seem to be in their interests. But like any large company, I wouldn't hold your breath for a response.
as for 1., you can try to determine the correct activity by evaulating the list of matching activities like this (i being the intent you created):
List<ResolveInfo> info = getPackageManager().queryIntentActivities(i, 0);
String packageName=null, className=null;
for ( ResolveInfo r: info){
if ( r.activityInfo.packageName.startsWith("com.amazon.mp3")){
packageName=r.activityInfo.packageName;
className=r.activityInfo.name;
break;
}
}
if ( packageName != null && className != null)
i.setClassName(packageName, className);
startActivity(i);
This is sort of a hack since one should not rely on the package name starting with a certain fixed string, but in fact it will probably work for long. Just be prepared in your code to deal with it changing (android will automatically display the activity chooser if the Amazon activity is not identified).
as for 2., sorry, I have no information about this.
Is it possible to show a list of applications (with intent.createChooser) that only show me my twitter apps on my phone (so htc peep (htc hero) or twitdroid). I have tried it with intent.settype("application/twitter") but it doesnt find any apps for twitter and only shows my mail apps.
Thank you,
Wouter
I'm posting this because I haven't seen a solution yet that does exactly what I want.
This primarily launches the official Twitter app, or if that is not installed, either brings up a "Complete action using..." dialog (like this) or directly launches a web browser.
For list of different parameters in the twitter.com URL, see the Tweet Button docs.
Remember to URL encode the parameter values. (This code is specifically for tweeting a URL; if you don't want that, just leave out the url param.)
// Create intent using ACTION_VIEW and a normal Twitter url:
String tweetUrl = String.format("https://twitter.com/intent/tweet?text=%s&url=%s",
urlEncode("Tweet text"),
urlEncode("https://www.google.fi/"));
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(tweetUrl));
// Narrow down to official Twitter app, if available:
List<ResolveInfo> matches = getPackageManager().queryIntentActivities(intent, 0);
for (ResolveInfo info : matches) {
if (info.activityInfo.packageName.toLowerCase().startsWith("com.twitter")) {
intent.setPackage(info.activityInfo.packageName);
}
}
startActivity(intent);
(URL encoding is cleaner if you have a little utility like this somewhere, e.g. "StringUtils".)
public static String urlEncode(String s) {
try {
return URLEncoder.encode(s, "UTF-8");
}
catch (UnsupportedEncodingException e) {
Log.wtf(TAG, "UTF-8 should always be supported", e);
throw new RuntimeException("URLEncoder.encode() failed for " + s);
}
}
For example, on my Nexus 7 device, this directly opens the official Twitter app:
If official Twitter app is not installed and user either selects Chrome or it opens automatically (as the only app which can handle the intent):
The solutions posted before, allow you to post directly on your first twitter app. To show a list of twitters app (if there are more then one), you can custom your Intent.createChooser to show only the Itents you want.
The trick is add EXTRA_INITIAL_INTENTS to the default list, generated from the createChoose, and remove the others Intents from the list.
Look at this sample where I create a chooser that shows only my e-mails apps. In my case appears three mails: Gmail, YahooMail and the default Mail.
private void share(String nameApp, String imagePath) {
List<Intent> targetedShareIntents = new ArrayList<Intent>();
Intent share = new Intent(android.content.Intent.ACTION_SEND);
share.setType("image/jpeg");
List<ResolveInfo> resInfo = getPackageManager().queryIntentActivities(share, 0);
if (!resInfo.isEmpty()){
for (ResolveInfo info : resInfo) {
Intent targetedShare = new Intent(android.content.Intent.ACTION_SEND);
targetedShare.setType("image/jpeg"); // put here your mime type
if (info.activityInfo.packageName.toLowerCase().contains(nameApp) ||
info.activityInfo.name.toLowerCase().contains(nameApp)) {
targetedShare.putExtra(Intent.EXTRA_TEXT, "My body of post/email");
targetedShare.putExtra(Intent.EXTRA_STREAM, Uri.fromFile(new File(imagePath)) );
targetedShare.setPackage(info.activityInfo.packageName);
targetedShareIntents.add(targetedShare);
}
}
Intent chooserIntent = Intent.createChooser(targetedShareIntents.remove(0), "Select app to share");
chooserIntent.putExtra(Intent.EXTRA_INITIAL_INTENTS, targetedShareIntents.toArray(new Parcelable[]{}));
startActivity(chooserIntent);
}
}
You can run like that: share("twi", "/sdcard/dcim/Camera/photo.jpg");
This was based on post: Custom filtering of intent chooser based on installed Android package name
This question is a bit older, but since I have just come across a similar problem, it may also still be of interest to others. First, as mentioned by Peter, create your intent:
Intent tweetIntent = new Intent(Intent.ACTION_SEND);
tweetIntent.putExtra(Intent.EXTRA_TEXT, "Test; please ignore");
tweetIntent.setType("application/twitter");
"application/twitter" is in fact a known content type, see here. Now, when you try to start an activity with this intent, it will show all sorts of apps that are not really Twitter clients, but want a piece of the action. As already mentioned in a couple of the "why do you even want to do that?" sort of answers, some users may find that useful. On the other hand, if I have a button in my app that says "Tweet this!", the user would very much expect this to bring up a Twitter client.
Which means that instead of just launching an activity, we need to filter out the ones that are appropriate:
PackageManager pm = getPackageManager();
List<ResolveInfo> lract
= pm.queryIntentActivities(tweetIntent,
PackageManager.MATCH_DEFAULT_ONLY);
boolean resolved = false;
for(ResolveInfo ri: lract)
{
if(ri.activityInfo.name.endsWith(".SendTweet"))
{
tweetIntent.setClassName(ri.activityInfo.packageName,
ri.activityInfo.name);
resolved = true;
break;
}
}
You would need to experiment a bit with the different providers, but if the name ends in ".SendTweet" you are pretty safe (this is the activity name in Twidroyd). You can also check your debugger for package names you want to use and adjust the string comparison accordingly (i.e. Twidroyd uses "com.twidroid.*").
In this simple example we just pick the first matching activity that we find. This brings up the Twitter client directly, without the user having to make any choices. If there are no proper Twitter clients, we revert to the standard activity chooser:
startActivity(resolved ? tweetIntent :
Intent.createChooser(tweetIntent, "Choose one"));
You could expand the code and take into account the case that there is more than one Twitter client, when you may want to create your own chooser dialog from all the activity names you find.
It is entirely possible your users will only ever, now and forever, only want to post to Twitter.
I would think that it is more likely that your users want to send information to people, and Twitter is one possibility. But, they might also want to send a text message, or an email, etc.
In that case, use ACTION_SEND, as described here. Twidroid, notably, supports ACTION_SEND, so it will appear in the list of available delivery mechanisms.
These answers are all overly complex.
If you just do a normal url Intent that does to Twitter.com, you'll get this screen:
which gives you the option of going to the website if you have no Twitter apps installed.
String url = "https://twitter.com/intent/tweet?source=webclient&text=TWEET+THIS!";
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(url));
startActivity(i);
Either
You start an activity with an Intent with action Intent.ACTION_SEND and the text/plain MIME type. You'll have all applications that support sending text. That should be any twitter client, as well as Gmail, dropbox, etc.
Or, you try to look up for the specific action of every client you are aware of, like "com.twitter.android.PostActivity" for the official client. That will point to this client, and that is unlikely to be a complete list.
Or, you start with the second point, and fall back on the first...
Nope. The intent type is something like image/png or application/pdf, i.e. a file type, and with createChooser you're basically asking which apps can open this file type.
Now, there's no such thing as an application/twitter file that can be opened, so that won't work. I'm not aware of any other way you can achieve what you want either.
From http://twidroid.com/plugins/
Twidroid’s ACTION_SEND intent
Intent sendIntent = new Intent(Intent.ACTION_SEND);
sendIntent.putExtra(Intent.EXTRA_TEXT, "This is a sample message via Public Intent");
sendIntent.setType("application/twitter");
startActivity(Intent.createChooser(sendIntent, null));
I used "billynomates" answer and was able to use hashtags by using the "URLEncoder.encode(, "UTF-8")" function. The hash tags showed up just fine.
String originalMessage = "some message #MESSAGE";
String originalMessageEscaped = null;
try {
originalMessageEscaped = String.format(
"https://twitter.com/intent/tweet?source=webclient&text=%s",
URLEncoder.encode(originalMessage, "UTF-8"));
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
if(originalMessageEscaped != null) {
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(originalMessageEscaped));
startActivity(i);
}
else {
// Some Error
}