Develop Reference

Android webview Load url doesn't work for Instagram webpage

I realized that not working for under android 4.3 versions.
I have an android app which has webview. When i try to load url "http://instagram.com" it's not working It shows blank page but facebook webpage is working.
It's really important for me please help.
WebView view = (WebView) findViewById(R.id.webView1);
view.getSettings().setJavaScriptEnabled(true);
view.loadUrl("http://www.instagram.com");

Have you tried using the method:
setDomStorageEnabled();
Sets whether the DOM storage API is enabled. The default value is
false.
for example:
WebView view = (WebView) findViewById(R.id.webView1);
view.getSettings().setJavaScriptEnabled(true);
view.getSettings().setDomStorageEnabled(true);
view.loadUrl("http://www.instagram.com");
I had previously problems loading Facebook and Twitter pages in some devices, solved using setDomStorageEnabled() method.

how to fetch a page link and get open it inside phone browser, on user click (Android)

i wonder how to get address of a page inside of a web view on user click, and take that address and open it inside phone browser. for example let's say i open google inside a web view and when i click on one of the links from search then i want to fetch that link and get open it inside phone browser. the code for the web view is as follows:
myWebView = (WebView) findViewById(R.id.webView1);
myWebView.setWebViewClient(new WebViewClient());
myWebView .getSettings().setJavaScriptEnabled(true);
myWebView .getSettings().setDomStorageEnabled(true);
myWebView.getSettings().setJavaScriptEnabled(true);
myWebView.getSettings().setSupportZoom(false);
myWebView.getSettings().setDomStorageEnabled(true);
myWebView.getSettings().setBuiltInZoomControls(true);
myWebView.loadUrl("http://www.google.com/");

you can inject javascript that will find the link and call function from your java activity with android java bridge like How to call javascript from Android?

Is there a way to hide addressbar in webchromeclient?

I am developing an android application in which I want to show a website, which have links in it. When any link is clicked, then it plays an online stream.
Till now I have developed an app which work alright. In this I have used webview to display first screen. The live stream is not supported in webview, so I used webchromeclient.
Now the problem is when any link is clicked, a new browser opens and plays the stream and also shows the address bar and address of page loaded page.
I want to hide the address of new loaded page.
and if possible, also I wnt to keep webchromeclient in existing screen, not a new browser.

in this case you have to customize the WebViewClient like this
private class MyWebViewClient extends WebViewClient {
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
// This is my web site, so do not override; let my WebView load the page
return true;
}
}
}
Then create an instance of this new WebViewClient for the WebView:
WebView myWebView = (WebView) findViewById(R.id.webview);
myWebView.setWebViewClient(new MyWebViewClient());
for further have a look on this, and read carefully

Force webview to open urls inside application - android app

How to force WebView to open all the urls inside the application?

You need to override the WebViewClient for your WebView.
See here for the details: it's pretty straight forward.
Notice Step 6 in particular.
To open links clicked by the user, simply provide a WebViewClient for
your WebView, using setWebViewClient(). For example:
WebView myWebView = (WebView) findViewById(R.id.webview);
myWebView.setWebViewClient(new WebViewClient());
That's it. Now all links the user clicks load in your WebView.

How to set WebView as non-fullscreen?

I am trying to use a WebView in my Android application. I am creating my webview in code-side (not in XML). My problem is; when I call loadUrl method of webview, the webview goes fullscreen mode. How can I keep the size of the webview for example 200x200 pixels?
If there is any other option instead of webview, of course welcome :)
Thanks,

Quite possibly what you are seeing is not your activity, but the Browser application, because the URL you linked to did a redirect. Use WebViewClient and shouldOverrideUrlLoading() to catch the redirect and send it back to your own WebView.

#Mahtias Lin, please see my code to create and use WebView;
WebView webView = new WebView(this);
RelativeLayout.LayoutParams p = new RelativeLayout.LayoutParams(LayoutParams.FILL_PARENT, 416);
WebSettings webSettings = webView.getSettings();
webSettings.setSavePassword(false);
webSettings.setSaveFormData(false);
webSettings.setJavaScriptEnabled(true);
webView.setLayoutParams(p);
webView.loadUrl("http://www.google.com/");
Above code is not set my webview to 416px height.
#CommonsWare, I tried your suggested with following code and amazingly it works, thanks.
webView.setWebViewClient(new WebViewClient() {
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url)
{
view.loadUrl(url);
return false;
}
});
But this usage brought some new problems. When I override shouldOverrideURLLoading, the webview displays with no-addressbar, no-navigation (back, forward etc...)?
And also, the webview doenst accept user inputs?
Ok, I am editing my question :)
I searched and I found the following additional set to make webview to able to get inputs;
webView.requestFocus(View.FOCUS_DOWN);
On the other hand, I guess I will create my own back, forward buttons and address-bar for my webview. I will also attach "what happened" to this thread when I create my buttons and address-bar.
Best,

WebView wb=new WebView();
wb.setInitialScale(60);
this is used for set layout of the emulator. 60 means % value. we can use 0% to 100%.

See my reply and comments on
how to show a webview inside an activity in the middle of screen
Apply LayoutParams to your WebView or to the Layout (i.e. LinearLayout) that's surrounding the WebView, if any, i.e. setLayoutParams(LinearLayout.LayoutParams(200, 200));