i am trying to get the text input/values from an EditText widget as its being typed. please anybody know how or which method i should use? can't seem to find one that will help. thanks for your consideration.
i tried this but not working:
Entry = (EditText)findViewById(R.id.typeEntryId);
viewEntry = (TextView)findViewById(R.id.viewEntryId);
if(Entry != null){
//viewEntry.setText(Entry.getEditableText().toString());
viewEntry.setText(Entry.getText().toString());
}
Use a TextWatcher.
EditText field = (EditText) findViewById(R.id.myField);
if ( field != null ) {
Log.d ("myField",field.getText().toString());
}
you should be able to just do that. The getText() method returns an Editable type which implements CharSequence
Related
I have an EditText and a Button.
I want if an EditText was empty when clicked on my Button. I want to show message as a toast, like "please enter a number".
You can do something like this:
boolean hasValue = editText.getText().length() > 0;
or
boolean hasValue = !editText.getText().toString().isEmpty();
or to make sure it doesn't contain only spaces:
boolean hasValue = !editText.getText().toString().trim().isEmpty();
The cleanest way to do this is TextUtils.isEmpty(editText.getText())
The reason I say this is the cleanest way is because:
You avoid pointless conversion between CharSequence and String. Which creates an object. editText.getText() returns Editable, calling toString() creates an additional object which is not good. This method will also never return null in my experience.
You get a null and a length check out of that. If you look at the code for TextUtils.isEmpty(), it basically checks if the CharSequence is null and length is zero.
It avoids code duplication and the same method can be used with Strings or CharSequence objects and Editable is an implementation of CharSequence.
It's provided as part of the Android framework.
If you want to check the length of the trimmed String. Then use:
TextUtils.isEmpty(editText.getText())
&& TextUtils.getTrimmedLength(editText.getText()) == 0
If you want, you can create your own utility method to do this so you don't have to add such a long condition in your code repeatedly.
I would attached an OnFocusChangeListener to your EditText to check the change in value or a TextWatcher or both depending on how critical your requirement is. If your field had focus and lost it, do your validation with the OnFocusChangeListener, if your field has focus and the user is typing and delete the content or the content is too short, use TextWatcher to let them know.
Use this on click of your button:
EditText editText = (EditText) view.findViewById(EditTextID);
if(editText.getText().toString().length()==0) {
Toast alert = Toast.makeText(context, toast_message, Toast.LENGTH_SHORT);
alert.show();
}
In the onClickListener() of the button:
int length = editText.getText().length();
if(length == 0)
{
Toast.makeText(getActivity(), "Please enter a number",Toast.LENGTH_LONG).show();
}
you probably already found your answer, but for the ones who came here hoping to find an answer here is how its done:
you have to make a String object or Int object first then in your button function Click write this:
#Override
public void onClick(View view) {
String numberValue;
numberValue = yourEditText.getText().toString();
if (emailEtValue.matches("")){
Snackbar sbEmptyValue = Snackbar.make(view, "You must enter an Integer Value", Snackbar.LENGTH_LONG);
sbEmptyValue.show();
} else {
//DO THE THING YOU WANT
}
}
you can also use Toast but i prefer Snackbar because its cooler than Toast.
I got null data while fetch data from text Box.
My Code is:
EditText msg=(EditText)findViewById(R.id.Et_Msg);
String setMsg=msg.getText().toString();
Log.v("Messge","Message::"+setMsg);
Please tell me where I am wrong ?
This is your code,
EditText msg=(EditText)findViewById(R.id.Et_Msg);
String setMsg=msg.getText().toString();
Log.v("Messge","Message::"+setMsg);
The first line is initializing the EditText. When it does by default there is no value ( string ) in the edittext.
In the second line you are trying to fetch a string from a blank edittext, that's why it is giving you NullPointerException.
Solution : I suggest you to move your line String setMsg=msg.getText().toString(); to somewhere else where you are actually going to use the value of EditText.
While getting your data from EditText, you must create a listener orelse you get the value as null for an example button click listener..
For an example:
public class A extends Activity implements OnClickListener{
Button btn;
EditText edt;
#Override
public void onCreate(Bundle saved){
super.onCreate(saved);
edt = (EditText) findViewById(R.id.your_id);
btn = (Button) findViewById(R.id.your_id);
btn.setOnClickListener(this);
}
#Override
public void onClick(View v){
if(v == btn){
String setMsg=edt.getText().toString();
Log.v("Messge","Message::"+setMsg);
}
}
}
see.. what you are doing.. immediately after obtaining and EditText's object you are calling getText() on it.. think logically.. obviously there is nothing (it should return blank though not sure why it is returing null) in the EditText unless you have it from the xml.. something like this;
<EditText
...
android:text="Hey there"
...
/>
try this.. or move getText() call under some button click..
Please replace your below line
String setMsg=msg.getText().toString();
with
String setMsg = String.valueOf(msg.getText());
Please try above line. Your problem will be solved.
I have entered values in my text field, But the debugger shows null value.
The text id's are correct yet no value is being printed.
The log cat is showing null pointer exception. I have declared all the variables in the class.
The edit text string functions are declared in the method itself.
et1 = (EditText)findViewById(R.id.editText1);
et2 = (EditText)findViewById(R.id.editText2);
et3 = (EditText)findViewById(R.id.editText3);
et4 = (EditText)findViewById(R.id.editText4);
et5 = (EditText)findViewById(R.id.editText5);
set1 = et1.getText().toString();
set2 = et2.getText().toString();
set3 = et3.getText().toString();
set4 = et4.getText().toString();
set5 = et5.getText().toString();
System.out.println("set1 ="+set1);
System.out.println("set2 ="+set2);
All values given input are showing null and these are the few values that are being declared in the xml.
I need to know what mistake i am doing and how to rectify it.
i have initialized the values after setContent the data access happens in button on click listener... i didnt want to post the entire code.. –
I think your problem is same as this question.
You are directly accesssing the EditText's value after initializtion of EditText. You should accept the value on some event like onClick.
Let me Explain,
public class MainActivity extends Activity
{
EditText editText;
#Override
public void onCreate ( Bundle savedInstanceState )
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
editText = (EditText) findViewById ( R.id.firstEditText );
String str = editText().getText().toString();
// Here Str will be null blank all the time because EditText it self is blank.
}
}
Now see this
public class MainActivity extends Activity implements OnClickListener
{
EditText editText;
#Override
public void onCreate ( Bundle savedInstanceState )
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
editText = (EditText) findViewById ( R.id.firstEditText );
String str = editText().getText().toString();
// Here Str will be null blank all the time, since you haven't input anything in your EditText
}
#Override
public void onClick ( View view )
{
// Assuming you have already put some text in edittext.
String newStr = editText().getText().toString();
}
}
I would suggest you to follow some steps to find out your actual problem
check that you have set right layout in the setContentView.
before getting text from edit text set some text in it and then get text form the EditText view. Check that it still printing null.
I think you have done some silly mistake because EditText.getText() never returns null.
NullPoint exception is thrown because you are converting a NULL value to a string
et1.getText() is null and you are doing
et1.getText().toString();
which is wrong.
Every EditText is initially NULL because it does not contain any value.
According to Android Docs
public Editable getText ()
Added in API level 1
Return the text the TextView is displaying.
Since the EditText has not been set any text hence its current value is null.
I have to get a EditText object which is nothing but a search bar in app with text visible as Current Location, however if I've already made a search query with myText, there is no Current Location text visible and search bar shows myText.
I am writing the test cases using Robotium solo object.
How can i write a conditional statement to get the EditText despite of what text it shows. Something like
if !found solo.getText("Current Location")
search solo.getText("myText");
This is what I am doing currently
EditText text = (EditText) solo.getText("Current Location");
if(text == null){
text = (EditText) solo.getText("myText");
//my rest of the code goes here....
But this throws exception if Current Location is not present in the search bar.
junit.framework.AssertionFailedError: TextView with text: 'Current Location' is not found!
Please suggest the correct way.
Try with this code:
if(!solo.searchText("Current Location"))
assertTrue(solo.searchText("my Text"))
else
assertTrue(solo.searchText("Current Location"));
EditText view = (EditText) solo.getView(view1);
if(view == null){
view = (EditText) solo.getView(view2)
}
view.getText().toString();
I am trying to get a message to appear when a button is clicked to tell the user to fill in the blank field. Currently, if the field is blank, it crashes/force closes the app. I tried to do the following code and had zero success. Originally I didn't have the if/else in there, I just ran the calculator(); method and the following imm code.
Could someone point me into the right direction?
public void onClick(View v)
{
if ((EditText)findViewById(R.id.amount1)== null)
{
Context context = getApplicationContext();
CharSequence text = "Enter a number";
int duration = Toast.LENGTH_SHORT;
Toast toast = Toast.makeText(context, text, duration);
toast.show();
}
else
{
calculator();
InputMethodManager imm = (InputMethodManager) getSystemService(INPUT_METHOD_SERVICE);
imm.hideSoftInputFromWindow(getCurrentFocus().getWindowToken(), 0);
}
}
Im pretty sure this is the bad code:
if ((EditText)findViewById(R.id.amount1)== null)
Just dont know how to word it the way I want.
Try checking the length of the text in the EditText widget
EditText e = (EditText)findViewById(R.id.amount1));
if(e.getText().length == 0){
//Show Toast
}else{
//continue your code
}
Use this code.
EditText et = (EditText)findViewById(R.id.amount1));
if(et1.getText().length() == 0){
//Display toast here
} else{
//Your code
}
EditText text = (EditText)findViewById(R.id.amount1);
if(TextUtils.isEmpty(text.toString())) {
// show toast
}
Even if the field is blank, the edittext is not null. Use:
EditText editText = (EditText)findViewById(R.id.amount1);
String text = new String(editText.getText());
if (test.equals("")) {
//...
((EditText)findViewById(R.id.amount1)== null is just getting a reference to the EditText with the id amount1, it is not checking to see if that EditText has a valid entry.
To see if the EditText has text, you can get the String it holds by via EditText#getText().toString()
To make this work, first store the reference to the EditText in a var, then perform your checks on the String:
EditText et = (EditText)findViewById(R.id.amount1);
String amount1 = et.getText().toString();
if (amount1.equals("")) {
// Do your stuff here
}
I'm using local variables and just assuming you want the string to have content. You will likely need to do other checks to handle all the cases (like malformed input). Some of this you can reduce by setting the inputType on the EditText. For example, you might set it to numberDecimal if you are trying to handle only decimal numbers.
You actually want to check if the contents of the EditText are null or an empty string.
The line in question should look something like this:
if("".equals(((EditText)findViewById(R.id.amount1)).getText().toString()))
Of course you may want to break that statement up into more lines to make it a bit more readable!