Open Twitter app from other app and load some page

Open Twitter app from other app and load some page - android

Is there a way to open the Twitter app from my own application?
For example, I have my own Android app and I want to open Twitter app using Intent.
How can I do that?
Answers with example would be much appreciated.

try {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?screen_name=" + twitter_user_name)));
}catch (Exception e) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/#!/" + twitter_user_name)));
}
This should do the necessary work for you.

Expanding on #Chrishan's answer you can open the twitter app to perform different functions based on the uri (list below from this post)
twitter://user?screen_name=lorenb
twitter://user?id=12345
twitter://status?id=12345
twitter://timeline
twitter://mentions
twitter://messages
twitter://list?screen_name=lorenb&slug=abcd
twitter://post?message=hello world
twitter://post?message=hello world&in_reply_to_status_id=12345
twitter://search?query=%23hashtag
e.g.
String uriStr = "twitter://post?message=hello world"
try {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(uriStr)));
}catch (Exception e) {
//the user doesn't have twitter installed
}
NOTE: I have only tried user and post, so if you come across any that don't work please let me know and I will update this answer.

If the user already has Twitter installed on their phone, something like this should take care of it:
try{
Intent intent = new Intent(Intent.ACTION_SEND);
intent.putExtra(Intent.EXTRA_TEXT, "this is a tweet");
intent.setType("text/plain");
final PackageManager pm = getPackageManager();
final List<?> activityList = pm.queryIntentActivities(intent, 0);
int len = activityList.size();
for (int i = 0; i < len; i++) {
final ResolveInfo app = (ResolveInfo) activityList.get(i);
if ("com.twitter.android.PostActivity".equals(app.activityInfo.name)) {
final ActivityInfo activity=app.activityInfo;
final ComponentName name=new ComponentName(activity.applicationInfo.packageName, activity.name);
intent.addCategory(Intent.CATEGORY_LAUNCHER);
intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED);
intent.setComponent(name);
startActivity(intent);
break;
}
}
}
catch(final ActivityNotFoundException e) {
Log.i("twitter", "no twitter native",e );
}

I use this:
Intent i = getOpenTwitterIntent(this, "UserName");
startActivity(i);
And the function:
public static Intent getOpenTwitterIntent(Context c, String Username) {
try {
c.getPackageManager().getPackageInfo("com.twitter.android", 0);
return new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?screen_name="+ Username));
} catch (Exception e) {
return new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/#!/" + Username));
}
}
If Twitter app is intalled in the device, this open that, else open web browser...

private void showTwitter(){
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setClassName("com.twitter.android", "com.twitter.android.ProfileActivity");
this.startActivity(intent);
}

Related

Is there a way to get or display the method name of an android app using another android app? [duplicate]

I want to launch an installed package from my Android application. I assume that it is possible using intents, but I didn't find a way of doing it. Is there a link, where to find the information?

If you don't know the main activity, then the package name can be used to launch the application.
Intent launchIntent = getPackageManager().getLaunchIntentForPackage("com.package.address");
if (launchIntent != null) {
startActivity(launchIntent);//null pointer check in case package name was not found
}

I know this has been answered but here is how I implemented something similar:
Intent intent = getPackageManager().getLaunchIntentForPackage("com.package.name");
if (intent != null) {
// We found the activity now start the activity
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
} else {
// Bring user to the market or let them choose an app?
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("market://details?id=" + "com.package.name"));
startActivity(intent);
}
Even better, here is the method:
public void startNewActivity(Context context, String packageName) {
Intent intent = context.getPackageManager().getLaunchIntentForPackage(packageName);
if (intent != null) {
// We found the activity now start the activity
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(intent);
} else {
// Bring user to the market or let them choose an app?
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("market://details?id=" + packageName));
context.startActivity(intent);
}
}
Removed duplicate code:
public void startNewActivity(Context context, String packageName) {
Intent intent = context.getPackageManager().getLaunchIntentForPackage(packageName);
if (intent == null) {
// Bring user to the market or let them choose an app?
intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse("market://details?id=" + packageName));
}
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(intent);
}

I found the solution. In the manifest file of the application I found the package name: com.package.address and the name of the main activity which I want to launch: MainActivity
The following code starts this application:
Intent intent = new Intent(Intent.ACTION_MAIN);
intent.setComponent(new ComponentName("com.package.address","com.package.address.MainActivity"));
startActivity(intent);

// in onCreate method
String appName = "Gmail";
String packageName = "com.google.android.gm";
openApp(context, appName, packageName);
public static void openApp(Context context, String appName, String packageName) {
if (isAppInstalled(context, packageName))
if (isAppEnabled(context, packageName))
context.startActivity(context.getPackageManager().getLaunchIntentForPackage(packageName));
else Toast.makeText(context, appName + " app is not enabled.", Toast.LENGTH_SHORT).show();
else Toast.makeText(context, appName + " app is not installed.", Toast.LENGTH_SHORT).show();
}
private static boolean isAppInstalled(Context context, String packageName) {
PackageManager pm = context.getPackageManager();
try {
pm.getPackageInfo(packageName, PackageManager.GET_ACTIVITIES);
return true;
} catch (PackageManager.NameNotFoundException ignored) {
}
return false;
}
private static boolean isAppEnabled(Context context, String packageName) {
boolean appStatus = false;
try {
ApplicationInfo ai = context.getPackageManager().getApplicationInfo(packageName, 0);
if (ai != null) {
appStatus = ai.enabled;
}
} catch (PackageManager.NameNotFoundException e) {
e.printStackTrace();
}
return appStatus;
}

Edit depending on comment
In some versions - as suggested in comments - the exception thrown may be different.
Thus the solution below is slightly modified
Intent launchIntent = null;
try{
launchIntent = getPackageManager().getLaunchIntentForPackage("applicationId");
} catch (Exception ignored) {}
if(launchIntent == null){
startActivity(new Intent(Intent.ACTION_VIEW).setData(Uri.parse("https://play.google.com/store/apps/details?id=" + "applicationId")));
} else {
startActivity(launchIntent);
}
Original Answer
Although answered well, there is a pretty simple implementation that handles if the app is not installed. I do it like this
try{
startActivity(getPackageManager().getLaunchIntentForPackage("applicationId"));
} catch (PackageManager.NameNotFoundException e) {
startActivity(new Intent(Intent.ACTION_VIEW).setData(Uri.parse("https://play.google.com/store/apps/details?id=" + "applicationId")));
}
Replace "applicationId" with the package that you want to open such as com.google.maps, etc.

Here is my example of launching bar/QR code scanner from my app if someone finds it useful
Intent intent = new Intent("com.google.zxing.client.android.SCAN");
intent.setPackage("com.google.zxing.client.android");
try
{
startActivityForResult(intent, SCAN_REQUEST_CODE);
}
catch (ActivityNotFoundException e)
{
//implement prompt dialog asking user to download the package
AlertDialog.Builder downloadDialog = new AlertDialog.Builder(this);
downloadDialog.setTitle(stringTitle);
downloadDialog.setMessage(stringMessage);
downloadDialog.setPositiveButton("yes",
new DialogInterface.OnClickListener()
{
public void onClick(DialogInterface dialogInterface, int i)
{
Uri uri = Uri.parse("market://search?q=pname:com.google.zxing.client.android");
Intent intent = new Intent(Intent.ACTION_VIEW, uri);
try
{
myActivity.this.startActivity(intent);
}
catch (ActivityNotFoundException e)
{
Dialogs.this.showAlert("ERROR", "Google Play Market not found!");
}
}
});
downloadDialog.setNegativeButton("no",
new DialogInterface.OnClickListener()
{
public void onClick(DialogInterface dialog, int i)
{
dialog.dismiss();
}
});
downloadDialog.show();
}

If you want to open specific activity of another application we can use this.
Intent intent = new Intent(Intent.ACTION_MAIN, null);
intent.addCategory(Intent.CATEGORY_LAUNCHER);
final ComponentName cn = new ComponentName("com.android.settings", "com.android.settings.fuelgauge.PowerUsageSummary");
intent.setComponent(cn);
intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
try
{
startActivity(intent)
}catch(ActivityNotFoundException e){
Toast.makeText(context,"Activity Not Found",Toast.LENGTH_SHORT).show()
}
If you must need other application, instead of showing Toast you can show a dialog. Using dialog you can bring the user to Play-Store to download required application.

Check for the app, avoiding any crashes. If the app exists in the phone then it will be launched, otherwise it will search in Google Play. If no Google Play app installed in the phone, it will search in the Google Play Store via browser:
public void onLunchAnotherApp() {
final String appPackageName = getApplicationContext().getPackageName();
Intent intent = getPackageManager().getLaunchIntentForPackage(appPackageName);
if (intent != null) {
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
} else {
onGoToAnotherInAppStore(intent, appPackageName);
}
}
public void onGoToAnotherInAppStore(Intent intent, String appPackageName) {
try {
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("market://details?id=" + appPackageName));
startActivity(intent);
} catch (android.content.ActivityNotFoundException anfe) {
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("http://play.google.com/store/apps/details?id=" + appPackageName));
startActivity(intent);
}
}

Starting from API 30 (Android 11) you can receive nullpointerexception with launchIntentForPackage
val launchIntent: Intent? = activity.packageManager.getLaunchIntentForPackage("com.google.android.gm")
startActivity(launchIntent)
To avoid this you need to add the needed package to the manifest
<queries>
<package android:name="com.google.android.gm" />
</queries>
Here is documentation
https://developer.android.com/training/package-visibility
And the medium article
https://medium.com/androiddevelopers/package-visibility-in-android-11-cc857f221cd9

It is possible to start an app's activity by using Intent.setClassName according to the docs.
An example:
val activityName = "com.google.android.apps.muzei.MuzeiActivity" // target activity name
val packageName = "net.nurik.roman.muzei" // target package's name
val intent = Intent().setClassName(packageName, activityName)
startActivity(intent)
To open it outside the current app, add this flag before starting the intent.
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
A related answer here

If you know the data and the action the installed package react on, you simply should add these information to your intent instance before starting it.
If you have access to the AndroidManifest of the other app, you can see all needed information there.

Steps to launch new activity as follows:
1.Get intent for package
2.If intent is null redirect user to playstore
3.If intent is not null open activity
public void launchNewActivity(Context context, String packageName) {
Intent intent = null;
if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.CUPCAKE) {
intent = context.getPackageManager().getLaunchIntentForPackage(packageName);
}
if (intent == null) {
try {
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("market://details?id=" + packageName));
context.startActivity(intent);
} catch (android.content.ActivityNotFoundException anfe) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + packageName)));
}
} else {
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(intent);
}
}

private fun openOtherApp() {
val sendIntent = packageManager.getLaunchIntentForPackage("org.mab.dhyanaqrscanner")
startActivity(sendIntent)
finishAffinity()
}

This will cover all scenarios
1.Get intent for package
2.If intent is null redirect user to playstore
3.If there is an issue with open playstore, then it opens on the default browser.
var intent = activity!!.packageManager.getLaunchIntentForPackage("com.google.android.youtube")
if (intent == null) {
if (intent == null) {
intent = try {
Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=com.google.android.youtube"))
} catch (e: Exception) {
Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=com.google.android.youtube"))
}
}
startActivity(intent)
For Android 11 (API level 30) or higher, in AndroidManifest.xml,
<queries>
<package android:name="com.google.android.youtube" />
<package android:name="com.example.app" />
</queries>
Or simply we can allow for all packages (not recommended)
<uses-permission android:name="android.permission.QUERY_ALL_PACKAGES" tools:ignore="QueryAllPackagesPermission" />
References
Package visibility filtering on Android
Declaring package visibility needs

Try code below:
Intent intent = new Intent(Intent.ACTION_MAIN);
intent.setComponent(new ComponentName("package_name", "Class_name"));
if (intent.resolveActivity(getPackageManager()) != null)
{
startActivity(intent);
}

In Kotlin
fun openApplicationOrMarket(packageName: String) {
var intent = requireContext().packageManager.getLaunchIntentForPackage(packageName)
if (intent == null) {
intent = Intent(Intent.ACTION_VIEW)
intent.data = Uri.parse("market://details?id=$packageName")
}
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
requireContext().startActivity(intent)
}

Pass the package name and the message you want to show if package isn't installed ;-)
void openApp(String appPackageName,String message){
Intent launchIntent = getPackageManager().getLaunchIntentForPackage(appPackageName);
if (launchIntent != null) {
startActivity(launchIntent);
} else {
Toast.makeText(MainActivity.this, message, Toast.LENGTH_LONG).show();
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + appPackageName)));
}
}

Since kotlin is becoming very popular these days, I think it's appropriate to provide a simple solution in Kotlin as well.
var launchIntent: Intent? = null
try {
launchIntent = packageManager.getLaunchIntentForPackage("applicationId")
} catch (ignored: Exception) {
}
if (launchIntent == null) {
startActivity(Intent(Intent.ACTION_VIEW).setData(Uri.parse("https://play.google.com/store/apps/details?id=" + "applicationId")))
} else {
startActivity(launchIntent)
}

Android open another app and jump to specific Activity [duplicate]

I want to launch an installed package from my Android application. I assume that it is possible using intents, but I didn't find a way of doing it. Is there a link, where to find the information?

If you don't know the main activity, then the package name can be used to launch the application.
Intent launchIntent = getPackageManager().getLaunchIntentForPackage("com.package.address");
if (launchIntent != null) {
startActivity(launchIntent);//null pointer check in case package name was not found
}

I know this has been answered but here is how I implemented something similar:
Intent intent = getPackageManager().getLaunchIntentForPackage("com.package.name");
if (intent != null) {
// We found the activity now start the activity
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
} else {
// Bring user to the market or let them choose an app?
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("market://details?id=" + "com.package.name"));
startActivity(intent);
}
Even better, here is the method:
public void startNewActivity(Context context, String packageName) {
Intent intent = context.getPackageManager().getLaunchIntentForPackage(packageName);
if (intent != null) {
// We found the activity now start the activity
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(intent);
} else {
// Bring user to the market or let them choose an app?
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("market://details?id=" + packageName));
context.startActivity(intent);
}
}
Removed duplicate code:
public void startNewActivity(Context context, String packageName) {
Intent intent = context.getPackageManager().getLaunchIntentForPackage(packageName);
if (intent == null) {
// Bring user to the market or let them choose an app?
intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse("market://details?id=" + packageName));
}
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(intent);
}

I found the solution. In the manifest file of the application I found the package name: com.package.address and the name of the main activity which I want to launch: MainActivity
The following code starts this application:
Intent intent = new Intent(Intent.ACTION_MAIN);
intent.setComponent(new ComponentName("com.package.address","com.package.address.MainActivity"));
startActivity(intent);

// in onCreate method
String appName = "Gmail";
String packageName = "com.google.android.gm";
openApp(context, appName, packageName);
public static void openApp(Context context, String appName, String packageName) {
if (isAppInstalled(context, packageName))
if (isAppEnabled(context, packageName))
context.startActivity(context.getPackageManager().getLaunchIntentForPackage(packageName));
else Toast.makeText(context, appName + " app is not enabled.", Toast.LENGTH_SHORT).show();
else Toast.makeText(context, appName + " app is not installed.", Toast.LENGTH_SHORT).show();
}
private static boolean isAppInstalled(Context context, String packageName) {
PackageManager pm = context.getPackageManager();
try {
pm.getPackageInfo(packageName, PackageManager.GET_ACTIVITIES);
return true;
} catch (PackageManager.NameNotFoundException ignored) {
}
return false;
}
private static boolean isAppEnabled(Context context, String packageName) {
boolean appStatus = false;
try {
ApplicationInfo ai = context.getPackageManager().getApplicationInfo(packageName, 0);
if (ai != null) {
appStatus = ai.enabled;
}
} catch (PackageManager.NameNotFoundException e) {
e.printStackTrace();
}
return appStatus;
}

Edit depending on comment
In some versions - as suggested in comments - the exception thrown may be different.
Thus the solution below is slightly modified
Intent launchIntent = null;
try{
launchIntent = getPackageManager().getLaunchIntentForPackage("applicationId");
} catch (Exception ignored) {}
if(launchIntent == null){
startActivity(new Intent(Intent.ACTION_VIEW).setData(Uri.parse("https://play.google.com/store/apps/details?id=" + "applicationId")));
} else {
startActivity(launchIntent);
}
Original Answer
Although answered well, there is a pretty simple implementation that handles if the app is not installed. I do it like this
try{
startActivity(getPackageManager().getLaunchIntentForPackage("applicationId"));
} catch (PackageManager.NameNotFoundException e) {
startActivity(new Intent(Intent.ACTION_VIEW).setData(Uri.parse("https://play.google.com/store/apps/details?id=" + "applicationId")));
}
Replace "applicationId" with the package that you want to open such as com.google.maps, etc.

Here is my example of launching bar/QR code scanner from my app if someone finds it useful
Intent intent = new Intent("com.google.zxing.client.android.SCAN");
intent.setPackage("com.google.zxing.client.android");
try
{
startActivityForResult(intent, SCAN_REQUEST_CODE);
}
catch (ActivityNotFoundException e)
{
//implement prompt dialog asking user to download the package
AlertDialog.Builder downloadDialog = new AlertDialog.Builder(this);
downloadDialog.setTitle(stringTitle);
downloadDialog.setMessage(stringMessage);
downloadDialog.setPositiveButton("yes",
new DialogInterface.OnClickListener()
{
public void onClick(DialogInterface dialogInterface, int i)
{
Uri uri = Uri.parse("market://search?q=pname:com.google.zxing.client.android");
Intent intent = new Intent(Intent.ACTION_VIEW, uri);
try
{
myActivity.this.startActivity(intent);
}
catch (ActivityNotFoundException e)
{
Dialogs.this.showAlert("ERROR", "Google Play Market not found!");
}
}
});
downloadDialog.setNegativeButton("no",
new DialogInterface.OnClickListener()
{
public void onClick(DialogInterface dialog, int i)
{
dialog.dismiss();
}
});
downloadDialog.show();
}

If you want to open specific activity of another application we can use this.
Intent intent = new Intent(Intent.ACTION_MAIN, null);
intent.addCategory(Intent.CATEGORY_LAUNCHER);
final ComponentName cn = new ComponentName("com.android.settings", "com.android.settings.fuelgauge.PowerUsageSummary");
intent.setComponent(cn);
intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
try
{
startActivity(intent)
}catch(ActivityNotFoundException e){
Toast.makeText(context,"Activity Not Found",Toast.LENGTH_SHORT).show()
}
If you must need other application, instead of showing Toast you can show a dialog. Using dialog you can bring the user to Play-Store to download required application.

Check for the app, avoiding any crashes. If the app exists in the phone then it will be launched, otherwise it will search in Google Play. If no Google Play app installed in the phone, it will search in the Google Play Store via browser:
public void onLunchAnotherApp() {
final String appPackageName = getApplicationContext().getPackageName();
Intent intent = getPackageManager().getLaunchIntentForPackage(appPackageName);
if (intent != null) {
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
} else {
onGoToAnotherInAppStore(intent, appPackageName);
}
}
public void onGoToAnotherInAppStore(Intent intent, String appPackageName) {
try {
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("market://details?id=" + appPackageName));
startActivity(intent);
} catch (android.content.ActivityNotFoundException anfe) {
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("http://play.google.com/store/apps/details?id=" + appPackageName));
startActivity(intent);
}
}

Starting from API 30 (Android 11) you can receive nullpointerexception with launchIntentForPackage
val launchIntent: Intent? = activity.packageManager.getLaunchIntentForPackage("com.google.android.gm")
startActivity(launchIntent)
To avoid this you need to add the needed package to the manifest
<queries>
<package android:name="com.google.android.gm" />
</queries>
Here is documentation
https://developer.android.com/training/package-visibility
And the medium article
https://medium.com/androiddevelopers/package-visibility-in-android-11-cc857f221cd9

It is possible to start an app's activity by using Intent.setClassName according to the docs.
An example:
val activityName = "com.google.android.apps.muzei.MuzeiActivity" // target activity name
val packageName = "net.nurik.roman.muzei" // target package's name
val intent = Intent().setClassName(packageName, activityName)
startActivity(intent)
To open it outside the current app, add this flag before starting the intent.
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
A related answer here

If you know the data and the action the installed package react on, you simply should add these information to your intent instance before starting it.
If you have access to the AndroidManifest of the other app, you can see all needed information there.

Steps to launch new activity as follows:
1.Get intent for package
2.If intent is null redirect user to playstore
3.If intent is not null open activity
public void launchNewActivity(Context context, String packageName) {
Intent intent = null;
if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.CUPCAKE) {
intent = context.getPackageManager().getLaunchIntentForPackage(packageName);
}
if (intent == null) {
try {
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("market://details?id=" + packageName));
context.startActivity(intent);
} catch (android.content.ActivityNotFoundException anfe) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + packageName)));
}
} else {
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(intent);
}
}

private fun openOtherApp() {
val sendIntent = packageManager.getLaunchIntentForPackage("org.mab.dhyanaqrscanner")
startActivity(sendIntent)
finishAffinity()
}

This will cover all scenarios
1.Get intent for package
2.If intent is null redirect user to playstore
3.If there is an issue with open playstore, then it opens on the default browser.
var intent = activity!!.packageManager.getLaunchIntentForPackage("com.google.android.youtube")
if (intent == null) {
if (intent == null) {
intent = try {
Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=com.google.android.youtube"))
} catch (e: Exception) {
Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=com.google.android.youtube"))
}
}
startActivity(intent)
For Android 11 (API level 30) or higher, in AndroidManifest.xml,
<queries>
<package android:name="com.google.android.youtube" />
<package android:name="com.example.app" />
</queries>
Or simply we can allow for all packages (not recommended)
<uses-permission android:name="android.permission.QUERY_ALL_PACKAGES" tools:ignore="QueryAllPackagesPermission" />
References
Package visibility filtering on Android
Declaring package visibility needs

Try code below:
Intent intent = new Intent(Intent.ACTION_MAIN);
intent.setComponent(new ComponentName("package_name", "Class_name"));
if (intent.resolveActivity(getPackageManager()) != null)
{
startActivity(intent);
}

In Kotlin
fun openApplicationOrMarket(packageName: String) {
var intent = requireContext().packageManager.getLaunchIntentForPackage(packageName)
if (intent == null) {
intent = Intent(Intent.ACTION_VIEW)
intent.data = Uri.parse("market://details?id=$packageName")
}
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
requireContext().startActivity(intent)
}

Pass the package name and the message you want to show if package isn't installed ;-)
void openApp(String appPackageName,String message){
Intent launchIntent = getPackageManager().getLaunchIntentForPackage(appPackageName);
if (launchIntent != null) {
startActivity(launchIntent);
} else {
Toast.makeText(MainActivity.this, message, Toast.LENGTH_LONG).show();
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + appPackageName)));
}
}

Since kotlin is becoming very popular these days, I think it's appropriate to provide a simple solution in Kotlin as well.
var launchIntent: Intent? = null
try {
launchIntent = packageManager.getLaunchIntentForPackage("applicationId")
} catch (ignored: Exception) {
}
if (launchIntent == null) {
startActivity(Intent(Intent.ACTION_VIEW).setData(Uri.parse("https://play.google.com/store/apps/details?id=" + "applicationId")))
} else {
startActivity(launchIntent)
}

How do I open an Android intent in a specific application? [duplicate]

I want to launch an installed package from my Android application. I assume that it is possible using intents, but I didn't find a way of doing it. Is there a link, where to find the information?

If you don't know the main activity, then the package name can be used to launch the application.
Intent launchIntent = getPackageManager().getLaunchIntentForPackage("com.package.address");
if (launchIntent != null) {
startActivity(launchIntent);//null pointer check in case package name was not found
}

I know this has been answered but here is how I implemented something similar:
Intent intent = getPackageManager().getLaunchIntentForPackage("com.package.name");
if (intent != null) {
// We found the activity now start the activity
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
} else {
// Bring user to the market or let them choose an app?
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("market://details?id=" + "com.package.name"));
startActivity(intent);
}
Even better, here is the method:
public void startNewActivity(Context context, String packageName) {
Intent intent = context.getPackageManager().getLaunchIntentForPackage(packageName);
if (intent != null) {
// We found the activity now start the activity
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(intent);
} else {
// Bring user to the market or let them choose an app?
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("market://details?id=" + packageName));
context.startActivity(intent);
}
}
Removed duplicate code:
public void startNewActivity(Context context, String packageName) {
Intent intent = context.getPackageManager().getLaunchIntentForPackage(packageName);
if (intent == null) {
// Bring user to the market or let them choose an app?
intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse("market://details?id=" + packageName));
}
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(intent);
}

I found the solution. In the manifest file of the application I found the package name: com.package.address and the name of the main activity which I want to launch: MainActivity
The following code starts this application:
Intent intent = new Intent(Intent.ACTION_MAIN);
intent.setComponent(new ComponentName("com.package.address","com.package.address.MainActivity"));
startActivity(intent);

// in onCreate method
String appName = "Gmail";
String packageName = "com.google.android.gm";
openApp(context, appName, packageName);
public static void openApp(Context context, String appName, String packageName) {
if (isAppInstalled(context, packageName))
if (isAppEnabled(context, packageName))
context.startActivity(context.getPackageManager().getLaunchIntentForPackage(packageName));
else Toast.makeText(context, appName + " app is not enabled.", Toast.LENGTH_SHORT).show();
else Toast.makeText(context, appName + " app is not installed.", Toast.LENGTH_SHORT).show();
}
private static boolean isAppInstalled(Context context, String packageName) {
PackageManager pm = context.getPackageManager();
try {
pm.getPackageInfo(packageName, PackageManager.GET_ACTIVITIES);
return true;
} catch (PackageManager.NameNotFoundException ignored) {
}
return false;
}
private static boolean isAppEnabled(Context context, String packageName) {
boolean appStatus = false;
try {
ApplicationInfo ai = context.getPackageManager().getApplicationInfo(packageName, 0);
if (ai != null) {
appStatus = ai.enabled;
}
} catch (PackageManager.NameNotFoundException e) {
e.printStackTrace();
}
return appStatus;
}

Edit depending on comment
In some versions - as suggested in comments - the exception thrown may be different.
Thus the solution below is slightly modified
Intent launchIntent = null;
try{
launchIntent = getPackageManager().getLaunchIntentForPackage("applicationId");
} catch (Exception ignored) {}
if(launchIntent == null){
startActivity(new Intent(Intent.ACTION_VIEW).setData(Uri.parse("https://play.google.com/store/apps/details?id=" + "applicationId")));
} else {
startActivity(launchIntent);
}
Original Answer
Although answered well, there is a pretty simple implementation that handles if the app is not installed. I do it like this
try{
startActivity(getPackageManager().getLaunchIntentForPackage("applicationId"));
} catch (PackageManager.NameNotFoundException e) {
startActivity(new Intent(Intent.ACTION_VIEW).setData(Uri.parse("https://play.google.com/store/apps/details?id=" + "applicationId")));
}
Replace "applicationId" with the package that you want to open such as com.google.maps, etc.

Here is my example of launching bar/QR code scanner from my app if someone finds it useful
Intent intent = new Intent("com.google.zxing.client.android.SCAN");
intent.setPackage("com.google.zxing.client.android");
try
{
startActivityForResult(intent, SCAN_REQUEST_CODE);
}
catch (ActivityNotFoundException e)
{
//implement prompt dialog asking user to download the package
AlertDialog.Builder downloadDialog = new AlertDialog.Builder(this);
downloadDialog.setTitle(stringTitle);
downloadDialog.setMessage(stringMessage);
downloadDialog.setPositiveButton("yes",
new DialogInterface.OnClickListener()
{
public void onClick(DialogInterface dialogInterface, int i)
{
Uri uri = Uri.parse("market://search?q=pname:com.google.zxing.client.android");
Intent intent = new Intent(Intent.ACTION_VIEW, uri);
try
{
myActivity.this.startActivity(intent);
}
catch (ActivityNotFoundException e)
{
Dialogs.this.showAlert("ERROR", "Google Play Market not found!");
}
}
});
downloadDialog.setNegativeButton("no",
new DialogInterface.OnClickListener()
{
public void onClick(DialogInterface dialog, int i)
{
dialog.dismiss();
}
});
downloadDialog.show();
}

If you want to open specific activity of another application we can use this.
Intent intent = new Intent(Intent.ACTION_MAIN, null);
intent.addCategory(Intent.CATEGORY_LAUNCHER);
final ComponentName cn = new ComponentName("com.android.settings", "com.android.settings.fuelgauge.PowerUsageSummary");
intent.setComponent(cn);
intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
try
{
startActivity(intent)
}catch(ActivityNotFoundException e){
Toast.makeText(context,"Activity Not Found",Toast.LENGTH_SHORT).show()
}
If you must need other application, instead of showing Toast you can show a dialog. Using dialog you can bring the user to Play-Store to download required application.

Check for the app, avoiding any crashes. If the app exists in the phone then it will be launched, otherwise it will search in Google Play. If no Google Play app installed in the phone, it will search in the Google Play Store via browser:
public void onLunchAnotherApp() {
final String appPackageName = getApplicationContext().getPackageName();
Intent intent = getPackageManager().getLaunchIntentForPackage(appPackageName);
if (intent != null) {
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
} else {
onGoToAnotherInAppStore(intent, appPackageName);
}
}
public void onGoToAnotherInAppStore(Intent intent, String appPackageName) {
try {
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("market://details?id=" + appPackageName));
startActivity(intent);
} catch (android.content.ActivityNotFoundException anfe) {
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("http://play.google.com/store/apps/details?id=" + appPackageName));
startActivity(intent);
}
}

Starting from API 30 (Android 11) you can receive nullpointerexception with launchIntentForPackage
val launchIntent: Intent? = activity.packageManager.getLaunchIntentForPackage("com.google.android.gm")
startActivity(launchIntent)
To avoid this you need to add the needed package to the manifest
<queries>
<package android:name="com.google.android.gm" />
</queries>
Here is documentation
https://developer.android.com/training/package-visibility
And the medium article
https://medium.com/androiddevelopers/package-visibility-in-android-11-cc857f221cd9

It is possible to start an app's activity by using Intent.setClassName according to the docs.
An example:
val activityName = "com.google.android.apps.muzei.MuzeiActivity" // target activity name
val packageName = "net.nurik.roman.muzei" // target package's name
val intent = Intent().setClassName(packageName, activityName)
startActivity(intent)
To open it outside the current app, add this flag before starting the intent.
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
A related answer here

If you know the data and the action the installed package react on, you simply should add these information to your intent instance before starting it.
If you have access to the AndroidManifest of the other app, you can see all needed information there.

Steps to launch new activity as follows:
1.Get intent for package
2.If intent is null redirect user to playstore
3.If intent is not null open activity
public void launchNewActivity(Context context, String packageName) {
Intent intent = null;
if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.CUPCAKE) {
intent = context.getPackageManager().getLaunchIntentForPackage(packageName);
}
if (intent == null) {
try {
intent = new Intent(Intent.ACTION_VIEW);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setData(Uri.parse("market://details?id=" + packageName));
context.startActivity(intent);
} catch (android.content.ActivityNotFoundException anfe) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + packageName)));
}
} else {
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(intent);
}
}

private fun openOtherApp() {
val sendIntent = packageManager.getLaunchIntentForPackage("org.mab.dhyanaqrscanner")
startActivity(sendIntent)
finishAffinity()
}

This will cover all scenarios
1.Get intent for package
2.If intent is null redirect user to playstore
3.If there is an issue with open playstore, then it opens on the default browser.
var intent = activity!!.packageManager.getLaunchIntentForPackage("com.google.android.youtube")
if (intent == null) {
if (intent == null) {
intent = try {
Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=com.google.android.youtube"))
} catch (e: Exception) {
Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=com.google.android.youtube"))
}
}
startActivity(intent)
For Android 11 (API level 30) or higher, in AndroidManifest.xml,
<queries>
<package android:name="com.google.android.youtube" />
<package android:name="com.example.app" />
</queries>
Or simply we can allow for all packages (not recommended)
<uses-permission android:name="android.permission.QUERY_ALL_PACKAGES" tools:ignore="QueryAllPackagesPermission" />
References
Package visibility filtering on Android
Declaring package visibility needs

Try code below:
Intent intent = new Intent(Intent.ACTION_MAIN);
intent.setComponent(new ComponentName("package_name", "Class_name"));
if (intent.resolveActivity(getPackageManager()) != null)
{
startActivity(intent);
}

In Kotlin
fun openApplicationOrMarket(packageName: String) {
var intent = requireContext().packageManager.getLaunchIntentForPackage(packageName)
if (intent == null) {
intent = Intent(Intent.ACTION_VIEW)
intent.data = Uri.parse("market://details?id=$packageName")
}
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
requireContext().startActivity(intent)
}

Pass the package name and the message you want to show if package isn't installed ;-)
void openApp(String appPackageName,String message){
Intent launchIntent = getPackageManager().getLaunchIntentForPackage(appPackageName);
if (launchIntent != null) {
startActivity(launchIntent);
} else {
Toast.makeText(MainActivity.this, message, Toast.LENGTH_LONG).show();
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + appPackageName)));
}
}

Since kotlin is becoming very popular these days, I think it's appropriate to provide a simple solution in Kotlin as well.
var launchIntent: Intent? = null
try {
launchIntent = packageManager.getLaunchIntentForPackage("applicationId")
} catch (ignored: Exception) {
}
if (launchIntent == null) {
startActivity(Intent(Intent.ACTION_VIEW).setData(Uri.parse("https://play.google.com/store/apps/details?id=" + "applicationId")))
} else {
startActivity(launchIntent)
}

Share Image and data to Twitter in android

I ma developing one application in i have to share data and image to Twitter from my android Application.I am following http://chintankhetiya.wordpress.com/2013/07/18/sharing-text-image-in-twitter-android-example/comment-page-1/#comment-285 this.I did change consumer key and consumer secret .While Running my App one Toast message coming Login Faild .Please tell me any thing required for this

For twitter sharing you can share file directly from the twitter app if it is install and if the app is not install you can use twitter api.
Below is the code for both the things
Boolean isTwitterAppAvailable =false;
try {
Intent shareIntent = new Intent(
android.content.Intent.ACTION_SEND);
shareIntent.setType("image/*");
shareIntent.putExtra(android.content.Intent.EXTRA_TEXT,
"Content to share");
PackageManager pm = getPackageManager();
List<ResolveInfo> activityList = pm.queryIntentActivities(
shareIntent, 0);
for (final ResolveInfo app : activityList) {
if (app.activityInfo.name.contains("twitter")) {
final ActivityInfo activity = app.activityInfo;
final ComponentName name = new ComponentName(
activity.applicationInfo.packageName,
activity.name);
shareIntent.setClassName("com.twitter.android",
"com.twitter.android.PostActivity");
shareIntent.addCategory(Intent.CATEGORY_LAUNCHER);
shareIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK
| Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED);
shareIntent.setComponent(name);
shareIntent.putExtra(Intent.EXTRA_TEXT,
GlobalApplication.twitter_share_msg);
if (GlobalApplication.isImageShareTwitter)
shareIntent.putExtra(Intent.EXTRA_STREAM,
Uri.parse("file:///sdcard/attachment.jpg"));
isTwitterAppAvailable = true;
startActivity(shareIntent);
break;
}
}
if (!isTwitterAppAvailable) {
if (isNetworkAvailable()) {
GlobalApplication.casted_image = casted_image;
// twitter web sharing using twitter4j api...
Twitt_Sharing twitt = new Twitt_Sharing(
ShowCampaignDetail.this, twitter_consumer_key,
twitter_secret_key);
twitt.shareToTwitter(
GlobalApplication.twitter_share_msg,
casted_image);
Twitter_Handler tHandler = new Twitter_Handler(
ShowCampaignDetail.this, twitter_consumer_key,
twitter_secret_key);
User user;
try {
user = tHandler.twitterObj
.showUser(tHandler.twitterObj.getId());
String url = user.getProfileImageURL();
} catch (IllegalStateException e) { // TODO
// Auto-generated
e.printStackTrace();
} catch (TwitterException e) {
e.printStackTrace();
}
} else {
Toast.makeText(ShowCampaignDetail.this,
"No Network Connection Available !!!",
Toast.LENGTH_LONG).show();
}
}
} catch (Exception e) {
e.printStackTrace();
}

Use Following code :
/*
* Share any Image.
*/
private void shareImage() {
Intent share = new Intent(Intent.ACTION_SEND);
// If you want to share a png image only, you can do:
// setType("image/png"); OR for jpeg: setType("image/jpeg");
share.setType("image/*");
// Make sure you put example png image named myImage.png in your
// directory
String imagePath = Environment.getExternalStorageDirectory()
+ "/myImage.png";
File imageFileToShare = new File(imagePath);
Uri uri = Uri.fromFile(imageFileToShare);
share.putExtra(Intent.EXTRA_STREAM, uri);
startActivity(Intent.createChooser(share, "Share image to..."));
}

Open Facebook page from Android app?

from my Android app, I would like to open a link to a Facebook profile in the official Facebook app (if the app is installed, of course). For iPhone, there exists the fb:// URL scheme, but trying the same thing on my Android device throws an ActivityNotFoundException.
Is there a chance to open a Facebook profile in the official Facebook app from code?

This works on the latest version:
Go to https://graph.facebook.com/<user_name_here> (https://graph.facebook.com/fsintents for instance)
Copy your id
Use this method:
public static Intent getOpenFacebookIntent(Context context) {
try {
context.getPackageManager().getPackageInfo("com.facebook.katana", 0);
return new Intent(Intent.ACTION_VIEW, Uri.parse("fb://page/<id_here>"));
} catch (Exception e) {
return new Intent(Intent.ACTION_VIEW, Uri.parse("https://www.facebook.com/<user_name_here>"));
}
}
This will open the Facebook app if the user has it installed. Otherwise, it will open Facebook in the browser.
EDIT: since version 11.0.0.11.23 (3002850) Facebook App do not support this way anymore, there's another way, check the response below from Jared Rummler.

In Facebook version 11.0.0.11.23 (3002850) fb://profile/ and fb://page/ no longer work. I decompiled the Facebook app and found that you can use fb://facewebmodal/f?href=[YOUR_FACEBOOK_PAGE]. Here is the method I have been using in production:
/**
* <p>Intent to open the official Facebook app. If the Facebook app is not installed then the
* default web browser will be used.</p>
*
* <p>Example usage:</p>
*
* {#code newFacebookIntent(ctx.getPackageManager(), "https://www.facebook.com/JRummyApps");}
*
* #param pm
* The {#link PackageManager}. You can find this class through {#link
* Context#getPackageManager()}.
* #param url
* The full URL to the Facebook page or profile.
* #return An intent that will open the Facebook page/profile.
*/
public static Intent newFacebookIntent(PackageManager pm, String url) {
Uri uri = Uri.parse(url);
try {
ApplicationInfo applicationInfo = pm.getApplicationInfo("com.facebook.katana", 0);
if (applicationInfo.enabled) {
// http://stackoverflow.com/a/24547437/1048340
uri = Uri.parse("fb://facewebmodal/f?href=" + url);
}
} catch (PackageManager.NameNotFoundException ignored) {
}
return new Intent(Intent.ACTION_VIEW, uri);
}

Is this not easier?
For example within an onClickListener?
try {
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("fb://profile/426253597411506"));
startActivity(intent);
} catch(Exception e) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("http://www.facebook.com/appetizerandroid")));
}
PS. Get your id (the large number) from http://graph.facebook.com/[userName]

For Facebook page:
try {
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("fb://page/" + pageId));
} catch (Exception e) {
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://www.facebook.com/" + pageId));
}
For Facebook profile:
try {
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("fb://profile/" + profileId));
} catch (Exception e) {
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://www.facebook.com/" + profileId));
}
...because none of the answers points out the difference
Both tested with Facebook v.27.0.0.24.15 and Android 5.0.1 on Nexus 4

Here's the way to do it in 2016. It works great, and is very simple to use.
I discovered this after looking into how emails sent by Facebook opened the Facebook app.
// e.g. if your URL is https://www.facebook.com/EXAMPLE_PAGE, you should
// put EXAMPLE_PAGE at the end of this URL, after the ?
String YourPageURL = "https://www.facebook.com/n/?YOUR_PAGE_NAME";
Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(YourPageURL));
startActivity(browserIntent);

this is the simplest code for doing this
public final void launchFacebook() {
final String urlFb = "fb://page/"+yourpageid;
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse(urlFb));
// If a Facebook app is installed, use it. Otherwise, launch
// a browser
final PackageManager packageManager = getPackageManager();
List<ResolveInfo> list =
packageManager.queryIntentActivities(intent,
PackageManager.MATCH_DEFAULT_ONLY);
if (list.size() == 0) {
final String urlBrowser = "https://www.facebook.com/"+pageid;
intent.setData(Uri.parse(urlBrowser));
}
startActivity(intent);
}

A more reusable approach.
This is a functionality we generally use in most of our apps. Hence here is a reusable piece of code to achieve this.
(Similar to other answers in terms for facts. Posting it here just to simplify and make the implementation reusable)
"fb://page/ does not work with newer versions of the FB app. You should use fb://facewebmodal/f?href= for newer versions. (Like mentioned in another answer here)
This is a full fledged working code currently live in one of my apps:
public static String FACEBOOK_URL = "https://www.facebook.com/YourPageName";
public static String FACEBOOK_PAGE_ID = "YourPageName";
//method to get the right URL to use in the intent
public String getFacebookPageURL(Context context) {
PackageManager packageManager = context.getPackageManager();
try {
int versionCode = packageManager.getPackageInfo("com.facebook.katana", 0).versionCode;
if (versionCode >= 3002850) { //newer versions of fb app
return "fb://facewebmodal/f?href=" + FACEBOOK_URL;
} else { //older versions of fb app
return "fb://page/" + FACEBOOK_PAGE_ID;
}
} catch (PackageManager.NameNotFoundException e) {
return FACEBOOK_URL; //normal web url
}
}
This method will return the correct url for app if installed or web url if app is not installed.
Then start an intent as follows:
Intent facebookIntent = new Intent(Intent.ACTION_VIEW);
String facebookUrl = getFacebookPageURL(this);
facebookIntent.setData(Uri.parse(facebookUrl));
startActivity(facebookIntent);
That's all you need.

To do this we need the "Facebook page id", you can get it :
from the page go to "About".
go to "More Info" section.
To opening facebook app on specified profile page,
you can do this:
String facebookId = "fb://page/<Facebook Page ID>";
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(facebookId)));
Or you can validate when the facebook app is not installed, then open the facebook web page.
String facebookId = "fb://page/<Facebook Page ID>";
String urlPage = "http://www.facebook.com/mypage";
try {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(facebookId )));
} catch (Exception e) {
Log.e(TAG, "Application not intalled.");
//Open url web page.
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(urlPage)));
}

This has been reverse-engineered by Pierre87 on the FrAndroid forum, but I can't find anywhere official that describes it, so it's has to be treated as undocumented and liable to stop working at any moment:
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setClassName("com.facebook.katana", "com.facebook.katana.ProfileTabHostActivity");
intent.putExtra("extra_user_id", "123456789l");
this.startActivity(intent);

try this code:
String facebookUrl = "https://www.facebook.com/<id_here>";
try {
int versionCode = getPackageManager().getPackageInfo("com.facebook.katana", 0).versionCode;
if (versionCode >= 3002850) {
Uri uri = Uri.parse("fb://facewebmodal/f?href=" + facebookUrl);
startActivity(new Intent(Intent.ACTION_VIEW, uri));
} else {
Uri uri = Uri.parse("fb://page/<id_here>");
startActivity(new Intent(Intent.ACTION_VIEW, uri));
}
} catch (PackageManager.NameNotFoundException e) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(facebookUrl)));
}

As of March 2020 this works perfectly.
private void openFacebookPage(String pageId) {
String pageUrl = "https://www.facebook.com/" + pageId;
try {
ApplicationInfo applicationInfo = getPackageManager().getApplicationInfo("com.facebook.katana", 0);
if (applicationInfo.enabled) {
int versionCode = getPackageManager().getPackageInfo("com.facebook.katana", 0).versionCode;
String url;
if (versionCode >= 3002850) {
url = "fb://facewebmodal/f?href=" + pageUrl;
} else {
url = "fb://page/" + pageId;
}
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(url)));
} else {
throw new Exception("Facebook is disabled");
}
} catch (Exception e) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(pageUrl)));
}
}

After much testing I have found one of the most effective solutions:
private void openFacebookApp() {
String facebookUrl = "www.facebook.com/XXXXXXXXXX";
String facebookID = "XXXXXXXXX";
try {
int versionCode = getActivity().getApplicationContext().getPackageManager().getPackageInfo("com.facebook.katana", 0).versionCode;
if(!facebookID.isEmpty()) {
// open the Facebook app using facebookID (fb://profile/facebookID or fb://page/facebookID)
Uri uri = Uri.parse("fb://page/" + facebookID);
startActivity(new Intent(Intent.ACTION_VIEW, uri));
} else if (versionCode >= 3002850 && !facebookUrl.isEmpty()) {
// open Facebook app using facebook url
Uri uri = Uri.parse("fb://facewebmodal/f?href=" + facebookUrl);
startActivity(new Intent(Intent.ACTION_VIEW, uri));
} else {
// Facebook is not installed. Open the browser
Uri uri = Uri.parse(facebookUrl);
startActivity(new Intent(Intent.ACTION_VIEW, uri));
}
} catch (PackageManager.NameNotFoundException e) {
// Facebook is not installed. Open the browser
Uri uri = Uri.parse(facebookUrl);
startActivity(new Intent(Intent.ACTION_VIEW, uri));
}
}

My answer builds on top of the widely-accepted answer from joaomgcd.
If the user has Facebook installed but disabled (for example by using App Quarantine), this method will not work. The intent for the Twitter app will be selected but it will not be able to process it as it is disabled.
Instead of:
context.getPackageManager().getPackageInfo("com.facebook.katana", 0);
return new Intent(Intent.ACTION_VIEW, Uri.parse("fb://profile/620681997952698"));
You can use the following to decide what to do:
PackageInfo info = context.getPackageManager().getPackageInfo("com.facebook.katana", 0);
if(info.applicationInfo.enabled)
return new Intent(Intent.ACTION_VIEW, Uri.parse("fb://profile/620681997952698"));
else
return new Intent(Intent.ACTION_VIEW, Uri.parse("https://www.facebook.com/620681997952698"));

Best answer I have found, it's working great.
Just go to your page on Facebook in the browser, right click, and click on "View source code", then find the page_id attribute: you have to use page_id here in this line after the last back-slash:
fb://page/pageID
For example:
Intent facebookAppIntent;
try {
facebookAppIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("fb://page/1883727135173361"));
startActivity(facebookAppIntent);
} catch (ActivityNotFoundException e) {
facebookAppIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("http://facebook.com/CryOut-RadioTv-1883727135173361"));
startActivity(facebookAppIntent);
}

You can check it for all Facebook Apps that any of Facebook apps are installed or not .
For supporting OS level 11 we need to add this in AndrodiManifest.xml to avoid package name not found exception -
<manifest ...
<queries>
<package android:name="com.facebook.katana" />
<package android:name="com.facebook.lite" />
<package android:name="com.facebook.android" />
<package android:name="com.example.facebook" />
</queries>
<application .....
Then add this method to you code -
public static String isFacebookAppInstalled(Context context){
if(context!=null) {
PackageManager pm=context.getPackageManager();
ApplicationInfo applicationInfo;
//First check that if the main app of facebook is installed or not
try {
applicationInfo = pm.getApplicationInfo("com.facebook.katana", 0);
return applicationInfo.enabled?"com.facebook.katana":"";
} catch (Exception ignored) {
}
//Then check that if the facebook lite is installed or not
try {
applicationInfo = pm.getApplicationInfo("com.facebook.lite", 0);
return applicationInfo.enabled?"com.facebook.lite":"";
} catch (Exception ignored) {
}
//Then check the other facebook app using different package name is installed or not
try {
applicationInfo = pm.getApplicationInfo("com.facebook.android", 0);
return applicationInfo.enabled?"com.facebook.android":"";
} catch (Exception ignored) {
}
try {
applicationInfo = pm.getApplicationInfo("com.example.facebook", 0);
return applicationInfo.enabled?"com.example.facebook":"";
} catch (Exception ignored) {
}
}
return "";
}
And then launch the app -
if (!TextUtils.isEmpty(isFacebookAppInstalled(context))) {
/* Facebook App is installed,So launch it.
It will return you installed facebook app's package
name which will be useful to launch the app */
Uri uri = Uri.parse("fb://facewebmodal/f?href=" + yourURL);
Intent intent = context.getPackageManager().getLaunchIntentForPackage(isFacebookAppInstalled(context);
if (intent != null) {
intent.setAction(Intent.ACTION_VIEW);
intent.setData(uri);
intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(intent);
}
else {
Intent intentForOtherApp = new Intent(Intent.ACTION_VIEW, uri);
context.startActivity(intentForOtherApp);
}
}

Intent intent = null;
try {
getPackageManager().getPackageInfo("com.facebook.katana", 0);
String url = "https://www.facebook.com/"+idFacebook;
intent = new Intent(Intent.ACTION_VIEW, Uri.parse("fb://facewebmodal/f?href="+url));
} catch (Exception e) {
// no Facebook app, revert to browser
String url = "https://facebook.com/"+idFacebook;
intent = new Intent(Intent.ACTION_VIEW);
intent .setData(Uri.parse(url));
}
this.startActivity(intent);

To launch facebook page from your app, let urlString = "fb://page/your_fb_page_id"
To launch facebook messenger let urlString = "fb-messenger://user/your_fb_page_id"
FB page id is usually numeric. To get it, goto Find My FB ID input your profile url, something like www.facebook.com/edgedevstudio then click "Find Numberic ID".
Voila, you now have your fb numeric id. replace "your_fb_page_id" with the generated Numeric ID
val intent = Intent(Intent.ACTION_VIEW, Uri.parse(urlString))
if (intent.resolveActivity(packageManager) != null) //check if app is available to handle the implicit intent
startActivity(intent)

As of July 2018 this works perfectly with or without the Facebook app on all the devices.
private void goToFacebook() {
try {
String facebookUrl = getFacebookPageURL();
Intent facebookIntent = new Intent(Intent.ACTION_VIEW);
facebookIntent.setData(Uri.parse(facebookUrl));
startActivity(facebookIntent);
} catch (Exception e) {
e.printStackTrace();
}
}
private String getFacebookPageURL() {
String FACEBOOK_URL = "https://www.facebook.com/Yourpage-1548219792xxxxxx/";
String facebookurl = null;
try {
PackageManager packageManager = getPackageManager();
if (packageManager != null) {
Intent activated = packageManager.getLaunchIntentForPackage("com.facebook.katana");
if (activated != null) {
int versionCode = packageManager.getPackageInfo("com.facebook.katana", 0).versionCode;
if (versionCode >= 3002850) {
facebookurl = "fb://page/1548219792xxxxxx";
}
} else {
facebookurl = FACEBOOK_URL;
}
} else {
facebookurl = FACEBOOK_URL;
}
} catch (Exception e) {
facebookurl = FACEBOOK_URL;
}
return facebookurl;
}

Check out my code for opening Facebook specific Page:
//ID initialization
ImageView facebook = findViewById(R.id.facebookID);
facebook.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
String facebookId = "fb://page/327031464582675";
String urlPage = "http://www.facebook.com/MDSaziburRahmanBD";
try {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(facebookId)));
}catch (Exception e){
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(urlPage)));
}
}
});

I have created a method to open facebook page into facebook app, if app is not existing then opening in chrome
String socailLink="https://www.facebook.com/kfc";
Intent intent = new Intent(Intent.ACTION_VIEW);
String facebookUrl = Utils.getFacebookUrl(getActivity(), socailLink);
if (facebookUrl == null || facebookUrl.length() == 0) {
Log.d("facebook Url", " is coming as " + facebookUrl);
return;
}
intent.setData(Uri.parse(facebookUrl));
startActivity(intent);
Utils.class add these method
public static String getFacebookUrl(FragmentActivity activity, String facebook_url) {
if (activity == null || activity.isFinishing()) return null;
PackageManager packageManager = activity.getPackageManager();
try {
int versionCode = packageManager.getPackageInfo("com.facebook.katana", 0).versionCode;
if (versionCode >= 3002850) { //newer versions of fb app
Log.d("facebook api", "new");
return "fb://facewebmodal/f?href=" + facebook_url;
} else { //older versions of fb app
Log.d("facebook api", "old");
return "fb://page/" + splitUrl(activity, facebook_url);
}
} catch (PackageManager.NameNotFoundException e) {
Log.d("facebook api", "exception");
return facebook_url; //normal web url
}
}
and this
/***
* this method used to get the facebook profile name only , this method split domain into two part index 0 contains https://www.facebook.com and index 1 contains after / part
* #param context contain context
* #param url contains facebook url like https://www.facebook.com/kfc
* #return if it successfully split then return "kfc"
*
* if exception in splitting then return "https://www.facebook.com/kfc"
*
*/
public static String splitUrl(Context context, String url) {
if (context == null) return null;
Log.d("Split string: ", url + " ");
try {
String splittedUrl[] = url.split(".com/");
Log.d("Split string: ", splittedUrl[1] + " ");
return splittedUrl.length == 2 ? splittedUrl[1] : url;
} catch (Exception ex) {
return url;
}
}

open fb on button click event without using facebook sdk
Intent FBIntent = new Intent(Intent.ACTION_SEND);
FBIntent.setType("text/plain");
FBIntent.setPackage("com.facebook.katana");
FBIntent.putExtra(Intent.EXTRA_TEXT, "The text you wanted to share");
try {
context.startActivity(FBIntent);
} catch (android.content.ActivityNotFoundException ex) {
Toast.makeText(context, "Facebook have not been installed.", Toast.LENGTH_SHORT).show( );
}

1-to get your id go to your image profile and click right click and take copy link adress.
try {
Intent intent = new Intent(Intent.ACTION_VIEW,Uri.parse("fb://profile/id"));
startActivity(intent);
} catch(Exception e) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("facebook url")));
}
}
});

Declare constants
private String FACEBOOK_URL="https://www.facebook.com/approids";
private String FACEBOOK_PAGE_ID="approids";
Declare Method
public String getFacebookPageURL(Context context) {
PackageManager packageManager = context.getPackageManager();
try {
int versionCode = packageManager.getPackageInfo("com.facebook.katana", 0).versionCode;
boolean activated = packageManager.getApplicationInfo("com.facebook.katana", 0).enabled;
if(activated){
if ((versionCode >= 3002850)) {
Log.d("main","fb first url");
return "fb://facewebmodal/f?href=" + FACEBOOK_URL;
} else {
return "fb://page/" + FACEBOOK_PAGE_ID;
}
}else{
return FACEBOOK_URL;
}
} catch (PackageManager.NameNotFoundException e) {
return FACEBOOK_URL;
}
}
Call Function
Intent facebookIntent = new Intent(Intent.ACTION_VIEW);
String facebookUrl = getFacebookPageURL(MainActivity.this);
facebookIntent.setData(Uri.parse(facebookUrl));
startActivity(facebookIntent);

To open the Facebook page in Facebook app from your Webview add this code in your shouldOverrideUrlLoading method
if (url.startsWith("https://www.facebook.com || Your Facebook page address")) {
try {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("fb://facewebmodal/f?href=" + url)));
} catch (Exception e2) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(url)));
}
return true;
}

Answering this in October 2018. The working code is the one using the pageID. I just tested it and it is functional.
public static void openUrl(Context ctx, String url){
Uri uri = Uri.parse(url);
if (url.contains(("facebook"))){
try {
ApplicationInfo applicationInfo = ctx.getPackageManager().getApplicationInfo("com.facebook.katana", 0);
if (applicationInfo.enabled) {
uri = Uri.parse("fb://page/<page_id>");
openURI(ctx, uri);
return;
}
} catch (PackageManager.NameNotFoundException ignored) {
openURI(ctx, uri);
return;
}
}

I implemented in this form in webview using fragment- inside oncreate:
webView.setWebViewClient(new WebViewClient()
{
public boolean shouldOverrideUrlLoading(WebView viewx, String urlx)
{
if(Uri.parse(urlx).getHost().endsWith("facebook.com")) {
{
goToFacebook();
}
return false;
}
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(urlx));
viewx.getContext().startActivity(intent);
return true;
}
});
and outside onCreateView :
private void goToFacebook() {
try {
String facebookUrl = getFacebookPageURL();
Intent facebookIntent = new Intent(Intent.ACTION_VIEW);
facebookIntent.setData(Uri.parse(facebookUrl));
startActivity(facebookIntent);
} catch (Exception e) {
e.printStackTrace();
}
}
//facebook url load
private String getFacebookPageURL() {
String FACEBOOK_URL = "https://www.facebook.com/pg/XXpagenameXX/";
String facebookurl = null;
try {
PackageManager packageManager = getActivity().getPackageManager();
if (packageManager != null) {
Intent activated = packageManager.getLaunchIntentForPackage("com.facebook.katana");
if (activated != null) {
int versionCode = packageManager.getPackageInfo("com.facebook.katana", 0).versionCode;
if (versionCode >= 3002850) {
facebookurl = "fb://page/XXXXXXpage_id";
}
} else {
facebookurl = FACEBOOK_URL;
}
} else {
facebookurl = FACEBOOK_URL;
}
} catch (Exception e) {
facebookurl = FACEBOOK_URL;
}
return facebookurl;
}

fun getOpenFacebookIntent(context: Context, url: String) {
return try {
context.packageManager.getPackageInfo("com.facebook.katana", 0)
context.startActivity(Intent(Intent.ACTION_VIEW, Uri.parse("fb://profile/$url/")))
} catch (e: Exception) {
context.startActivity(Intent(Intent.ACTION_VIEW, Uri.parse(url)))
}
}

Answer worked for me but one missing thing was to add query in manifest, here is my solution:
private void openFacebookApp() {
String facebookUrl = "www.facebook.com/XXXXXXXXXX";
String facebookID = "XXXXXXXXX";
try {
int versionCode = getActivity().getApplicationContext().getPackageManager().getPackageInfo("com.facebook.katana", 0).versionCode;
if(!facebookID.isEmpty()) {
// open the Facebook app using facebookID (fb://profile/facebookID or fb://page/facebookID)
Uri uri = Uri.parse("fb://page/" + facebookID);
startActivity(new Intent(Intent.ACTION_VIEW, uri));
} else if (versionCode >= 3002850 && !facebookUrl.isEmpty()) {
// open Facebook app using facebook url
Uri uri = Uri.parse("fb://facewebmodal/f?href=" + facebookUrl);
startActivity(new Intent(Intent.ACTION_VIEW, uri));
} else {
// Facebook is not installed. Open the browser
Uri uri = Uri.parse(facebookUrl);
startActivity(new Intent(Intent.ACTION_VIEW, uri));
}
} catch (PackageManager.NameNotFoundException e) {
// Facebook is not installed. Open the browser
Uri uri = Uri.parse(facebookUrl);
startActivity(new Intent(Intent.ACTION_VIEW, uri));
}
}
and add that in Manifest outside the application tag
<queries>
<package android:name="com.google.android.gm" />
<package android:name="com.facebook.katana" />
<intent>
<action android:name="android.intent.action.VIEW" />
<data android:scheme="https" />
</intent>
<intent>
<action android:name="android.intent.action.DIAL" />
<data android:scheme="tel" />
</intent>
<intent>
<action android:name="android.intent.action.SEND" />
<data android:mimeType="*/*" />
</intent>
</queries>

I have been trying all of these methods with no luck because the ID... to find the one that works for my profile and for any profile you must go to the profile you want to open without been logged in (sorry for my english), inspect the page (in chrome Ctrl+Shift+I or just F12), and look for the line that holds the attribute al:android:url, the profile id should be there...
enter image description here
... And then:
public static void OpenFacebookProfile(String profileID, String username)
{
boolean isFacebookInstalled =
null != PA.getPackageManager().getLaunchIntentForPackage("com.facebook.katana");
Intent intent = isFacebookInstalled ?
new Intent(Intent.ACTION_VIEW, Uri.parse("fb://profile/" + profileID)) :
new Intent(Intent.ACTION_VIEW, Uri.parse("https://www.facebook.com/" + username));
PA.startActivity(intent);
}

try {
String[] parts = url.split("//www.facebook.com/profile.php?id=");
getPackageManager().getPackageInfo("com.facebook.katana", 0);
startActivity(new Intent (Intent.ACTION_VIEW, Uri.parse(String.format("fb://page/%s", parts[1].trim()))));
} catch (Exception e) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(url)));
}

Develop Reference

The Android operating system is a mobile operating system that was developed by Google (GOOGL?) to be primarily used for touchscreen devices, cell phones, and tablets.

Open Twitter app from other app and load some page - android

Is there a way to open the Twitter app from my own application? For example, I have my own Android app and I want to open Twitter app using Intent. How can I do that? Answers with example would be much appreciated.

try { startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("twitter://user?screen_name=" + twitter_user_name))); }catch (Exception e) { startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://twitter.com/#!/" + twitter_user_name))); } This should do the necessary work for you.

private void showTwitter(){ Intent intent = new Intent(Intent.ACTION_VIEW); intent.setClassName("com.twitter.android", "com.twitter.android.ProfileActivity"); this.startActivity(intent); }

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