I'm trying to set the font to a custom font. the font is in a subfolder of the assets folder called "fonts" . This is code in my onCreate() function. Eclipse suddendly brings up the debugger saying "source not found"
Typeface centuryGothic = Typeface.createFromAsset(this.getAssets(), "fonts/Century_Gothic_Bold.ttf");
TextView tv = (TextView) findViewById(R.id.TitleAct_title);
tv.setTypeface(centuryGothic);
setContentView(tv);
This is the xml in My main at the moment
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
>
<LinearLayout
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:layout_weight="1">
<TextView
android:text="#string/TitleAct_title"
android:id="#+id/TitleAct_title"
android:textColor="#fff"
android:gravity="center_horizontal"
android:background="#347"
android:textSize="15pt"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:layout_weight="1"/>
</LinearLayout>
</LinearLayout>
I can't see anything wrong with this. Why is it bringing up the debugger and error "source not found"?
What you saw was the eclipse debugger looking for the source of the exception. next time, press continue and look ad the log of the exception in the Logcat window.
You should call setContentView(R.layout.main); before TextView tv = (TextView) findViewById(R.id.TitleAct_title);, and probably drop the call setContentView(tv);.
Related
I'm getting a resource not found error when I try to do this:
TabWidget tabz = FindViewById<TabWidget>(Resource.Id.tabs);
compiler doesn't see the TabWidget even when it's clearly labeled by id in my Main.axml file
Error CS0117 'Resource.Id' does not contain a definition for 'tabs'
Here's my full code:
<LinearLayout
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:padding="5dp">
<TabWidget
android:id="#android:id/tabs"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:visibility="visible" />
<FrameLayout
android:id="#android:id/tabcontent"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:padding="5dp" />
</LinearLayout>
EDIT, sorry, this is the full code... I don't know why I didn't copy this last time. The above example is missing TabHost
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="match_parent"
android:layout_height="match_parent">
<TabHost
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:minWidth="25px"
android:minHeight="25px"
android:id="#+id/tabHost1">
<LinearLayout
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical"
android:id="#+id/linearLayout1">
<TabWidget
android:id="#android:id/tabs"
android:layout_width="match_parent"
android:layout_height="wrap_content" />
<FrameLayout
android:id="#android:id/tabcontent"
android:layout_width="match_parent"
android:layout_height="match_parent" />
</LinearLayout>
</TabHost>
</LinearLayout>
How can I force the compiler to recognize my tabs id? I've tried rebuilding the resource.designer.cs .. putting the declaration of TabWidget inside all of the activities... nothing works. My C# can't see the TabWidget
full project can be found here:
https://github.com/hexag0d/BitChute_Mobile_Android_a2
I also tried this and it didn't work
Xamarin Android Resource file not found
thanks, in advance
The issue is not with the visual studio compiler but the way that you have declared the id for your View,
If you check this blog by James White you will see how Id and the Layout Attributes actually work in Android,
The Right way of declaring the Id would be something like this android:id="#+id/tabs" whereas what you are doing is this android:id="#android:id/tabs"
Hence, When you do add them and try to find it using Resource.Id.tabs, There is nothing available in Id by the name tabs as it was never added by the Xamarin ResourceDesginer.cs file.
So the end result should actually be something like this :
<TabHost
android:id="#+id/tabhost"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:layout_alignParentTop="true"
android:layout_centerHorizontal="true">
<LinearLayout
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical">
<TabWidget
android:id="#android:id/tabs"
android:layout_width="match_parent"
android:layout_height="wrap_content"></TabWidget>
<FrameLayout
android:id="#android:id/tabcontent"
android:layout_width="match_parent"
android:layout_height="match_parent">
<LinearLayout
android:id="#+id/tab1"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="#ffc916"
android:orientation="vertical">
</LinearLayout>
</FrameLayout>
</LinearLayout>
</TabHost>
Also, note that I have replaced all the fill_parent's with match_parent's the reason behind it being that fill parent is now obsolete or you can say replaced (After API-8) and hence must not be used, which can be found here.
Update:
I have updated the way tab host works, Also updated the XML above and I am adding a reference link where you can find the right way of using both the TabHost and TabWidget, Also a good SO example for the same.
About the questions in your comment:
1,
that is very good advice, but one note is that when
SetContentView(localLayout); is used inside an activity that already
has a content view, it crashes the app.
The app crashed because localLayout in SetContentView(localLayout) is a LinearLayout but a TabWidget needs a TabHost. So you can directly use:
SetContentView(Resource.Layout.Main);
where Main.xaml is like:
<?xml version="1.0" encoding="utf-8"?>
<TabHost xmlns:android="http://schemas.android.com/apk/res/android"
android:id="#android:id/tabhost"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:theme="#style/MyTheme">
<LinearLayout
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:padding="5dp">
<TabWidget
android:id="#android:id/tabs"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:layout_weight="0.0"
android:visibility="visible" />
<FrameLayout
android:id="#android:id/tabcontent"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:padding="5dp" />
</LinearLayout>
</TabHost>
2,
LinearLayout localLayout =
FindViewById(Resource.Layout.Main); View
whichYouWantToUse_findViewById =
LayoutInflater.Inflate(Resource.Layout.Main, null); TextView tv =
FindViewById(Resource.Id.textView169); TabHost _tabHost =
(TabHost)whichYouWantToUse_findViewById.FindViewById(Resource.Id.tabhost);
' still can't see the tabhost ... I'm losing my mind here
The reason why you cannot see the tabhost is, firt, TabHost is FrameLayout, not LinearLayout, second, Resource.Id.tabhost should be Android.Resource.Id.TabHost. So I edited your code to :
FrameLayout localLayout = FindViewById<FrameLayout>(Resource.Layout.Main);
whichYouWantToUse_findViewById = LayoutInflater.Inflate(Resource.Layout.Main, null);
//TextView tv = FindViewById<TextView>(Resource.Id.textView1);
TabHost _tabHost = (TabHost)whichYouWantToUse_findViewById.FindViewById(Android.Resource.Id.TabHost);
3,
So the interesting thing is if I change tabhost to tahost ala
android:id="#+id/tahost" the resource appears in the designer but when
I change to android:id="#+id/tabhost" the resource disappears.. very
strange..
The id of TabHost need always be #android:id/tabhost", it cannot be modified to tahost or any others.
So the code in the onCreat Method is like this:
base.OnCreate(bundle);
SetContentView(Resource.Layout.Main);
View whichYouWantToUse_findViewById = LayoutInflater.Inflate(Resource.Layout.layout1, null);
TextView textInAnotherLayout = (TextView)whichYouWantToUse_findViewById.FindViewById(Resource.Id.textView1);
textInAnotherLayout.Text = "Yeah";
TabHost tabHost = FindViewById<TabHost>(Android.Resource.Id.TabHost);
TabWidget tabWidget = tabHost.TabWidget;
var tabContent = tabHost.TabContentView;
FrameLayout localLayout = FindViewById<FrameLayout>(Resource.Layout.Main);
whichYouWantToUse_findViewById = LayoutInflater.Inflate(Resource.Layout.Main, null);
TabHost _tabHost = (TabHost)whichYouWantToUse_findViewById.FindViewById(Android.Resource.Id.TabHost);
The following is the old answer.
Answer modified: The way to get TabHost and TabWidget in Activity:
TabHost tabHost = this.TabHost;
TabWidget tabWidget = tabHost.TabWidget;
The way to use one resource from one XAML file in the activity for
another:
LinearLayout localLayout = FindViewById<LinearLayout>(Resource.Layout.Main);
SetContentView(localLayout);
View whichYouWantToUse_findViewById = LayoutInflater.Inflate(Resource.Layout.layout1, null);
Button button1 = (Button)whichYouWantToUse_findViewById.FindViewById(Resource.Id.button1);
I download your project and fixed this problem by modifying the property of >android:id
We don't have a compilation problem, we just want to expand our knowledge. Reading through Google Code Documentation, we have read that +id doesn't have to be unique layout-wide.
Below a compiling example:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:id="#+id/activity_main"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:paddingBottom="#dimen/activity_vertical_margin"
android:paddingLeft="#dimen/activity_horizontal_margin"
android:paddingRight="#dimen/activity_horizontal_margin"
android:paddingTop="#dimen/activity_vertical_margin"
android:orientation="vertical"
tools:context="com.bq.testviewids.MainActivity">
<TextView
android:id="#+id/text"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Hello World!" />
<TextView
android:id="#+id/text"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Hola Mundo" />
</LinearLayout>
private void initViews() {
txtText = (TextView) findViewById(R.id.text);
txtText.setId(View.generateViewId());
txtText = (TextView) findViewById(R.id.text);
}
private void changeTextView() {
txtText.setText("");
}
If in initViews() we don't have the last two lines:
txtText.setId(View.generateViewId());
txtText = (TextView) findViewById(R.id.text);
When we do a change to txtText (in changeTextView()), the first TextView gets modified.
If we do have the last two lines the second TextView gets modified.
We didn't know that this was possible, and we thought that if you had two items layout-wide with the same +id, it wouldn't compile. Now, we understand that the identifier doesn't have to be unique in this view's hierarchy, but, we don't understand the usefulness of this behavior.
Does someone know a use case in which a non-unique identifier is useful?
This doubt comes to us when we see in Android for MSM (CAF) in Settings project this code with a duplicate id (#+id/fields):
<LinearLayout android:id="#+id/fields"
android:layout_width="match_parent"
android:layout_height="wrap_content"
style="#style/wifi_section"
android:visibility="gone">
<LinearLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
style="#style/wifi_item">
...
</LinearLayout>
<LinearLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
style="#style/wifi_item">
...
</LinearLayout>
<LinearLayout android:id="#+id/fields"
android:layout_width="match_parent"
android:layout_height="wrap_content"
style="#style/wifi_section" >
...
</LinearLayout>
The use case that comes to mind are the duplicate id's that you would have if you have a layout that is included two or more times in another layout. It would save you the headache of trying to get unique id's in each duplicated layout.
It would also allow you to work within each included layout using the same code without having to track different id's depending upon which sub-layout you are working on.
i would like to know why eclipse is showing warning "[I18N] Hardcoded string "TextView", should use #string resource" in the xml code below .Actually i am trying to get the text written by user in an edit Text in an activity to this current activity.
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
<TextView
android:id="#+id/textView1"
android:layout_width="match_parent"
android:layout_height="0dip"
android:layout_weight="0.01"
android:text="TextView" />
</LinearLayout>
The reason that you are receiving a warning, is due to the fact that you are trying to hardcode a string which is not good convention in Android programming due to possible redundancy:
<TextView
...
android:text="TextView" />
You should rather create a reference to a string in the .../res/values/strings.xml file like so:
<TextView
...
android:text="#string/TextView" />
.. and define it in your strings.xml file:
<string name="TextView">TextView</string>
Hope this helps.
As it says, you are using a "hard-coded" string which is less efficient than using the String resource. Simply remove
android:text="TextView"
if you don't want the warning to show. If you want it there then disregard the warning or add it to the String resource file. The Text property isn't needed. If you are expecting user input then you should change it to an EditText anyway unless you have a reason for using TextView
<EditText
android:id="#+id/textView1"
android:layout_width="match_parent"
android:layout_height="0dip"
android:layout_weight="0.01" />
Then if you want it to display something such as "Enter input here" in the View then you can add android:hint"Text to display". But this will give you the same warning if you don't add it to the strings.xml and use android:hint="#string/nameInStringsFile".
But these warnings are just that. Suggesting possibly more efficient methods or ways of implementing whatever you are doing.
Change the XML to the following to remove the warning
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
<TextView
android:id="#+id/textView1"
android:layout_width="match_parent"
android:layout_height="0dip"
android:layout_weight="0.01" />
</LinearLayout>
The reason you are seeing the warning is because you had set the text to "TextView" inside the XML layout file. It is Android best practice to put all Strings inside the strings.xml file in your res/values folder which creates string resources. One you have a string in a resource file you can reference it from your layout file using the syntax "#string/string_name".
while i have programming an android program about voice recognizing i have a little problem.what is the r.id cannot be resolved i have try to change my xml files which includes res folder.it doesnt works.what can i do ?
my main.xml
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical" >
<TextView
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:text="#string/hello" />
</LinearLayout>
Try cleaning your project (in Eclipse: Project->Clean...).
If that does not fix it delete your R.java file located under the gen folder. The R.java file should be regenerated for you.
I have done these thing to fix the problem you are describing, but your mileage may vary.
If somewhere in your class file you have a line like this:
TextView tv = (TextView) findViewById(R.id.tv1);
then R.id.tv1 must point to a TextView in your xml, which must first be given the id. So for example if you wanted to change the text in your TextView above you would have something like this to set the id in the xml:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical" >
<TextView
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:text="#string/hello"
//Set your id here:
android:id="#+id/TEXTVIEW1"
/>
and then to change the text, in your class you'd have this:
TextView tv = (TextView) findViewById(R.id.TEXTVIEW1);
tv.setText("How are you");
Insert this to your xml file's view tags.
android:id="#+id/YOUR_VIEW_ID"
I am having a very weird glitch that I cannot get my head around. Any help will be appreciated as this works on a phone running Android 2.3, tablet running 3.1 but not on a phone running Android 2.1.
I am trying to get the LinearLayout defined in the following XML with the ID of "overview_linear_layout".
overview_view.xml
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent">
<include layout="#layout/listing_view" android:layout_width="fill_parent" android:id="#+id/header_view" android:layout_height="wrap_content"></include>
<ScrollView android:id="#+id/scrollView1" android:layout_weight="1" android:layout_width="fill_parent" android:layout_height="wrap_content">
<LinearLayout android:layout_width="fill_parent" android:orientation="vertical" android:layout_height="fill_parent" android:id="#+id/overview_linear_layout">
<TextView android:scrollbars="vertical" android:longClickable="false" android:layout_weight="1" android:clickable="false" android:layout_width="fill_parent" android:layout_height="wrap_content" android:id="#+id/main_description"></TextView>
</LinearLayout>
</ScrollView>
<include layout="#layout/listing_view" android:layout_width="fill_parent" android:id="#+id/footer_view" android:layout_height="wrap_content" android:layout_weight="0.0"></include>
</LinearLayout>
The code I am using to get the view is as follows:
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.overview_view);
LinearLayout linearLayout = (LinearLayout)findViewById(R.id.overview_linear_layout);
if(linearLayout!=null) {
System.out.println("Found linear layout");
}
else {
System.out.println("Did not find linear layout");
}
}
I have tried Project->Clean in Eclipse but that does not help either.
if eclipse don't show overview_linear_layout when you type click on the red cross and click create constant overview_linear_layout in R .
change this
LinearLayout linearLayout = (LinearLayout)findViewById(R.id.overview_linear_layout);
to
LinearLayout linearLayout = (LinearLayout)findViewById(R.layout.overview_linear_layout);`