Custom Raw File Path - Android - android

In my raw folder I have a number of folders, how can I target these, Ive tried a path var as below but no luck:
String path = "R.raw.myFolder";
mSoundManager.addSound(1, path.myFile);

I do not understand why you have folders inside your raw folder. That folder is there to store the media you need. Do not over complicate the project by having to reference a folder name on top of the file name. the code below is for accessing files straight out of the raw folder.
Try giving this a go:
mSoundManager.addSound("android.resource://"+getPackageName()+ "/" + R.raw.filename);
I am not sure if this is what you are looking for but this is what works for me for all my raw files.
I left out a piece. Code is now correct.

Related

How to get path to file in android apk

My app depends on 3 different files. I already put the two larger ones as expansion files which seems to work fine. Now I don't know where to put the third one (small file). I tried the raw folder but actually I don't know what the path of the file is once it is in those folders.
I tried this here for the raw folder
myClassifier.loadModel( pathToExpansionFiles + "/File1",
pathToExpansionFiles + "/File2",
R.raw.File3);
However the return value of R.raw.File3 is an integer, but the function myClassifier expects a string that is the path to File3. Has anyone an idea how to do that?
I tried the raw folder but actually I don't know what the path of the file is once it is in those folders.
There is no path to it. That is a file on your development machine. It is not a file on the device. It is merely an entry inside your APK file.
but the function myClassifier expects a string that is the path to File3
Either switch to some library that works with an InputStream (from getResources().openRawResource()) or make a copy of the data to a local file using that InputStream yourself.

what is OpenNLP's model file path?

I try to use OpenNLP in an Android application with eclipse, and I imported the 4 JARs into the libs folder.
It's probably a stupid question.. but where should I put the model files "en-pos-maxent.bin"? I can't find anything regarding the path anywhere
I try to run the code contains this line:
POSModel model = new POSModelLoader()
.load(new File("en-pos-maxent.bin"));
I tried putting the en-pos-maxent.bin inside a new folder within the project("tagger/en-pos-maxent.bin"), inside the libs folder, or simply give the path where the en-pos-maxent.bin is put when downloaded("Users/ariel/Downloads/en-pos-maxent.bin"), it always give me the error: POS Tagger model file does not exist path: (the path I typed in)
Could anybody help please?
When you use new File("filename") the file is expected to be in the current working directory, I don't think that's different on Android. You can use System.getProperty("user.dir") to get the current working directory. It's by default the directory you start the program from. You could also specify a full path like new File("/full/path/filename") instead.
In android the right way to add file to the application (inside APK) is to put into the assets folder. Then you can't get File object from assets folder but, you can create that File using a buffer or in you case just get it into the InputStream. For example if you will create models folder into the assets folder (assets/models), your code will look like this:
AssetManager am = getAssets();
InputStream inputStream = am.open("models/en-pos-maxent.bin");
POSModel posModel = new POSModel(inputStream);

How to list folders in raw resources

I have a huge directory of infrared remote control codes, and I'd like to parse through each of them when needed. However, I am having issues trying to access the folders I have in my application's res/raw/ folder. I'd like to be able to get the folder names, because that would essentially sort for me and list out all the brands that I'd like to list in a Spinner, and then pull files from inside that folder later.
What's wrong with me doing something like this?
String path = "android.resource://" + getPackageName() + "/res/raw/";
File f = new File(path);
File[] files = f.listFiles();
for(File inFile : files){
if(inFile.isDirectory()){
Log.d(TAG, inFile.getName());
}
}
Just found out that I can't create subdirectories in my res/raw folder, and I'd have to go about this through the assets folder. Would this be as simple as this structure?
assets
- remotes
- Samsung
- remote1.txt
- remote2.txt
- Sony
- remote1.txt
- etc
However, I am having issues trying to access the folders I have in my application's res/raw/ folder.
You cannot have folders inside of res/raw/. A resource directory can contain files, not subdirectories.
If you want to package a directory tree with your app, use assets/ and AssetManager, not raw resources.

android data save directories

My application is mostly c++ (using NDK) so I use fopen, fwrite, etc. standard functions to create and game save files and write into them.
When I use fopen("game.sav", "wb"), it appears that it's being created at path
/data/user/10/com.my.game/files/game.sav.
My app is multi-user. So I want to have a separated folders where users store their save-files. And instead of the path above I'd like to have paths like
/data/user/10/com.my.game/files/user0/game.sav,
/data/user/10/com.my.game/files/user1/game.sav, etc
My app's frontend is in Java, and when new user is being registered, I want to create a folder /data/user/10/com.my.game/files/user0/. But I don't know how to do it, because
final File newDir = context.getDir("user0", Context.MODE_PRIVATE);
results in path being created at /data/user/10/com.my.game/app_user0 that's a different path.
It is possible to create folders at /data/user/10/com.my.game/files/ and how ?
Simple way to do it, this code you can change it suit many conditions. If you know that your path is different from what getFilesDir() gets you then you can create a File first of all by using a path that you know and the last 2 lines of code will still be same.
File file = this.getFilesDir(); // this will get you internal directory path
Log.d("BLA BLA", file.getAbsolutePath());
File newfile = new File(file.getAbsolutePath() + "/foo"); // foo is the directory 2 create
newfile.mkdir();
And if you know the path to "files" directory:
File newfile2 = new File("/data/data/com.example.stackoverflow/files" + "/foo2");
newfile2.mkdir();
Both code works.
Proof of Working:

android assetManager

I need to get Absolute path to Folder in Assets.
Some like this for sd-card:
final String sdDir = Environment.getExternalStorageDirectory() + "Files";
What i do incorrect?
First I try to get path (in green ractangle) this way but I alwase get "False".
Then I comment this block and try to get path from getAssets().list();
But I get 3 folders witch I see first time.
I want to make massive like this "green" but I need to use files from assets:
Look the image
Help me to get absolute path to my Files folder.
I'm not exactly sure what you're trying to do, so I'll try to cover the bases, and maybe this will help.
If you are just trying to get a list of what's in your assets, then
use getAssets().list("Files"). (You have to use the subdirectory,
because of this).
If you are trying to get an absolute path to your assets directory
(or any subdirectory), you can't. Whatever is in the assets directory
is in the APK. It's not in external storage like on an SD card.
If you are trying to open up files in the assets directory, use
AssetManager.open(filename) to get the InputStream. Here,
filename should be the relative path from the assets directory.
EDIT
I'm not sure what you mean by "massive", but if you want to load the file black.png from assets instead of the SD card, then write this:
// must be called from Activity method, such as onCreate()
AssetManager assetMgr = this.getAssets();
mColors = new Bitmap[] {
BitmapFactory.decodeStream(assetMgr.open("black.png"));
// and the rest
};
Assets are stored in the APK file so there are no absolute path than your application can use. But, I would suggest to take a look at file:///android_asset. It might fits your needs. Here is a good example on how to display an Asset in a WebView.

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